1) The document discusses the motion of a model train T travelling around a circular track with radius a and constant speed u. It derives an expression for the rate of change of the angle θ between the train and a point N distance x from the track, in terms of a, u, x, and the angle φ between NT and the track.
2) It shows that when the line NT is tangent to the track, the rate of change of φ is 0.
3) The overall document solves various kinematic problems related to the motion of the train T around the circular track.
IJERD (www.ijerd.com) International Journal of Engineering Research and Devel...IJERD Editor
This document presents a theorem that establishes the existence of a fixed point for a mapping under a general contractive condition of integral type. The mapping considered generalizes various types of contractive mappings in an integral setting. The theorem proves that if a self-mapping on a complete metric space satisfies the given integral inequality involving the distance between images of points, where the integral involves a non-negative, summable function, then the mapping has a unique fixed point. Furthermore, the sequence of repeated applications of the mapping to any starting point will converge to this fixed point. The proof involves showing the distance between successive terms in the sequence decreases according to the integral inequality.
In this section we look at problems where changing quantities are related. For instance, a growing oil slick is changing in diameter and volume at the same time. How are the rates of change of these quantities related? The chain rule for derivatives is the key.
In this section we look at problems where changing quantities are related. For instance, a growing oil slick is changing in diameter and volume at the same time. How are the rates of change of these quantities related? The chain rule for derivatives is the key.
This document contains notes from a calculus class. It provides the outline and key points about the Fundamental Theorem of Calculus. It discusses the first and second Fundamental Theorems of Calculus, including proofs and examples. It also provides brief biographies of several important mathematicians that contributed to the development of calculus, including the Fundamental Theorem of Calculus, such as Isaac Newton, Gottfried Leibniz, James Gregory, and Isaac Barrow.
This document is a section from a Calculus I course at New York University that discusses basic differentiation rules. It covers objectives like differentiating constant, sum, and difference functions. It also covers derivatives of sine and cosine. Examples are provided, like finding the derivative of the squaring function x^2, which is 2x. Notation for derivatives is explained, including Leibniz notation. The concept of the second derivative is also introduced.
This document proposes a model for a multilateral virtual currency market that is synthetically connected to the real-world bilateral foreign exchange market. The model defines "multilateral structures" which represent new virtual super currencies, and establishes exchange and interest rates for these structures. The goal is to present an alternative to constructs like the Euro that maintains stability through local currency supervision as well as oversight of the super currency structures. Key aspects of the model include:
1) Defining multilateral structures (FS) that represent sums of base currencies and can be represented through single currency exchange rates.
2) Establishing exchange rates (Q) for converting between the virtual super currencies and constituent base currencies.
3) Demonstr
Digital Signal Processing[ECEG-3171]-Ch1_L02Rediet Moges
This Digital Signal Processing Lecture material is the property of the author (Rediet M.) . It is not for publication,nor is it to be sold or reproduced
#Africa#Ethiopia
IJERD (www.ijerd.com) International Journal of Engineering Research and Devel...IJERD Editor
This document presents a theorem that establishes the existence of a fixed point for a mapping under a general contractive condition of integral type. The mapping considered generalizes various types of contractive mappings in an integral setting. The theorem proves that if a self-mapping on a complete metric space satisfies the given integral inequality involving the distance between images of points, where the integral involves a non-negative, summable function, then the mapping has a unique fixed point. Furthermore, the sequence of repeated applications of the mapping to any starting point will converge to this fixed point. The proof involves showing the distance between successive terms in the sequence decreases according to the integral inequality.
In this section we look at problems where changing quantities are related. For instance, a growing oil slick is changing in diameter and volume at the same time. How are the rates of change of these quantities related? The chain rule for derivatives is the key.
In this section we look at problems where changing quantities are related. For instance, a growing oil slick is changing in diameter and volume at the same time. How are the rates of change of these quantities related? The chain rule for derivatives is the key.
This document contains notes from a calculus class. It provides the outline and key points about the Fundamental Theorem of Calculus. It discusses the first and second Fundamental Theorems of Calculus, including proofs and examples. It also provides brief biographies of several important mathematicians that contributed to the development of calculus, including the Fundamental Theorem of Calculus, such as Isaac Newton, Gottfried Leibniz, James Gregory, and Isaac Barrow.
This document is a section from a Calculus I course at New York University that discusses basic differentiation rules. It covers objectives like differentiating constant, sum, and difference functions. It also covers derivatives of sine and cosine. Examples are provided, like finding the derivative of the squaring function x^2, which is 2x. Notation for derivatives is explained, including Leibniz notation. The concept of the second derivative is also introduced.
This document proposes a model for a multilateral virtual currency market that is synthetically connected to the real-world bilateral foreign exchange market. The model defines "multilateral structures" which represent new virtual super currencies, and establishes exchange and interest rates for these structures. The goal is to present an alternative to constructs like the Euro that maintains stability through local currency supervision as well as oversight of the super currency structures. Key aspects of the model include:
1) Defining multilateral structures (FS) that represent sums of base currencies and can be represented through single currency exchange rates.
2) Establishing exchange rates (Q) for converting between the virtual super currencies and constituent base currencies.
3) Demonstr
Digital Signal Processing[ECEG-3171]-Ch1_L02Rediet Moges
This Digital Signal Processing Lecture material is the property of the author (Rediet M.) . It is not for publication,nor is it to be sold or reproduced
#Africa#Ethiopia
NEC Commercial monitors are now available from Dukane.
I am an authorized Consultant for Dukane
Bill McIntosh
Phone : 843-442-8888
Email : WKMcIntosh@Comcast.net
Xamarin User Group San Diego - Building Cross-Platform Native Apps with Xamarin & MVVMCross.
We meet every second Thursday of the month to discuss Xamarin's past, present, and future. For more Meetup details or to join the group visit bit.ly/XamarinUserGroupSanDiego.
Xamarin day8 - Xamarin forms. Common code / controls on iOS, Android, WindowsSubodh Pushpak
The team continued their work on the project, making good progress on several key tasks. While some challenges emerged, they were able to work through them collaboratively. Overall the project remains on track to be completed by the deadline.
Xaivier Smith has over 4 years of experience providing enterprise level IT support through roles at Hewlett Packard Enterprises, as an independent field technician, and at Elite Computing LLC. He has handled over 50 support cases per day, performed network installations, PC hardware support, software deployment, and end user training. Smith has CompTIA A+, Network+, and Security+ certifications and experience operating surveying instruments from his time in the Army National Guard.
