BY ---- MOHIT DUREJA
BY ---- MOHIT DUREJA
BY ---- MOHIT DUREJA
INSTRUEMENT USED IN TACHEOMETRY
1) TACHEOMETER
• IT IS A TRANSIT
THEODOLITE FITTED WITH
A STADIA DIAPHRAGAM.
• THE STADIA DIAPHRAGAM
CONSIST OF ONE STADIA
ABOVE AND OTHER AN
EQUAL DISTANCE BELOW
THE HORIZONTAL CROSS
HAIR
BY ---- MOHIT DUREJA
DIFFERENT TYPES OF DIAPHRAGAM
CROSS HAIR DIAPHRAGAM
STADIA HAIR DIAPHRAGAM
BY ---- MOHIT DUREJA
2) STADIA ROD
• For small sights
ordinary leveling staff
is used. It has a least
count of 5mm.
• For long sight stadia
rod is used. The least
count is 5mm or 10mm
cont… INSTRUEMENT USED IN TACHEOMETRY
BY ---- MOHIT DUREJA
Requirement/ Characteristics of
Tacheometer
• The value of multiplying constant should be
100
• The central horizontal hair must be exactly
mid way between the other two horizontal
hair
• The value of additive constant should be zero.
• In order to have bright image the aperture of
objective should be 35 to 45 mm.
BY ---- MOHIT DUREJA
METHODS OF TECHEOMETRY
BY ---- MOHIT DUREJA
STADIA INTERVAL
0R
STAFF INTERCEPT (S)
S=(12.38 - 11.98)
S= 0.40 M
BY ---- MOHIT DUREJA
BY ---- MOHIT DUREJA
:-The stadia method is based on the principle that
the ratio of the perpendicular to the base is
constant in similar isosceles
triangles
D
BY ---- MOHIT DUREJA
D= K s + C
WHERE;
K= MULTIPLYING CONSTANT
C = ADDITIVE CONSTANT TACHEOMETRIC CONSTANT
Multiplying constant is usually taken as 100
Additive constant is taken as zero(0)
There values are generally provide by manufacturers BY ---- MOHIT DUREJA
DETERMINATION OF STADIA CONSTANT
1) BY DIRECTLY MEASURE FROM THE INSTRUMENT
D= f s + (f+d)
i
f
BY ---- MOHIT DUREJA
2) BY COMPUTATION
D1= f S1 + (f+d)
i
D2= f S2 + (f+d)
i
D3= f S3 + (f+d)
i
…………..1
…………..2
…………..3
SOLVE
EQ. 1 & 2
EQ. 2 & 3
EQ. 3 & 1
And find exact value by
their mean
f
i
(f+d) = ?
= ?K
C
BY ---- MOHIT DUREJA
Q .) Two distance of 90m and 250m were accurately measured out and the
intercepts on the vertical were 0.895 & 2.495m respectively. Calculate
Tacheometric constant.
BY ---- MOHIT DUREJA
Q. With telescope horizontal, the readings taken by upper and
lower wires were 3.840 and1.060 m. Find the horizontal distance
and elevation of staff station if the RL of instrument axis is
341.540m. The central hair reading was 2.450. (K=100, c=0.4)
BY ---- MOHIT DUREJA
Distance and elevation formula with inclined sight
D=K Cos α S Cos α + C Cos α
V=K Sin α S Cos α + C Sinα
D= K S + C ……from Case 1
RL of staff station (M)= RL of Inst. Axis + (V-h)
D
α =ANGLE OF ELEVATION
BY ---- MOHIT DUREJA
Distance and elevation formula with inclined sight
D=K Cos α S Cos α + C Cos α
V=K Sin α S Cos α + C Sinα
D= K S + C ……from Case 1
RL of staff station (M)= RL of Instrument Axis - (V+h)
α =ANGLE OF DEPRESSION
BY ---- MOHIT DUREJA
Q.) A tacheometer was set up at A and the readings on staff held
vertical at B were 1.215, 1.825, 2.435, the line of sight at
elevation of 6ᴼ30’. Calculate distance between them and RL of
point B if the RL of the sight is 350.700 m. ( K=100 ,C=0.35)
BY ---- MOHIT DUREJA

Tacheometry

  • 1.
