Stars from what part of the main sequence are likely to become black holes? Explain your
answer (You may need to look for additional information to answer this question) b)If you were
to look up into the sky for a few hours, and see 100 stars (or take a picture of 100 stars making
up a starfield), why would you see the particular stars that you see out of the billions of stars in
the Universe\'? Include two main reasons (Thinking about magnitude might help you answer this
question) C)Many variable stars are stars in the Yellow or Red Giant stages List at least two such
categories of variable stars.
Solution
a) Most black holes form from the remnants of a large star that dies in a supernova explosion.
(Smaller stars become dense neutron stars, which are not massive enough to trap light.) If the
total mass of the star is large enough (about three times the mass of the Sun), it can be proven
theoretically that no force can keep the star from collapsing under the influence of gravity.
However, as the star collapses, a strange thing occurs. As the surface of the star nears an
imaginary surface called the \"event horizon,\" time on the star slows relative to the time kept by
observers far away. When the surface reaches the event horizon, time stands still, and the star
can collapse no more - it is a frozen collapsing object.
b)
Whether we are able to see an object or not just depends only on the amount of light that is
reaching us and is independent of its size. If you cannot see an object, it just means that the
amount of light coming is not enough for your eye to discern it.
It is true that the angular size of stars is extremely small and that is the reason why no telescope
has ever taken a well resolved picture of a star. For us at the Earth, the atmosphere causes an
angular blurring by scintillation (which is why stars twinkle) and smears their size to about 1
arcsecond (which is 1/3600 of a degree).
Even for telescopes like Hubble which is above the Earth\'s atmosphere, the star\'s angular size is
too small to be resolved. But remember that each star produces a lot of light which is more than
enough for the eye to discern them. Hence we see stars; However they are too small; so we see
them as points and not disks (as you would with planets).
c)
Variable stars may be either intrinsic or extrinsic.
These subgroups themselves are further divided into specific types of variable stars that are
usually named after their prototype. For example, dwarf novae are designated U Geminorum
stars after the first recognized star in the class, U Geminorum..
Detailed Desription of Stars. What is a Star? , Classification of stars, Hertzsprung-Russel Diagram, Spectral Classes, Luminosity, Variable Stars, Composite Stars, Neutron Stars, Black Holes, Star Clusters, Supernovae, Binary Star, Chandrashekhar Limit, Limit Value Calculation Formulae, Applications of the limit, Tolman-Openheimer Volkoff Limit, About Subrahmanyam Chandrasekhar
stars life .. how they are formed ... supernova , what is black hole, worm hole ..... very very interesting topic in very simple language and many images that make u understand easily
Materials RequiredComputer and internet accessCalcula.docxwkyra78
Materials Required:
Computer and internet access
Calculator
Ruler
Pencils and pens, eraser
Digital camera and/or scanner
Print out
Galaxy Image
Prints document
Total Time Required:
Approximately 2-3 Hours
Part 1. The Local Group
In Table 1, you will find a list of most of the galaxies in the Local Group. This group is made up of our own galaxy, the Milky Way, and its closest neighbors. (Note: 1 kpc = 1 kiloparsec = 1000 parsec; 1 parsec = 3.26 light years)
Table 1. Galaxies of the Local Group
Name
Distance (kpc)
Diameter (kpc)
Name
Distance (kpc)
Diameter (kpc)
Milky Way
-
40.0
IC 1522
610
1.5
Sculptor
60
0.3
WLM
610
2.1
Large Magellanic Cloud (LMC)
60
6.1
Andromeda I
675
0.6
Carina
90
0.2
Andromeda II
675
0.6
Draco
90
0.2
Andromeda III
675
0.9
Ursa Minor
90
0.3
M32
675
1.5
Sextans I
90
0.9
NGC 185
675
1.8
Small Magellanic Cloud (SMC)
90
4.6
NGC 147
675
3.1
Fornax
150
0.9
NGC 205
675
3.1
Leo II
185
0.2
M31 (Andromeda Galaxy)
675
61
Leo I
185
0.3
IC 1613
765
3.7
NGC 6822
520
2.5
M33 (Triangulum Galaxy)
765
14.0
DDO 210
920
1.2
Below is a visual representation of our Local Group of galaxies. You can access and zoom into this image to see galaxies more clearly using this link
Local Group
.
Figure 1.
Local Group Visualization.
Type and label your answers to the below questions in your lab report.
Using Table 1 above and noting the diameters of the galaxies, which
five
galaxies in the Local Group are the largest? In a few sentences, compare the sizes of the other galaxies in the Local Group to the two largest ones.
Which
three
galaxies have the largest angular size (not including the Milky Way)? These galaxies are the ones that look the largest in the sky. Explain how you get your answer.
By hand and with pencil, create a
scale drawing
of the Milky Way and the Large Magellanic Cloud, showing their
relative sizes
and the
distance
between them in kiloparsecs (the galaxies can be represented by circles).
