§ 7.3 7.6 Which member of the following pairs is likely to decompose .pdf

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Write the converse, inverse, and contrapositive of the statement. If you clean your room, then you can play outside. Solution Coverse statement : \"If you can play outside then you clean your room.\" Contrapositive statement : \" If you can not clean your room, then you can not play outside.\" Inverse statement : \" If you can not play outside, then you can not clean your room.\".

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§ 7.3 7.6 Which member of the following pairs is likely to decompose at lower temperature? (a)
Li2CO and K2CO (decompose to M20 and CO2) (b) Csls and [N(CH3)]l (decompose to MI and
I2)
Solution
Decomposition temperature of k2co3 is higher than li2co3 Due to stable carbonate.
CsI3 have lower decomposition temperature as other one is complex compound is thermally
stable

Given 8 distinct integers from the set {1, 2, . . . , 16}, prove that there exists k such that ai aj = k has at least 3 distinct solutions (ai , aj ) ? Solution For any k (unless the K is zero), at least 3 distinct solutions need not be existing. Let\'s look at the next most favourable case If k= 2; We have to consider the case where the number of solutions of ai-aj=2 are minimum since we have to show that at least 3 distinct solutions exist (which means even in the most unfavourable case for a chosen k there will be 3 distinct solutions satisfying the equation ai-aj=2) If k = 2; we start by taking numbers that are not at all 2 units apart from each other; So we start with 1 and move 3 units successively ahead 1, 4, 7, 10,13, 16; Now we notice that these 6 numbers are of 3k+1 form; remaining numbers can be any 2 ranomdly selected say 2 and 11; we get 4-2 = 2 and 13-11=2; Hence only 2 distinct solutions are possible..

Find the sum of the infinite geometric series if it exists. (If an .pdf

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Find the general solution to the following differential equation. d^2y/dx^2 - 2 dy/dx - 35 y = 1 + 13sin x - e^3x. Solution Ans- A differential equation is a mathematical equation that relates some function with its derivatives. In applications, the functions usually represent physical quantities, the derivatives represent their rates of change, and the equation defines a relationship between the two. Because such relations are extremely common, differential equations play a prominent role in many disciplines including engineering, physics, economics, and biology. In pure mathematics, differential equations are studied from several different perspectives, mostly concerned with their solutions—the set of functions that satisfy the equation. Only the simplest differential equations are solvable by explicit formulas; however, some properties of solutions of a given differential equation may be determined without finding their exact form. If a self-contained formula for the solution is not available, the solution may be numerically approximated using computers. The theory of dynamical systems puts emphasis on qualitative analysis of systems described by differential equations, while manynumerical methods have been developed to determine solutions with a given degree of accuracy..

A new class will be added to the startup package to start up the eve.pdf

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A new class will be added to the startup package to start up the event-driven application. This should be a small class to create the main window (JFrame) and make it visible. The other new classes are to be placed in a new package called ‘gui’. When the project first starts, a window should appear and give the user six options. Five of the options will be buttons to press, while the sixth will be a prompt and a text field. Each of these options will be discussed. The first button will be one to initiate the task of adding a flight to the system. When it is pressed, a new window should appear. In this window, there should be prompts and fields for the entry of the flight’s number, width and capacity. Provide a Submit button that will cause the data to be collected from the fields and passed to the command to add the flight. If the command fails, the error message should appear in the window, and the window remains visible for the user to correct the information. If the command is successful, the window should disappear, so that the user is returned to the main menu. The second button is for the addition of a new passenger. Its affect will be very similar to the add flight button: a new window will appear for the entry of the data for the new passenger. This time, instead of a Submit button, the command to add a passenger should be created and executed whenever the user presses the Enter key in either one of the fields. If the addition of a passenger fails, the error message should appear in the window for the user to correct the data. If the addition was successful, the window to add a passenger should remain visible (with the fields blank) for the user to enter another passenger. The user can close the window via the X in the upper right corner, or you can supply a close button (the close button is optional). The third and fourth buttons are to display the all passengers in the system, and to display all the flights in the system. In both cases, when the button is pressed, a new window should appear with the information. It should have a 2-D field to display the information, and scroll bars should be provided in case there is too much information for the field. This can be done by and put myPane into a suitable JPanel, or directly into a JFrame. The preferred size of the scroll pane may want to be set to a suitable size if it is placed in a JPanel. If a scroll pane is directly added into a JFrame, it will take on the size of the available window. Don’t worry about formatting the text in a fancy way. The fifth button is to terminate the project. The project can also be terminated by the X in the right hand corner of the main window. However, selecting the X in another window should just close that window (the default action for that (built in) button). The sixth option in the main window are a prompt and a text field to handle an existing flight. When the user enters a number in the field (presumably the number of a flight) and presses the En.