The document discusses the X-38 project, which is developing technology for a crew return vehicle (CRV) that would return astronauts from the International Space Station in an emergency. Three prototype X-38 vehicles are conducting atmospheric flight tests, and a fourth vehicle will be space-rated. The CRV is expected to be operational at the International Space Station by 2006. It will carry up to 7 astronauts back to Earth after detaching from the space station and gliding back through the atmosphere, guided by an onboard computer and parachute system.
Slideshare is discontinuing its Slidecast feature as of February 28, 2014. Existing Slidecasts will be converted to static presentations without audio by April 30, 2014. The document informs users that new slidecasts can be found on myPlick.com or the author's blog starting in 2014. However, myPlick proved unreliable, so future slidecasts will instead be hosted on the author's YouTube channel.
The document discusses different methods for factorising expressions:
1) Looking for a common factor and dividing it out of all terms
2) Using the difference of two squares formula (a2 - b2 = (a - b)(a + b))
3) Factorising quadratic trinomials into two binomial factors by identifying the values that multiply to give the constant term and sum to give the coefficient of the linear term.
The document provides information on index laws and the meaning of indices in algebra:
- Index laws state that am × an = am+n, am ÷ an = am-n, and (am)n = amn. Exponents can be added or subtracted when multiplying or dividing terms with the same base.
- Positive exponents indicate a term is raised to a power. Negative exponents indicate a root is being taken. Terms with exponents are evaluated from left to right.
- Examples demonstrate how to simplify expressions using index laws and interpret different types of indices.
12 x1 t01 03 integrating derivative on function (2013)Nigel Simmons
The document discusses integrating derivatives of functions. It states that the integral of the derivative of a function f(x) is equal to the natural log of f(x) plus a constant. It then provides examples of integrating several derivatives: (i) ∫(1/(7-3x)) dx = -1/3 log(7-3x) + c, (ii) ∫(1/(8x+5)) dx = 1/8 log(8x+5) + c, and (iii) ∫(x5/(x-2)) dx = 1/6 log(x6-2) + c. It also discusses techniques for integrating fractions by polynomial long division and finds
The document discusses logarithms and their properties. Logarithms are defined as the inverse of exponentials. If y = ax, then x = loga y. The natural logarithm is log base e, written as ln. Properties of logarithms include: loga m + loga n = loga mn; loga m - loga n = loga(m/n); loga mn = n loga m; loga 1 = 0; loga a = 1. Examples of evaluating logarithmic expressions are provided.
The document discusses relationships between the coefficients and roots of polynomials. It states that for a polynomial P(x) = axn + bxn-1 + cxn-2 + ..., the sum of the roots equals -b/a, the sum of the roots taken two at a time equals c/a, and so on for higher order terms. It also provides examples of using these relationships to find the sums of roots for a given polynomial.
P
4
3
2
The document discusses properties of polynomials with multiple roots. It first proves that if a polynomial P(x) has a root x = a of multiplicity m, then the derivative of P(x), P'(x), will have a root x = a of multiplicity m-1. It then provides an example of solving a cubic equation given it has a double root. Finally, it examines a quartic polynomial and shows that its root α cannot be 0, 1, or -1, and that 1/
The document discusses factorizing complex expressions. The main points are:
- If a polynomial's coefficients are real, its roots will appear in complex conjugate pairs.
- Any polynomial of degree n can be factorized into a mixture of quadratic and linear factors over real numbers, or into n linear factors over complex numbers.
- Odd degree polynomials must have at least one real root.
- Examples of factorizing polynomials over both real and complex numbers are provided.
NEC Commercial monitors are now available from Dukane.
I am an authorized Consultant for Dukane
Bill McIntosh
Phone : 843-442-8888
Email : WKMcIntosh@Comcast.net
Xamarin User Group San Diego - Building Cross-Platform Native Apps with Xamarin & MVVMCross.
We meet every second Thursday of the month to discuss Xamarin's past, present, and future. For more Meetup details or to join the group visit bit.ly/XamarinUserGroupSanDiego.
Xamarin day8 - Xamarin forms. Common code / controls on iOS, Android, WindowsSubodh Pushpak
The team continued their work on the project, making good progress on several key tasks. While some challenges emerged, they were able to work through them collaboratively. Overall the project remains on track to be completed by the deadline.
Xaivier Smith has over 4 years of experience providing enterprise level IT support through roles at Hewlett Packard Enterprises, as an independent field technician, and at Elite Computing LLC. He has handled over 50 support cases per day, performed network installations, PC hardware support, software deployment, and end user training. Smith has CompTIA A+, Network+, and Security+ certifications and experience operating surveying instruments from his time in the Army National Guard.
The document discusses the X-38 project, which is developing technology for a crew return vehicle (CRV) that would return astronauts from the International Space Station in an emergency. Three prototype X-38 vehicles are conducting atmospheric flight tests, and a fourth vehicle will be space-rated. The CRV is expected to be operational at the International Space Station by 2006. It will carry up to 7 astronauts back to Earth after detaching from the space station and gliding back through the atmosphere, guided by an onboard computer and parachute system.
Slideshare is discontinuing its Slidecast feature as of February 28, 2014. Existing Slidecasts will be converted to static presentations without audio by April 30, 2014. The document informs users that new slidecasts can be found on myPlick.com or the author's blog starting in 2014. However, myPlick proved unreliable, so future slidecasts will instead be hosted on the author's YouTube channel.
The document discusses different methods for factorising expressions:
1) Looking for a common factor and dividing it out of all terms
2) Using the difference of two squares formula (a2 - b2 = (a - b)(a + b))
3) Factorising quadratic trinomials into two binomial factors by identifying the values that multiply to give the constant term and sum to give the coefficient of the linear term.
The document provides information on index laws and the meaning of indices in algebra:
- Index laws state that am × an = am+n, am ÷ an = am-n, and (am)n = amn. Exponents can be added or subtracted when multiplying or dividing terms with the same base.
- Positive exponents indicate a term is raised to a power. Negative exponents indicate a root is being taken. Terms with exponents are evaluated from left to right.
- Examples demonstrate how to simplify expressions using index laws and interpret different types of indices.
