This C program uses stack operations to perform two tasks: 1) Convert an infix expression to a postfix expression by pushing and popping operators and operands to a stack. 2) Evaluate the postfix expression by pushing operands, popping operands and operators, and performing operations. It includes functions to push and pop from the stack, determine operator precedence, convert expressions, and evaluate the postfix form.
Eduvision verzorgt met regelmaat Joomla proeflessen. Interesse? Kijk dan op onze website. URL staat op eerste dia.
Deze proefles wordt je aangeboden door Eduvision Opleidingen.
Eduvision verzorgt opleidingen binnen een groot aantal sectoren. We hebben o.a. gewerkt voor KLM, DTG, BNN-VARA, ING, de Belastingdienst, Gemeente Amsterdam, Interpolis, Nuon en de Atlant Zorggroep. Eduvision heeft als missie om actuele kennis te delen. Niet alleen in de vorm van cursussen, maar ook met webinars, whitepapers en blogs.
Sinds 2015 is Eduvision Opleidingen aanbieder van officieel gecertificeerde Big Data opleidingen (ISO 9001 & 17024). De Big Data Academy is de plek waar jij en/of jouw werknemers opgeleid worden tot gecertificeerd Big Data specialist.
Tijdens alle cursussen van Eduvision Opleidingen staan jouw wensen en informatiebehoefte centraal. Je past de kennis toe op jouw praktijkcase en zowel Eduvision als de docenten staan volledig tot jouw beschikking.
#include<iostream>
#include<cctype>
using namespace std;
class evalPostFix
{
public:
int s[50];
int top;
char str[50];
evalPostFix() {
top=-1;
}
void push(int val) {
top++;
s[top]=val;
}
int pop() {
int val=s[top];
top--;
return val;
}
int oper(int x,int y,char op) {
switch(op) {
case '+':return x+y;
case '-':return x-y;
case '*':return x*y;
case '/':return x/y;
default: return 0;
}
}
int calc();
};
int evalPostFix::calc() {
int i=0;
while(str[i]!='=') {
if(isdigit(str[i])) {
push(str[i]-'0');
}
else {
int x=pop();
int y=pop();
int r=oper(x,y,str[i]);
push(r);
}
i++;
}
return pop();
}
int main()
{
char answer;
evalPostFix eval;
do
{
cout<<"Enter a postfix expression:" << endl;
cin>>eval.str;
int r=eval.calc();
cout<<"Final Value : "<<r <<"\n";
cout << "Continue (Y or N)" << endl;
cin >> answer;
}
while(answer!='N');
system("pause");
}
Here is the output, but I do not want it to be like this.
I want the output to be like this
...
Implementing Software Machines in Go and CEleanor McHugh
Early draft of a tutorial on techniques for implementing virtual machines and language interpreters. Contains example programs for functional stacks and despatch loops.
Program of sorting using shell sort #include stdio.h #de.pdfanujmkt
/* Program of sorting using shell sort */
#include
#define MAX 20
main()
{
int arr[MAX], i,j,k,n,incr;
printf(\"Enter the number of elements : \");
scanf(\"%d\",&n);
for(i=0;i=1)
{
for(j=incr;j= 0 && k < arr[i]; i = i-incr)
arr[i+incr]=arr[i];
arr[i+incr]=k;
}
printf(\"Increment=%d \ \",incr);
for (i = 0; i < n; i++)
printf(\"%d \", arr[i]);
printf(\"\ \");
incr=incr-2; /*Decrease the increment*/
}/*End of while*/
printf(\"Sorted list is :\ \");
for (i = 0; i < n; i++)
printf(\"%d \", arr[i]);
printf(\"\ \");
}/*End of main()*/
redix sort
/*Program of sorting using radix sort*/
# include
# include
struct node
{
int info ;
struct node *link;
}*start=NULL;
main()
{
struct node *tmp,*q;
int i,n,item;
printf(\"Enter the number of elements in the list : \");
scanf(\"%d\", &n);
for(i=0;iinfo=item;
tmp->link=NULL;
if(start==NULL) /* Inserting first element */
start=tmp;
else
{
q=start;
while(q->link!=NULL)
q=q->link;
q->link=tmp;
}
}/*End of for*/
printf(\"Unsorted list is :\ \");
display();
radix_sort();
printf(\"Sorted list is :\ \");
display ();
}/*End of main()*/
display()
{
struct node *p=start;
while( p !=NULL)
{
printf(\"%d \", p->info);
p= p->link;
}
printf(\"\ \");
}/*End of display()*/
radix_sort()
{
int i,k,dig,maxdig,mindig,least_sig,most_sig;
struct node *p, *rear[10], *front[10];
least_sig=1;
most_sig=large_dig(start);
for(k = least_sig; k <= most_sig ; k++)
{
printf(\"PASS %d : Examining %dth digit from right \",k,k);
for(i = 0 ; i <= 9 ; i++)
{
rear[i] = NULL;
front[i] = NULL ;
}
maxdig=0;
mindig=9;