Write down the scale you use ,
and your calculations to find the scaled-down sizes and distance. (An example of a good scale to use would like something like: 5 mm = 10 kpc, also see this site
Basic-Mathematics.com
for more information on scaling.) You will photo your drawing and insert it into your lab report.
Figure 2.
Local Supercluster Print
Image courtesy of Palomar Sky Survey Photographs
As you have already seen, galaxies can vary a lot in size. Now, we will look at how their shapes are different. Two basic types of galaxies are the spiral galaxies and the elliptical galaxies. Spiral galaxies have a disk-like structure,and a central bulge. Our own Milky Way is a spiral galaxy. Elliptical galaxies appear round, looking a lot like a football .
The Sky
Astronomy is about us. As we learn about astronomy, we learn about ourselves. We search for an answer to the question “What are we?” The quick answer is that we are thinking creatures living on a planet that circles a star we call the sun. In this chapter, we begin trying to understand that answer. What does it mean to live on a planet?
The preceding chapter gave us a quick overview of the universe, and chapters later in the book will discuss the details. This chapter and the next help us understand what the universe looks like seen from the surface of our spinning planet.
But appearances are deceiving. We will see in Chapter 4 how difficult it has been for humanity to understand what we see in the #sky every day. In fact, we will discover that modern science was born when people tried to understand the appearance of the sky.
Find the indicial roots then solve the following ODE using series. Yo.pdfarbaazrabs
Find the indicial roots then solve the following ODE using series. You must show the first 4
terms of each series. xy\" + 2y\' + xy = 0
Solution
Ans-
Let X be a set and let be a family of subsets of X. Then is called a topology on X if:[1][2]
If is a topology on X, then the pair (X, ) is called a topological space. The notation X may be
used to denote a set X endowed with the particular topology .
The members of are called open sets in X. A subset of X is said to be closed if its complement is
in (i.e., its complement is open). A subset of X may be open, closed, both (clopen set), or
neither. The empty set and X itself are always both closed and open.
Basis for a topology
Main article: Basis (topology)
A base (or basis) B for a topological space X with topology T is a collection of open sets in T
such that every open set in T can be written as a union of elements of B.[3][4] We say that the
base generates the topology T. Bases are useful because many properties of topologies can be
reduced to statements about a base that generates that topology—and because many topologies
are most easily defined in terms of a base that generates them.
Subspace and quotient
Every subset of a topological space can be given the subspace topology in which the open sets
are the intersections of the open sets of the larger space with the subset. For any indexed family
of topological spaces, the product can be given the product topology, which is generated by the
inverse images of open sets of the factors under the projection mappings. For example, in finite
products, a basis for the product topology consists of all products of open sets. For infinite
products, there is the additional requirement that in a basic open set, all but finitely many of its
projections are the entire space.
A quotient space is defined as follows: if X is a topological space and Y is a set, and if f : XY is
a surjective function, then the quotient topology on Y is the collection of subsets of Y that have
open inverse images under f. In other words, the quotient topology is the finest topology on Y for
which f is continuous. A common example of a quotient topology is when an equivalence
relation is defined on the topological space X. The map f is then the natural projection onto the
set of equivalence classes.
Examples of topological spaces
A given set may have many different topologies. If a set is given a different topology, it is
viewed as a different topological space. Any set can be given the discrete topology in which
every subset is open. The only convergent sequences or nets in this topology are those that are
eventually constant. Also, any set can be given the trivial topology (also called the indiscrete
topology), in which only the empty set and the whole space are open. Every sequence and net in
this topology converges to every point of the space. This example shows that in general
topological spaces, limits of sequences need not be unique. However, often topological spaces
must b.
Design verilog code [in ISE Project Navigator Verilog Module, Veril.pdfarbaazrabs
Design verilog code [in ISE Project Navigator: Verilog Module, Verilog Text Fixture_TB] for:
4-bits synchronous up/down counter with an enable. This counter has three inputs Clock,
ENABLE, and UP/DOWN’ and four outputs O3 (MSB),O2,O1, and O0 (LSB). The table below
defines the circuit behavior: ENABLE UP/DOWN\' Function 0 X Stop counting 0 Count down:
15,14,...,1,0,15,14, Count up: 0,1,...,14,15,0,1
Solution
What is the verilog code for 4-bit updown counter with synchronous clear?
2 ANSWERS
[Sanket Naik]
Sanket Naik, been there, done that...!
1.7k Views
module up_dn_cnt (
input clk,
input clr, //Active high clear
input up, //Active high up count enable
input dn, //Active down up count enable
output [3:0] count
);
always @(posedge clk, posedge clr) begin
if(clr == 1) begin
count <= \'b0;
end else begin
if(up == 1) begin
count <= count + 1;
end else if(dn == 1) begin
count <= count - 1;
end
end
end
endmodule.