12 x1 t01 03 integrating derivative on function (2013)Nigel Simmons
The document discusses integrating derivatives of functions. It states that the integral of the derivative of a function f(x) is equal to the natural log of f(x) plus a constant. It then provides examples of integrating several derivatives: (i) ∫(1/(7-3x)) dx = -1/3 log(7-3x) + c, (ii) ∫(1/(8x+5)) dx = 1/8 log(8x+5) + c, and (iii) ∫(x5/(x-2)) dx = 1/6 log(x6-2) + c. It also discusses techniques for integrating fractions by polynomial long division and finds
The document discusses logarithms and their properties. Logarithms are defined as the inverse of exponentials. If y = ax, then x = loga y. The natural logarithm is log base e, written as ln. Properties of logarithms include: loga m + loga n = loga mn; loga m - loga n = loga(m/n); loga mn = n loga m; loga 1 = 0; loga a = 1. Examples of evaluating logarithmic expressions are provided.
The document discusses relationships between the coefficients and roots of polynomials. It states that for a polynomial P(x) = axn + bxn-1 + cxn-2 + ..., the sum of the roots equals -b/a, the sum of the roots taken two at a time equals c/a, and so on for higher order terms. It also provides examples of using these relationships to find the sums of roots for a given polynomial.
P
4
3
2
The document discusses properties of polynomials with multiple roots. It first proves that if a polynomial P(x) has a root x = a of multiplicity m, then the derivative of P(x), P'(x), will have a root x = a of multiplicity m-1. It then provides an example of solving a cubic equation given it has a double root. Finally, it examines a quartic polynomial and shows that its root α cannot be 0, 1, or -1, and that 1/
The document discusses factorizing complex expressions. The main points are:
- If a polynomial's coefficients are real, its roots will appear in complex conjugate pairs.
- Any polynomial of degree n can be factorized into a mixture of quadratic and linear factors over real numbers, or into n linear factors over complex numbers.
- Odd degree polynomials must have at least one real root.
- Examples of factorizing polynomials over both real and complex numbers are provided.
The document describes the Trapezoidal Rule for approximating the area under a curve between two points. It shows that the area A is estimated by dividing the region into trapezoids with height equal to the function values at the interval endpoints and bases equal to the intervals. In general, the area is approximated as the sum of the areas of each trapezoid, which is equal to the average of the endpoint function values multiplied by the interval length.
The document discusses methods for calculating the volumes of solids of revolution. It provides formulas for finding volumes when an area is revolved around either the x-axis or y-axis. Examples are given for finding volumes of common solids like cones, spheres, and others. Steps are shown for using the formulas to calculate volumes based on given functions and limits of revolution.
The document discusses different methods for calculating the area under a curve or between curves.
(1) The area below the x-axis is given by the integral of the function between the bounds, which can be positive or negative depending on whether the area is above or below the x-axis.
(2) To calculate the area on the y-axis, the function is solved for x in terms of y, then the bounds are substituted into the integral of this new function with respect to y.
(3) The area between two curves is calculated by taking the integral of the upper curve minus the integral of the lower curve, both between the same bounds on the x-axis.
The document discusses 8 properties of definite integrals:
1) Integrating polynomials results in a fraction.
2) Constants can be factored out of integrals.
3) Integrals of sums are equal to the sum of integrals.
4) Splitting an integral range results in the sum of the integrals.
5) Integrals of positive functions over a range are positive, and negative if the function is negative.
6) Integrals can be compared based on the relative values of the integrands.
7) Changing the limits of integration flips the sign of the integral.
8) Integrals of odd functions over a symmetric range are zero, and integrals of even functions are twice the integral over
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UPRAHUL
This Dissertation explores the particular circumstances of Mirzapur, a region located in the
core of India. Mirzapur, with its varied terrains and abundant biodiversity, offers an optimal
environment for investigating the changes in vegetation cover dynamics. Our study utilizes
advanced technologies such as GIS (Geographic Information Systems) and Remote sensing to
analyze the transformations that have taken place over the course of a decade.
The complex relationship between human activities and the environment has been the focus
of extensive research and worry. As the global community grapples with swift urbanization,
population expansion, and economic progress, the effects on natural ecosystems are becoming
more evident. A crucial element of this impact is the alteration of vegetation cover, which plays a
significant role in maintaining the ecological equilibrium of our planet.Land serves as the foundation for all human activities and provides the necessary materials for
these activities. As the most crucial natural resource, its utilization by humans results in different
'Land uses,' which are determined by both human activities and the physical characteristics of the
land.
The utilization of land is impacted by human needs and environmental factors. In countries
like India, rapid population growth and the emphasis on extensive resource exploitation can lead
to significant land degradation, adversely affecting the region's land cover.
Therefore, human intervention has significantly influenced land use patterns over many
centuries, evolving its structure over time and space. In the present era, these changes have
accelerated due to factors such as agriculture and urbanization. Information regarding land use and
cover is essential for various planning and management tasks related to the Earth's surface,
providing crucial environmental data for scientific, resource management, policy purposes, and
diverse human activities.
Accurate understanding of land use and cover is imperative for the development planning
of any area. Consequently, a wide range of professionals, including earth system scientists, land
and water managers, and urban planners, are interested in obtaining data on land use and cover
changes, conversion trends, and other related patterns. The spatial dimensions of land use and
cover support policymakers and scientists in making well-informed decisions, as alterations in
these patterns indicate shifts in economic and social conditions. Monitoring such changes with the
help of Advanced technologies like Remote Sensing and Geographic Information Systems is
crucial for coordinated efforts across different administrative levels. Advanced technologies like
Remote Sensing and Geographic Information Systems
9
Changes in vegetation cover refer to variations in the distribution, composition, and overall
structure of plant communities across different temporal and spatial scales. These changes can
occur natural.
This slide is special for master students (MIBS & MIFB) in UUM. Also useful for readers who are interested in the topic of contemporary Islamic banking.
How to Add Chatter in the odoo 17 ERP ModuleCeline George
In Odoo, the chatter is like a chat tool that helps you work together on records. You can leave notes and track things, making it easier to talk with your team and partners. Inside chatter, all communication history, activity, and changes will be displayed.
it describes the bony anatomy including the femoral head , acetabulum, labrum . also discusses the capsule , ligaments . muscle that act on the hip joint and the range of motion are outlined. factors affecting hip joint stability and weight transmission through the joint are summarized.
Executive Directors Chat Leveraging AI for Diversity, Equity, and InclusionTechSoup
Let’s explore the intersection of technology and equity in the final session of our DEI series. Discover how AI tools, like ChatGPT, can be used to support and enhance your nonprofit's DEI initiatives. Participants will gain insights into practical AI applications and get tips for leveraging technology to advance their DEI goals.
