This document provides step-by-step instructions for solving various one-step equations by isolating the variable. It demonstrates circling the variable, moving other terms to the opposite side using the opposite operation (addition for subtraction and vice versa, division for multiplication and vice versa), and solving for the variable. Examples include equations with addition, subtraction, multiplication and division. The goal is to get the variable alone on one side of the equal sign.
1) The document discusses inequalities involving real numbers. It introduces basic rules for how inequalities are affected by addition, multiplication, taking squares, and taking reciprocals.
2) Several examples are provided to demonstrate how to solve various inequalities by applying these rules. For instance, it is shown that the inequality 4x + 7 < 3 is equivalent to x < -1.
3) Graphs are used to confirm the solutions obtained from manipulating the inequalities. The key results are that addition preserves inequalities while multiplication preserves or reverses them depending on whether the number being multiplied is positive or negative.
This chapter introduces matrices and their basic arithmetic operations. Matrices allow linear equations to be written in a compact matrix form. The key operations covered are:
1) Matrix addition and subtraction are performed element-wise.
2) A matrix can be multiplied by a scalar by multiplying each element.
3) Matrix multiplication involves multiplying the rows of the first matrix by the columns of the second.
4) For matrix multiplication to have an inverse, the matrices must satisfy a condition on their elements.
1. The matrix is not invertible as it has repeated rows.
2. The eigenvalue is 0 since a matrix is not invertible if it has 0 as an eigenvalue.
3. The eigenvectors corresponding to 0 can be found by reducing the matrix A - 0I to row echelon form. This gives the equation x1 + x2 + x3 = 0 with x2 and x3 as free variables, so two linearly independent eigenvectors are (1, -1, 0) and (1, 0, -1).
Unit 3 hw 4 - solving equations variable both sidesLori Rapp
The document provides steps for solving equations with variables on both sides: (1) distribute any parentheses, (2) combine like terms on each side, (3) move variables to one side using opposite operations, (4) isolate the variable term, and (5) simplify the coefficient of the variable to 1 if possible. It then works through examples applying these steps, such as distributing, combining like terms, moving variables to isolate the term with x, and solving for x.
The document describes how to solve an inequality problem step-by-step: (1) isolate the variable on one side of the inequality sign using the opposite operations of addition, subtraction, multiplication, and division; (2) determine whether the coefficient of the variable is 1; and (3) check the solution by graphing the inequality. It provides an example problem of solving 2x - 7 > 11 to illustrate the process.
The student will be able to solve systems of equations using elimination with addition and subtraction. There are 5 steps to solving a system by elimination: 1) put the equations in standard form, 2) determine which variable to eliminate, 3) add or subtract the equations to eliminate the variable, 4) plug back into one equation to find the other variable, and 5) check the solution by substituting into both original equations. Two examples are provided to demonstrate the process.
The student will learn to solve systems of equations using elimination with addition and subtraction. This involves putting the equations in standard form, eliminating one variable by adding or subtracting the equations, solving for the eliminated variable, plugging back into one equation to solve for the other variable, and checking the solution. Two examples are shown of solving systems of two equations with two variables using this elimination method.
1) The document discusses graphing linear inequalities on a number line and coordinate plane. It provides examples of solving inequalities for y and graphing the corresponding boundary lines, shading the appropriate regions.
2) Methods for graphing inequalities include solving for y, graphing the boundary line, and shading the correct region based on whether the inequality is <, ≤, >, or ≥.
3) An example problem models an inequality describing the maximum number of nickels and dimes that can be had with less than $5.00, graphing the solution on the n-d plane.
1) The document discusses inequalities involving real numbers. It introduces basic rules for how inequalities are affected by addition, multiplication, taking squares, and taking reciprocals.
2) Several examples are provided to demonstrate how to solve various inequalities by applying these rules. For instance, it is shown that the inequality 4x + 7 < 3 is equivalent to x < -1.
3) Graphs are used to confirm the solutions obtained from manipulating the inequalities. The key results are that addition preserves inequalities while multiplication preserves or reverses them depending on whether the number being multiplied is positive or negative.
This chapter introduces matrices and their basic arithmetic operations. Matrices allow linear equations to be written in a compact matrix form. The key operations covered are:
1) Matrix addition and subtraction are performed element-wise.
2) A matrix can be multiplied by a scalar by multiplying each element.
3) Matrix multiplication involves multiplying the rows of the first matrix by the columns of the second.
4) For matrix multiplication to have an inverse, the matrices must satisfy a condition on their elements.