More Related Content
Similar to Stars from what part of the main sequence are likely to become black .pdf
Detailed Desription of Stars. What is a Star? , Classification of stars, Hertzsprung-Russel Diagram, Spectral Classes, Luminosity, Variable Stars, Composite Stars, Neutron Stars, Black Holes, Star Clusters, Supernovae, Binary Star, Chandrashekhar Limit, Limit Value Calculation Formulae, Applications of the limit, Tolman-Openheimer Volkoff Limit, About Subrahmanyam Chandrasekhar
stars life .. how they are formed ... supernova , what is black hole, worm hole ..... very very interesting topic in very simple language and many images that make u understand easily
Materials RequiredComputer and internet accessCalcula.docxwkyra78
Materials Required:
Computer and internet access
Calculator
Ruler
Pencils and pens, eraser
Digital camera and/or scanner
Print out
Galaxy Image
Prints document
Total Time Required:
Approximately 2-3 Hours
Part 1. The Local Group
In Table 1, you will find a list of most of the galaxies in the Local Group. This group is made up of our own galaxy, the Milky Way, and its closest neighbors. (Note: 1 kpc = 1 kiloparsec = 1000 parsec; 1 parsec = 3.26 light years)
Table 1. Galaxies of the Local Group
Name
Distance (kpc)
Diameter (kpc)
Name
Distance (kpc)
Diameter (kpc)
Milky Way
-
40.0
IC 1522
610
1.5
Sculptor
60
0.3
WLM
610
2.1
Large Magellanic Cloud (LMC)
60
6.1
Andromeda I
675
0.6
Carina
90
0.2
Andromeda II
675
0.6
Draco
90
0.2
Andromeda III
675
0.9
Ursa Minor
90
0.3
M32
675
1.5
Sextans I
90
0.9
NGC 185
675
1.8
Small Magellanic Cloud (SMC)
90
4.6
NGC 147
675
3.1
Fornax
150
0.9
NGC 205
675
3.1
Leo II
185
0.2
M31 (Andromeda Galaxy)
675
61
Leo I
185
0.3
IC 1613
765
3.7
NGC 6822
520
2.5
M33 (Triangulum Galaxy)
765
14.0
DDO 210
920
1.2
Below is a visual representation of our Local Group of galaxies. You can access and zoom into this image to see galaxies more clearly using this link
Local Group
.
Figure 1.
Local Group Visualization.
Type and label your answers to the below questions in your lab report.
Using Table 1 above and noting the diameters of the galaxies, which
five
galaxies in the Local Group are the largest? In a few sentences, compare the sizes of the other galaxies in the Local Group to the two largest ones.
Which
three
galaxies have the largest angular size (not including the Milky Way)? These galaxies are the ones that look the largest in the sky. Explain how you get your answer.
By hand and with pencil, create a
scale drawing
of the Milky Way and the Large Magellanic Cloud, showing their
relative sizes
and the
distance
between them in kiloparsecs (the galaxies can be represented by circles).
Write down the scale you use ,
and your calculations to find the scaled-down sizes and distance. (An example of a good scale to use would like something like: 5 mm = 10 kpc, also see this site
Basic-Mathematics.com
for more information on scaling.) You will photo your drawing and insert it into your lab report.
Figure 2.
Local Supercluster Print
Image courtesy of Palomar Sky Survey Photographs
As you have already seen, galaxies can vary a lot in size. Now, we will look at how their shapes are different. Two basic types of galaxies are the spiral galaxies and the elliptical galaxies. Spiral galaxies have a disk-like structure,and a central bulge. Our own Milky Way is a spiral galaxy. Elliptical galaxies appear round, looking a lot like a football .
The Sky
Astronomy is about us. As we learn about astronomy, we learn about ourselves. We search for an answer to the question “What are we?” The quick answer is that we are thinking creatures living on a planet that circles a star we call the sun. In this chapter, we begin trying to understand that answer. What does it mean to live on a planet?
The preceding chapter gave us a quick overview of the universe, and chapters later in the book will discuss the details. This chapter and the next help us understand what the universe looks like seen from the surface of our spinning planet.
But appearances are deceiving. We will see in Chapter 4 how difficult it has been for humanity to understand what we see in the #sky every day. In fact, we will discover that modern science was born when people tried to understand the appearance of the sky.
Find the indicial roots then solve the following ODE using series. Yo.pdfarbaazrabs
Find the indicial roots then solve the following ODE using series. You must show the first 4
terms of each series. xy\" + 2y\' + xy = 0
Solution
Ans-
Let X be a set and let be a family of subsets of X. Then is called a topology on X if:[1][2]
If is a topology on X, then the pair (X, ) is called a topological space. The notation X may be
used to denote a set X endowed with the particular topology .
The members of are called open sets in X. A subset of X is said to be closed if its complement is
in (i.e., its complement is open). A subset of X may be open, closed, both (clopen set), or
neither. The empty set and X itself are always both closed and open.
Basis for a topology
Main article: Basis (topology)
A base (or basis) B for a topological space X with topology T is a collection of open sets in T
such that every open set in T can be written as a union of elements of B.[3][4] We say that the
base generates the topology T. Bases are useful because many properties of topologies can be
reduced to statements about a base that generates that topology—and because many topologies
are most easily defined in terms of a base that generates them.