हिंदी वर्णमाला पीपीटी, hindi alphabet PPT presentation, hindi varnamala PPT, Hindi Varnamala pdf, हिंदी स्वर, हिंदी व्यंजन, sikhiye hindi varnmala, dr. mulla adam ali, hindi language and literature, hindi alphabet with drawing, hindi alphabet pdf, hindi varnamala for childrens, hindi language, hindi varnamala practice for kids, https://www.drmullaadamali.com
A review of the growth of the Israel Genealogy Research Association Database Collection for the last 12 months. Our collection is now passed the 3 million mark and still growing. See which archives have contributed the most. See the different types of records we have, and which years have had records added. You can also see what we have for the future.
Strategies for Effective Upskilling is a presentation by Chinwendu Peace in a Your Skill Boost Masterclass organisation by the Excellence Foundation for South Sudan on 08th and 09th June 2024 from 1 PM to 3 PM on each day.
A workshop hosted by the South African Journal of Science aimed at postgraduate students and early career researchers with little or no experience in writing and publishing journal articles.
The simplified electron and muon model, Oscillating Spacetime: The Foundation...RitikBhardwaj56
Discover the Simplified Electron and Muon Model: A New Wave-Based Approach to Understanding Particles delves into a groundbreaking theory that presents electrons and muons as rotating soliton waves within oscillating spacetime. Geared towards students, researchers, and science buffs, this book breaks down complex ideas into simple explanations. It covers topics such as electron waves, temporal dynamics, and the implications of this model on particle physics. With clear illustrations and easy-to-follow explanations, readers will gain a new outlook on the universe's fundamental nature.
How to Build a Module in Odoo 17 Using the Scaffold MethodCeline George
Odoo provides an option for creating a module by using a single line command. By using this command the user can make a whole structure of a module. It is very easy for a beginner to make a module. There is no need to make each file manually. This slide will show how to create a module using the scaffold method.
How to Build a Module in Odoo 17 Using the Scaffold Method
X2 t06 07 miscellaneous dynamics questions (2012)
1. Miscellaneous Dynamics
Questions
e.g. (i) (1992) – variable angular velocity
The diagram shows a model train T that is
moving around a circular track, centre O
and radius a metres.
The train is travelling at a constant speed of
u m/s. The point N is in the same plane as
the track and is x metres from the nearest
point on the track. The line NO produced
meets the track at S.
Let TNS and TOS as in the diagram
4. dθ
a) Express in terms of a and u l a
dt dl d
a
dt dt
5. dθ
a) Express in terms of a and u l a
dt dl d
a
dt dt
d
ua
dt
d u
dt a
6. dθ
a) Express in terms of a and u l a
dt dl d
a
dt dt
d
ua
dt
d u
dt a
b) Show that a sin - x a sin 0 and deduce that;
d u cos
dt x a cos a cos
7. dθ
a) Express in terms of a and u l a
dt dl d
a
dt dt
d
ua
dt
d u
dt a
b) Show that a sin - x a sin 0 and deduce that;
d u cos
dt x a cos a cos
NTO TNO TOS (exterior , OTN )
8. dθ
a) Express in terms of a and u l a
dt dl d
a
dt dt
d
ua
dt
d u
dt a
b) Show that a sin - x a sin 0 and deduce that;
d u cos
dt x a cos a cos
NTO TNO TOS (exterior , OTN )
NTO
NTO
9. dθ
a) Express in terms of a and u l a
dt dl d
a
dt dt
d
ua
dt
d u
dt a
b) Show that a sin - x a sin 0 and deduce that;
d u cos
dt x a cos a cos
NTO TNO TOS (exterior , OTN )
NTO a ax
In NTO;
NTO sin sin
10. dθ
a) Express in terms of a and u l a
dt dl d
a
dt dt
d
ua
dt
d u
dt a
b) Show that a sin - x a sin 0 and deduce that;
d u cos
dt x a cos a cos
NTO TNO TOS (exterior , OTN )
NTO a ax
In NTO;
NTO sin sin
a sin a x sin
a sin a x sin 0
12. differentiate with respect to t
a cos d d a x cos d 0
dt dt dt
d d
a cos a cos a x cos 0
dt dt
13. differentiate with respect to t
a cos d d a x cos d 0
dt dt dt
d d
a cos a cos a x cos 0
dt dt
a cos a x cos d a cos u
dt a
14. differentiate with respect to t
a cos d d a x cos d 0
dt dt dt
d d
a cos a cos a x cos 0
dt dt
a cos a x cos d a cos u
dt a
d u cos
dt a cos a x cos
15. differentiate with respect to t
a cos d d a x cos d 0
dt dt dt
d d
a cos a cos a x cos 0
dt dt
a cos a x cos d a cos u
dt a
d u cos
dt a cos a x cos
d
c) Show that 0 when NT is tangential to the track.
dt
when NT is a tangent;
16. differentiate with respect to t
a cos d d a x cos d 0
dt dt dt
d d
a cos a cos a x cos 0
dt dt
a cos a x cos d a cos u
dt a
d u cos
dt a cos a x cos
d
c) Show that 0 when NT is tangential to the track.
dt T
N O
17. differentiate with respect to t
a cos d d a x cos d 0
dt dt dt
d d
a cos a cos a x cos 0
dt dt
a cos a x cos d a cos u
dt a
d u cos
dt a cos a x cos
d
c) Show that 0 when NT is tangential to the track.
dt T
when NT is a tangent;
N O
18. differentiate with respect to t
a cos d d a x cos d 0
dt dt dt
d d
a cos a cos a x cos 0
dt dt
a cos a x cos d a cos u
dt a
d u cos
dt a cos a x cos
d
c) Show that 0 when NT is tangential to the track.
dt T
when NT is a tangent;
NTO 90 (tangent radius)
N O
19. differentiate with respect to t
a cos d d a x cos d 0
dt dt dt
d d
a cos a cos a x cos 0
dt dt
a cos a x cos d a cos u
dt a
d u cos
dt a cos a x cos
d
c) Show that 0 when NT is tangential to the track.
dt T
when NT is a tangent;
NTO 90 (tangent radius)
N O
90
20. differentiate with respect to t
a cos d d a x cos d 0
dt dt dt
d d
a cos a cos a x cos 0
dt dt
a cos a x cos d a cos u
dt a
d u cos
dt a cos a x cos
d
c) Show that 0 when NT is tangential to the track.