1. The matrix is not invertible as it has repeated rows.
2. The eigenvalue is 0 since a matrix is not invertible if it has 0 as an eigenvalue.
3. The eigenvectors corresponding to 0 can be found by reducing the matrix A - 0I to row echelon form. This gives the equation x1 + x2 + x3 = 0 with x2 and x3 as free variables, so two linearly independent eigenvectors are (1, -1, 0) and (1, 0, -1).
Unit 3 hw 4 - solving equations variable both sidesLori Rapp
The document provides steps for solving equations with variables on both sides: (1) distribute any parentheses, (2) combine like terms on each side, (3) move variables to one side using opposite operations, (4) isolate the variable term, and (5) simplify the coefficient of the variable to 1 if possible. It then works through examples applying these steps, such as distributing, combining like terms, moving variables to isolate the term with x, and solving for x.
The document describes how to solve an inequality problem step-by-step: (1) isolate the variable on one side of the inequality sign using the opposite operations of addition, subtraction, multiplication, and division; (2) determine whether the coefficient of the variable is 1; and (3) check the solution by graphing the inequality. It provides an example problem of solving 2x - 7 > 11 to illustrate the process.
The student will be able to solve systems of equations using elimination with addition and subtraction. There are 5 steps to solving a system by elimination: 1) put the equations in standard form, 2) determine which variable to eliminate, 3) add or subtract the equations to eliminate the variable, 4) plug back into one equation to find the other variable, and 5) check the solution by substituting into both original equations. Two examples are provided to demonstrate the process.
The student will learn to solve systems of equations using elimination with addition and subtraction. This involves putting the equations in standard form, eliminating one variable by adding or subtracting the equations, solving for the eliminated variable, plugging back into one equation to solve for the other variable, and checking the solution. Two examples are shown of solving systems of two equations with two variables using this elimination method.
1) The document discusses graphing linear inequalities on a number line and coordinate plane. It provides examples of solving inequalities for y and graphing the corresponding boundary lines, shading the appropriate regions.
2) Methods for graphing inequalities include solving for y, graphing the boundary line, and shading the correct region based on whether the inequality is <, ≤, >, or ≥.
3) An example problem models an inequality describing the maximum number of nickels and dimes that can be had with less than $5.00, graphing the solution on the n-d plane.
One-step equations can be solved in 3 steps:
1) Isolate the variable by undoing the operation on one side of the equation. To undo addition, subtract. To undo subtraction, add. To undo multiplication, divide. To undo division, multiply.
2) Apply the inverse operation to both sides of the equation to keep it balanced.
3) Solve for the variable and write it equal to a number.
To solve equations with variables on both sides:
1) Distribute any parentheses and combine like terms on each side of the equal sign.
2) Isolate the variable term by moving all other terms to one side of the equal sign using the operation that is opposite of the variable's current side.
3) Divide both sides by the coefficient of the isolated variable term to solve for the variable.
This document introduces algebra tiles, which are used to represent algebraic expressions visually. It provides examples of using the tiles to represent expressions like 2x2+3x-5 and -x2-4x+7. The document explains that the tiles can be used to model equations by placing them on both sides of an equals sign. It emphasizes that to isolate the variable in an equation, the same operations must be performed on both sides so that the equation remains balanced. Several examples are given of using the tiles to solve equations algebraically, such as finding the value of x in equations like x-2=7, x+4=8, 2x=6, and 4x-6=10.
This document provides instructions and examples for solving multi-step equations. It outlines the objective of isolating the variable to find its value and lists the rules as keeping the equation balanced, simplifying each side by combining like terms, and moving the variable to one side using inverse operations. It then provides 6 examples of equations to solve showing the steps to isolate the variable.
The document discusses solving literal equations by isolating variables. It defines literal equations as equations with more than one variable. The rules for solving literal equations are: 1) simplify each side if needed, 2) move the variable being solved for to one side using the opposite operation, 3) isolate the variable being solved for by applying the opposite operation to each side. Examples are provided of solving for different variables in equations and formulas. Practice problems are given at the end to solve for specific variables.
Chapter 3. linear equation and linear equalities in one variablesmonomath
Here are the steps to solve this inequality problem:
1) Write an expression for the perimeter in terms of x
2) Set the perimeter expression ≤ 40
3) Isolate x by undoing the operations
4) Write the solution set
The solution is 0 ≤ x ≤ 7
This document provides instructions on how to solve equations with variables on both sides by using inverse operations to isolate the variable. It explains that you must keep the equation balanced, simplify each side by combining like terms, and use inverse operations such as addition, subtraction, multiplication, and division to remove the variable from one side of the equation. Several examples of solving equations with variables on both sides are shown step-by-step.
This document provides instructions on how to solve equations with variables on both sides by using inverse operations to isolate the variable. It explains that you must keep the equation balanced, simplify each side by combining like terms, and use inverse operations such as addition, subtraction, multiplication, and division to remove the variable from one side of the equation. It then provides examples of equations and the steps to solve them by isolating the variable.
