1. Example 2 Determine the instantaneous value of a sine wave that has a positive slope passing through zero at 30  . The sine wave has the following values. Am = 15 V f = 50 Hz t = 15 mS Note : Multiply ω t by 57.2958 to convert Radians to Degrees. Working e = E m sin ( ω t + 30) = 15 x sin (( 2 π f t )+ 30) = 15 x sin (( 2 x 3.141593 x 50 x 0.015 x 57.2958) + 30 ) = 15 x sin (270 + 30) = 15 x sin 300 = 15 x -0.866 Answer= - 12.99 V

2. Example 2 Determine the instantaneous value of a sine wave that has a positive slope passing through zero at 30  . The sine wave has the following values. Am = 15 V f = 50 Hz t = 15 mS Note : Multiply ω t by 57.2958 to convert Radians to Degrees. Working e = E m sin ( ω t + 30) = 15 x sin (( 2 π f t )+ 30) = 15 x sin (( 2 x 3.141593 x 50 x 0.015 x 57.2958) + 30 ) = 15 x sin (270 + 30) = 15 x sin 300 = 15 x -0.866 Answer= - 12.99 V