Are these statements regarding Rhizobacteria true Plant Growth P.pdf

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Are these statements regarding Rhizobacteria true ?: Plant Growth Promoting Rhizobacteria, known as PGPRs, are bacteria that colonize the roots of plants through the formation of nodules. They are beneficial to the plant because they fix Nitrogen, and stimulate the plant to grow. There are many kinds of bacteria found in the root nodules of plants, but not all have the ability to stimulate the formation of nodules or promote growth. In order to find out what kinds of bacteria were found in the nodule of the Adzuki bean plant, we obtained an Adzuki bean plant grown in soil from Temescal canyon, and isolated bacteria from the nodule. Anything incorrect about what is said above? Solution Symbiosis: It is an ecological relationship between two different species organisms that live together in direct intimate contact. Ex: Legumes Nitrogen fixation Formula: Bacteria reduce N2 (nitrogen) to NH3 (ammonia). Legume Species: Legumes are the plants that forms a relationship with rhizbacteria (N fixing bacteria). Ex: Beans, peanuts, etc... Rhizobacteria: The statements above give in the question is True. Explanation: It is a soil bacteria lives closely to the plant roots in the soil. It capable to form nodules and inside the nodules rhizobacteria are present. Rhizosphere activites: It is Biological N2 fixation bacteria and also known as a PGPRs(Plant Growth Promoting Rhizobacteria). PGPR\'s are the bacteria that colonize the roots of plants through the formation of nodules. They are beneficial to the plant because they fix Nitrogen, and stimulate the plant to grow. This bacteria increasing plant nutrient availability of P, Mn, Fe, Z, Cu and controlling deleterious microorganisms. It improves soil aggregation. Adzuki bean plant: The statements above give in the question is True. Explanation: Adzuki bean, Vigna angularis (Willd.) is an important legume crop, It is widely used as a diet due to its highest protein and low fat content. In developing countries Europe and America it is used highly. it is valued for its high protein adzuki bean did not increase yield with inorganic N fertilization, indicating the priority of symbiotic nitrogen fixation (SNF). In this plant symbiosis (N2 fixation) is taken placed with some bacterial strains of the genera Bradyrhizobium, Rhizobium and Sinorhizobium. The native rhizobial strains are generally poor efficient in N fixation in this plant..

1. Prices may be different between two countries whenA. Both count.pdf

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1. Prices may be different between two countries when A. Both countries have the same endowment but different preferences B Both countries have the same preferences but different endowments C There are differences in endowment and preference D (a) or (b) may be true E All of the above Solution Ans is E As prices are determined by demand and supply where demand comes from preferences and supply comes from endowment. Thus both prefernce and endowment determines price. And thus difference in any one factor leads to different pricing in the market..

[10 points]Add the.pdf

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You are requested to write the SQL commands to perform the following.pdf

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Write a function Noodles(), with int parameter minutes, and void return type. Print \"N minutes\" for each minute in decreasing order, where N is the number of minutes, followed by \"Done\".End with a newline. The number of minutes is generated from a random number generator that selects between 1-3 minutes. The seed for the random number generator is input by the user. Example output for minutes = 2: Solution #include #include using namespace std; void Noodles(int); int main() { int minutes = 0; int seed; cout<<\"enter random seed\"<<\"\ \"; cin >> seed; // reading seed srand(seed); minutes=rand()%3; // random number generation cout<.

write a prgoram that displays four images or objects in a 2 x 2 grid.pdf

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Which of the three types of activities reported on the statement of cash flows is the MOST critical for a company\'s long-tetm OA. operating activities O B. investing activities O C. financing activities O D. noncash investing and financing activities Solution A. Operating activities This are the functions of business related to the provision of its offering. It is an activity that directly affects an orgainzation\'s cash inflows and outflows, and determine its net income..

