calculate the mol of NaOH so mol= concentration * volume n=C x V n= 0.175 x 0.0206 = 0.0036 then you get the ratio of acid to base from the equation above which is 1:1 so the number of mol of base is equal to the number of mol of acid n(acid)=0.0036 the concentration of that which is C=n/V C= 0.0036/0.025 C=0.144M Solution calculate the mol of NaOH so mol= concentration * volume n=C x V n= 0.175 x 0.0206 = 0.0036 then you get the ratio of acid to base from the equation above which is 1:1 so the number of mol of base is equal to the number of mol of acid n(acid)=0.0036 the concentration of that which is C=n/V C= 0.0036/0.025 C=0.144M.

1. Step1 NaOH (aq) -----> Na(+)(aq) + Cl(-)(aq) Step2 NaOH is a strong base ; it is
completely ionised in water. Step3 pOH = -log[8.26x10^-4] = 4 -log 8.26 Step4 pH + p OH =
14 Step5 pH = 14 - [4-log 8.26] = 10- log 8.26
Solution
Step1 NaOH (aq) -----> Na(+)(aq) + Cl(-)(aq) Step2 NaOH is a strong base ; it is
completely ionised in water. Step3 pOH = -log[8.26x10^-4] = 4 -log 8.26 Step4 pH + p OH =
14 Step5 pH = 14 - [4-log 8.26] = 10- log 8.26