chapter 8- data handling
terms related to it, types of graphs i.e bar graph, histogram , double bar graph and graphs interpretation with examples.
tally marks and frequency distributions and related questions to it
chapter 8- data handling
terms related to it, types of graphs i.e bar graph, histogram , double bar graph and graphs interpretation with examples.
tally marks and frequency distributions and related questions to it
Một số chuyên đề bồi dưỡng HSG môn Toán lớp 8. Mọi thông tin cần hỗ trợ tư vấn và đăng ký học tập môn Toán lớp 8 vui lòng liên hệ văn phòng gia sư: 0936.128.126.
Gauss jordan and Guass elimination methodMeet Nayak
This ppt is based on engineering maths.
the topis is Gauss jordan and gauss elimination method.
This ppt having one example of both method and having algorithm.
Ôn tập phương trình nghiệm nguyên trong toán THCS ôn thi vào lớp 10. Đăng ký học tập bồi dưỡng, ôn luyện thi toán lớp 9 vào lớp 10 các trường tại Hà Nội vui lòng liên hệ tới văn phòng gia sư Toán thủ khoa Tài Đức Việt theo số máy: 0936.128.126.
Website: http://giasutoan.giasuthukhoa.edu.vn
Tuyển tập 20 đề thi học sinh giỏi môn Toán lớp 5 có đáp án. Mọi thông tin cần hỗ trợ tư vấn, tìm giải pháp học tập môn Toán lớp 4, lớp 5, tìm giáo viên dạy bồi dưỡng HSG Toán tiểu học, mua tài liệu, vui lòng liên hệ: 0919.281.916 - 0936.128.126.
Một số chuyên đề bồi dưỡng HSG môn Toán lớp 8. Mọi thông tin cần hỗ trợ tư vấn và đăng ký học tập môn Toán lớp 8 vui lòng liên hệ văn phòng gia sư: 0936.128.126.
Gauss jordan and Guass elimination methodMeet Nayak
This ppt is based on engineering maths.
the topis is Gauss jordan and gauss elimination method.
This ppt having one example of both method and having algorithm.
Ôn tập phương trình nghiệm nguyên trong toán THCS ôn thi vào lớp 10. Đăng ký học tập bồi dưỡng, ôn luyện thi toán lớp 9 vào lớp 10 các trường tại Hà Nội vui lòng liên hệ tới văn phòng gia sư Toán thủ khoa Tài Đức Việt theo số máy: 0936.128.126.
Website: http://giasutoan.giasuthukhoa.edu.vn
Tuyển tập 20 đề thi học sinh giỏi môn Toán lớp 5 có đáp án. Mọi thông tin cần hỗ trợ tư vấn, tìm giải pháp học tập môn Toán lớp 4, lớp 5, tìm giáo viên dạy bồi dưỡng HSG Toán tiểu học, mua tài liệu, vui lòng liên hệ: 0919.281.916 - 0936.128.126.
This is a collection of fifty questions from important topics in Aptitude where students should pay more attention and practice. Questions taken from various net sources. Some of the answers were edited. This presentation could be run only in office 2010 or latest.
Questions of quantitative aptitude tests for competitive examinations Dr. Trilok Kumar Jain
This material is for PGPSE / CSE students of AFTERSCHOOOL. PGPSE / CSE are free online programme - open for all - free for all - to promote entrepreneurship and social entrepreneurship PGPSE is for those who want to transform the world. It is different from MBA, BBA, CFA, CA,CS,ICWA and other traditional programmes. It is based on self certification and based on self learning and guidance by mentors. It is for those who want to be entrepreneurs and social changers. Let us work together. Our basic idea is that KNOWLEDGE IS FREE & AND SHARE IT WITH THE WORLD
This material is for PGPSE / CSE students of AFTERSCHOOOL. PGPSE / CSE are free online programme - open for all - free for all - to promote entrepreneurship and social entrepreneurship
This material is for PGPSE / CSE students of AFTERSCHOOOL. PGPSE / CSE are free online programme - open for all - free for all - to promote entrepreneurship and social entrepreneurship PGPSE is for those who want to transform the world. It is different from MBA, BBA, CFA, CA,CS,ICWA and other traditional programmes. It is based on self certification and based on self learning and guidance by mentors. It is for those who want to be entrepreneurs and social changers. Let us work together. Our basic idea is that KNOWLEDGE IS FREE & AND SHARE IT WITH THE WORLD
The Art of the Pitch: WordPress Relationships and SalesLaura Byrne
Clients don’t know what they don’t know. What web solutions are right for them? How does WordPress come into the picture? How do you make sure you understand scope and timeline? What do you do if sometime changes?