Subspace and quotient
Every subset of a topological space can be given the subspace topology in which the open sets
are the intersections of the open sets of the larger space with the subset. For any indexed family
of topological spaces, the product can be given the product topology, which is generated by the
inverse images of open sets of the factors under the projection mappings. For example, in finite
products, a basis for the product topology consists of all products of open sets. For infinite
products, there is the additional requirement that in a basic open set, all but finitely many of its
projections are the entire space.
A quotient space is defined as follows: if X is a topological space and Y is a set, and if f : XY is
a surjective function, then the quotient topology on Y is the collection of subsets of Y that have
open inverse images under f. In other words, the quotient topology is the finest topology on Y for
which f is continuous. A common example of a quotient topology is when an equivalence
relation is defined on the topological space X. The map f is then the natural projection onto the
set of equivalence classes.
Examples of topological spaces
A given set may have many different topologies. If a set is given a different topology, it is
viewed as a different topological space. Any set can be given the discrete topology in which
every subset is open. The only convergent sequences or nets in this topology are those that are
eventually constant. Also, any set can be given the trivial topology (also called the indiscrete
topology), in which only the empty set and the whole space are open. Every sequence and net in
this topology converges to every point of the space. This example shows that in general
topological spaces, limits of sequences need not be unique. However, often topological spaces
must b.
Design verilog code [in ISE Project Navigator Verilog Module, Veril.pdfarbaazrabs
Design verilog code [in ISE Project Navigator: Verilog Module, Verilog Text Fixture_TB] for:
4-bits synchronous up/down counter with an enable. This counter has three inputs Clock,
ENABLE, and UP/DOWN’ and four outputs O3 (MSB),O2,O1, and O0 (LSB). The table below
defines the circuit behavior: ENABLE UP/DOWN\' Function 0 X Stop counting 0 Count down:
15,14,...,1,0,15,14, Count up: 0,1,...,14,15,0,1
Solution
What is the verilog code for 4-bit updown counter with synchronous clear?
2 ANSWERS
[Sanket Naik]
Sanket Naik, been there, done that...!
1.7k Views
module up_dn_cnt (
input clk,
input clr, //Active high clear
input up, //Active high up count enable
input dn, //Active down up count enable
output [3:0] count
);
always @(posedge clk, posedge clr) begin
if(clr == 1) begin
count <= \'b0;
end else begin
if(up == 1) begin
count <= count + 1;
end else if(dn == 1) begin
count <= count - 1;
end
end
end
endmodule.
DNA and RNA are both stands of nucleotides but RNA can carry out for .pdfarbaazrabs
DNA and RNA are both stands of nucleotides but RNA can carry out for more functions than
DNA. How docs the structure of RNA differ from DNA? What additional activities/function can
RNA do that DNA cannot?
Solution
The structure of ribonucleic acid is single stranded in which thymine replaces uracil as
complimentary base and other adenine, guanine, cytosine are the nucleotides but
deoxyribonucleic acid is double stranded & duplex.
The additive activities can RNA performing are to undergo \"translation\" to code for proteins
the following are the other functions where as DNA cannot undergo translation directly to code
for proteins
Small nuclear ribonucleic acid (snRNA): It is also known as U-RNA as it contains many uridine
contents in its complex structure. This is composed of 150 nucleotides nearly to produce
spliceosomes and to act along with snRNP. This snRNA has a predominant role in splicing.
mRNA: It is produced by the transcription of DNA in the presence of RNA polymerase enzyme
and it has amino acid coding exons to code for specific proteins as per genetic code.
rRNA (ribosomal RNA): It has 50S and 30S ribosomal subunits which have aminoacyl site and
peptidyl site to carry out translation process during protein synthesis with mRNA.
tRNA (transfer RNA): It has clover leaf structure & common to all tRNA structure. It has
anticodon site to bind to the mRNA and to displace mRNA transcript from nuclear region onto
the rRNA for protein synthesis. It is considered as an adaptor molecule mainly consist of 76 to
90 ribonucleotides in length
piRNA:
Piwi-interacting RNAs (piRNA) are the small non-coding RNA molecules with 26 to 31
nucleotides that are expressed in many of the germ lines of eukaryotic animals. piRNAs interact
with piwi proteins to form RNA-protein complexes..
Distinguish between the concepts of stereotyping, prejudice, and dis.pdfarbaazrabs
Distinguish between the concepts of stereotyping, prejudice, and discrimination.
***PSYCHOLOGY
Solution
Stereotyping: generalised belief about a group of people in which identical characters are
assigned to virtually all members of the group, regardless actual variation among the members.
Prejudice: it is attitude or feeling, favourable or unfavorable towards a person or group of people,
prior to, or not based on, actual experience. Discrimination: negative or harmful beheaviour
towards the member or members of a group simply because of their membership in that group..
38 Cats eat only animals. Something fuzzy exists. Everything that\'s fuzzy is a cat. And
everything eats some- thing. So animals exist. C(a), E(r, y), A(x),Fx)
Solution
Cats eat only animals.C(x)
Somthing fuzzy exists E(x,y)
Everything that is a fuzzy is a cat. A(x)
Everything eats something F(x)
E(x,y) implies A(x)
If F(x) is true then A(x) is also true.