5-11 Relating Multiplication and DivisionRudy Alfonso
To find n, I would use the inverse operation of the rule.
Since the rule is to multiply by 6, I would divide 156 by 6 to isolate n.
Doing so gives n = 26.
To find n, I would use the inverse operation of the rule.
Since the rule is to multiply by 6, I would divide both sides by 6.
13 ÷ 6 = n
n = 2
Therefore, the value of n is 2.
The document provides an algebra review on manipulating algebraic equations to solve for an unknown variable x. It covers topics such as: adding/subtracting numbers, multiplying/dividing numbers, using a combination of operations, dealing with x in the denominator, misconceptions to avoid, exponents, and practice problems. The review explains that any manipulation done to one side of an equation must also be done to the other side to solve for x. It provides examples of isolating the term containing x and then solving.
Algebra Review for General Chemistry Placementjwallach
This document provides an algebra review covering manipulating algebraic equations to solve for unknown variables. It discusses adding, subtracting, multiplying, and dividing terms on both sides of equations. It also covers solving equations with exponents and variables in denominators. Examples are provided for each concept and worked out step-by-step. Readers are encouraged to practice these skills on sample equations. Key points are to manipulate both sides of an equation equally and be careful not to incorrectly change a variable from the denominator to the numerator.
Notes solving polynomials using synthetic divisionLori Rapp
This document discusses using synthetic division to evaluate polynomials at specific values and factor polynomials. It provides examples of using synthetic division to:
1) Evaluate polynomials like f(x) = x^2 - x + 5 at specific values such as f(-2)
2) Factor polynomials when one factor is known, such as factoring x^3 - 3x^2 - 13x + 15 after determining (x + 3) is a factor
3) Find all zeros of a polynomial by setting each factor equal to 0 after factoring
Step-by-step instructions and additional examples are provided to illustrate the process.
The document discusses absolute value and inequalities involving absolute value. It explains that absolute value provides the distance from zero, regardless of the number's sign. Absolute value inequalities can be expressed as intervals, with solutions falling between the interval boundaries or including the boundaries. For an inequality like x < a, the solution is the interval (-a, a); for x > a it is the union of the intervals (-∞, -a) and (a, ∞). Examples are provided to demonstrate solving absolute value inequalities algebraically.
The document discusses using synthetic division to evaluate polynomials at specific values and factor polynomials. It provides examples of using synthetic division to:
1) Evaluate polynomials like f(x) = x^2 - x + 5 at specific values such as f(-2).
2) Factor polynomials when one factor is known, such as factoring x^3 - 3x^2 - 13x + 15 after determining (x + 3) is a factor using synthetic division.
3) Determine if a binomial is a factor of a polynomial, such as showing (x - 3) is a factor of x^3 + 4x^2 - 15x - 18.
The document discusses linear equations and how to graph them. It defines linear equations as having variables with exponents of 1 that are added or subtracted. It explains how to identify the slope and y-intercept of a linear equation in slope-intercept form (y=mx+b) in order to graph it as a line on the coordinate plane. Key steps include solving for y and identifying the slope (m) and y-intercept (b). Examples are provided to demonstrate finding intercepts and graphing various linear equations.
1) The document outlines objectives and methods for solving linear equations, including solving single equations, equations with fractions, and simultaneous equations.
2) Key methods discussed are transposing terms, multiplying/dividing both sides by the same amount to isolate the variable, and using substitution or elimination for simultaneous equations.
3) Examples are provided to illustrate solving single equations with various operations like addition, subtraction, multiplication and division as well as equations containing fractions or brackets.
The document provides mathematical formulas, terms, and concepts. It includes definitions for speed, indices, parallel lines, standard form, fractions, inequalities, and sequences. It also lists steps for operations like adding and subtracting fractions, multiplying fractions, dividing fractions, expanding brackets, factorizing, and changing the subject of a formula.
The document summarizes how various Avengers calculate and solve different math problems related to their superpowers and equipment. Captain America finds the area of his shield as a function of circumference. Iron Man solves a quadratic equation to power his arc reactor. The Hulk smashes a wall and calculates how many pieces it breaks into. Hawkeye finds the equation of a parabola based on its vertex and a point. Thor analyzes the domain and graph of a skipping hammer's movement. Black Widow determines the domain and range of a radical function.
The document discusses the normal curve and its key properties. A normal curve is a bell-shaped distribution that is symmetrical around the mean value, with half of the data falling above and half below the mean. The standard deviation measures how spread out the data is from the mean. In a normal distribution, 68% of the data lies within 1 standard deviation of the mean, 95% within 2 standard deviations, and 99.7% within 3 standard deviations, following the 68-95-99.7 rule.