p = start ;
while( p != NULL)
{
/*Find kth digit in the number*/
dig = digit(p->info, k);
if(dig>maxdig)
maxdig=dig;
if(diglink = p ;
rear[dig] = p ;
p=p->link;/*Go to next number in the list*/
}/*End while */
/* maxdig and mindig are the maximum amd minimum
digits of the kth digits of all the numbers*/
printf(\"mindig=%d maxdig=%d\ \",mindig,maxdig);
/*Join all the queues to form the new linked list*/
start=front[mindig];
for(i=mindig;ilink=front[i+1];
else
rear[i+1]=rear[i];
}
rear[maxdig]->link=NULL;
printf(\"New list : \");
display();
}/* End for */
}/*End of radix_sort*/
/* This function finds number of digits in the largest element of the list */
int large_dig()
{
struct node *p=start ;
int large = 0,ndig = 0 ;
while(p != NULL)
{
if(p ->info > large)
large = p->info;
p = p->link ;
}
printf(\"Largest Element is %d , \",large);
while(large != 0)
{
ndig++;
large = large/10 ;
}
printf(\"Number of digits in it are %d\ \",ndig);
return(ndig);
} /*End of large_dig()*/
/*This function returns kth digit of a number*/
int digit(int number, int k)
{
int digit, i ;
for(i = 1 ; i <=k ; i++)
{
digit = number % 10 ;
number = number /10 ;
}
return(digit);
}/*End of digit()*/
Solution
/* Program of sorting using shell sort */
#include
#define MAX 20
main()
{
int arr[MAX], i,j,k,n,incr;
printf(\"Enter the number of elements : \");
scanf(\"%d\",&n);
for(i=0;i=1)
{
for(j=incr;j= 0 && k < arr[i]; i = i-incr)
arr[i+incr]=arr[i];
arr[i+incr]=k;
}
printf(\.
Welcome to TechSoup New Member Orientation and Q&A (May 2024).pdfTechSoup
In this webinar you will learn how your organization can access TechSoup's wide variety of product discount and donation programs. From hardware to software, we'll give you a tour of the tools available to help your nonprofit with productivity, collaboration, financial management, donor tracking, security, and more.
Instructions for Submissions thorugh G- Classroom.pptxJheel Barad
This presentation provides a briefing on how to upload submissions and documents in Google Classroom. It was prepared as part of an orientation for new Sainik School in-service teacher trainees. As a training officer, my goal is to ensure that you are comfortable and proficient with this essential tool for managing assignments and fostering student engagement.
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptxEduSkills OECD
Andreas Schleicher presents at the OECD webinar ‘Digital devices in schools: detrimental distraction or secret to success?’ on 27 May 2024. The presentation was based on findings from PISA 2022 results and the webinar helped launch the PISA in Focus ‘Managing screen time: How to protect and equip students against distraction’ https://www.oecd-ilibrary.org/education/managing-screen-time_7c225af4-en and the OECD Education Policy Perspective ‘Students, digital devices and success’ can be found here - https://oe.cd/il/5yV
Synthetic Fiber Construction in lab .pptxPavel ( NSTU)
Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
Model Attribute Check Company Auto PropertyCeline George
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
The Roman Empire A Historical Colossus.pdfkaushalkr1407
The Roman Empire, a vast and enduring power, stands as one of history's most remarkable civilizations, leaving an indelible imprint on the world. It emerged from the Roman Republic, transitioning into an imperial powerhouse under the leadership of Augustus Caesar in 27 BCE. This transformation marked the beginning of an era defined by unprecedented territorial expansion, architectural marvels, and profound cultural influence.
The empire's roots lie in the city of Rome, founded, according to legend, by Romulus in 753 BCE. Over centuries, Rome evolved from a small settlement to a formidable republic, characterized by a complex political system with elected officials and checks on power. However, internal strife, class conflicts, and military ambitions paved the way for the end of the Republic. Julius Caesar’s dictatorship and subsequent assassination in 44 BCE created a power vacuum, leading to a civil war. Octavian, later Augustus, emerged victorious, heralding the Roman Empire’s birth.