Which mechanism does not repair double strand breaks? recombination photolyase followed by photoreactivation synthesis-dependent strand annealing (SDSA) non-homologous end joining The fluctuation test, regarding the origin of mutations, shows that: Mutations occur randomly, prior to selective pressure The mutation rate fluctuates greatly from organism to organism The mutation rate fluctuates greatly from cell to cell The mutation rate is fairly even across organisms The P element in Drosophila: is active in all cells during embryogenesis is a functional transposon carrying the transposase gene is active when crossing a P female with any male is a functional retrotransposon carrying the reverse transcriptase gene During bacterial conjugation, the F element: is transferred as a double stranded molecule is transferred as a single stranded molecule. 3\' end first enters the donor is transferred as a single stranded molecule. 5\' end first enters the donor is transferred as a single stranded molecule, the leading end is random Which of the following could result in a frameshift mutation? deletion of one nucleotide deletion of three nucleotides deletion of six nucleotides incorporation of a base analog Solution 1Repair of double strand DNA break is a very serious problem if not solved it may cause mutation. So there is several repair mechanisms are present. in the above question all mechanisms can repair DNA break. recombination repair is of two types homologous recombination and NHEJ ( non homologous end joining). in NHEJ no homologous template is used and break ends are linked directly. photolyase is a enzyme activated by light it repairs the mutagenic effect caused by UV light. such as formation of THYMINE dimer. SDSA or synthesis dependent strand annealing is a repair mechanism seen in yeast. in this process repair is initiated by resection of a double strand break to provide 3\' single stranded DNA..

Which of the three types of activities reported on the statement of c.pdf

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What led to the demise of ‘conventional Keynesian wisdom’ in the mid 1970s and why did the theory of rational expectations make the ‘monetarist experiment’ in the early 1980s more attractive to politicians? Solution theory has its origins in the study of business cycles and monetary theory.[1][2] In general, early theorists believed monetary factors could not affect real factors such as real output. John Maynard Keynes attacked some of these \"classical\" theories and produced a general theory that described the whole economy in terms of aggregates rather than individual, microeconomic parts. Attempting to explain unemployment and recessions, he noticed the tendency for people and businesses to hoard cash and avoid investment during a recession. He argued that this invalidated the assumptions of classical economists who thought that markets always clear, leaving no surplus of goods and no willing labor left idle.[3] The generation of economists that followed Keynes synthesized his theory with neoclassical microeconomics to form the neoclassical synthesis. Although Keynesian theory originally omitted an explanation of price levels and inflation, later Keynesians adopted the Phillips curve to model price-level changes. Some Keynesians opposed the synthesis method of combining Keynes\'s theory with an equilibrium system and advocated disequilibrium models instead. Monetarists, led by Milton Friedman, adopted some Keynesian ideas, such as the importance of the demand for money, but argued that Keynesians ignored the role of money supply in inflation.[4] Robert Lucas and other new classical macroeconomists criticized Keynesian models that did not work under rational expectations. Lucas also argued that Keynesian empirical models would not be as stable as models based on microeconomic foundations..

111. Definition Explanation (15) 1. Job speciation SolutionIII.pdf

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111. Definition Explanation (15%) 1. Job speciation Solution III. 1. Job specification refers to job description which includes the work that needs to be performed, roles and responsibilities, and the minimum qualification required to perform the job effectively. Job specification is one of the essential part of job analysis information. Job analysis helps in determining job requirements and is comprehensive in nature. It focus on developing the techniques of doing a job and helps in recruitment and selection, appraisal, job evaluation, job designing, compensation, training and development and to assess the job worth..