All these questions and more will be explored as we talk about matching clients’ needs with what your agency offers without pulling teeth or pulling your hair out. Practical tips, and strategies for successful relationship building that leads to closing the deal.
JMeter webinar - integration with InfluxDB and GrafanaRTTS
Watch this recorded webinar about real-time monitoring of application performance. See how to integrate Apache JMeter, the open-source leader in performance testing, with InfluxDB, the open-source time-series database, and Grafana, the open-source analytics and visualization application.
In this webinar, we will review the benefits of leveraging InfluxDB and Grafana when executing load tests and demonstrate how these tools are used to visualize performance metrics.
Length: 30 minutes
Session Overview
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During this webinar, we will cover the following topics while demonstrating the integrations of JMeter, InfluxDB and Grafana:
- What out-of-the-box solutions are available for real-time monitoring JMeter tests?
- What are the benefits of integrating InfluxDB and Grafana into the load testing stack?
- Which features are provided by Grafana?
- Demonstration of InfluxDB and Grafana using a practice web application
To view the webinar recording, go to:
https://www.rttsweb.com/jmeter-integration-webinar
Neuro-symbolic is not enough, we need neuro-*semantic*Frank van Harmelen
Neuro-symbolic (NeSy) AI is on the rise. However, simply machine learning on just any symbolic structure is not sufficient to really harvest the gains of NeSy. These will only be gained when the symbolic structures have an actual semantics. I give an operational definition of semantics as “predictable inference”.
All of this illustrated with link prediction over knowledge graphs, but the argument is general.
State of ICS and IoT Cyber Threat Landscape Report 2024 previewPrayukth K V
The IoT and OT threat landscape report has been prepared by the Threat Research Team at Sectrio using data from Sectrio, cyber threat intelligence farming facilities spread across over 85 cities around the world. In addition, Sectrio also runs AI-based advanced threat and payload engagement facilities that serve as sinks to attract and engage sophisticated threat actors, and newer malware including new variants and latent threats that are at an earlier stage of development.
The latest edition of the OT/ICS and IoT security Threat Landscape Report 2024 also covers:
State of global ICS asset and network exposure
Sectoral targets and attacks as well as the cost of ransom
Global APT activity, AI usage, actor and tactic profiles, and implications
Rise in volumes of AI-powered cyberattacks
Major cyber events in 2024
Malware and malicious payload trends
Cyberattack types and targets
Vulnerability exploit attempts on CVEs
Attacks on counties – USA
Expansion of bot farms – how, where, and why
In-depth analysis of the cyber threat landscape across North America, South America, Europe, APAC, and the Middle East
Why are attacks on smart factories rising?
Cyber risk predictions
Axis of attacks – Europe
Systemic attacks in the Middle East
Download the full report from here:
https://sectrio.com/resources/ot-threat-landscape-reports/sectrio-releases-ot-ics-and-iot-security-threat-landscape-report-2024/
Kubernetes & AI - Beauty and the Beast !?! @KCD Istanbul 2024Tobias Schneck
As AI technology is pushing into IT I was wondering myself, as an “infrastructure container kubernetes guy”, how get this fancy AI technology get managed from an infrastructure operational view? Is it possible to apply our lovely cloud native principals as well? What benefit’s both technologies could bring to each other?