Since A(x) is true, C(x) implies there exist animals..
An octapeptide was hydrolyzed and the amino acids separated. It was .pdfarbaazrabs
An octapeptide was hydrolyzed and the amino acids separated. It was found to have the
following amino acid composition: Gly (1); Ala (2); Val (1); Lys (2); Met (1); Asp (1). After
incubation with FDNB and hydrolysis, 2,4-dinitrophenylalanine was detected. Treatment with
cyanogen bromide, which cleaves at M, resulted in two fragments: a pentapeptide containing two
K residues and a tripeptide containing V, G, and A. (The residues are not listed in any particular
order.) After treatment with trypsin, which cleaves at R and K, there were 3 fragments: two
dipeptides and MGAV. What is the sequence of the peptide? Use the one-letter abbreviations for
the amino acids, and do not use dashes. An octapeptide was hydrolyzed and the amino acids
separated. It was found to have the following amino acid composition: Gly (1), Ala (2); Val (1),
Lys (2), Met (1), Asp (1). After incubation with FDNB and hydrolysis, 2,4-dinitrophenylalanine
was detected. NO2 NO2 NH H3C-CH OO Treatment with cyanogen bromide, which cleaves at
M, resulted in two fragments: a pentapeptide containing two K residues and a tripeptide
containing V, G, and A. (The residues are not listed in any particular order.) After treatment with
trypsin, which cleaves at R and K, there were 3 fragments: two dipeptides and M What is the
sequence of the peptide? Use the one-letter abbreviations for the amino acids, and do not use
dashes.
Solution
An octapeptide was hydrolyzed and the amino acids separated. It was found to have the
following amino acid composition: Gly (1); Ala (2); Val (1); Lys (2); Met (1); Asp (1).
After incubation with FDNB and hydrolysis, 2,4-dinitrophenylalanine was detected.
1-fluoro-2,4-dinitrobenzene (FDNB) is an reagent that always react with N-terminal aminoacid
of a peptide chain and after acid hydrolysis it produces 2.4-dinitrophenyl derivative of
aminoacid. As there is production of 2,4-dinitrophenylalanine, that means alanine is present at
the N-terminal end of the octapeptide.
Treatment with cyanogen bromide, which cleaves at M, resulted in two fragments: a
pentapeptide containing two K residues and a tripeptide containing V, G, and A. (The residues
are not listed in any particular order.)
Cyanogen bromide always cleaves the peptide at the carboxylic end of methionine and after
cleavage it gives two fragments of pentapeptide and tripeptide. So it indicates that methionine is
present at 5th position of the octapeptide.
After treatment with trypsin, which cleaves at R and K, there were 3 fragments: two dipeptides
and MGAV.
Trypsin always cleaves at the carboxy-terminal of arginine and lysine. After cleavage, two
dipeptide and one tetrapeptide (MGAV) is produced. So it is cleared that, the two dipeptide
would be AK and DK.
Therefore the final aminoacid sequence of the octapeptide would be H2N-AKDKMGAV-COOH
Answer: AKDKMGAV.
c. hydrophillic heads; sticking out toward the interior and exterior.pdfarbaazrabs
c. hydrophillic heads; sticking out toward the interior and exterior of the cell
d. hydrophobic and hydrophylic sides, facing in toward another Properties of Phospholipids The
plasma membrane is made up of a phospholipid bilayer, with the of the phospholipids Multiple
Choice hydrophobic tails: sticking out toward the interior and exterior of the cell hydrophilic
heads facing in toward one another
Solution
(C).hydrophilic heads;sticking out toward the interior and exterior of the cell.
According to the fluid-mosaic model,the hydrophobic tails are present in between the
phospholipid bilayer and the hydrophilic heads facing outward top and bottom of the layer.These
heads are made up of phosphate and glycerol whereas the tail is made up of unsatuarated and
saturated fatty acids..
Biology Lab questions1. Units of amino acid are carried to the ri.pdfarbaazrabs
Biology Lab questions:
1. Units of amino acid are carried to the ribosomes by (A) transfer RNA (B) radioactive uracil
(C) template RNA (D) messenger RNA
Solution
The units of amino acids are carried to the ribosomes by t-rna which is charged.. According to
the codon present in the ribosomes that charged t-rna of that particular amino acid are carried to
the ribosomes..!!.
Why is it important to use several sources of power and influence, r.pdfarbaazrabs
Why is it important to use several sources of power and influence, rather than relying on one or
two?
Solution
There are 5 various sources of influence that are as follows
1. Reward power
2. Coercive power
3. Legitimate power
4. Expert power
5. Recent power
Reward power is that in which we can provide reqare for obtaining power
Coercive power is that we can take a disciplinary action to obtain power or to influence for work.
Legitimate power is that which can be granted by your position or rights that as a MD of a
company have a power towards the employees who report him
Expert power is that which is received by your knowledge and experience of any work .