What are the pros and cons of using exFAT and ReFS on a Windows 2012.pdf

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Using C++, Write a program segment that dynamically allocates an array large enough to hold a user defined number of (double) test scores. Once all the scores are entered, the array should be passed to a function that calculates and returns the average score. Use Pointer notation whenever possible. double calculateAverage(function parameter goes here) // int main() { int size; double * ptrScores; // complete rest of the main function following the directions above } double calculateAverage(function parameter goes here) { // complete the rest of this function following the directions above } Solution Program: #include #include using namespace std; double calcAverage(double, int); void bubbleSort(double scores[], int numScores); int main() { double *scores, // To dynamically allocate an array total = 0.0, // Accumulator average; // To hold average scores int numScores, // To hold the number of days of scores count; // Counter variable // Get the number of days of scores. cout << \"How many days of test scores do you wish \"; cout << \"to process? \ \"; cin >> numScores; // Dynamically allocate an array large enough to hold // that many days of scores amounts. scores = new double[numScores]; // Get the scores figures for each day. cout << \"Enter the test scores below.\ \"; for (count = 0; count < numScores; count++) { cout << \"Day \" << (count + 1) << \": \"; cin >> scores[count]; } // Calculate the total scores for (count = 0; count < numScores; count++) { total += scores[count]; } bubbleSort(scores,numScores); average = calcAverage(total, numScores); cout << endl; for (count = 0; count < numScores; count++) { cout<<\"Day \"<<(count+1)<<\": \"<< *(scores + count) < array[count + 1]) { temp = array[count]; array[count] = array[count + 1]; array[count + 1] = temp; swap = true; } } } while (swap); }.

What led to the demise of ‘conventional Keynesian wisdom’ in the mid.pdf

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What are the pros and cons of using exFAT and ReFS on a Windows 2012 server? How do they compare to NTFS? Solution ReFS: Pros: 1.unique in private cloud manipulations 2.also in age of big data 3.storage space assits the mirroring and striping. cons: 1.it is unable to utilize for booting drives. 2.seen only in case of windows server 2012 3.unable to format the removable drives. Hence due to all the above prons and cons the REFS are used and prefered in widows server 2012 . ........................................................................................................................................................... ........... NFTS pros: 1.File compression 2.Advanced auditing cons: The NFTS are unable to manipulate on REFS disks though several features operate on REFS like bitlocker..

What is the connection between relative frequency and probability.pdf

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Waterways prepared the balance sheet and income statement for the irrigation installation division for last year. Now the company needs to prepare a cash flow statement for the same division. The comparative balance sheets for Waterways Corporation’s Irrigation Installation Division for last year and the prior year and the income statement for last year are presented below. (Note: Work in Process is a current asset and should be treated as any other current asset.) Additional information: 1. Waterways sold a piece of company equipment for $30,000. The equipment had been used for six years. It had cost $100,000 when purchases and had a 10-years life and a $10,000 salvage value. Straight-line depreciation was used. 2. Waterways purchased new equipment costing $200,000. 3. The division paid $100,000 in dividends. Waterways Corporation - Installation Division Income Statement For the Year Ending December 31, Last Year Sales $5,536,077 Less: Cost of goods sold 3,132,777 Gross Profit 2,403,300 Operating expenses: Advertising $52,000 Insurance 382,000 Salaries and wages 594,650 Depreciation 72,500 Other operating expenses 30,500 Total operating expenses 1,131,650 Income from operations 1,271,650 Other income Loss on sale of equip (16,000) Other expenses Interest expense (12,200) Net other income and expenses (28,200) Income before income tax 1,243,450 Income tax expenses 373,035 Net income $870,415 Waterways Corporation - Installation Division Balance Sheet December 31 Assets Last Year Prior Year Current assets Cash $792,306 $746,681 Accounts receivable 680,750 542,685 Work in process 680,450 0 Inventory 16,750 7,500 Prepaid expenses 71,500 42,590 Total current assets 2,241,756 1,339,456 Property, plant, and equipment Furnishings 40,416 40,416 Equipment 900,200 800,200 Buildings 450,000 450,000 Land 300,000 300,000 Accumulated depreciation (503,704) (485,204) Total property, plant, and equipment 1,186,912 1,105,412 Total Assets $3,428,668 $2,444,868 Liabilities and Stockholders\' Equity Current liabilities Accounts payable $156,300 $128,360 Income taxes payable 100,344 79,989 Wages payable 600 1,984 Interest payable 1,200 0 Other current liabilities 14,520 15,246 Revolving bank loan payable 16,000 0 Total current liabilities 288,964 225,579 Long-term liabilities Notes payable 150,000 0 Total liabilities 438,964 225,579 Stockholders\' equity Common stock 1,250,000 1,250,000 Retained earnings 1,739,704 969,289 Total stockholders\' equity 2,989,704 2,219,289 Total liabilities and stockholders\' equity $3,428,668 $2,444,868 Instructions: For last year: a. Prepare a statement of cash flow using the indirect method. b. Determine free cash flow. Waterways Corporation - Installation Division Income Statement For the Year Ending December 31, Last Year Sales $5,536,077 Less: Cost of goods sold 3,132,777 Gross Profit 2,403,300 Operating expenses: Advertising $52,000 Insurance 382,000 Salaries and wages 594,650 Depreciation 72,500 Other operating expenses 30,50.