Let me take this questions and provide you a short journey through existing deployment models and use cases for AI software. On practical examples, we discuss what cloud/on-premise strategy we may need for applying it to our own infrastructure to get it to work from an enterprise perspective. I want to give an overview about infrastructure requirements and technologies, what could be beneficial or limiting your AI use cases in an enterprise environment. An interactive Demo will give you some insides, what approaches I got already working for real.
DevOps and Testing slides at DASA ConnectKari Kakkonen
My and Rik Marselis slides at 30.5.2024 DASA Connect conference. We discuss about what is testing, then what is agile testing and finally what is Testing in DevOps. Finally we had lovely workshop with the participants trying to find out different ways to think about quality and testing in different parts of the DevOps infinity loop.
Builder.ai Founder Sachin Dev Duggal's Strategic Approach to Create an Innova...Ramesh Iyer
In today's fast-changing business world, Companies that adapt and embrace new ideas often need help to keep up with the competition. However, fostering a culture of innovation takes much work. It takes vision, leadership and willingness to take risks in the right proportion. Sachin Dev Duggal, co-founder of Builder.ai, has perfected the art of this balance, creating a company culture where creativity and growth are nurtured at each stage.
Search and Society: Reimagining Information Access for Radical FuturesBhaskar Mitra
The field of Information retrieval (IR) is currently undergoing a transformative shift, at least partly due to the emerging applications of generative AI to information access. In this talk, we will deliberate on the sociotechnical implications of generative AI for information access. We will argue that there is both a critical necessity and an exciting opportunity for the IR community to re-center our research agendas on societal needs while dismantling the artificial separation between the work on fairness, accountability, transparency, and ethics in IR and the rest of IR research. Instead of adopting a reactionary strategy of trying to mitigate potential social harms from emerging technologies, the community should aim to proactively set the research agenda for the kinds of systems we should build inspired by diverse explicitly stated sociotechnical imaginaries. The sociotechnical imaginaries that underpin the design and development of information access technologies needs to be explicitly articulated, and we need to develop theories of change in context of these diverse perspectives. Our guiding future imaginaries must be informed by other academic fields, such as democratic theory and critical theory, and should be co-developed with social science scholars, legal scholars, civil rights and social justice activists, and artists, among others.
Transcript: Selling digital books in 2024: Insights from industry leaders - T...BookNet Canada
The publishing industry has been selling digital audiobooks and ebooks for over a decade and has found its groove. What’s changed? What has stayed the same? Where do we go from here? Join a group of leading sales peers from across the industry for a conversation about the lessons learned since the popularization of digital books, best practices, digital book supply chain management, and more.
Link to video recording: https://bnctechforum.ca/sessions/selling-digital-books-in-2024-insights-from-industry-leaders/
Presented by BookNet Canada on May 28, 2024, with support from the Department of Canadian Heritage.
Smart TV Buyer Insights Survey 2024 by 91mobiles.pdf91mobiles
91mobiles recently conducted a Smart TV Buyer Insights Survey in which we asked over 3,000 respondents about the TV they own, aspects they look at on a new TV, and their TV buying preferences.
Smart TV Buyer Insights Survey 2024 by 91mobiles.pdf
Questions on average, percentage, profit
1. QUESTIONS ON AVERAGE, PERCENTAGE & PROFIT by : DR. T.K. JAIN AFTERSCHO ☺ OL centre for social entrepreneurship sivakamu veterinary hospital road bikaner 334001 rajasthan, india FOR – PGPSE / CSE PARTICIPANTS mobile : 91+9414430763
2. My words.... Here I present a few basic questions on average, percentage & profit . I wish that more people should become entrepreneurs. An ordinary Indian entrepreneur wishes to remain an honest entrepreneur and contribute to the development of nation but we have to strengthen those institutions which truly promote entrepreneurship, not just degree granting institutions. Let us work together to promote knowledge, wisdom, social development and education. We believe in free education for all, free support for all, entrepreneurship opportunities and training for all. Let us work together for these goals. ... I alone cant do much, I need support of perosns like you .......... ...