One-step equations can be solved in 3 steps:
1) Isolate the variable by undoing the operation on one side of the equation. To undo addition, subtract. To undo subtraction, add. To undo multiplication, divide. To undo division, multiply.
2) Apply the inverse operation to both sides of the equation to keep it balanced.
3) Solve for the variable and write it equal to a number.
To solve equations with variables on both sides:
1) Distribute any parentheses and combine like terms on each side of the equal sign.
2) Isolate the variable term by moving all other terms to one side of the equal sign using the operation that is opposite of the variable's current side.
3) Divide both sides by the coefficient of the isolated variable term to solve for the variable.
This document introduces algebra tiles, which are used to represent algebraic expressions visually. It provides examples of using the tiles to represent expressions like 2x2+3x-5 and -x2-4x+7. The document explains that the tiles can be used to model equations by placing them on both sides of an equals sign. It emphasizes that to isolate the variable in an equation, the same operations must be performed on both sides so that the equation remains balanced. Several examples are given of using the tiles to solve equations algebraically, such as finding the value of x in equations like x-2=7, x+4=8, 2x=6, and 4x-6=10.
This document provides instructions and examples for solving multi-step equations. It outlines the objective of isolating the variable to find its value and lists the rules as keeping the equation balanced, simplifying each side by combining like terms, and moving the variable to one side using inverse operations. It then provides 6 examples of equations to solve showing the steps to isolate the variable.
The document discusses solving literal equations by isolating variables. It defines literal equations as equations with more than one variable. The rules for solving literal equations are: 1) simplify each side if needed, 2) move the variable being solved for to one side using the opposite operation, 3) isolate the variable being solved for by applying the opposite operation to each side. Examples are provided of solving for different variables in equations and formulas. Practice problems are given at the end to solve for specific variables.
Chapter 3. linear equation and linear equalities in one variablesmonomath
Here are the steps to solve this inequality problem:
1) Write an expression for the perimeter in terms of x
2) Set the perimeter expression ≤ 40
3) Isolate x by undoing the operations
4) Write the solution set
The solution is 0 ≤ x ≤ 7
This document provides instructions on how to solve equations with variables on both sides by using inverse operations to isolate the variable. It explains that you must keep the equation balanced, simplify each side by combining like terms, and use inverse operations such as addition, subtraction, multiplication, and division to remove the variable from one side of the equation. Several examples of solving equations with variables on both sides are shown step-by-step.
This document provides instructions on how to solve equations with variables on both sides by using inverse operations to isolate the variable. It explains that you must keep the equation balanced, simplify each side by combining like terms, and use inverse operations such as addition, subtraction, multiplication, and division to remove the variable from one side of the equation. It then provides examples of equations and the steps to solve them by isolating the variable.
5-11 Relating Multiplication and DivisionRudy Alfonso
To find n, I would use the inverse operation of the rule.
Since the rule is to multiply by 6, I would divide 156 by 6 to isolate n.
Doing so gives n = 26.
To find n, I would use the inverse operation of the rule.
Since the rule is to multiply by 6, I would divide both sides by 6.
13 ÷ 6 = n
n = 2
Therefore, the value of n is 2.
The document provides an algebra review on manipulating algebraic equations to solve for an unknown variable x. It covers topics such as: adding/subtracting numbers, multiplying/dividing numbers, using a combination of operations, dealing with x in the denominator, misconceptions to avoid, exponents, and practice problems. The review explains that any manipulation done to one side of an equation must also be done to the other side to solve for x. It provides examples of isolating the term containing x and then solving.
Algebra Review for General Chemistry Placementjwallach
This document provides an algebra review covering manipulating algebraic equations to solve for unknown variables. It discusses adding, subtracting, multiplying, and dividing terms on both sides of equations. It also covers solving equations with exponents and variables in denominators. Examples are provided for each concept and worked out step-by-step. Readers are encouraged to practice these skills on sample equations. Key points are to manipulate both sides of an equation equally and be careful not to incorrectly change a variable from the denominator to the numerator.
Notes solving polynomials using synthetic divisionLori Rapp
This document discusses using synthetic division to evaluate polynomials at specific values and factor polynomials. It provides examples of using synthetic division to:
1) Evaluate polynomials like f(x) = x^2 - x + 5 at specific values such as f(-2)
2) Factor polynomials when one factor is known, such as factoring x^3 - 3x^2 - 13x + 15 after determining (x + 3) is a factor
3) Find all zeros of a polynomial by setting each factor equal to 0 after factoring
Step-by-step instructions and additional examples are provided to illustrate the process.