dt T
when NT is a tangent;
NTO 90 (tangent radius)
N O
90
d u cos 90
dt a cos 90 a x cos
21. differentiate with respect to t
a cos d d a x cos d 0
dt dt dt
d d
a cos a cos a x cos 0
dt dt
a cos a x cos d a cos u
dt a
d u cos
dt a cos a x cos
d
c) Show that 0 when NT is tangential to the track.
dt T
when NT is a tangent;
NTO 90 (tangent radius)
N O
90
d u cos 90 d
0
dt a cos 90 a x cos dt
22. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
23. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
24. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T
N O
25. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T
a
N O
26. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T
a
N O
2a
27. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T
5a a
N O
2a
28. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T 2
cos
5a 5
a
N O
2a
29. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T 2
cos
5a 5
a
1
cos
N
2a
O 2 5
30. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T u cos
2 d 2
cos
5 dt
5a a a cos 2a cos
2
1
cos
N
2a
O 2 5
31. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T u cos
2 d 2
cos
5 dt
5a a a cos 2a cos
2
1
cos
u
1
N
2a
O 2 5
5
1 2a 2
a
5 5
32. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T u cos
2 d 2
cos
5 dt
5a a a cos 2a cos
2
1
cos
u
1
N
2a
O 2 5
5
1 2a 2
a
5 5
u
5a
33. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T u cos
2 d 2
cos
5 dt
5a a a cos 2a cos
2
1
cos
u
1
N
2a
O 2 5
5
when 0 1 2a 2
a
5 5
u
5a
34. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T u cos
2 d 2
cos
5 dt
5a a a cos 2a cos
2
1
cos
u
1
N
2a
O 2 5
5
when 0 1 2a 2
a
d u cos 0 5 5
dt a cos 0 2a cos 0 u
5a
35. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T u cos
2 d 2
cos
5 dt
5a a a cos 2a cos
2
1
cos
u
1
N
2a
O 2 5
5
when 0 1 2a 2
a
d u cos 0 5 5
dt a cos 0 2a cos 0 u
u
5a
3a
36. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T u cos
2 d 2
cos
5 dt
5a a a cos 2a cos
2
1
cos
u
1
N
2a
O 2 5
5
when 0 1 2a 2
a
d u cos 0 5 5
dt a cos 0 2a cos 0 u
u
5a
3a
5 u
3 5a
37. d) Suppose that x = a
3
Show that the train’s angular velocity about N when is
times the angular velocity about N when 0 2 5
when
2
T u cos
2 d 2
cos
5 dt
5a a a cos 2a cos
2
cos
1
u
1
N
2a
O 2 5
5
when 0 1 2a 2
a
d u cos 0 5 5
dt a cos 0 2a cos 0 u
u
5a
3a 3
Thus the angular velocity when is times
5 u 2 5
3 5a the angular velocity when 0
38. (ii) (2000) A string of length l is initially vertical and has a mass
P of m kg attached to it. The mass P is given a
horizontal velocity of magnitude V and begins to
move along the arc of a circle in a counterclockwise
direction.
Let O be the centre of this circle and A the initial
ds
position of P. Let s denote the arc length AP, v ,
dt
AOP and let the tension in the string be T. The acceleration due to
gravity is g and there are no frictional forces acting on P.
For parts a) to d), assume the mass is moving along the circle.
39. (ii) (2000) A string of length l is initially vertical and has a mass
P of m kg attached to it. The mass P is given a
horizontal velocity of magnitude V and begins to
move along the arc of a circle in a counterclockwise
direction.
Let O be the centre of this circle and A the initial
ds
position of P. Let s denote the arc length AP, v ,
dt
AOP and let the tension in the string be T. The acceleration due to
gravity is g and there are no frictional forces acting on P.
For parts a) to d), assume the mass is moving along the circle.
d 2s 1 d 1 2
a) Show that the tangential acceleration of P is given by 2 v
dt l d 2
40. (ii) (2000) A string of length l is initially vertical and has a mass
P of m kg attached to it. The mass P is given a
horizontal velocity of magnitude V and begins to
move along the arc of a circle in a counterclockwise
direction.
Let O be the centre of this circle and A the initial
ds
position of P. Let s denote the arc length AP, v ,
dt
AOP and let the tension in the string be T. The acceleration due to
gravity is g and there are no frictional forces acting on P.
For parts a) to d), assume the mass is moving along the circle.
d 2s 1 d 1 2
a) Show that the tangential acceleration of P is given by 2 v
dt l d 2
s l
41. (ii) (2000) A string of length l is initially vertical and has a mass
P of m kg attached to it. The mass P is given a
horizontal velocity of magnitude V and begins to
move along the arc of a circle in a counterclockwise
direction.
Let O be the centre of this circle and A the initial
ds
position of P. Let s denote the arc length AP, v ,
dt
AOP and let the tension in the string be T. The acceleration due to
gravity is g and there are no frictional forces acting on P.
For parts a) to d), assume the mass is moving along the circle.
d 2s 1 d 1 2
a) Show that the tangential acceleration of P is given by 2 v
dt l d 2
s l
ds
v
dt
d
l
dt
42. (ii) (2000) A string of length l is initially vertical and has a mass
P of m kg attached to it. The mass P is given a
horizontal velocity of magnitude V and begins to
move along the arc of a circle in a counterclockwise
direction.
Let O be the centre of this circle and A the initial
ds
position of P. Let s denote the arc length AP, v ,
dt
AOP and let the tension in the string be T. The acceleration due to
gravity is g and there are no frictional forces acting on P.
For parts a) to d), assume the mass is moving along the circle.
d 2s 1 d 1 2
a) Show that the tangential acceleration of P is given by 2 v
dt l d 2
s l d s dv
2
ds dt 2
dt
v
dt
d
l
dt
43. (ii) (2000) A string of length l is initially vertical and has a mass
P of m kg attached to it. The mass P is given a
horizontal velocity of magnitude V and begins to
move along the arc of a circle in a counterclockwise
direction.
Let O be the centre of this circle and A the initial
ds
position of P. Let s denote the arc length AP, v ,
dt
AOP and let the tension in the string be T. The acceleration due to
gravity is g and there are no frictional forces acting on P.
For parts a) to d), assume the mass is moving along the circle.
d 2s 1 d 1 2
a) Show that the tangential acceleration of P is given by 2 v
dt l d 2
s l d s dv
2
ds dt 2
dt
v dv d
dt
d d dt
l
dt
44. (ii) (2000) A string of length l is initially vertical and has a mass
P of m kg attached to it. The mass P is given a
horizontal velocity of magnitude V and begins to
move along the arc of a circle in a counterclockwise
direction.
