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CHEMISTRY   FORM 4  PREPARATION FOR STANDARDIZED TEST
QUESTION 1: An experiment is conducted to investigate the effect of temperature on the rate of reaction. 5 set of 50cm 3  of 1.0 mol dm -3  sulphuric acid is reacted with 5g of magnesium ribbon at a different temperature.
DOES THE TEMPERATURE AFFECT THE RATE OF REACTION BETWEEN SULPHURIC ACID AND MAGNESIUM RIBBON? ,[object Object]
[object Object],[object Object],[object Object],[object Object],TEMPERATURE OF ACID  RATE OF REACTION  ,[object Object]
[object Object],THE HIGHER THE TEMPERATURE , THE HIGHER THE RATE OF REACTION BETWEEN SULPHURIC ACID AND MAGNESIUM RIBBON.
QUESTION 2: A group of students has carried out an experiment to determine the melting point of substance Y.  A boiling tube contained substance Y solid is heated in a water bath.  The temperature of substance Y is recorded every 30 seconds.  The result is as shown in table 2  below.
Time (min) 0 ½ 1 1½ 2 2½ 3 3½ Temp. ( o  C) 60.0 64.0 68.0 72.0 76.0 80.0 80.0 80.0 Time (min) 4 4 ½  5 5½ 6 6½ 7 7½ Temp. ( o  C) 80.0 80.0 80.0 80.0 80.0 83.0 86.0 89.0
a) Draw a graph of the temperature against time for the experiment and locate the melting point for  substance Y  [4 m]
 
b) Explain why there is no change in temperature from min 2½ to 6 min HEAT ABSORB BY THE PARTICLES  IS USE  TO OVERCOME THE ATTRACTIVE FORCES BETWEEN THE PARTICLES
c) Draw the arrangement of particles at 2 minutes of heating.  [1m]
QUESTION 3 Table 3 shows the  proton number and nucleon number for atom V,  W, X, Y and Z Atom Proton number Nucleon number V 1 1 W 1 2 X 3 7 Y 6 12 Z 20 40
[object Object],[object Object],TOTAL NUMBER OF PROTON AND NEUTRON IN THE NUCLEUS OF AN ATOM
[object Object],1 ,[object Object],V :  1 Z:  2.8.8.2
[object Object]
e) Which of the above atoms are isotopes? Explain your answer.  [2 m] V AND W. BOTH ATOMS HAVE  SAME PROTON NUMBER  BUT  DIFFERENT NUCLEON NUMBER OR V AND W. BOTH ATOMS HAVE  SAME NUMBER OF PROTON  BUT  DIFFERENT NUMBER OF NEUTRON
[object Object],Electron arrangement: 2.1 Therefore; valence electron = 1
Seminar form four= revision for selaras 1- april 2011
[object Object],[object Object],IS THE FORMULA THAT GIVES THE SIMPLEST WHOLE NUMBER RATIO OF ATOM OF EACH ELEMENT IN A COMPOUND
[object Object],[object Object],[object Object],TO REMOVE THE OXIDE LAYER TO PREVENT THE WHITE FUMES FROM ESCAPING
[object Object],MASS OF Mg  = (24.70-22.30)   = 2.4 g d) Description Mass, g Mass of crucible + lid 22.30 Mass of crucible + lid + magnesium  24.70 Mass of crucible + lid + magnesium oxide 26.30
[object Object],[object Object],MASS OF OXYGEN   = 26.30-24.70   = 1.6  MOLE OF MAGNESIUM = 2.4 / 24   = 0.1
[object Object],MOLE OF OXYGEN = 1.6/16   = 0.1 ,[object Object],Mg: O 0.1 : 0.1 1 : 1 MgO
 
[object Object],[object Object]
Rewrite the equation above as chemical equation.  [2 m] hydrochloric acid  +  zinc carbonate    zinc chloride + carbon dioxide + water HCl  + 2 ZnCO 3      ZnCl 2  +  CO 2  + H 2 O
If 12.5 g of zinc carbonate react completely in the reaction above calculate, i)  the number of mole of  hydrochloric acid being used?  [3m]
2HCl  +  ZnCO 3      ZnCl 2  +  CO 2  + H 2 O
ii)  the mass of zinc chloride obtained.  2HCl  +  ZnCO 3      ZnCl 2  +  CO 2  + H 2 O
iii) the vol of gas collected at room temp  2HCl  +  ZnCO 3      ZnCl 2  +  CO 2  + H 2 O

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Seminar form 4= revision on intro to chemistry, structure of atoms, formulae and chemical equation with answers

  • 1.  
  • 2. CHEMISTRY FORM 4 PREPARATION FOR STANDARDIZED TEST
  • 3. QUESTION 1: An experiment is conducted to investigate the effect of temperature on the rate of reaction. 5 set of 50cm 3 of 1.0 mol dm -3 sulphuric acid is reacted with 5g of magnesium ribbon at a different temperature.
  • 4.
  • 5.
  • 6.
  • 7. QUESTION 2: A group of students has carried out an experiment to determine the melting point of substance Y. A boiling tube contained substance Y solid is heated in a water bath. The temperature of substance Y is recorded every 30 seconds. The result is as shown in table 2 below.
  • 8. Time (min) 0 ½ 1 1½ 2 2½ 3 3½ Temp. ( o C) 60.0 64.0 68.0 72.0 76.0 80.0 80.0 80.0 Time (min) 4 4 ½ 5 5½ 6 6½ 7 7½ Temp. ( o C) 80.0 80.0 80.0 80.0 80.0 83.0 86.0 89.0
  • 9. a) Draw a graph of the temperature against time for the experiment and locate the melting point for substance Y [4 m]
  • 10.  
  • 11. b) Explain why there is no change in temperature from min 2½ to 6 min HEAT ABSORB BY THE PARTICLES IS USE TO OVERCOME THE ATTRACTIVE FORCES BETWEEN THE PARTICLES
  • 12. c) Draw the arrangement of particles at 2 minutes of heating. [1m]
  • 13. QUESTION 3 Table 3 shows the proton number and nucleon number for atom V, W, X, Y and Z Atom Proton number Nucleon number V 1 1 W 1 2 X 3 7 Y 6 12 Z 20 40
  • 14.
  • 15.
  • 16.
  • 17. e) Which of the above atoms are isotopes? Explain your answer. [2 m] V AND W. BOTH ATOMS HAVE SAME PROTON NUMBER BUT DIFFERENT NUCLEON NUMBER OR V AND W. BOTH ATOMS HAVE SAME NUMBER OF PROTON BUT DIFFERENT NUMBER OF NEUTRON
  • 18.
  • 19. Seminar form four= revision for selaras 1- april 2011
  • 20.
  • 21.
  • 22.
  • 23.
  • 24.
  • 25.  
  • 26.
  • 27. Rewrite the equation above as chemical equation. [2 m] hydrochloric acid + zinc carbonate  zinc chloride + carbon dioxide + water HCl + 2 ZnCO 3  ZnCl 2 + CO 2 + H 2 O
  • 28. If 12.5 g of zinc carbonate react completely in the reaction above calculate, i) the number of mole of hydrochloric acid being used? [3m]
  • 29. 2HCl + ZnCO 3  ZnCl 2 + CO 2 + H 2 O
  • 30. ii) the mass of zinc chloride obtained. 2HCl + ZnCO 3  ZnCl 2 + CO 2 + H 2 O
  • 31. iii) the vol of gas collected at room temp 2HCl + ZnCO 3  ZnCl 2 + CO 2 + H 2 O