2. Applications:
-Construction of the fourth
proportional
-Dividing a segment into equal
parts.
-Constructions of points
-Enlargement โReduction
3. Construction of the fourth proportional
โข Question :construct the fourth proportional to 4,7 and 5.
Etape 1:Trace a straight line (d) and place 3 points O,A & B in the following order :OA = 4cm and OB =7cm.
O A B (d)
0 4 7
Etape 2:Trace a straight line (dโฒ) that cuts (d) at O and place the point C such that OC = 5cm.
O A B (d)
0 4 7
C
5
D
x (dโฒ)
4. Step 3: construct the parallel to (AC) passing through B, it cuts (dโ) at D.
According to Thalesโ theorem, the length x of segment [OD] is: 5/x = 4/7 or x x 4 = 5 x 7
The length x of segment [OD] is the fourth proportional to 4,7 and 5.
23. Elements of enlargement and reduction
The elements of enlargement or reduction are:
1) The ratio or the coefficient k:
๐ =
๐๐๐๐๐กโ ๐๐ ๐๐๐ค ๐ ๐๐๐ (๐๐๐๐๐)
๐๐๐๐๐กโ ๐๐ ๐กโ๐ ๐๐๐๐๐๐๐๐
โข If k>1,then the image is an enlargement
โข If k<1, then the image is reduction
2) Center of enlargement or reduction
24.
25.
26. Application:
Given segment AB and AโBโ the image of AB by enlargement
A
B
Aโ
Bโ
1) Find the center of enlargement O
2)Suppose that OAโ=12 and OA=3
Find the ratio of enlargement
O
27. Enlarge triangle ABC of ratio 3 and center O
๐๐ตโฒ
๐๐ต
= 3 ๐กโ๐๐ ๐๐ตโฒ
= 3๐๐ต
๐๐ถโฒ
๐๐ถ
= 3 ๐กโ๐๐ ๐๐ถโฒ = 3๐๐ถ
๐๐ดโฒ
๐๐ด
= 3 ๐กโ๐๐ ๐๐ดโฒ = 3๐๐ด
28. Enlarge triangle ABC of ratio 3 and center A
๐ด๐ตโฒ
๐ด๐ต
= 3 ๐กโ๐๐ ๐ด๐ตโฒ
= 3๐ด๐ต
๐ด๐ถโฒ
๐ด๐ถ
= 3 ๐กโ๐๐ ๐ด๐ถโฒ = 3๐ด๐ถ
๐ด๐ดโฒ
๐ด๐ด
= 3 ๐กโ๐๐ ๐ด๐ดโฒ
= 3๐ด๐ด
But AA=0 then AAโ=0
This means that A and Aโ are
confounded
29. Reduce triangle ABC of ratio 1/2 and center O
๐๐ตโฒ
๐๐ต
=
1
2
๐กโ๐๐ ๐๐ตโฒ
=
1
2
๐๐ต
๐๐ถโฒ
๐๐ถ
=
1
2
๐กโ๐๐ ๐๐ถโฒ =
1
2
๐๐ถ
๐๐ดโฒ
๐๐ด
=
1
2
๐กโ๐๐ ๐๐ดโฒ =
1
2
๐๐ด
30. Reduce triangle ABC of ratio 1/2 and center A
๐ด๐ตโฒ
๐ด๐ต
=
1
2
๐กโ๐๐ ๐ด๐ตโฒ
=
1
2
๐ด๐ต
๐ด๐ถโฒ
๐ด๐ถ
=
1
2
๐กโ๐๐ ๐ด๐ถโฒ =
1
2
๐ด๐ถ
๐ด๐ดโฒ
๐ด๐ด
=
1
2
๐กโ๐๐ ๐ด๐ดโฒ
=
1
2
๐ด๐ด
But AA=0 then AAโ=0
This means that A and Aโ are
confounded