What factors led President Truman to support the creation of Israel .pdf

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var testScores = []; testScores[0] = [80, 82, 90, 87, 85]; testScores[1] = [79, 80, 74, 82, 81]; testScores[2] = [93, 95, 89, 100, 85]; testScores[3] = [60, 72, 65, 71, 79]; This code creates a tabular structure that has 5 rows and 4 columns 4 rows and 5 columns 4 rows and 4 columns 5 rows and 5 columnsa. 5 rows and 4 columnsb. 4 rows and 5 columnsc. 4 rows and 4 columnsd. 5 rows and 5 columns Solution Here is the given structure:- var testScores = []; testScores[0] = [80, 82, 90, 87, 85]; testScores[1] = [79, 80, 74, 82, 81]; testScores[2] = [93, 95, 89, 100, 85]; testScores[3] = [60, 72, 65, 71, 79]; And this will create a tabular structure that has 4 rows and 5 columns.

unixlinux - kernelexplain yield in user spaceexplain yield in k.pdf

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this is java. problem. i already make employee class. but i can not make employeetester class. i want to know Employeetester class. EmployeeTester class: Write a main method that produces a dialog like this: -->Enter a name : dave -->Enter hours worked (7 values separated by spaces): 5 2 1 0 0 3 3 Output: dave worked for 5 day(s) for a total of 14.0 hours. -->Enter a day of the week (0-6): 2 Output: Hours worked on day 2 is 1.0 ************and this is my employee class.********************** public class Employee { private double[] hours=new double[7]; private String name; public Employee(String name){ this.name=name; } public double getHours(int day){ return hours[day]; } public void setHours(int day,double hrs){ hours[day]=hrs; } public int numDaysWorked(){ int totalD=0; for(int i=0;i<7;i++){ if(hours[i]==0.0){ }else{ totalD=totalD+1; } } return totalD; } public double totalHours(){ double totalH=0; for(int i=0;i<7;i++){ if(hours[i]==0.0){ }else{ totalH=totalH+hours[i]; } } return totalH; } public String toString(){ return name+\" Worked \" +numDaysWorked() + \" day(s) for a total of \"+totalHours() + \"hours\ .\"; } } Solution Note: I have made some changes to the Employee class which have provided to meet the required output.Thank You. ________________________ Employee.java public class Employee { //Creating an double type array of size 7 private double[] hours=new double[7]; //Declaring variable private String name; //Parameterized constructor public Employee(double[] hours, String name) { super(); this.hours = hours; this.name = name; } //Setters and getters public double[] getHours() { return hours; } public void setHours(double[] hours) { this.hours = hours; } public String getName() { return name; } public void setName(String name) { this.name = name; } //This method will calculate the no of days worked by an employee public int numDaysWorked(){ int totalD=0; for(int i=0;i<7;i++){ if(hours[i]!=0.0){ totalD=totalD+1; } } return totalD; } //This method will return the total no of hours worked by an employee public double totalHours(){ double totalH=0; for(int i=0;i<7;i++){ //Calculating the total hours worked totalH=totalH+hours[i]; } return totalH; } //this method will return the hours worked on particular day of an employee public double hoursWorkedOnParticularday(int day) { return hours[day]; } //this method will display the contents of an object inside it public String toString(){ return name+\" Worked \" +numDaysWorked() + \" day(s) for a total of \"+totalHours() + \" hours\ .\"; } } ____________________ EmployeeTester.java import java.util.Scanner; public class EmployeeTester { public static void main(String[] args) { //Declaring variables String name; double tot_hours=0; int no_of_days_worked=0; int week_day=0; //Scanner object is used to get the inputs entered by the user Scanner sc=new Scanner(System.in); //Creating an double type array of size 7 double hours[]=new double[7]; //getting the name of an employee entered by the us.