3. 1 liter of water is add to 5 liters of a 20 % solution of alcohol in water . Find the strength of alcohol in new solution? At present we have 1 liter alcohol and 4 liters water. But now water becomes 5 liters. The strength of alchoal is : 1/(1+5) *100 = 16.66% answer
4. If A earns 33 1/3 more than B .Then B earns less than A by what percent? If B earns 100, A earns 133.33 B earns 33.33 less than A or in % : 33.33 / 133.33 *100 = 25% answer
5. A school has only three classes which contain 40,50,60 students respectively.The pass percent of these classes are 10, 20 and 10 respectively . Then find the pass percent in the school. Number of students passing out : 4,10 and 6 from the 3 classes. Total pass = 20 total students = 150 pass percentage=20/150 *100 = 13.33%
6. There are 600 boys in a hostel . Each plays either hockey or football or both .If 75% play hockey and 45 % play football ,Find how many play both? Add 75+45 = 120, (120 -100 = 20), thus 20% play both the games. 120 students play both football and hockey. Answer
7. A bag contains 600 coins of 25p denomination and 1200 coins of 50p denomination. If 12% of 25p coins and 24 % of 50p coins are removed, Find the percentage of money removed from the bag ? Toal amount = (600 .25) + (1200* .5) = 750 amount of coins removed = (72*.25) + (288*.5) = 162 162/750 * 100 = 21.6% answer
8. P is six times as large as Q.Find the percent that Q is less than P? Let us assume Q = X P = 6X Q is less by (6X – X) = 5X 5X/6X * 100 = 83% approximately. Answer
9. For a sphere of radius 10 cm ,the numerical value of surface area is what percent of the numerical value of its volume? Volume of shpere = 4/3 * pi * r^3 surphace area of sphere = 4pi*r^2 ratio of surface area to volume = 4pir^2 / 4/3pir^3 * 100 = 3/10 * 100 = 30% answer
10. A reduction of 21 % in the price of wheat enables a person to buy 10 .5 kg more for Rs 100.What is the reduced price per kg. Let us assume reduced price = X 100 /1.27X - 100 / X = 10.5 (100 – 127) / 1.27X = 10.5 -27 / (10.5*1.27) =x X = 2.02 answer
11. The average temperature of the town in the first four days of a month was 58 degrees. The average for the second ,third,fourth and fifth days was 60 degree .If the temperature of the first and fifth days were in the ratio 7:8 then what is the temperature on the fifth day? 1 st day = 7X, 5 th day = 8x Total for first 4 days : 58*4 = 232 total for 2,3,4,5 day = 60*4 = 240 difference between 5 th and 1 st day = 8X-7X or 240 -232 X = 8 temperature on fifth day = 8*8 = 64 degrees answer
12. The average of 5 numbers is 7.When 3 new numbers are added the average of the eight numbers is 8.5. The average of the three new number is? Total of first 5 = (5*7) = 35 total of 8 (including 3 new digits) = (8*8.5) = 68 total of 3 new digits = (68 – 35 = 33 average of 3 new digits=33/3 = 11 answer
13. Of the three numbers the first is twice the second and the second is twice the third .The average of the reciprocal of the numbers is 7/72,the numbers are Assume 3 rd number = x, 2 nd number = 2x and 1 st number = 4x actually the total is : 7/72 * 3 = 7/24 if we take average of reciprocals :, then 1/x + 1/2x + 1/4x = 7/4x 7/4x = 7/24 x = 7/24 * 4/7 = 1/6 x = 6, other two numbers are 12 and 24 answer
14. 16 children are to be divided into two groups A and B of 10 and 6 children. The average percent marks obtained by the children of group A is 75 and the average percent marks of all the 16 children is 76. What is the average percent marks of children of groups B? Total of 16 children = (16 * 76) = 1216 total of group A = ( 10 * 75)= 750 total of group B = 466 average of B = 466 / 6 = 77.6 answer