Let O be the centre of this circle and A the initial
ds
position of P. Let s denote the arc length AP, v ,
dt
AOP and let the tension in the string be T. The acceleration due to
gravity is g and there are no frictional forces acting on P.
For parts a) to d), assume the mass is moving along the circle.
d 2s 1 d 1 2
a) Show that the tangential acceleration of P is given by 2 v
dt l d 2
s l d s dv
2
ds dt 2
dt
v dv d
dt
d d dt
l
dt dv v
d l
45. (ii) (2000) A string of length l is initially vertical and has a mass
P of m kg attached to it. The mass P is given a
horizontal velocity of magnitude V and begins to
move along the arc of a circle in a counterclockwise
direction.
Let O be the centre of this circle and A the initial
ds
position of P. Let s denote the arc length AP, v ,
dt
AOP and let the tension in the string be T. The acceleration due to
gravity is g and there are no frictional forces acting on P.
For parts a) to d), assume the mass is moving along the circle.
d 2s 1 d 1 2
a) Show that the tangential acceleration of P is given by 2 v
dt l d 2
s l d s dv
2 1 dv
v
ds dt 2 dt l d
v dv d
dt
d d dt
l
dt dv v
d l
46. (ii) (2000) A string of length l is initially vertical and has a mass
P of m kg attached to it. The mass P is given a
horizontal velocity of magnitude V and begins to
move along the arc of a circle in a counterclockwise
direction.
Let O be the centre of this circle and A the initial
ds
position of P. Let s denote the arc length AP, v ,
dt
AOP and let the tension in the string be T. The acceleration due to
gravity is g and there are no frictional forces acting on P.
For parts a) to d), assume the mass is moving along the circle.
d 2s 1 d 1 2
a) Show that the tangential acceleration of P is given by 2 v
dt l d 2
s l d s dv
2 1 dv
v
ds dt 2 dt l d
v dv d
1 dv d 1 2
dt v
l d dv 2
d d dt
l
dt dv v
d l
47. (ii) (2000) A string of length l is initially vertical and has a mass
P of m kg attached to it. The mass P is given a
horizontal velocity of magnitude V and begins to
move along the arc of a circle in a counterclockwise
direction.
Let O be the centre of this circle and A the initial
ds
position of P. Let s denote the arc length AP, v ,
dt
AOP and let the tension in the string be T. The acceleration due to
gravity is g and there are no frictional forces acting on P.
For parts a) to d), assume the mass is moving along the circle.
d 2s 1 d 1 2
a) Show that the tangential acceleration of P is given by 2 v
dt l d 2
s l d s dv
2 1 dv
v
ds dt 2 dt l d
v dv d
1 dv d 1 2
dt v
l d dv 2
d d dt
l 1 d 1 2
dt dv v v
l d 2
d l
48. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
49. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
50. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T
51. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T
mg
52. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T
mg
53. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T
mg
mg sin
54. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T m
s
mg
mg sin
55. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T m
s m mg sin
s
mg
mg sin
56. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T m
s m mg sin
s
mg g sin
s
mg sin
57. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T m
s m mg sin
s
mg g sin
s
mg sin
1 d 1 2
v g sin
l d 2
58. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T m
s m mg sin
s
mg g sin
s
mg sin
1 d 1 2
v g sin
l d 2
c) Deduce that V 2 v 2 2 gl 1 cos
59. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T m
s m mg sin
s
mg g sin
s
mg sin
1 d 1 2
v g sin
l d 2
c) Deduce that V 2 v 2 2 gl 1 cos
1 d 1 2
v g sin
l d 2
60. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T m
s m mg sin
s
mg g sin
s
mg sin
1 d 1 2
v g sin
l d 2
c) Deduce that V 2 v 2 2 gl 1 cos
1 d 1 2
v g sin
l d 2
d 1 2
v gl sin
d 2
61. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T m
s m mg sin
s
mg g sin
s
mg sin
1 d 1 2
v g sin
l d 2
c) Deduce that V 2 v 2 2 gl 1 cos
1 d 1 2
v g sin
l d 2
d 1 2
v gl sin
d 2
1 2
v gl cos c
2
v 2 2 gl cos c
62. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T m
s m mg sin
s
mg g sin
s
mg sin
1 d 1 2
v g sin
l d 2
c) Deduce that V 2 v 2 2 gl 1 cos
when 0, v V
1 d 1 2
v g sin V 2 2 gl c
l d 2
c V 2 2 gl
d 1 2
v gl sin
d 2
1 2
v gl cos c
2
v 2 2 gl cos c
63. 1 d 1 2
b) Show that the equation of motion of P is v g sin
l d 2
T m
s m mg sin
s
mg g sin
s
mg sin
1 d 1 2
v g sin
l d 2
c) Deduce that V 2 v 2 2 gl 1 cos
when 0, v V
1 d 1 2
v g sin V 2 2 gl c
l d 2
c V 2 2 gl
d 1 2
v gl sin v 2 2 gl cos V 2 2 gl
d 2
1 2 V 2 v 2 2 gl 2 gl cos
v gl cos c
2 V 2 v 2 2 gl 1 cos
v 2 2 gl cos c
69. 1 2
d) Explain why T-mg cos θ mv
l
T mg cos m T mg cos
x
m
x
70. 1 2
d) Explain why T-mg cos θ mv
l
T mg cos m T mg cos
x
m
x But, the resultant force towards the centre is
centripetal force.
71. 1 2
d) Explain why T-mg cos θ mv
l
T mg cos m T mg cos
x
m
x But, the resultant force towards the centre is
centripetal force.
mv 2
T mg cos
l
1 2
T mg cos mv
l
72. 1 2
d) Explain why T-mg cos θ mv
l
T mg cos m T mg cos
x
m
x But, the resultant force towards the centre is
centripetal force.
mv 2
T mg cos
l
1 2
T mg cos mv
l
e) Suppose that V 2 3 gl. Find the value of at which T 0
73. 1 2
d) Explain why T-mg cos θ mv
l
T mg cos m T mg cos
x
m
x But, the resultant force towards the centre is
centripetal force.
mv 2
T mg cos
l
1 2
T mg cos mv
l
e) Suppose that V 2 3 gl. Find the value of at which T 0
T mg cos mV 2 2 gl 1 cos
1
l
74. 1 2
d) Explain why T-mg cos θ mv
l
T mg cos m T mg cos
x
m
x But, the resultant force towards the centre is
centripetal force.