this is java. problem.i already make employee class. but i can not.pdf

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The price p and the quantity x sold of a certain product obey the demand equation x =- 8p + 80, 0 p l 10 (a) Express the revenue R as a function of x. (b) What is the revenue if 24 units are sold? (c) What quantity x maximizes revenue? What is the maximum revenue? (d) What price should the company charge to maximize revenue? Solution A. Revenue = Price*quantity x = -8p + 80, and 0 <= P <= 10 8p = 80 - x p = -x/8 + 10 R = p*x R = x*(-x/8 + 10) R = -x^2/8 + 10x B. x = 24 R = -x^2/8 + 10x R = -24^2/8 + 10*24 R = 168 C. In this parabolic equation R = -x^2/8 + 10x a = -1/8, b = 10 maximize x = -b/2a x = -10/(2*(-1/8)) = 40 maximum revenue R = -x^2/8 + 10x R = -40^2/8 + 10*40 = 200 D. p = -x/8 + 10 so for x = 40 p = -40/8 + 10 = 5 price = 5.

This fall Millie finally repaid her student loan. She originally bor.pdf

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The preprocessor is part of vi checks for correct C++ syntax converts Unicode characters to ASCII all of the above none of the above Which of the following is true in C++? A literal is an expression A literal is an lvalue A literal is an rvalue all of the above none of the above Solution Answer: Preprocessor is used in C++ to process the data before the compilation. 2) d) All of the above , Literal is written inside the code and is not been altered by the program , it remains as such . It can be any expression , lvalue , rvalue ..

The term refers to a. Global Analysis of the proteins produced in .pdf

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The issues of inflation, unemployment, and business cycles are Multiple Choice major topics of macroeconomics. not relevant to the U.S. economy the primary focus of microeconomics. Solution a) Major topics of macroeconomics. Macroeconomics is that branch of economics which deals in economic relations and economic problems at the level of economy as a whole. It includes inflation, national income, government budget, unemployment, business cycle..

The inflation rate of Country Alpha in 2014 was 3.5. Due to their w.pdf

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The circuit below shows 2 batteries and 3 equal resistors. E1= 35.8 volts, and E2=19.3 volts. Each resistor is 20.4 ohms. Find the power P2 dissipated in the resistor R2 . Enter your answer in Watts. QUESTION 6 5 pointsSave Answer The circuit below shows 2 batteries and 3 equal resistors. E1 35.8 volts, and E2-19.3 volts. Each resistor is 20.4 ohms. The circuit below shows 2 batteries and 3 equal resistors. E17 35.8 volts, and E2=19.3 volts. Each resistor is 20.4 ohms Find the power P2 dissipated in the resistor R2. Enter your answer in Watts. R1 2 R2 3 R3 58% Solution Here, Here, for the current flowing through the R2 current through R2 = E2/R2 current through R2 = 19.3/20.4 A current through R2 = 0.946 A Now , for the power dissipated through R2 power dissipated through R2 = I2^2 * R2 power dissipated through R2 = 0.946^2 * 20.4 power dissipated through R2 = 18.26 W the power dissipated through R2 is 18.26 W.

