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# 4.1.3 Example Solution Three

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### 4.1.3 Example Solution Three

1. 1. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
2. 2. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
3. 3. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
4. 4. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
5. 5. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
6. 6. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
7. 7. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
8. 8. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
9. 9. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
10. 10. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
11. 11. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
12. 12. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
13. 13. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
14. 14. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool ﬁlter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool ﬁlter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5