15. The mean temperature of Monday to Wednesday was 37 degrees and of Tuesday to Thursday was 34 degrees .If the temperature on Thursday was 4/5th that of Monday. The temperature on Thursday was Total from Monday to Wednesday = (3 * 37) = 111 total from tuesday to thursday = (3* 34) = 102 difference between Monday and Thursday : 5X – 4X = (111 -102) = 9 X = 9, temperature on tursday = (4*9) = 36 answer
16. A man whose bowling average is 12.4,takes 5 wickets for 26 runs and there by decrease his average by 0.4. The number of wickets,taken by him before his last match is: Let us assume number of wickets taken before start of this match = x and number of runs = Y Y/X = 12.4 or Y -12.4X = 0 (Y+26) / (X +5) = 12 or Y-12X=34 X = 85 (number of wickets) Y = 1054 answer
17. A team of 8 persons joins in a shooting competition. The best marksman scored 85 points.If he had scored 92 points ,the average score for the team would have been 84.The team scored was. Total of team = (8*84) – (92-85) =672 – 7 =665 answer
18. The average weight of 3 men A,B and C is 84 Kgs. Another man D joins the group and the average now becomes 80 Kgs.If another man E whose weight is 3 Kgs more than that of D ,replaces A then the average weight B,C,D and E becomes 79 Kgs. The weight of A is. Weight of A+B+C = (3*84) = 252 Weight of A+B+C+D= ((4*80) = 320 weight of D = 320-252 = 68 weight of E= 71 total of B+C+D+E = (4*79) = 316 difference of A and E is just 4 Kg. (320-316) weight of A = 71+4 = 75 kg. Answer
19. Five years ago, the average age of P and Q was 15 years ,average age of P,Q, and R today is 20 years,how old will R be after 10 years? Total of P & Q = (15+5) * 2 = 40 total of P,Q,R = (20*3) = 60 R = 20 age of R after 10 years = 20+10 = 30 answer
20. The average age of the boys in the class is twice the number of girls in the class .If the ratio of boys and girls in the class of 36 be 5:1, what is the total of the age (in years) of the boys in the class? Number of girls = 1/(1+5) * 36 = 6 average age of boys = 2*6 = 12 Number of boys= 36-6 = 30 total age of boys=30*12 = 360 answer
21. .In a cricket eleven ,the average of eleven players is 28 years .Out of these ,the average ages of three groups of players each are 25 years,28 years, and 30 years respectively. If in these groups ,the captain and the youngest player are not included and the captain is eleven years older than the youngest players , what is the age of the captain? Total of 11 = (11*28) = 308 total of 3 groups (3*25 + 3*28 + 3*30) = (75+84+90) = 249 remaining = 59 Captain + Y = 59 C-Y= 11 2C = 70 or C = 35 answer
22. Dhoni scored 87 in his 17 th innings and this increased his average by 3. What is the new average of Dhoni ? Let us assume that his average is X total runs = (number of innings * the average run rate) = 17 *x 17x – 87 = 16(x-3) 17x – 87 = 16x – 48 x = 39 answer
23. The average weight of 24 students is 35 kg. If the weight of teacher is also included, the average rises by 400 grams. What is the weight of the teacher ? Let us assume the weight of teacher = x total weight earlier : (number of students * average weight) =24*35 = 840 new total weight = (24+1) * (35+.400) = 885 (difference is due to inclusion of teacher) weight of teacher = 885 – 840 = 45 Kgs.