mv 2
T mg cos
l
1 2
T mg cos mv
l
e) Suppose that V 2 3 gl. Find the value of at which T 0
T mg cos mV 2 2 gl 1 cos
1
l
1
0 mg cos m3 gl 2 gl 1 cos
l
75. 1 2
d) Explain why T-mg cos θ mv
l
T mg cos m T mg cos
x
m
x But, the resultant force towards the centre is
centripetal force.
mv 2
T mg cos
l
1 2
T mg cos mv
l
e) Suppose that V 2 3 gl. Find the value of at which T 0
T mg cos mV 2 2 gl 1 cos
1
l
1
0 mg cos m3 gl 2 gl 1 cos
l
mg cos m g 2 g cos
76. 1 2
d) Explain why T-mg cos θ mv
l
T mg cos m T mg cos
x
m
x But, the resultant force towards the centre is
centripetal force.
mv 2
T mg cos
l
1 2
T mg cos mv
l
e) Suppose that V 2 3 gl. Find the value of at which T 0
T mg cos mV 2 2 gl 1 cos
1
l
1
0 mg cos m3 gl 2 gl 1 cos
l
mg cos m g 2 g cos
3mg cos mg
77. 1 2
d) Explain why T-mg cos θ mv
l
T mg cos m T mg cos
x
m
x But, the resultant force towards the centre is
centripetal force.
mv 2
T mg cos
l
1 2
T mg cos mv
l
e) Suppose that V 2 3 gl. Find the value of at which T 0
T mg cos mV 2 2 gl 1 cos
1
l cos
1
1
0 mg cos m3 gl 2 gl 1 cos 3
l
mg cos m g 2 g cos
3mg cos mg
78. 1 2
d) Explain why T-mg cos θ mv
l
T mg cos m T mg cos
x
m
x But, the resultant force towards the centre is
centripetal force.
mv 2
T mg cos
l
1 2
T mg cos mv
l
e) Suppose that V 2 3 gl. Find the value of at which T 0
T mg cos mV 2 2 gl 1 cos
1
l cos
1
1
0 mg cos m3 gl 2 gl 1 cos 3
l 1.911radians
mg cos m g 2 g cos
3mg cos mg
79. f) Consider the situation in part e). Briefly describe, in words, the path of
P after the tension T becomes zero.
80. f) Consider the situation in part e). Briefly describe, in words, the path of
P after the tension T becomes zero.
When T = 0, the particle would undergo projectile motion, i.e. it
would follow a parabolic arc.
Its initial velocity would be tangential to the circle with magnitude;
81. f) Consider the situation in part e). Briefly describe, in words, the path of
P after the tension T becomes zero.
When T = 0, the particle would undergo projectile motion, i.e. it
would follow a parabolic arc.
Its initial velocity would be tangential to the circle with magnitude;
1 2
T mg cos mv
l
82. f) Consider the situation in part e). Briefly describe, in words, the path of
P after the tension T becomes zero.
When T = 0, the particle would undergo projectile motion, i.e. it
would follow a parabolic arc.
Its initial velocity would be tangential to the circle with magnitude;
1 2
T mg cos mv
l
1 1 mv 2
mg
3 l
83. f) Consider the situation in part e). Briefly describe, in words, the path of
P after the tension T becomes zero.
When T = 0, the particle would undergo projectile motion, i.e. it
would follow a parabolic arc.
Its initial velocity would be tangential to the circle with magnitude;
1 2
T mg cos mv
l
1 1 mv 2
mg
3 l
gl
v2
3
gl
v
3
84. f) Consider the situation in part e). Briefly describe, in words, the path of
P after the tension T becomes zero.
When T = 0, the particle would undergo projectile motion, i.e. it
would follow a parabolic arc.
Its initial velocity would be tangential to the circle with magnitude;
1 2
T mg cos mv
l
1 1 mv 2
mg
3 l
gl
v2
3
gl
v
3
85. f) Consider the situation in part e). Briefly describe, in words, the path of
P after the tension T becomes zero.
When T = 0, the particle would undergo projectile motion, i.e. it
would follow a parabolic arc.
Its initial velocity would be tangential to the circle with magnitude;
1 2
T mg cos mv
l
1 1 mv 2
mg
3 l
gl
v2
3
gl
v
3
86. f) Consider the situation in part e). Briefly describe, in words, the path of
P after the tension T becomes zero.
When T = 0, the particle would undergo projectile motion, i.e. it
would follow a parabolic arc.
Its initial velocity would be tangential to the circle with magnitude;
1 2
T mg cos mv
l
1 1 mv 2
mg
3 l
gl
v2
3
gl
v
3
87. f) Consider the situation in part e). Briefly describe, in words, the path of
P after the tension T becomes zero.
When T = 0, the particle would undergo projectile motion, i.e. it
would follow a parabolic arc.
Its initial velocity would be tangential to the circle with magnitude;
1 2
T mg cos mv
l
1 1 mv 2
mg
3 l
gl
v2
3
gl
v
3
88. f) Consider the situation in part e). Briefly describe, in words, the path of
P after the tension T becomes zero.
When T = 0, the particle would undergo projectile motion, i.e. it
would follow a parabolic arc.
Its initial velocity would be tangential to the circle with magnitude;
1 2
T mg cos mv
l
1 1 mv 2
mg
3 l
gl
v2
3
gl
v
3
89. (iii) (2003)
A particle of mass m is thrown from the top, O, of a very tall building
with an initial velocity u at an angle of to the horizontal. The
particle experiences the effect of gravity, and a resistance
proportional to its velocity in both directions.
The equations of motion in the horizontal and
vertical directions are given respectively by
kx and ky g
x y
where k is a constant and the acceleration due
to gravity is g.