Referent power is that which is related to your reference when you know someone and feel that
you know him means you connect with him
All the five sources of power and influence are important because with the help of all the five
sources we can do the best of himself nothing has been left. And we know every person has
different different thoughts and views. Not all the person preferred same thing . And we don\'t
know the person clearly so if we use all the five sources it helps us to increase or obtaining good
and satisfactory results .
If we use only one or two and rely on it . May be it happens that person don\'t like these two
means these two sources are not good as per that person for obtaining good response. May be it
happens that we wants more position as compared to monetary benefits so if we can use all the
five sources then It makes more chance of better influencing..
What is special about the colugos teethLower incisors are comb-li.pdfarbaazrabs
What is special about the colugos teeth?
Lower incisors are comb-like
Only two upper incisors
Upper canines are reduced
Only one lower molar
Solution
Lower incisor are comb like.
Upper incisors are 2 in each quadrant since dental formula for colugos is 2.1.2.3 for upper jaw.
Colugos has special feature that their incisor are comb shape,which has almost 20 tines on it.
These comb in incisors are used for grooming. As is seen in stepsirrihines they hav similar
function and appearance..
write simple program in c++ in which source reads a file of integers.pdfarbaazrabs
write simple program in c++ in which source reads a file of integers and outputs the average
Solution
Average.cpp
#include
#include
using namespace std;
int main()
{
ifstream inputFile;
inputFile.open(\"numbers.txt\");
int n;
int sum =0;
int count = 0;
double average = 0;
if (inputFile.is_open()) {
while (!inputFile.eof()) {
inputFile >> n;
sum = sum + n;
count++;
}
}
average = sum/(double)count;
cout<<\"The average is \"<.
Write an example of a unit test for a Class methods using JUnitfr.pdfarbaazrabs
Write an example of a unit test for a Class methods using JUnitframework
Write an example of a unit test for a Class methods using JUnitframework
Solution
Example of test case java using JUnitframework:
import org.junit.Test;
import static org.junit.Assert.assertEquals;
public class TestJunit {
String message = \"Hello World\";
MessageUtil messageUtil = new MessageUtil(message);
@Test
public void testPrintMessage() {
assertEquals(message,messageUtil.printMessage());
}
}
Test suit Examples:
import org.junit.runner.RunWith;
import org.junit.runners.Suite;
//JUnit Suite Test
@RunWith(Suite.class)
@Suite.SuiteClasses({
TestJunit1.class ,TestJunit2.class
})
public class JunitTestSuite {
}
import org.junit.Test;
import org.junit.Ignore;
import static org.junit.Assert.assertEquals;
public class TestJunit1 {
String message = \"Robert\";
MessageUtil messageUtil = new MessageUtil(message);
@Test
public void testPrintMessage() {
System.out.println(\"Inside testPrintMessage()\");
assertEquals(message, messageUtil.printMessage());
}
}
import org.junit.Test;
import org.junit.Ignore;
import static org.junit.Assert.assertEquals;
public class TestJunit2 {
String message = \"Robert\";
MessageUtil messageUtil = new MessageUtil(message);
@Test
public void testSalutationMessage() {
System.out.println(\"Inside testSalutationMessage()\");
message = \"Hi!\" + \"Robert\";
assertEquals(message,messageUtil.salutationMessage());
}
}.
whats in plasmaSolutionAnswerBlood is the fluid connecti.pdfarbaazrabs
what\'s in plasma?
Solution
Answer:
Blood is the fluid connective tissue possesses plasma (45%) and remaining blood cells such as
monocytes, macrophages, clotting factors, platelets, and nutrients. This plasma is composed of
protein compartment in which various serum albumins, globulins along with clotting factors are
existing. Plasma protein components such as “beta globulin” and “glycoproteins” have extensive
saturable binding affinity.
What is a reason we want to write in a concise manner 1. To elimina.pdfarbaazrabs
What is a reason we want to write in a concise manner? 1. To eliminate redundant and repetitive
words 2. To allow better use of bullets 3. To avoid jargon or industry language 4. To indicate the
main point of the message
Solution
4. To indicate main point of message
We write in a concise manner to brief eth content clearly using few words.
What are the advantages of Credit Suisse’s new supplier managemente.pdfarbaazrabs
What are the advantages of Credit Suisse’s new supplier management/evaluation system?
Please write in your own words, and atlest 2 paragraphs
Solution
Historically, the IT industry has been mostly a reactive unit. Enterprise IT departments were
essentially order-takers that were quick to adopt the latest programs. Stephen Hilton, managing
director and CIO of technology infrastructure for Credit Suisse, will have none of that. Known
for his stick-to-itiveness and indifference to flavor-of-the-week technology, Hilton has shown
leadership in building a unified culture and developed a reputation for his steady pace of
improvement.
As most Industry leaders know, since 2007 capital markets revenues have decreased rapidly,
resulting in budget cuts across the board. At the same time, most financial institutions had built
up significant fixed costs during the prior decade when revenues were high and budgets were
bloated. \"People were surprised that IT was not as variable as they thought it would be,\" says
Hilton, whose firm has a market capitalization of $42 billion and $1.3 trillion in assets under
management.