24. Average earning of 11 days is 50000. the average for first 6 days is 49000 and the average for last 6 days is 52000. what is the earning on 6 th day? Total for 11 = (11 * 50000) = 550000 total for first 6 = (6*49000) = 294000 total for last 6 = (6*52000) = 312000 let us add the last two : 294000+312000 = 606000 find the difference of this and total of 11 : 606000 – 550000=56000 (which is income of the 6 th day)
25. Find the average of all these numbers.142,147,153,165,157. Formula for average = total for all / number of digits First add them all : total = 764 there are 5 digits so divide it by 5 = 764/5 = 152.8 answer
26. Find the average of all these numbers: 4,10,16,22,28 Total = 80 there are 5 digits so divide by 5 average = 80 / 5 = 16 answer shortcut = difference of all the numbers is equal, so mid value (16) is the average – so there is no need for all this calculation)
27. Find the average of all these numbers: =4,10,16,22,28,34. Here also we have same difference between continuous digits, so take the middle digits : middle digits are : 16 and 22. find the mid point of these two digits : (16+22)/2 = 19 or 16 + 3 (half of 6, which is common difference). Answer
28. The average marks of a student in 4 Examinations is 40.If he got 80 marks in 5th Exam then what is his new average. His total for 4 examinations = 160 total after 5 examinations = 160+80 = 240 new average = 240/5 = 48 answer
29. The average marks of Surabhi Daga in 10 Examinations is 80%.If she got 90 marks in 5th Exam then what is her new average. her total for 10 examinations = 800 total after 11 examinations =800+90 new average = 890/11 = 80.9 answer
30. In a group the average income of 6 men is 500 and that of 5 women is 280, then what is average income of the group. Total for men = (6*500) = 3000 total for women = (5*280) = 1400 total for all= 4400 there are 11 persons (6 men + 5 women), so average = 4400/11 = 400 per person.
31. The average weight of a class of 30 students is 40 kgs if the teacher weight is included then average increases by 2 kgs then find the weight of the teacher? Total for students = 30 * 40 = 1200 total with teacher (30+1) * (40+2) = 1302 the difference is due to teacher : 1302– 1200 = 102 kgs. Answer
32. The average age of Mr and Mrs Sharma (Ilahabad Wale) 4 years ago is 28 years . If the present average age of Mr and Mrs Sharma and their son is 22 years. What is the age of their son? Age of Mrs and Mr. Sharma : (28+4) * 2 = 64 age with son : (3*22) = 66 age of son = 66 – 64 = 2 years. Answer
33. The average price of 10 books is increased by 17 Rupees when one of them whose value is Rs.400 is replaced by a new book. What is the price of new book? Old price = 400 addition = 10 * 17 = 170 new price = 570 answer
34. The average marks of girls in a class is 62.5. The average marks of 4 girls among them is 60.The average marks of remaining girls is 63,then what is the number of girls in the class? Let us assume the number of students = X total = 62.5x (4*60)+(63 * ( X -4) = 62.5X 240+ 63X- 252 = 62.5x .5X = 12 X = 24 answer
35. Find the average of first 50 natural numbers? Just add 1 and divide by 2, you will get the mid point. Simply find the mid point (50+1) / 2 = 51/2 = 25.5 answer
36. The average of the first nine prime number is? Add them : (2+3+5+7+11+13+17+19+23) =100 now divide this total by 9, we get : 11.11 answer
37. The average of 2,7,6 and x is 5 and the average of and the average of 18,1,6,x and y is 10 .what is the value of y? Total of first 4 digits = (4*5 ) = 20 X = 20 – (2+7+6) = 5 total next 5 digits = (5*10) = 50 value of Y = 50 - (18+1+6+5) = 20 Y = 20 answer
38. The average of a non-zero number and its square is 5 times the number.The number is? Let us assume the number to be X X + X^2 = 2(5X) X^2 = 10x- X X^2 = 9X X = 9 answer
39. P and Q started a business investing Rs 85,000 and Rs 15,000 respectively. In what ratio the profit earned after 2 years be divided between P and Q respectively? Profit can be divided either in capital ratio or equally. Here we assume that profit is divided in capital ratio : 85:15 or 17:3 answer