(You are NOT required to show these)
91. a) Derive the result x ue kt cos
dx
kx
dt
92. a) Derive the result x ue kt cos
dx
kx
dt x
1 dx
t
k u cos x
93. a) Derive the result x ue kt cos
dx
kx
dt x
1 dx
t
k u cos x
1
t log x u cos
x
k
94. a) Derive the result x ue kt cos
dx
kx
dt x
1 dx
t
k u cos x
1
t log x u cos
x
k
1
t log x logu cos
k
95. a) Derive the result x ue kt cos
1 x
dx t log
kx
k u cos
dt x
1 dx
t
k u cos x
1
t log x u cos
x
k
1
t log x logu cos
k
96. a) Derive the result x ue kt cos
1 x
dx t log
kx
k u cos
dt x
1 dx x
t kt log
k u cos x u cos
1 x
t log x u cos e kt
x
k u cos
1
t log x logu cos
x ue kt cos
k
97. a) Derive the result x ue kt cos
1 x
dx t log
kx
k u cos
dt x
1 dx x
t kt log
k u cos x u cos
1 x
t log x u cos e kt
x
k u cos
1
t log x logu cos
x ue kt cos
k
b) Verify that y ku sin g e kt g satisfies the appropriate
1
k
equation of motion and initial condition
98. a) Derive the result x ue kt cos
1 x
dx t log
kx
k u cos
dt x
1 dx x
t kt log
k u cos x u cos
1 x
t log x u cos e kt
x
k u cos
1
t log x logu cos
x ue kt cos
k
b) Verify that y ku sin g e kt g satisfies the appropriate
1
k
equation of motion and initial condition
dy
ky g
dt
99. a) Derive the result x ue kt cos
1 x
dx t log
kx k u cos
dt x
1 dx x
t kt log
k u cos x u cos
1 x
t log x u cos e kt
x
k u cos
1
t log x logu cos
x ue kt cos
k
b) Verify that y ku sin g e kt g satisfies the appropriate
1
k
equation of motion and initial condition
dy
ky g
dt y
dy
t
u sin
ky g
100. a) Derive the result x ue kt cos
1 x
dx t log
kx k u cos
dt x
1 dx x
t kt log
k u cos x u cos
1 x
t log x u cos e kt
x
k u cos
1
t log x logu cos
x ue kt cos
k
b) Verify that y ku sin g e kt g satisfies the appropriate
1
k
equation of motion and initial condition
dy
ky g
dt y
dy
t
u sin
ky g
1
t logky g u sin
y
k
101. a) Derive the result x ue kt cos
1 x
dx t log
kx k u cos
dt x
1 dx x
t kt log
k u cos x u cos
1 x
t log x u cos e kt
x
k u cos
1
t log x logu cos
x ue kt cos
k
b) Verify that y ku sin g e kt g satisfies the appropriate
1
k
equation of motion and initial condition
dy kt logky g logku sin g
ky g
dt y
dy
t
u sin
ky g
1
t logky g u sin
y
k
102. a) Derive the result x ue kt cos
1 x
dx t log
kx k u cos
dt x
1 dx x
t kt log
k u cos x u cos
1 x
t log x u cos e kt
x
k u cos
1
t log x logu cos
x ue kt cos
k
b) Verify that y ku sin g e kt g satisfies the appropriate
1
k
equation of motion and initial condition
dy kt logky g logku sin g
ky g
dt y ky g
dy kt log
t ku sin g
u sin
ky g
1
t logky g u sin
y
k
103. a) Derive the result x ue kt cos
1 x
dx t log
kx k u cos
dt x
1 dx x
t kt log
k u cos x u cos
1 x
t log x u cos e kt
x
k u cos
1
t log x logu cos
x ue kt cos
k
b) Verify that y ku sin g e kt g satisfies the appropriate
1
k
equation of motion and initial condition
dy kt logky g logku sin g
ky g
dt y ky g
dy kt log
t ku sin g
u sin
ky g
ky g
e kt
1
t logky g u sin
y
ku sin g
k
104. a) Derive the result x ue kt cos
1 x
dx t log
kx k u cos
dt x
1 dx x
t kt log
k u cos x u cos
1 x
t log x u cos e kt
x
k u cos
1
t log x logu cos
x ue kt cos
k
b) Verify that y ku sin g e kt g satisfies the appropriate
1
k
equation of motion and initial condition
dy kt logky g logku sin g
ky g
dt y ky g
dy kt log
t ku sin g
u sin
ky g
ky g
e kt
1
t logky g u sin
y
ku sin g
y ku sin g e kt g
1
k
k
105. c) Find the value of t when the particle reaches its maximum height
106. c) Find the value of t when the particle reaches its maximum height
Maximum height occurs when y 0
107. c) Find the value of t when the particle reaches its maximum height
Maximum height occurs when y 0
1
t logky g u sin
0
k
108. c) Find the value of t when the particle reaches its maximum height
Maximum height occurs when y 0
1
t logky g u sin
0
k
1
t log g logku sin g
k
109. c) Find the value of t when the particle reaches its maximum height
Maximum height occurs when y 0
1
t logky g u sin
0
k
1
t log g logku sin g
k
1 ku sin g
t log
k g
110. c) Find the value of t when the particle reaches its maximum height
Maximum height occurs when y 0
1
t logky g u sin
0
k
1
t log g logku sin g
k
1 ku sin g
t log
k g
d) What is the limiting value of the horizontal displacement of the
particle?
111. c) Find the value of t when the particle reaches its maximum height
Maximum height occurs when y 0
1
t logky g u sin
0
k
1
t log g logku sin g
k
1 ku sin g
t log
k g
d) What is the limiting value of the horizontal displacement of the
particle?
x ue kt cos
dx
ue kt cos
dt
112. c) Find the value of t when the particle reaches its maximum height
Maximum height occurs when y 0
1
t logky g u sin
0
k
1
t log g logku sin g
k
1 ku sin g
t log
k g
d) What is the limiting value of the horizontal displacement of the
particle?
x lim u cos e kt dt
x ue kt cos
t
0
dx
ue kt cos
dt
113. c) Find the value of t when the particle reaches its maximum height
Maximum height occurs when y 0
1
t logky g u sin
0
k
1
t log g logku sin g
k
1 ku sin g
t log
k g
d) What is the limiting value of the horizontal displacement of the
particle?
x lim u cos e kt dt
x ue kt cos
t
0
t
x lim u cos e
dx 1 kt
ue cos
kt
k
dt t 0
114. c) Find the value of t when the particle reaches its maximum height
Maximum height occurs when y 0
1
t logky g u sin
0
k
1
t log g logku sin g
k
1 ku sin g
t log
k g
d) What is the limiting value of the horizontal displacement of the
particle?
x lim u cos e kt dt
x ue kt cos
t
0
t
x lim u cos e
dx 1 kt
ue cos
kt
k
dt t 0
u cos
x lim e kt 1
t k
115. c) Find the value of t when the particle reaches its maximum height
Maximum height occurs when y 0
1
t logky g u sin
0
k
1
t log g logku sin g
k
1 ku sin g
t log
k g
d) What is the limiting value of the horizontal displacement of the
particle?
x lim u cos e kt dt
x ue kt cos
t
0
t
x lim u cos e
dx 1 kt
ue cos
kt
k
dt t 0
u cos
x lim e kt 1
t k
u cos
x
k