sp3d since it has 1s 3p and 1d orbitals available.pdf

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sp3d since it has 1s 3p and 1d orbitals available for hybridization Solution sp3d since it has 1s 3p and 1d orbitals available for hybridization.

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e =mc^2. m is the defected mass, or mass that isn\'t there and is instead used as binding energy. For Mg, you have 25 nucleons: 12 protons and 13 neutrons. So your expected mass would be 1.007825x12 + 1.008665x13 = 25.206545. The defected mass is the supposed mass minus the actual mass. so its 25.206545-24.985839= .220706 amu. Then you have to convert this into kilograms. so, divide 220706 amu by 1 kg = 6.022 x 10^26 and you get: 3.664996*10^-28 Solution e =mc^2. m is the defected mass, or mass that isn\'t there and is instead used as binding energy. For Mg, you have 25 nucleons: 12 protons and 13 neutrons. So your expected mass would be 1.007825x12 + 1.008665x13 = 25.206545. The defected mass is the supposed mass minus the actual mass. so its 25.206545-24.985839= .220706 amu. Then you have to convert this into kilograms. so, divide 220706 amu by 1 kg = 6.022 x 10^26 and you get: 3.664996*10^-28.

Definition of Log-Normal DistributionA statistical distr.pdf

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calculate the mol of NaOH so mol= concentration * volume n=C x V n= 0.175 x 0.0206 = 0.0036 then you get the ratio of acid to base from the equation above which is 1:1 so the number of mol of base is equal to the number of mol of acid n(acid)=0.0036 the concentration of that which is C=n/V C= 0.0036/0.025 C=0.144M Solution calculate the mol of NaOH so mol= concentration * volume n=C x V n= 0.175 x 0.0206 = 0.0036 then you get the ratio of acid to base from the equation above which is 1:1 so the number of mol of base is equal to the number of mol of acid n(acid)=0.0036 the concentration of that which is C=n/V C= 0.0036/0.025 C=0.144M.

Step1 NaOH (aq) ----- Na(+)(aq) + Cl(-)(aq) Ste.pdf

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The compounds with low oxidation states (O.S.) be.pdf

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A) ionic compounds generally formed between the combination of 1st and 2nd group elements with 7th group elements . ex: NaCl, MgF, CaCl2 and so on B) Molecular compounds means vanderwall forces acting btw the molecule these may be crystals or liguids .ex Iodine(I2) is molecular crystal ,Quartz, phosphorous(P4), sulphur(S8) C) hydrocarbons in general contain carbon and hydrogen in some cases hetero atoms may present in the compound . ex CH4 , C2H6, C2H2, C6H5N02, C6H12O6 (glucose) etc D) in general 5th, 6th, 7th groups oxides , oxy acids behaves as acid . ex: N20, N205, F20,HNO3, HClO4, HCl, HF, H2SO4, H2S208 etc along with these metal with lower oxidation state can also act as acidic compound ex: MnO MnO2 MnO3 in the above three oxides oxidation states of metals in orderly +2,+4,+6. so first compound can act as an acid last one is a base Solution A) ionic compounds generally formed between the combination of 1st and 2nd group elements with 7th group elements . ex: NaCl, MgF, CaCl2 and so on B) Molecular compounds means vanderwall forces acting btw the molecule these may be crystals or liguids .ex Iodine(I2) is molecular crystal ,Quartz, phosphorous(P4), sulphur(S8) C) hydrocarbons in general contain carbon and hydrogen in some cases hetero atoms may present in the compound . ex CH4 , C2H6, C2H2, C6H5N02, C6H12O6 (glucose) etc D) in general 5th, 6th, 7th groups oxides , oxy acids behaves as acid . ex: N20, N205, F20,HNO3, HClO4, HCl, HF, H2SO4, H2S208 etc along with these metal with lower oxidation state can also act as acidic compound ex: MnO MnO2 MnO3 in the above three oxides oxidation states of metals in orderly +2,+4,+6. so first compound can act as an acid last one is a base.

