Successfully reported this slideshow.
Upcoming SlideShare
×

# 4.1.1 Example Single

580 views

Published on

• Full Name
Comment goes here.

Are you sure you want to Yes No
• Be the first to comment

• Be the first to like this

### 4.1.1 Example Single

1. 1. 21 x lighting points 12 x double 10 A socket-outlets 1 x 15 A socket-outlet 1 x 230 V, 6.0 kW oven 1 x 230 V, 2.4 kW instantaneous water heater
2. 2. Load Description Current Calculation Demand Group of load allowance current (column 1) (given list) per unit (Amps) (column 2) 21 lighting 3A 3+2 5.0 A (i) points 12 double 10 A (1st 20) 10 + 5 15.0 outlets 5 A (next 20) B (i) (equivalent 24 sockets) 15 single-phase 10 A None 10.0 B (ii) outlets 50% (6000 / 240) x 12.5 C Oven rating (or x 0.5) 0.5 E Instantaneous 33.3 % (2400 / 240) x 3.33 HWS (or x 0.33) 0.33 Total demand current = 45.83 A
3. 3. Load Description Current Calculation Demand Group of load allowance current (column 1) (given list) per unit (Amps) (column 2) 21 lighting 3A 3+2 5.0 A (i) points 12 double 10 A (1st 20) 10 + 5 15.0 outlets 5 A (next 20) B (i) (equivalent 24 sockets) 15 single-phase 10 A None 10.0 B (ii) outlets 50% (6000 / 240) x 12.5 C Oven rating (or x 0.5) 0.5 E Instantaneous 33.3 % (2400 / 240) x 3.33 HWS (or x 0.33) 0.33 Total demand current = 45.83 A
4. 4. Load Description Current Calculation Demand Group of load allowance current (column 1) (given list) per unit (Amps) (column 2) 21 lighting 3A 3+2 5.0 A (i) points 12 double 10 A (1st 20) 10 + 5 15.0 outlets 5 A (next 20) B (i) (equivalent 24 sockets) 15 single-phase 10 A None 10.0 B (ii) outlets 50% (6000 / 240) x 12.5 C Oven rating (or x 0.5) 0.5 E Instantaneous 33.3 % (2400 / 240) x 3.33 HWS (or x 0.33) 0.33 Total demand current = 45.83 A
5. 5. Load Description Current Calculation Demand Group of load allowance current (column 1) (given list) per unit (Amps) (column 2) 21 lighting 3A 3+2 5.0 A (i) points 12 double 10 A (1st 20) 10 + 5 15.0 outlets 5 A (next 20) B (i) (equivalent 24 sockets) 15 single-phase 10 A None 10.0 B (ii) outlets 50% (6000 / 240) x 12.5 C Oven rating (or x 0.5) 0.5 E Instantaneous 33.3 % (2400 / 240) x 3.33 HWS (or x 0.33) 0.33 Total demand current = 45.83 A
6. 6. Load Description Current Calculation Demand Group of load allowance current (column 1) (given list) per unit (Amps) (column 2) 21 lighting 3A 3+2 5.0 A (i) points 12 double 10 A (1st 20) 10 + 5 15.0 outlets 5 A (next 20) B (i) (equivalent 24 sockets) 15 single-phase 10 A None 10.0 B (ii) outlets 50% (6000 / 240) x 12.5 C Oven rating (or x 0.5) 0.5 E Instantaneous 33.3 % (2400 / 240) x 3.33 HWS (or x 0.33) 0.33 Total demand current = 45.83 A
7. 7. Load Description Current Calculation Demand Group of load allowance current (column 1) (given list) per unit (Amps) (column 2) 21 lighting 3A 3+2 5.0 A (i) points 12 double 10 A (1st 20) 10 + 5 15.0 outlets 5 A (next 20) B (i) (equivalent 24 sockets) 15 single-phase 10 A None 10.0 B (ii) outlets 50% (6000 / 240) x 12.5 C Oven rating (or x 0.5) 0.5 E Instantaneous 33.3 % (2400 / 240) x 3.33 HWS (or x 0.33) 0.33 Total demand current = 45.83 A
8. 8. Load Description Current Calculation Demand Group of load allowance current (column 1) (given list) per unit (Amps) (column 2) 21 lighting 3A 3+2 5.0 A (i) points 12 double 10 A (1st 20) 10 + 5 15.0 outlets 5 A (next 20) B (i) (equivalent 24 sockets) 15 single-phase 10 A None 10.0 B (ii) outlets 50% (6000 / 240) x 12.5 C Oven rating (or x 0.5) 0.5 E Instantaneous 33.3 % (2400 / 240) x 3.33 HWS (or x 0.33) 0.33 Total demand current = 45.83 A