The document discusses absolute value and inequalities involving absolute value. It explains that absolute value provides the distance from zero, regardless of the number's sign. Absolute value inequalities can be expressed as intervals, with solutions falling between the interval boundaries or including the boundaries. For an inequality like x < a, the solution is the interval (-a, a); for x > a it is the union of the intervals (-∞, -a) and (a, ∞). Examples are provided to demonstrate solving absolute value inequalities algebraically.
The document discusses using synthetic division to evaluate polynomials at specific values and factor polynomials. It provides examples of using synthetic division to:
1) Evaluate polynomials like f(x) = x^2 - x + 5 at specific values such as f(-2).
2) Factor polynomials when one factor is known, such as factoring x^3 - 3x^2 - 13x + 15 after determining (x + 3) is a factor using synthetic division.
3) Determine if a binomial is a factor of a polynomial, such as showing (x - 3) is a factor of x^3 + 4x^2 - 15x - 18.
The document discusses linear equations and how to graph them. It defines linear equations as having variables with exponents of 1 that are added or subtracted. It explains how to identify the slope and y-intercept of a linear equation in slope-intercept form (y=mx+b) in order to graph it as a line on the coordinate plane. Key steps include solving for y and identifying the slope (m) and y-intercept (b). Examples are provided to demonstrate finding intercepts and graphing various linear equations.
1) The document outlines objectives and methods for solving linear equations, including solving single equations, equations with fractions, and simultaneous equations.
2) Key methods discussed are transposing terms, multiplying/dividing both sides by the same amount to isolate the variable, and using substitution or elimination for simultaneous equations.
3) Examples are provided to illustrate solving single equations with various operations like addition, subtraction, multiplication and division as well as equations containing fractions or brackets.
The document provides mathematical formulas, terms, and concepts. It includes definitions for speed, indices, parallel lines, standard form, fractions, inequalities, and sequences. It also lists steps for operations like adding and subtracting fractions, multiplying fractions, dividing fractions, expanding brackets, factorizing, and changing the subject of a formula.
The document summarizes how various Avengers calculate and solve different math problems related to their superpowers and equipment. Captain America finds the area of his shield as a function of circumference. Iron Man solves a quadratic equation to power his arc reactor. The Hulk smashes a wall and calculates how many pieces it breaks into. Hawkeye finds the equation of a parabola based on its vertex and a point. Thor analyzes the domain and graph of a skipping hammer's movement. Black Widow determines the domain and range of a radical function.
Similar to Unit 3 hw 2 - solving 1 step equations (20)
The document discusses the normal curve and its key properties. A normal curve is a bell-shaped distribution that is symmetrical around the mean value, with half of the data falling above and half below the mean. The standard deviation measures how spread out the data is from the mean. In a normal distribution, 68% of the data lies within 1 standard deviation of the mean, 95% within 2 standard deviations, and 99.7% within 3 standard deviations, following the 68-95-99.7 rule.
The document explains how to organize information from a survey using a Venn diagram. It provides data on the percentage of people who visited Spain, Canada, and Germany. The Venn diagram is then completed by placing this information in the relevant areas: 4% visited all 3 countries, 13% visited Spain and Germany, 21% visited Canada and Germany, 3% visited Spain and Canada but not Germany, and the remaining percentages visited only one country.
The document discusses using the distance formula to determine if a point lies on a circle. It explains that if the center point and radius of a circle are known, as well as a point on the circle, the distance formula can be used to calculate the radius. Then, the distance formula can be applied to the center point and the unknown point to obtain its distance. If the distance equals the radius, then the point lies on the circle. Several examples are worked through to demonstrate this process.
The document discusses determining what type of quadrilateral a shape is on a coordinate plane. It reviews properties of different quadrilaterals and provides steps to systematically check if a shape is a trapezoid, parallelogram, rectangle, square, or just a quadrilateral. The document then works through determining the type of quadrilateral formed by the points A(-4, -2), B(-2, 4), C(4, 2), D(2, -4) by checking properties such as parallel sides, perpendicular sides, and side lengths. Through this process, it is proven that the shape is a square.
The document discusses multiplying polynomials by monomials. It explains that to multiply a polynomial by a monomial, you distribute the monomial to each term inside the parentheses. This is done by multiplying each term by the monomial. The number of terms after multiplying will be the same as the number of terms inside the original parentheses. It provides examples of multiplying different polynomials by monomials. It has students work through examples on their own and check their work.
The document describes how ancient mathematicians derived the formula for the area of a circle by cutting a circle into pieces and rearranging them to form a rectangle. They determined that the height of the rectangle is equal to the radius of the circle, and the base is equal to half the circumference. Substituting these relationships into the area formula for a rectangle produces the area of a circle formula: A = πr2.