A) ionic compounds generally formed between the c.pdf

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A ethers ethers contain R-O-R linkage not carbony.pdf

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The fact that a molecule vibrates does not in itself insure that the molecule will exhibit an IR spectrum. For a particular vibrational mode to absorb infrared radiation, the vibrational motion associated with that mode must produce a change in the dipole moment of the molecule. HCl, for example, with a center of positive charge at the H atom and a center of negative charge at the Cl atom, has a dipole moment. The magnitude of the dipole moment changes as the HCl bond stretches, so this vibration absorbs IR radiation. We say that the vibration is IR active. The N2 molecule, on the other hand, has no dipole moment. Further, stretching the N-N bond does not produce a change in dipole moment, so the vibration is infrared inactive (i.e., cannot directly absorb IR radiation). It is important to realize that there are many molecules that, although possessing no permanent dipole moment, still undergo vibrations that cause changes in the value of the dipole moment from 0 to some non-zero value. An example is CO2, which has no permanent dipole moment because the individual bond dipoles exactly cancel. However, when CO2 undergoes a bending vibration, its dipole moment changes from zero to some non-zero value. This vibration produces a change in dipole moment and is IR active. These vibrational modes are responsible for the \"greenhouse\" effect in which heat radiated from the earth is absorbed (trapped) by CO2 molecules in the atmosphere. The arrows indicate the directions of motion. Vibrations labeled A and B represent the stretching of the chemical bonds, one in a symmetric (A) fashion, in which both C=O bonds lengthen and contract together (in-phase), and the other in an asymmetric (B) fashion, in which one bond shortens while the other lengthens. The asymmetric stretch (B) is infrared active because there is a change in the molecular dipole moment during this vibration. Solution The fact that a molecule vibrates does not in itself insure that the molecule will exhibit an IR spectrum. For a particular vibrational mode to absorb infrared radiation, the vibrational motion associated with that mode must produce a change in the dipole moment of the molecule. HCl, for example, with a center of positive charge at the H atom and a center of negative charge at the Cl atom, has a dipole moment. The magnitude of the dipole moment changes as the HCl bond stretches, so this vibration absorbs IR radiation. We say that the vibration is IR active. The N2 molecule, on the other hand, has no dipole moment. Further, stretching the N-N bond does not produce a change in dipole moment, so the vibration is infrared inactive (i.e., cannot directly absorb IR radiation). It is important to realize that there are many molecules that, although possessing no permanent dipole moment, still undergo vibrations that cause changes in the value of the dipole moment from 0 to some non-zero value. An example is CO2, which has no permanent dipole moment because the individual bond dipo.

The fact that a molecule vibrates does not in its.pdf

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The compounds of interest are Na2S and H2SO4. The molecular equation then is: Na2S + H2SO4 ---> Na2SO4 + H2S. Just exchange one anion for the other. Now, we need to know a little bit about the properties of these compounds. Almost all sodium salts are soluble, so both Na2S and Na2SO4 are fully dissociated: 2 Na+ + S2- + 2 H+ + SO42- ---> 2 Na+ + SO42- + H2S. Crossing out terms that appear on both sides, we obtain the net ionic equation: 2 H+ + S2- ----> H2S. Conveniently, H2S is a gas, and escapes from solution. Thus, it selectively removes H+ and S2- ions from the equilibrium, driving the reaction to completion (favoring Na2SO4) Solution The compounds of interest are Na2S and H2SO4. The molecular equation then is: Na2S + H2SO4 ---> Na2SO4 + H2S. Just exchange one anion for the other. Now, we need to know a little bit about the properties of these compounds. Almost all sodium salts are soluble, so both Na2S and Na2SO4 are fully dissociated: 2 Na+ + S2- + 2 H+ + SO42- ---> 2 Na+ + SO42- + H2S. Crossing out terms that appear on both sides, we obtain the net ionic equation: 2 H+ + S2- ----> H2S. Conveniently, H2S is a gas, and escapes from solution. Thus, it selectively removes H+ and S2- ions from the equilibrium, driving the reaction to completion (favoring Na2SO4).

The compounds of interest are Na2S and H2SO4. Th.pdf

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sucrose has a formula of C12H22O11while ammonia h.pdf

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reduction strength Fe Pb As .pdf

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No standard potential data given. .pdf

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x2 + 4xSolutionx2 + 4x.pdf

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moles of Al = 1227 Since chlorine is in excess ,.pdf

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We can make a chart for the above data in a following waySoluti.pdf