40. P and Q started a business investing Rs 85,000 each. However, P withdrew 20% of his capital after 1.5 year and Q doubled his investment after 20 months. . In what ratio the profit earned after 2 years be divided between P and Q respectively? Profit can be divided either in capital ratio or equally. Here we assume that profit for 2 nd year is divided in capital ratio : p = (85*6 + 68*6) =918 Q = (85*6 + 170*6) =1530 their ratio : 918:1530 or 3:5 answer
41. A,B and C started a business by investing Rs 1,20,000, Rs 1,35,000 and Rs 1,50,000.Find the share of each ,out of an annual profit of Rs 56,700? Their profit sharing ratio as per their capital : 120: 135:150 or 8:9:10 share of A =8/27 *56700 = 16800 share of B = 9/27 *56700 = 18900 share of C = 10/27 *56700 = 21000 answer
42. A,B and C started a business by investing Rs 2,20,000, Rs 350000 and Rs 4,50,000.Find the share of each ,out of an annual profit of Rs 10200 ? Their profit sharing ratio as per their capital : 22:35:45 share of A =22/102 *10200 = 2200 share of B = 35/102 *10200 = 3500 share of C =45/102 *10200 = 4500 answer
43. 3 milkman A,B,C rented a pasture A grazed his 45 cows for 12 days B grazed his 36 cows for 15 days and c 60 cows for 10 days. If b's share of rent was Rs 540 What is the total rent? Share of A = 45*12 = 540 share of B = 36*15 = 540 share of C = 60 * 10 = 600 share of B's rent is 540, that means total rent is : (540+540+600) = 1680 answer
44. 3 milkman A,B,C rented a pasture A grazed his 90 cows for 6 days B grazed his 15 cows for 20 days and c 30 cows for 5 days. If C's share of rent was Rs 300 What is A's rent ? Share of A = 90*6 = 540 share of B = 15*20= 300 share of C = 30*5= 150 share of c's rent is 300, that meansthe rent is twice the total cow-days. So A's rent should be 1080 answer
45. Ram and Krishn entered into a partnership with Rs 50,000 and Rs 60,000, after 4 months Ram invested Rs 25,000 more while Krishn withdraw Rs 20,000 . Find the share of Ram in the annual profit of Rs 289,000. Ram's share = (50*4 + 75*8) =800 Krishn's share = (60*4 + 40*8) =560 share of ram = (80)/(80+56) * 289000 =170000 answer
46. A,B,C enter into partnership .A invests 3 times as much as B invests and B invests two third of what C invests. At the end of the year ,the profit earned is Rs 6600. what is the share of B? Let us start from C. Suppose C invests Rs. 3. B will invest 2/3 of 3 = 2. Thus A would invest 6 total investment = 11 share of B = 2/11 * 6600 = 1200 answer
47. A,B,C enter into partnership . A invests two third of what B invests and B invests two third of what C invests. At the end of the year ,the share of A is 2000, what is the share of B and C? (start with the last - here C) Suppose C invests (3*3) = 9 B will invest = 9 * 2/3 = 6 A will invest = 6 * 2/3 = 4 thus if share of A is known, we can find share of B and C also. B = 6/4 * 2000 = 3000 C = 9/4 * 2000 = 4500 shortcut = simply multiply 2000 *3/2 for B and again by 3/2 for C. You will get the answer
48. A,B and C enter into a partnership by investing in the ratio of 3:2:4. After one year ,B invests another Rs 2,70,000 and C,at the end of 2 years, also invests Rs 2,70,000.At the end of 3 years,profit are shared in the ratio of 3:4:5.Find the initial investment of each? Share of A = 3x*3 = 9x share of B = 2x*3 + 270*2 = 6x+540 Share of C =4x*3+270*1 = 12x+270 based on new ratio : 9x/3 = (12x+270)/5 3x=2.4x+54 or .6x=54 or x= 54/.6 = 90 so initial investments were : A : 270, B 180 and C 360 (all in thousands). Answer
49. A,B and C enter into a partnership by investing in the ratio of 3:2:4. After one year ,B invests another Rs 300,000 and C,at the end of 2 years, also invests Rs 300,000.At the end of 3 years,profit are shared in the ratio of 2:2:3 .Find the initial investment of each? Share of A = 3x*3 = 9x share of B = 2x*3 + 300*2 = 6x+600 Share of C =4x*3+300*1 = 12x+300 based on new ratio : 9x / 2 = (12x+300)/3 4.5x = 4x+100 or .5x = 100 or x = 200 initial investment by A = 600, B = 400 and C =800 (all in '000) answer
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