Unit 4 hw 8 - pointslope, parallel & perpLori Rapp
The document discusses the point-slope formula for writing the equation of a line given a point and slope. It provides examples of using the formula, such as writing the equation of the line through point (3, -2) with slope 5. It also discusses that horizontal lines have a slope of 0 and the equation y=b, since the y-coordinate remains constant while the x-coordinate changes. The slope of a horizontal line is 0 because when calculating slope using two points, the change in y-values is 0.
The document describes sets and Venn diagrams using data about members of math, science, and chess clubs. It provides examples of representing sets using brackets and defining the intersection, union, and relationship between sets visually in a Venn diagram. Key points covered include using set notation to represent membership of each club, observing relationships like some students belonging to multiple clubs, and how intersection, union, and Venn diagrams can model relationships between sets.
The document discusses absolute value, absolute value equations, and absolute value inequalities. It defines absolute value as the distance from zero on the number line, which is always positive. Absolute value equations account for both positive and negative cases, while absolute value inequalities split into two cases - one for positive values and one for negative values. An example shows how to write the inequalities for both cases of |x| < 4, determine the solution is an intersection of the cases, and represent the solution set as {x | -4 < x < 4}.
The document discusses compound inequalities, which are statements combining two or more inequalities using AND or OR. AND means the solution must satisfy both inequalities, while OR means it must satisfy at least one. Examples are provided to demonstrate solving and graphing compound inequalities on a number line, including checking solutions in the original inequalities.
This document provides instruction on solving quadratic equations. It begins with an introduction explaining why quadratic equations are useful and includes a video example. It then defines quadratic equations and shows students how to identify the coefficients a, b, and c. The bulk of the document demonstrates two methods for solving quadratic equations: factoring and using the quadratic formula. It includes examples of each method and practice problems for students to work through. The goal is to teach students how to solve quadratic equations through factoring and using the formula.
- The document discusses the associative properties of addition, subtraction, and multiplication.
- It shows that addition and multiplication are associative by working through examples with different groupings, but subtraction is not associative as the examples produce different results depending on grouping.
- The key idea is that for operations to be associative, the result must be the same regardless of how the numbers are grouped during calculation.
The document discusses the benefits of exercise for mental health. Regular physical activity can help reduce anxiety and depression and improve mood and cognitive functioning. Exercise causes chemical changes in the brain that may help protect against mental illness and improve symptoms.
Unit 4 hw 7 - direct variation & linear equation give 2 pointsLori Rapp
This document discusses direct variation, which is a linear equation that passes through the origin. It defines direct variation as y=kx, where k is the constant of variation. It provides examples of graphs that do and do not represent direct variations. It also shows step-by-step processes for finding the direct variation equation from two points, and for solving a direct variation problem when given a point and asked to find the corresponding y-value for a different x-value.
The document discusses solving absolute value equations. It explains that absolute value is the distance a number is from 0, and provides examples. It then states that when solving absolute value equations, two separate equations must be created to account for the number inside the absolute value being positive or negative. Steps are provided for solving sample absolute value equations.
The document provides steps for solving literal equations (equations with more than one variable) by solving for a specific variable. The steps are: 1) Identify the term with the variable being solved for, 2) Move all other terms to the opposite side, 3) Isolate the variable term by undoing any operations like multiplication or division.
Unit 4 hw 1 - coordinate plane, d&r, midpointLori Rapp
The document discusses key concepts related to coordinate planes and graphing points, including:
1) How to graph points using two perpendicular number lines called axes, with their point of intersection called the origin.
2) How coordinate pairs (x,y) are used to name points, with the first coordinate being the x-coordinate and the second being the y-coordinate.
3) How the axes divide the plane into four quadrants and examples of points in different quadrants.
4) How to find the midpoint between two points by taking the average of their x-coordinates and y-coordinates.
The document provides steps for multiplying rational numbers and fractions. It begins with examples of multiplying fractions such as -2/6 × -3/11, and provides steps like multiplying straight across and simplifying the answer. It then discusses multiplying mixed numbers, like changing to improper fractions first before multiplying. Further examples include multiplying rational expressions like 3.2(8x - 2x) and evaluating expressions with fractions of quantities. The document emphasizes best practices for rational number operations like simplifying before multiplying.
How to Manage Your Lost Opportunities in Odoo 17 CRMCeline George
Odoo 17 CRM allows us to track why we lose sales opportunities with "Lost Reasons." This helps analyze our sales process and identify areas for improvement. Here's how to configure lost reasons in Odoo 17 CRM
This presentation includes basic of PCOS their pathology and treatment and also Ayurveda correlation of PCOS and Ayurvedic line of treatment mentioned in classics.