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There is nothing much wrong in the code. Error is due to the the entity name. You may have a another entity with same name in same library. You may defined the specified entity in the specified files. However, all entities are being compiled to the same library. Compile the specified entities in different libraries. That is compile entity prob_c5_1 in different library. or you can change the entity name and compile entity in same library. Find the code with different entity name as below: and compile it in same library. library IEEE; USE ieee.std_logic_1164.all; ENTITY prob_c5_differ IS PORT( V,F,H : In std_logic; original,reduced : OUT std_logic ); END prob_c5_differ; Architecture arc OF prob_c5_differ IS begin original <= (H and F) OR (H and V); reduced <= (F OR V) AND (H); End arc; If it still give some errors than compile the entity in different library other than work. Solution There is nothing much wrong in the code. Error is due to the the entity name. You may have a another entity with same name in same library. You may defined the specified entity in the specified files. However, all entities are being compiled to the same library. Compile the specified entities in different libraries. That is compile entity prob_c5_1 in different library. or you can change the entity name and compile entity in same library. Find the code with different entity name as below: and compile it in same library. library IEEE; USE ieee.std_logic_1164.all; ENTITY prob_c5_differ IS PORT( V,F,H : In std_logic; original,reduced : OUT std_logic ); END prob_c5_differ; Architecture arc OF prob_c5_differ IS begin original <= (H and F) OR (H and V); reduced <= (F OR V) AND (H); End arc; If it still give some errors than compile the entity in different library other than work..

There is nothing much wrong in the code.Error is due to the the en.pdf

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The term business cycle is used in several ways in business. This article defines business cycle in context with related terms including economic cycle, recession, and depression. The first and primary meaning of business cycle refers to fluctuations in economic output in a country or countries, characterized by well-known phases of a business cycle such as recession, depression, recovery, and expansion. The business cycle or economic cycle in this sense may be accompanied by changes in stock market prices, known as the stock market cycle. For more on these cycles and their phases, see the sections below. The second meaning of business cycle sometimes refers to stages in the life span of a single company. In this regard, important phases in a company\'s life may include: birth (or start up), growth, maturity, decline, and demise. Progress through these cycles may be impacted heavily by the economic business cycle. To accountants, companies are viewed as ongoing entities that will continue in business indefinitely. In reality, the vast majority of business startups move through these stages and cease business within a few years or within the founder\'s life time at most. The third meaning of business cycle also refers to phases in the life of an ongoing business covering a year or several years, whereby the company takes in revenues from normal operations for a year or more, re-evaluates business performance and growth prospects, adjusts or changes the business model (especially competitive strategy, marketing strategy, and pricing and margin models), and then resumes business under the new model for a period before re-evaluating again. The business cycle is the pattern of expansion, contraction and recovery in the economy. Generally speaking, the business cycle is measured and tracked in terms of GDP and unemployment – GDP rises and unemployment shrinks during expansion phases, while reversing in periods of recession. Wherever one starts in the cycle, the economy is observed to go through four periods – expansion, peak, contraction and trough. Recession is typically used to mean a downturn in economic activity, but most economists use a specific definition of \"two consecutive quarters of declining real GDP\" for recession. By comparison, there is no formal definition of depression. While recessions have averaged around 10 months in length since the 1950s, the recovery/expansion phases have a much wider range of lengths, though around three years is relatively common. The movement of the economy through business cycles also highlights certain economic relationships. While growth will rise and fall with cycles, there is a long-term trend line for growth; when economic growth is above the trend line, unemployment usually falls. One expression of this relationship is Okun\'s Law, an equation that holds that every 1% of GDP above trend equates to 0.5% less unemployment. While the business cycle is a relatively simple concept, there is great debat.

The term business cycle is used in several ways in business. This ar.pdf

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The Renaissance was a time of great intellectual growth and rebirth.The word Renaissance means \"rebirth\" in French. Renaissance changed the world for the better.The renaissance brought the world out of dark ages into the light.The Renaissance taught us many great ideas. The main factors for change in Renaissance are: .The invention of printing press. .The revival of classic learning. .The church was critised for the first time. .Voyages of exploration .Turning point in the history of medicine Many other achivements were accomplished during this time.In general the World became a new place.But still the ideas or beliefs stayed the same. Solution The Renaissance was a time of great intellectual growth and rebirth.The word Renaissance means \"rebirth\" in French. Renaissance changed the world for the better.The renaissance brought the world out of dark ages into the light.The Renaissance taught us many great ideas. The main factors for change in Renaissance are: .The invention of printing press. .The revival of classic learning. .The church was critised for the first time. .Voyages of exploration .Turning point in the history of medicine Many other achivements were accomplished during this time.In general the World became a new place.But still the ideas or beliefs stayed the same..

