You are requested to write the SQL commands to perform the following.pdf

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Write a function Noodles(), with int parameter minutes, and void return type. Print \"N minutes\" for each minute in decreasing order, where N is the number of minutes, followed by \"Done\".End with a newline. The number of minutes is generated from a random number generator that selects between 1-3 minutes. The seed for the random number generator is input by the user. Example output for minutes = 2: Solution #include #include using namespace std; void Noodles(int); int main() { int minutes = 0; int seed; cout<<\"enter random seed\"<<\"\ \"; cin >> seed; // reading seed srand(seed); minutes=rand()%3; // random number generation cout<.

Education

You are requested to write the SQL commands to perform the following operations on the tables
in the CONSTRUCTION database.
TABLES IN THE CONSTRUCTION DATABASE
WORKER Table
Primary key: WORKER_ID
Foreign keys: none
WORKER_ID
WORKER_NAME
HRLY_RATE
SKILL_TYPE
1235
Faraday
12.50
Electric
1412
Nemo
13.75
Plumbing
2920
Garret
10.00
Roofing
3231
Mason
17.40
Framing
- etc.-
ASSIGNMENT Table
Primary key: WK_ID + BLDG_ID + START_DATE
Foreign keys: WK_ID (references the WORKER table)
BLDG_ID (references the BUILDING table)
WK_ID
BLDG_ID
START_DATE

NUM_DAYS
1235
321
2016-10-10
5
1412
321
2016-10-01
10
1235
515
2016-10-17
22
2920
460
2016-12-09
18
- etc.-
BUILDING Table
Primary key: BLDG_ID
Foreign keys: none
BLDG_ID
BLDG_ADDRESS
TYPE
QLTY_LEVEL
STATUS
321
123 Elm
Office
2
2
435
456 Maple
Retail
1
1

515
789 Oak
Residence
3
1
460
1011 Birch
Office
2
3
- etc.-
Quality Level is a major concern in building construction. List the number of buildings that have
a quality level of 2 or below and the names of employees working at these buildings.
WORKER_ID
WORKER_NAME
HRLY_RATE
SKILL_TYPE
1235
Faraday
12.50
Electric
1412
Nemo
13.75
Plumbing
2920
Garret
10.00
Roofing
3231
Mason
17.40
Framing
- etc.-
Solution

CREATE TABLE WORKER
(
WORKER_ID NUMBER(5) NOT NULL,
WORKER_NAME VARCHAR2(100),
HRLY_RATE NUMBER(4,2),
SKILL_TYPE VARCHAR2(50),
CONSTRAINT WORKER_PK PRIMARY KEY (WORKER_ID)
);
CREATE TABLE BUILDING
(
BLDG_ID NUMBER(4),
BLDG_ADDRESS VARCHAR2(200),
TYPE VARCHAR2(50),
QLTY_LEVEL INT,
STATUS INT,
CONSTRAINT BUILDING_PK PRIMARY KEY (BLDG_ID)
);
CREATE TABLE ASSIGNMENT
(
WK_ID NUMBER(5),
BLDG_ID NUMBER(4),
START_DATE DATE,
NUM_DAYS INT,
CONSTRAINT ASSIGNMENT_PK PRIMARY KEY (WK_ID,BLDG_ID,START_DATE),
CONSTRAINT FK_WORKER
FOREIGN KEY (WK_ID)
REFERENCES WORKER(WORKER_ID),
CONSTRAINT FK_BUILDING
FOREIGN KEY (BLDG_ID)
REFERENCES BUILDING(BLDG_ID)
);
SELECT COUNT(B.BLDG_ID), W.WORKER_NAME
FROM

BUILDING B, WORKER W
WHERE WORKER.WORKER_ID IN (SELECT WK_ID FROM ASSIGNMENT WHERE
B.BLDG_ID IN
(SELECT BLDG_ID FROM BUILDING WHERE QLTY_LEVEL < 3))
;

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The circuit below shows 2 batteries and 3 equal resistors. E1= 35.8 volts, and E2=19.3 volts. Each resistor is 20.4 ohms. Find the power P2 dissipated in the resistor R2 . Enter your answer in Watts. QUESTION 6 5 pointsSave Answer The circuit below shows 2 batteries and 3 equal resistors. E1 35.8 volts, and E2-19.3 volts. Each resistor is 20.4 ohms. The circuit below shows 2 batteries and 3 equal resistors. E17 35.8 volts, and E2=19.3 volts. Each resistor is 20.4 ohms Find the power P2 dissipated in the resistor R2. Enter your answer in Watts. R1 2 R2 3 R3 58% Solution Here, Here, for the current flowing through the R2 current through R2 = E2/R2 current through R2 = 19.3/20.4 A current through R2 = 0.946 A Now , for the power dissipated through R2 power dissipated through R2 = I2^2 * R2 power dissipated through R2 = 0.946^2 * 20.4 power dissipated through R2 = 18.26 W the power dissipated through R2 is 18.26 W.

The inflation rate of Country Alpha in 2014 was 3.5. Due to their w.pdf

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