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...PECB
Denis is a dynamic and results-driven Chief Information Officer (CIO) with a distinguished career spanning information systems analysis and technical project management. With a proven track record of spearheading the design and delivery of cutting-edge Information Management solutions, he has consistently elevated business operations, streamlined reporting functions, and maximized process efficiency.
Certified as an ISO/IEC 27001: Information Security Management Systems (ISMS) Lead Implementer, Data Protection Officer, and Cyber Risks Analyst, Denis brings a heightened focus on data security, privacy, and cyber resilience to every endeavor.
His expertise extends across a diverse spectrum of reporting, database, and web development applications, underpinned by an exceptional grasp of data storage and virtualization technologies. His proficiency in application testing, database administration, and data cleansing ensures seamless execution of complex projects.
What sets Denis apart is his comprehensive understanding of Business and Systems Analysis technologies, honed through involvement in all phases of the Software Development Lifecycle (SDLC). From meticulous requirements gathering to precise analysis, innovative design, rigorous development, thorough testing, and successful implementation, he has consistently delivered exceptional results.
Throughout his career, he has taken on multifaceted roles, from leading technical project management teams to owning solutions that drive operational excellence. His conscientious and proactive approach is unwavering, whether he is working independently or collaboratively within a team. His ability to connect with colleagues on a personal level underscores his commitment to fostering a harmonious and productive workplace environment.
Date: May 29, 2024
Tags: Information Security, ISO/IEC 27001, ISO/IEC 42001, Artificial Intelligence, GDPR
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This presentation was provided by Steph Pollock of The American Psychological Association’s Journals Program, and Damita Snow, of The American Society of Civil Engineers (ASCE), for the initial session of NISO's 2024 Training Series "DEIA in the Scholarly Landscape." Session One: 'Setting Expectations: a DEIA Primer,' was held June 6, 2024.
Reimagining Your Library Space: How to Increase the Vibes in Your Library No ...Diana Rendina
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Chapter wise All Notes of First year Basic Civil Engineering.pptxDenish Jangid
Chapter wise All Notes of First year Basic Civil Engineering
Syllabus
Chapter-1
Introduction to objective, scope and outcome the subject
Chapter 2
Introduction: Scope and Specialization of Civil Engineering, Role of civil Engineer in Society, Impact of infrastructural development on economy of country.
Chapter 3
Surveying: Object Principles & Types of Surveying; Site Plans, Plans & Maps; Scales & Unit of different Measurements.
Linear Measurements: Instruments used. Linear Measurement by Tape, Ranging out Survey Lines and overcoming Obstructions; Measurements on sloping ground; Tape corrections, conventional symbols. Angular Measurements: Instruments used; Introduction to Compass Surveying, Bearings and Longitude & Latitude of a Line, Introduction to total station.
Levelling: Instrument used Object of levelling, Methods of levelling in brief, and Contour maps.
Chapter 4
Buildings: Selection of site for Buildings, Layout of Building Plan, Types of buildings, Plinth area, carpet area, floor space index, Introduction to building byelaws, concept of sun light & ventilation. Components of Buildings & their functions, Basic concept of R.C.C., Introduction to types of foundation
Chapter 5
Transportation: Introduction to Transportation Engineering; Traffic and Road Safety: Types and Characteristics of Various Modes of Transportation; Various Road Traffic Signs, Causes of Accidents and Road Safety Measures.
Chapter 6
Environmental Engineering: Environmental Pollution, Environmental Acts and Regulations, Functional Concepts of Ecology, Basics of Species, Biodiversity, Ecosystem, Hydrological Cycle; Chemical Cycles: Carbon, Nitrogen & Phosphorus; Energy Flow in Ecosystems.
Water Pollution: Water Quality standards, Introduction to Treatment & Disposal of Waste Water. Reuse and Saving of Water, Rain Water Harvesting. Solid Waste Management: Classification of Solid Waste, Collection, Transportation and Disposal of Solid. Recycling of Solid Waste: Energy Recovery, Sanitary Landfill, On-Site Sanitation. Air & Noise Pollution: Primary and Secondary air pollutants, Harmful effects of Air Pollution, Control of Air Pollution. . Noise Pollution Harmful Effects of noise pollution, control of noise pollution, Global warming & Climate Change, Ozone depletion, Greenhouse effect
Text Books:
1. Palancharmy, Basic Civil Engineering, McGraw Hill publishers.
2. Satheesh Gopi, Basic Civil Engineering, Pearson Publishers.
3. Ketki Rangwala Dalal, Essentials of Civil Engineering, Charotar Publishing House.
4. BCP, Surveying volume 1
A review of the growth of the Israel Genealogy Research Association Database Collection for the last 12 months. Our collection is now passed the 3 million mark and still growing. See which archives have contributed the most. See the different types of records we have, and which years have had records added. You can also see what we have for the future.