At Credit Suisse, only 30% to 40% of IT cost was allocated to staffing, reports Hilton. \"A lot of
the budget covers other IT assets, obligations, liabilities and licensing costs we built up over the
years that just are not variable in a short period of time.\" The only way you can really drive the
cost base down is through business process reengineering, he says, and that\'s exactly what his
team has been working toward.
\"It was quite a learning process for people to understand that. And if I\'m honest, that
realization, a very good realization, has actually changed the business attitude,\" Hilton says.
\"They\'re having different conversations with us now.\" Business leaders are aware that asking
for \"please do it quickly and just get it in\"-style requests aren\'t acceptable anymore. \"They
have to be more patient and more strategic in their decisions.\"
Challenge Silliness
While the old way of approaching technology may have been fitting given the short lifespan of
IT and massive innovation cycles, things began to change in the mid-2000s. For Credit Suisse
the focus shifted to optimizing the company\'s massive, complex infrastructure and improving
end user productivity. As CIO of technology infrastructure, Hilton prepared to make tough
decisions to meet company goals.
\"My view is that at the scale we now run at, process efficiency is key. I am a technologist, but
my master\'s degree is in mechanical engineering and making manufacturing decisions. So I
learned back in the late \'80s about industrialized processes and how to optimize factories. Those
skill sets are what I\'ve applied in the last five years.\" He adds, \"I very much encourage my
teams to be challenging partners. I\'ve spent five years really empowering them, saying, \'Look,
you\'re the experts. Challenge inefficiencies whenever you see them.\'\".
The PRIMARY structure of a protein isformed by alpha helices and .pdfarbaazrabs
The PRIMARY structure of a protein is:
formed by alpha helices and beta sheets
formed by multiple polypeptide chains binding to one another
formed by dehydration reactions that join amino acids together
all of the above are true
The PRIMARY structure of a protein is:
Solution
option C.
The primrary structure of a protein is formed by dehydration reactions that join amino acids
together.
dehydration reaction removes H2O between two amino acids to form peptide bond. this is the
native primary structure that consists of a linear chain of amino acids.
alpha and beta structures are secondary structures.
tertiary structure involves the interaction between different polypeptide chains..
The figure below shows the chromosomes in a cell for some species (.pdfarbaazrabs
The figure below shows the chromosomes in a cell for some species (\"pretend\" that
chromosomes are always visible for this exercise & ignore any nuclear membrane). 1. How
many chromosomes do you see? ___________ Is this haploid or diploid? What do the letters
represent? ___________ Why does the letter \"g\" appear only as lower case but the letter \"F\"
appears as both upper- AND lowercase (F & f)
Solution
1.The number of chromosomes is equal to the number of centromeres.Here in this case ,it is 6
chromosomes.
2.This is haploid as only single chromosomes are seen.
3.The letters represent the alleles of gene.
4.The letter \'g \'appears in the lower case because it is present only in recessive form while \' F\'
appears as both upper and lower case as it is present in both dominant and recessive forms..
A mistake occurs during lambda phage excision from the E. coli genom.pdfarbaazrabs
A mistake occurs during lambda phage excision from the E. coli genome: a portion of the E.
colichromosome is excised with the phage genome, leaving behind a portion of the lambda
genome that includes the int gene. This defective genome is packaged and infects an E. coli
strain that is recA- (it lacks RecA). What do you think happens to this genetic material?
1) injected DNA is degraded
2) integrates into new host genome
3) The transferred portion of E. coli chromosome recombines with the new host genome
4) All of these are possible
Solution
The answer is Option no 1 that is injected DNA is degraded.
The defective genome does not carry int gene. So, the lambda phge cannot insert its genetic
material into host genome.
Homologus recombination and DNA reapir does not possible because the host genome is recA-
Strain.(rec A protein plays a major role in homologus recombination)..
Assume a System Engineering class has 27 students, of which one thir.pdfarbaazrabs
Assume a System Engineering class has 27 students, of which one third are female and two
thirds are male. There were a total of 17 students (4 female and 13 male) that got the correct
answer to the first problem in their 8th homework assignment. What is the probability that a
male student got the correct answer?
Solution
total correct 17 srudents
4 female and 13 male
probability that male student correct answer = 13/27 = 0.481.
Unit 8 - Information and Communication Technology (Paper I).pdfThiyagu K
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
The Roman Empire A Historical Colossus.pdfkaushalkr1407
The Roman Empire, a vast and enduring power, stands as one of history's most remarkable civilizations, leaving an indelible imprint on the world. It emerged from the Roman Republic, transitioning into an imperial powerhouse under the leadership of Augustus Caesar in 27 BCE. This transformation marked the beginning of an era defined by unprecedented territorial expansion, architectural marvels, and profound cultural influence.
