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4.1.7 Example Domestic 3

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4.1.7 Example Domestic 3

  1. 1. Communal services loading Load Description Qty Current Calculatio Group of load per allowance n Demand (A) (given list) phase per unit (column 4) L1 L2 L3 Full connected (24 x 60) / 6.0 Lighting H 24 load 240 points 2 A per point up 2 x 6 12.0 10 A socket to a max of 15A I 6 outlet Total demand current per phase for communal 18.0 services
  2. 2. Communal services loading Load Description Qty Current Calculatio Group of load per allowance n Demand (A) (given list) phase per unit (column 4) L1 L2 L3 Full connected (24 x 60) / 6.0 Lighting H 24 load 240 points 2 A per point up 2 x 6 12.0 10 A socket to a max of 15A I 6 outlet Total demand current per phase for communal 18.0 services
  3. 3. Communal services loading Load Description Qty Current Calculatio Group of load per allowance n Demand (A) (given list) phase per unit (column 4) L1 L2 L3 Full connected (24 x 60) / 6.0 Lighting H 24 load 240 points 2 A per point up 2 x 6 12.0 10 A socket to a max of 15A I 6 outlet Total demand current per phase for communal 18.0 services
  4. 4. 154.4 + 18.00 = 172.4 A
  5. 5. The following explanation is not in the workbook

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