Under Augustus, the empire experienced the Pax Romana, a 200-year period of relative peace and stability. Augustus reformed the military, established efficient administrative systems, and initiated grand construction projects. The empire's borders expanded, encompassing territories from Britain to Egypt and from Spain to the Euphrates. Roman legions, renowned for their discipline and engineering prowess, secured and maintained these vast territories, building roads, fortifications, and cities that facilitated control and integration.
The Roman Empire’s society was hierarchical, with a rigid class system. At the top were the patricians, wealthy elites who held significant political power. Below them were the plebeians, free citizens with limited political influence, and the vast numbers of slaves who formed the backbone of the economy. The family unit was central, governed by the paterfamilias, the male head who held absolute authority.
Culturally, the Romans were eclectic, absorbing and adapting elements from the civilizations they encountered, particularly the Greeks. Roman art, literature, and philosophy reflected this synthesis, creating a rich cultural tapestry. Latin, the Roman language, became the lingua franca of the Western world, influencing numerous modern languages.
Roman architecture and engineering achievements were monumental. They perfected the arch, vault, and dome, constructing enduring structures like the Colosseum, Pantheon, and aqueducts. These engineering marvels not only showcased Roman ingenuity but also served practical purposes, from public entertainment to water supply.
1. /* Write a C program that uses Stack operations to perform the following:
i) Converting infix expression into postfix expression
ii) Evaluating the postfix expression */
#include<stdio.h>
#include<conio.h>
int st[100];
int st_top=-1;
int cal(char post[]);
void in_post(char in[]);
void push_item(int it);
int pop_item();
int st_ISP(char t);
int st_ICP(char t);
/*main function*/
void main()
{
char in[100],post[100];
clrscr();
printf("ntEnter the Infix Expression: ");
gets(in);
2. in_post(in);
getch();
}
/*end main*/
void push_item(int it)
{
if(st_top==99)
{
printf("nnt*STACK is Full*");
getch();
exit(1);
}
st[++st_top]=it;
}
int pop_item()
{
int it;
if(st_top==-1)
{
getch();
}
return(st[st_top--]);
3. }
/*Function for converting an infix expression to a postfix expression. */
void in_post(char in[])
{
int x=0,y=0,z,result=0;
char a,c, post[100];
char t;
push_item('0');
t=in[x];
while(t!='0')
{
if(isalnum(t))
/*For checking whether the value in t is an alphabet or number. */
{
post[y]=t;
y++;
}
else if(t=='(')
{
push_item('(');
}
else if(t==')')
{
5. c=pop_item();
post[y]=c;
y++;
}
printf("ntThe Postfix Expression is:");
for(z=0;z<y;z++)
printf("%c",post[z]);
printf("nnDo you want to evaluate the Result of Postfix Expression?(Y/N):");
scanf("%c",&a);
if(a=='y' || a=='Y')
{
result=cal(post);
printf("nntResult is: %dn",result);
getch();
}
else if(a=='n' || a=='N')
{
exit(0);
}
}
/*Determining priority of inside elements*/
int st_ISP(char t)
6. {
switch(t)
{
case '(':return (10);
case ')':return (9);
case '+':return (7);
case '-':return (7);
case '*':return (8);
case '/':return (8);
case '0':return (0);
default: printf("Expression is invalid.");
break;
}
return 0;
}
/*Determining priority of approaching elements*/
int st_ICP(char t)
{
switch(t)
{
case '(':return (10);
case ')':return (9);
7. case '+':return (7);
case '-':return (7);
case '*':return (8);
case '/':return (8);
case '0':return (0);
default: printf("Expression is invalid.");
break;
}
return 0;
}
/*Evaluating the result of postfix expression*/
int cal(char post[])
{
int m,n,x,y,j=0,len;
len=strlen(post);
while(j<len)
{
if(isdigit(post[j]))
{
x=post[j]-'0';
push_item(x);
}
else
8. {
m=pop_item();
n=pop_item();
switch(post[j])
{
case '+':x=n+m;
break;
case '-':x=n-m;
break;
case '*':x=n*m;
break;
case '/':x=n/m;
break;
}
push_item(x);
}
j++;
}
if(st_top>0)
{
printf("Number of Operands are more than Operators.");
exit(0);
}