The empire's roots lie in the city of Rome, founded, according to legend, by Romulus in 753 BCE. Over centuries, Rome evolved from a small settlement to a formidable republic, characterized by a complex political system with elected officials and checks on power. However, internal strife, class conflicts, and military ambitions paved the way for the end of the Republic. Julius Caesar’s dictatorship and subsequent assassination in 44 BCE created a power vacuum, leading to a civil war. Octavian, later Augustus, emerged victorious, heralding the Roman Empire’s birth.
Under Augustus, the empire experienced the Pax Romana, a 200-year period of relative peace and stability. Augustus reformed the military, established efficient administrative systems, and initiated grand construction projects. The empire's borders expanded, encompassing territories from Britain to Egypt and from Spain to the Euphrates. Roman legions, renowned for their discipline and engineering prowess, secured and maintained these vast territories, building roads, fortifications, and cities that facilitated control and integration.
The Roman Empire’s society was hierarchical, with a rigid class system. At the top were the patricians, wealthy elites who held significant political power. Below them were the plebeians, free citizens with limited political influence, and the vast numbers of slaves who formed the backbone of the economy. The family unit was central, governed by the paterfamilias, the male head who held absolute authority.
Culturally, the Romans were eclectic, absorbing and adapting elements from the civilizations they encountered, particularly the Greeks. Roman art, literature, and philosophy reflected this synthesis, creating a rich cultural tapestry. Latin, the Roman language, became the lingua franca of the Western world, influencing numerous modern languages.
Roman architecture and engineering achievements were monumental. They perfected the arch, vault, and dome, constructing enduring structures like the Colosseum, Pantheon, and aqueducts. These engineering marvels not only showcased Roman ingenuity but also served practical purposes, from public entertainment to water supply.
A Strategic Approach: GenAI in EducationPeter Windle
Artificial Intelligence (AI) technologies such as Generative AI, Image Generators and Large Language Models have had a dramatic impact on teaching, learning and assessment over the past 18 months. The most immediate threat AI posed was to Academic Integrity with Higher Education Institutes (HEIs) focusing their efforts on combating the use of GenAI in assessment. Guidelines were developed for staff and students, policies put in place too. Innovative educators have forged paths in the use of Generative AI for teaching, learning and assessments leading to pockets of transformation springing up across HEIs, often with little or no top-down guidance, support or direction.
This Gasta posits a strategic approach to integrating AI into HEIs to prepare staff, students and the curriculum for an evolving world and workplace. We will highlight the advantages of working with these technologies beyond the realm of teaching, learning and assessment by considering prompt engineering skills, industry impact, curriculum changes, and the need for staff upskilling. In contrast, not engaging strategically with Generative AI poses risks, including falling behind peers, missed opportunities and failing to ensure our graduates remain employable. The rapid evolution of AI technologies necessitates a proactive and strategic approach if we are to remain relevant.
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
For more information, visit-www.vavaclasses.com
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
2024.06.01 Introducing a competency framework for languag learning materials ...Sandy Millin
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
2024.06.01 Introducing a competency framework for languag learning materials ...
Stars from what part of the main sequence are likely to become black .pdf
1. Stars from what part of the main sequence are likely to become black holes? Explain your
answer (You may need to look for additional information to answer this question) b)If you were
to look up into the sky for a few hours, and see 100 stars (or take a picture of 100 stars making
up a starfield), why would you see the particular stars that you see out of the billions of stars in
the Universe'? Include two main reasons (Thinking about magnitude might help you answer this
question) C)Many variable stars are stars in the Yellow or Red Giant stages List at least two such
categories of variable stars.
Solution
a) Most black holes form from the remnants of a large star that dies in a supernova explosion.
(Smaller stars become dense neutron stars, which are not massive enough to trap light.) If the
total mass of the star is large enough (about three times the mass of the Sun), it can be proven
theoretically that no force can keep the star from collapsing under the influence of gravity.
However, as the star collapses, a strange thing occurs. As the surface of the star nears an
imaginary surface called the "event horizon," time on the star slows relative to the time kept by
observers far away. When the surface reaches the event horizon, time stands still, and the star
can collapse no more - it is a frozen collapsing object.
b)
Whether we are able to see an object or not just depends only on the amount of light that is
reaching us and is independent of its size. If you cannot see an object, it just means that the
amount of light coming is not enough for your eye to discern it.
It is true that the angular size of stars is extremely small and that is the reason why no telescope
has ever taken a well resolved picture of a star. For us at the Earth, the atmosphere causes an
angular blurring by scintillation (which is why stars twinkle) and smears their size to about 1
arcsecond (which is 1/3600 of a degree).
Even for telescopes like Hubble which is above the Earth's atmosphere, the star's angular size is
too small to be resolved. But remember that each star produces a lot of light which is more than
enough for the eye to discern them. Hence we see stars; However they are too small; so we see
them as points and not disks (as you would with planets).
c)
Variable stars may be either intrinsic or extrinsic.
These subgroups themselves are further divided into specific types of variable stars that are
usually named after their prototype. For example, dwarf novae are designated U Geminorum
stars after the first recognized star in the class, U Geminorum.