The issues of inflation, unemployment, and business cycles are Multip.pdf

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The data frame Econ contains the following variables: Year, Income, Population, which represent the year of each observation, the total income earned by everyone in the US in that year, and the total population of the US respectively. How would you create a variable in the data frame named AvgIncome that represents the average income earned by each person in the USA for each year? (Remove any spaces) Solution Average Income = Total Income / Total Population ( of that year) Therefore the variable in the table can be created using the following formula and can be added to the table..

Need to make a program using the scanner class that outputs F to C 3.pdf

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matching question: a)africa b)Asia c)America d)lesser ape e)great ape Geographic location category 1)Hylobate 2)Pongo 3)Gorilla a)flowers b)fruit c) leaves d)everything e)grass 1)Folivorous primates eat 2)Omnivorous primates eat 3)Frugivorous primates east Solution Matching question: 1) Hylobate- geographical location is b) Asia. - belong to category d) lesser ape. 2) Pongo- geographical location is b) Asia. They are native to Indonesia. - belong to category e) great ape. 3) Gorilla- geographical location is a) Africa. They inhabit parts of central Africa. - belong to category e) great ape. 1) Folivorous primates eat c) leaves. 2) Omnivorous primates eat d) everything. 3) Frugivorous primates eat b) fruit..

Name the process by which RNA is used to make a polypeptide or prote.pdf

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Mansion Corp. sells its product for $500 per unit. Budgeted sales units for the next three months are: March, 5,000 ; April, 6,250; May, 7,750. The inventory on March 1st is 2,500 units. The company wants to maintain 50% of the next month’s sales in inventory. Calculate the budgeted production for the second month of the quarter. Solution Beginning inventory(0.5*6250) 3125 units Add:production(balance)(6250+3875-3125) 7000 units. Less:ending inventory(0.5*7750) (3875) Sales 6250 units.

Recall the steps whereby recombinant DNA technology was used to make .pdf

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QUESTION 19 Suppose that there are diminishing returns to capital. Suppose also that two countries are the same except one has less capital and so less real GDP per person. Suppose that both increase their saving rate from 3 percent to 4 percent. In the long run a. both countries will have higher levels of real GDP per person, and the temporary increase in growth in the level of real GDP per person will have been greater in the country with less capital b. both countries will have permanently higher growth rates of real GDP per person, and the growth rate will be higher in the country with less capital. c. both countries will have higher levels of real GDP per person, and the temporary increase in growth in the level of real GDP per person will have been greater in the country with more capita d. both countries will have permanently higher growth rates of real GDP per person, and the growth rate will be higher in the country with more capital QUESTION 20 In 2010, the imaginary nation of Mainland had a population of 6,000 and real GDP of 120,000. In 2011 the population was 6,200 and real GDP of 128,960. Over the year in question, real GDP per person in Mainland grew by a. 2 percent, which is about the same as average U.S. growth over the last one-hundred years. b.4 percent, which is high compared to average U.S. growth over the last one-hundred years c.2 percent, which is high compared to average U.S. growth over the last one-hundred years. d.4 percent, which is about the same as average U.S. growth over the last one-hundred years Solution Given, Income of the consumer = $50 Now, given that price of marshmallows = $2.50 Assume, if consumer was to spend all of his income on Marshmallow, then Maximum quantity of marshmallow he can have = 50/2.50 = 20 units. Thus, the consumer can be on any of the income curve which start from the point (0,20) on the y axis. Thus, consumer will be on either of 3 indifference curves, i.e. the ones on which we have points B, C and D. Now, let’s try to see what all conditions are there for Chocolate chips and then see what the optimum decision for the consumer in the given scenario would be? If you look at the graph, we can see the budget lines which are starting from point (0,20). Thus, there are only 2 budget lines possible in this case, one which is from (0,20) and (10,0) and the other one being from (0,20) to (20,0). Now, let’s go one by one, Here if P = $2.50 for Chips, then if consumer spend all of his budget on Chips, then he would on the point (20,0) or he will be on the outermost budget line. Total spending on chips = $2.5 * 10 = $25 Remaining budget = 50-25 = $25 Quantity of Marshmallows that can be bought = $25 / 2.5 = 10 units Thus, optimum solution here = (10,10) You can do the similar calculations for other options as well and see if we have solutions coming within the range and whether consumer lying somewhere on the outermost two budget lines..

