Strain
1. Strain
Goal
2. Normal & Lateral Strain
3. Shear Strain
1/6
Which deformation is large?
100 mmOriginal
Length
60 mm
10 N
10 N
Total deformation depends on original length !
2/6
→ characterize as material property
Strain
Elongation per unit length
[ non-dimensional quantity]
Normal Strain
Shear Strain
ε
γ
:
:
Lateral Strainε’:
epsilon
gamma
epsilon prime
Mode and Symbol
3/6
Normal & Lateral Strain
l
d
PP
l + Δl
d+ Δd
ε =
Δl
l
Parallel to load
Normal Strain
ε’=
Δd
d
Perpendicular to load
Lateral Strain
2D
4/6
Shear Stress
P
P
l
γ =
l
Δl
Δl = tanl ∠ c’b c
γ =
l
Δl ~−∠ c’b c
Δl ~− l ∠ c’b c
∠ c’b c 0∵(
)
~−
∠ a b cAngle variation ofShear Stress =
Δl
a
b c
d
c’
d’
5/6
Summary
1. Normal Strain
2. Lateral Strain
3. Shear Strain
Elongation per Unit Length [ - ]
6/6

Strain

  • 1.
    Strain 1. Strain Goal 2. Normal& Lateral Strain 3. Shear Strain 1/6
  • 2.
    Which deformation islarge? 100 mmOriginal Length 60 mm 10 N 10 N Total deformation depends on original length ! 2/6 → characterize as material property
  • 3.
    Strain Elongation per unitlength [ non-dimensional quantity] Normal Strain Shear Strain ε γ : : Lateral Strainε’: epsilon gamma epsilon prime Mode and Symbol 3/6
  • 4.
    Normal & LateralStrain l d PP l + Δl d+ Δd ε = Δl l Parallel to load Normal Strain ε’= Δd d Perpendicular to load Lateral Strain 2D 4/6
  • 5.
    Shear Stress P P l γ = l Δl Δl= tanl ∠ c’b c γ = l Δl ~−∠ c’b c Δl ~− l ∠ c’b c ∠ c’b c 0∵( ) ~− ∠ a b cAngle variation ofShear Stress = Δl a b c d c’ d’ 5/6
  • 6.
    Summary 1. Normal Strain 2.Lateral Strain 3. Shear Strain Elongation per Unit Length [ - ] 6/6

Editor's Notes

  • #2 それでは,まず「応力とひずみ」についての講義を始めます. ここでの目標は,次の3つです. 一つ目が、 5min
  • #3 材料が同じでも変形の度合いが変わってしまう! 基本的にな特性が形状に依存してしまう よろしくない たとえば,Aさんは10mm Bさんは100mmで 変形両を議論すると,Bさんのほうがよく変形するざいりょうだとおもわれてしまう
  • #5 deltaはマイナスのあたいかもしれません