Strategies for Effective Upskilling is a presentation by Chinwendu Peace in a Your Skill Boost Masterclass organisation by the Excellence Foundation for South Sudan on 08th and 09th June 2024 from 1 PM to 3 PM on each day.
4. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.
5. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.
6. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.
Anything outside the circle
needs to move to the other
side by doing the opposite
operation.
7. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.
Anything outside the circle
needs to move to the other
side by doing the opposite
operation.
Opposite of addition is
Subtraction.
8. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.
−3 −3 Anything outside the circle
needs to move to the other
side by doing the opposite
operation.
Opposite of addition is
Subtraction.
9. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.
−3 −3 Anything outside the circle
needs to move to the other
side by doing the opposite
x=2 operation.
Opposite of addition is
Subtraction.
10. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.
−3 −3 Anything outside the circle
needs to move to the other
side by doing the opposite
x=2 operation.
Opposite of addition is
Subtraction.
x is alone so you are done.
12. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
isolate.
13. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
isolate.
14. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
isolate.
Move 8 by opposite
operation.
15. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
isolate.
Move 8 by opposite
operation.
Opposite of subtraction is
addition.
16. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
+8 +8 isolate.
Move 8 by opposite
operation.
Opposite of subtraction is
addition.
17. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
+8 +8 isolate.
Move 8 by opposite
x=6 operation.
Opposite of subtraction is
addition.
18. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
+8 +8 isolate.
Move 8 by opposite
x=6 operation.
Opposite of subtraction is
addition.
x is alone so you are done.
20. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.
21. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.
22. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.
There is nothing outside
the circle so look inside
now.
23. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.
There is nothing outside
the circle so look inside
now.
Opposite of multiplication is
division.
24. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.
− 3 −3 There is nothing outside
the circle so look inside
now.
Opposite of multiplication is
division.
25. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.
− 3 −3 There is nothing outside
the circle so look inside
8 now.
x= Opposite of multiplication is
3 division.
26. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.
− 3 −3 There is nothing outside
the circle so look inside
8 now.
x= Opposite of multiplication is
3 division.
x is alone so you are done.
28. Solve for x.
x Circle the term with the
=7 variable you need to
5 isolate.
29. Solve for x.
x Circle the term with the
=7 variable you need to
5 isolate.
30. Solve for x.
x Circle the term with the
=7 variable you need to
5 isolate.
There is nothing outside
the circle so look inside.
31. Solve for x.
x Circle the term with the
=7 variable you need to
5 isolate.
There is nothing outside
the circle so look inside.
Opposite of division is
multiplication.
32. Solve for x.
x Circle the term with the
5 ⋅ = 7⋅ 5 variable you need to
5 isolate.
There is nothing outside
the circle so look inside.
Opposite of division is
multiplication.
33. Solve for x.
x Circle the term with the
5 ⋅ = 7⋅ 5 variable you need to
5 isolate.
There is nothing outside
x = 35 the circle so look inside.
Opposite of division is
multiplication.
34. Solve for x.
x Circle the term with the
5 ⋅ = 7⋅ 5 variable you need to
5 isolate.
There is nothing outside
x = 35 the circle so look inside.
Opposite of division is
multiplication.
x is alone so you are done.
36. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
37. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
38. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
Anything outside the circle
needs to move to the other
side by doing the opposite
operation.
39. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
Anything outside the circle
needs to move to the other
side by doing the opposite
operation.
The 7 is positive so Subtract.
40. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
−7 −7 Anything outside the circle
needs to move to the other
side by doing the opposite
operation.
The 7 is positive so Subtract.
41. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
−7 −7 Anything outside the circle
needs to move to the other
−x = −8 side by doing the opposite
operation.
The 7 is positive so Subtract.
42. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
−7 −7 Anything outside the circle
needs to move to the other
−x = −8 side by doing the opposite
operation.
The 7 is positive so Subtract.
x is NOT alone. Divide by
negative one.
43. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
−7 −7 Anything outside the circle
needs to move to the other
−x = −8 side by doing the opposite
operation.
−1 −1 The 7 is positive so Subtract.
x is NOT alone. Divide by
negative one.
44. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
−7 −7 Anything outside the circle
needs to move to the other
−x = −8 side by doing the opposite
operation.
−1 −1 The 7 is positive so Subtract.
x is NOT alone. Divide by
x=8 negative one.
45. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
−7 −7 Anything outside the circle
needs to move to the other
−x = −8 side by doing the opposite
operation.
−1 −1 The 7 is positive so Subtract.
x is NOT alone. Divide by
x=8 negative one.
x is alone so you are done.