  • 2.
  • 3.
  • 4.
    INSTRUEMENT USED INTACHEOMETRY 1) TACHEOMETER • IT IS A TRANSIT THEODOLITE FITTED WITH A STADIA DIAPHRAGAM. • THE STADIA DIAPHRAGAM CONSIST OF ONE STADIA ABOVE AND OTHER AN EQUAL DISTANCE BELOW THE HORIZONTAL CROSS HAIR BY ---- MOHIT DUREJA
  • 5.
    DIFFERENT TYPES OFDIAPHRAGAM CROSS HAIR DIAPHRAGAM STADIA HAIR DIAPHRAGAM BY ---- MOHIT DUREJA
  • 6.
    2) STADIA ROD •For small sights ordinary leveling staff is used. It has a least count of 5mm. • For long sight stadia rod is used. The least count is 5mm or 10mm cont… INSTRUEMENT USED IN TACHEOMETRY BY ---- MOHIT DUREJA
  • 7.
    Requirement/ Characteristics of Tacheometer •The value of multiplying constant should be 100 • The central horizontal hair must be exactly mid way between the other two horizontal hair • The value of additive constant should be zero. • In order to have bright image the aperture of objective should be 35 to 45 mm. BY ---- MOHIT DUREJA
  • 8.
    METHODS OF TECHEOMETRY BY---- MOHIT DUREJA
  • 9.
    STADIA INTERVAL 0R STAFF INTERCEPT(S) S=(12.38 - 11.98) S= 0.40 M BY ---- MOHIT DUREJA
  • 10.
  • 11.
    :-The stadia methodis based on the principle that the ratio of the perpendicular to the base is constant in similar isosceles triangles D BY ---- MOHIT DUREJA
  • 12.
    D= K s+ C WHERE; K= MULTIPLYING CONSTANT C = ADDITIVE CONSTANT TACHEOMETRIC CONSTANT Multiplying constant is usually taken as 100 Additive constant is taken as zero(0) There values are generally provide by manufacturers BY ---- MOHIT DUREJA
  • 13.
    DETERMINATION OF STADIACONSTANT 1) BY DIRECTLY MEASURE FROM THE INSTRUMENT D= f s + (f+d) i f BY ---- MOHIT DUREJA
  • 14.
    2) BY COMPUTATION D1=f S1 + (f+d) i D2= f S2 + (f+d) i D3= f S3 + (f+d) i …………..1 …………..2 …………..3 SOLVE EQ. 1 & 2 EQ. 2 & 3 EQ. 3 & 1 And find exact value by their mean f i (f+d) = ? = ?K C BY ---- MOHIT DUREJA
  • 15.
    Q .) Twodistance of 90m and 250m were accurately measured out and the intercepts on the vertical were 0.895 & 2.495m respectively. Calculate Tacheometric constant. BY ---- MOHIT DUREJA
  • 16.
    Q. With telescopehorizontal, the readings taken by upper and lower wires were 3.840 and1.060 m. Find the horizontal distance and elevation of staff station if the RL of instrument axis is 341.540m. The central hair reading was 2.450. (K=100, c=0.4) BY ---- MOHIT DUREJA
  • 17.
    Distance and elevationformula with inclined sight D=K Cos α S Cos α + C Cos α V=K Sin α S Cos α + C Sinα D= K S + C ……from Case 1 RL of staff station (M)= RL of Inst. Axis + (V-h) D α =ANGLE OF ELEVATION BY ---- MOHIT DUREJA
  • 18.
    Distance and elevationformula with inclined sight D=K Cos α S Cos α + C Cos α V=K Sin α S Cos α + C Sinα D= K S + C ……from Case 1 RL of staff station (M)= RL of Instrument Axis - (V+h) α =ANGLE OF DEPRESSION BY ---- MOHIT DUREJA
  • 19.
    Q.) A tacheometerwas set up at A and the readings on staff held vertical at B were 1.215, 1.825, 2.435, the line of sight at elevation of 6ᴼ30’. Calculate distance between them and RL of point B if the RL of the sight is 350.700 m. ( K=100 ,C=0.35) BY ---- MOHIT DUREJA