The Renaissance was a time of great intellectual growth and rebirth..pdf

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The mixture of microorganism regularly found at any anatomical site is called 33 normal microflorae. These microorganisms often offer some protection from transient microbes, but can become 34 virulent and cause disease under certain circumstance. When they do so, they are termed 35 opportunistic pathogens. Individuals with lowered resistance are called 36 immunocompromised and they are vulnerable to such infection. The normal microflora/ flora are the groups of microbes normally present at specified anatomical sites (GIT, oral cavity, nose, skin, etc.). They provide protection by not letting other harmful bacteria/microbes grow at these sites. In immunocompromised individuals (natural immune system becomes less effective, like in patients suffering from AIDS, Tuberculosis, etc.), the normal microflora may become virulent/ pathogenic and cause disease in the host. Solution The mixture of microorganism regularly found at any anatomical site is called 33 normal microflorae. These microorganisms often offer some protection from transient microbes, but can become 34 virulent and cause disease under certain circumstance. When they do so, they are termed 35 opportunistic pathogens. Individuals with lowered resistance are called 36 immunocompromised and they are vulnerable to such infection. The normal microflora/ flora are the groups of microbes normally present at specified anatomical sites (GIT, oral cavity, nose, skin, etc.). They provide protection by not letting other harmful bacteria/microbes grow at these sites. In immunocompromised individuals (natural immune system becomes less effective, like in patients suffering from AIDS, Tuberculosis, etc.), the normal microflora may become virulent/ pathogenic and cause disease in the host..

The mixture of microorganism regularly found at any anatomical site .pdf

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The One Ring to Rule them AllSolutionThe One Ring to Rule them.pdf

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the double bond in these compound is highly sensitive to the (Ozone).it craeates a radical,it breaks the all double in the polymer and weakens and the tire loses it.elasticity.polyurethane and polyisobutylene are not affect by Ozone. Solution the double bond in these compound is highly sensitive to the (Ozone).it craeates a radical,it breaks the all double in the polymer and weakens and the tire loses it.elasticity.polyurethane and polyisobutylene are not affect by Ozone..

the double bond in these compound is highly sensitive to the (Ozone).pdf

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Please find the answers and explanations below: Answer 1: According to the arterial blood gas data, it can be seen the PO2 and PCO2 of Charles are within normal ranges but PCO and PN2 are very high. This clearly suggests toxic accumulation of these gases in his blood probably due to partial combustion of kerosene oil. Thus option d seems most correct. Answer 8: Option c is correct. Toxicity of CO and N2 has not changed the PO2 and PCO2 values of Charles but PCO and PN2 are exceedingly high. Since CO and N2 have higher affinitiy for hemoglobin binding than O2, they will prevent transport of oxygen from the blood to cells and the exchange of CO2 for O2. Thus, ventilation will be affected in later stages but fundamentally, the transport of gases will be highly and directly impaired. Answer 9: Option c is correct. Emphysema is a respiratory disease where toxic chemicals are entrapped in the alveolar/arterial blood gas and prevent further transport of gases to different cells of the body. It primarily occurs due to tobacco smoke and lead to chronic obstructive pulmonary disorder. The condition of Charles is very much similar to it. Answer 10: Option d is correct: Increasing the blood pCO2 levels will further dampen the respiratory system and impair the medical condition of Charles. He should be given general alkalosis of blood along with a gaseous mixture of high oxygen content to sustain life. Solution Please find the answers and explanations below: Answer 1: According to the arterial blood gas data, it can be seen the PO2 and PCO2 of Charles are within normal ranges but PCO and PN2 are very high. This clearly suggests toxic accumulation of these gases in his blood probably due to partial combustion of kerosene oil. Thus option d seems most correct. Answer 8: Option c is correct. Toxicity of CO and N2 has not changed the PO2 and PCO2 values of Charles but PCO and PN2 are exceedingly high. Since CO and N2 have higher affinitiy for hemoglobin binding than O2, they will prevent transport of oxygen from the blood to cells and the exchange of CO2 for O2. Thus, ventilation will be affected in later stages but fundamentally, the transport of gases will be highly and directly impaired. Answer 9: Option c is correct. Emphysema is a respiratory disease where toxic chemicals are entrapped in the alveolar/arterial blood gas and prevent further transport of gases to different cells of the body. It primarily occurs due to tobacco smoke and lead to chronic obstructive pulmonary disorder. The condition of Charles is very much similar to it. Answer 10: Option d is correct: Increasing the blood pCO2 levels will further dampen the respiratory system and impair the medical condition of Charles. He should be given general alkalosis of blood along with a gaseous mixture of high oxygen content to sustain life..

Please find the answers and explanations belowAnswer 1 According.pdf

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