Rex and Felix are the sole shareholders of the Dogs and Cats Corpora.pdf

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Please show work with the answer Gerald plans to prepare steak picado for a dinner party of 25. He will use a recipe for 4. When Gerald shops for the ingredients of the recipe, his best choice would be to use 1. D. 4. his calculator to figure approximate ingredients, and then round amounts to the nearest whole number. paper-and-pencil to figure approximate amounts of ingredients and buy that amount. mental math to get a rough estimate of ingredients and then double estimate to be on the safe side. a spreadsheet to convert the recipe for 25 so that he buys exactly what he needs. a calculator or pencil-and-paper to convert the recipe and then round, up the ingredients to ensure he has enough for 25 people. Solution Gerald plans to prepare steak picado for a dinner party for 25. Since he has arecipe for 4 and since 25/4 = 6.25, he needs a calculator or pencil -and-paper to convert the recipe ( by multiplying each ingrdient in the recipe for 4 by 6.25)and then round up the ingredients to ensure that he has enpugh for 25 people. Option E is the appropriate answer..

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Part A) As a technician in a large pharmaceutical research firm, you need to produce 150. mL of a potassium dihydrogen phosphate buffer solution of pH = 6.77. The pKa of H2PO4 is 7.21. You have the following supplies: 2.00 L of 1.00 M KH2PO4 stock solution, 1.50 L of 1.00 M K2HPO4 stock solution, and a carboy of pure distilled H2O. How much 1.00 M KH2PO4 will you need to make this solution? (Assume additive volumes.) Express your answer to three significant digits with the appropriate units. Part B) If the normal physiological concentration of HCO3 is 24 mM, what is the pH of blood if PCO2 drops to 33.0 mmHg ? Extra Info: The Henderson-Hasselbalch equation in medicine Carbon dioxide (CO2) and bicarbonate (HCO3) concentrations in the bloodstream are physiologically controlled to keep blood pH constant at a normal value of 7.40. Physicians use the following modified form of the Henderson-Hasselbalch equation to track changes in blood pH: pH=pKa+log([HCO3]/(0.030)(PCO2)) where [HCO3] is given in millimoles/liter and the arterial blood partial pressure of CO2 is given in mmHg. The pKaof carbonic acid is 6.1. Hyperventilation causes a physiological state in which the concentration of CO2 in the bloodstream drops. The drop in the partial pressure of CO2constricts arteries and reduces blood flow to the brain, causing dizziness or even fainting. Solution We use Henderson-Hasselbalch equation. pH= pKA + log [Base] / [Acid] 6.79 = 7.21 + log [HPO4] / [H2PO4] log [HPO4] / [H2PO4] = -0.42 [HPO4] / [H2PO4] = 0.380 / 1.00 But, we know that [HPO4] + [H2PO4] = 1.00 M [HPO4] = 1.00 - [H2PO4] 0.380 = [1.00 - [H2PO4] ] / [H2PO4] 0.380 [H2PO4] = 1.00 - [H2PO4] 1.380 [H2PO4] = 1.00 [H2PO4] = 0.725 M We have 2.00 L of 1.00 M KH2PO4 stock solution. We need 150.0 mL of 0.725 M Thus, M1V1 = M2V2 (1.00)(V1) = (0.725) (150) V1 = 108.75 mL = 109 mL Thus, we need 109 mL of 1.00 M KH2PO4 is needed..

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Let G be a finite group. Show that if G has exactly one nontrivial subgroup, then order of G is p^2 for some prime p. Solution Lagrange \'s theorem in group theory states that : ( G ,* ) is a group , His a sub group of G then O (H) divides O(G) using the above fact we conclude that : If O(G) = n then order of the subgroups are the factors of \'n\' ie if 1, a, b , ------n are the distinct factors of \'n then there are subgroups of order 1,a,b, ---n the proper subgroups will have order a,b , there is only one subgroup => the factors of \'n\' are 1,a,n => 1xn=a2 =p2 where \'p \' is a prime no Example n = 9 only one proper subgroup of order =3 n= 25 ---------------- \'\'-----------------------=5 and so on.

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