PRELIMINARY DESIGN OF SLAB
STEP 1:-
LOAD CALCULATIONS
Inner dimensions = (4×3.6) m2
Assuming fy = 415 N/mm2
Fck = 20 N/mm2
Effective span (Lx) = 3.6m
Effective span (Ly) = 4 m
Aspect ratio (Ly/Lx) = [4/ 3.6] = 1.1 < 2
Assume over all depth of slab = 120 m
Effective depth = 120 – 15-10/2 = 100mm
Self weight of slab = 0.12 × 25 =3 kN/m2
Live load = 2kN/m2
Dead load = 1kN/m2
Total weight = 6kN/m2
Load per meter run = 6.0 × 1.0 = 6.0kN/m
Factored load = 1.5 × 6.0 = 9.0 kN/m
Edge condition = Interior panel.
STEP 2:-
DESIGN MOMENTS
Using bending moment coefficients from table – 26 of IS 456:2000, the bending moments are
calculated as follows.
Mx=αxwLx
2 My=αywLx
2
BENDING MOMENTCOEFFICIENTS
AT SUPPORTS AT MID SPAN
ALONG SHORT SPAN (αx) - 0.037 0.028
ALONG LONG SPAN (αy) -0.032 0.024
BENDING MOMENTS
AT SUPPORTS (kN-m) AT MID SPANS (kN-m)
ALONG SHORT SPAN Mx (-ve) = -4.3 Mx (+ve) = 3.2
ALONG LONG SPAN My (-ve) = -3.73 My (+ve) = 2.79
STEP:-3
CHECK FOR EFFECTIVE DEPTH
Maximum bending moment (Mu) = 0.138 × fck × bd2
4.3 ×106 = 0.138 × 20 × 1000 × d2
d = 42.56 mm < 100.00mm
Therefore, provide total depth of slab( D) = 120mm
S.NO SPAN(m x m) EDGE CONDITION REQUIRED
DEPTH(mm)
PROVIDED
DEPTH(mm)
1 3 x 6.1 Two Adjacent edges
Discontinuous
51.6 100
2 3 x 3.6 One Long Edge
Discontinuous
39 100
3 2 x 3 One Short Edge
Discontinuous
27.2 100
4 4 x 3.6 One Short Edge
Discontinuous
42 100
5 1.5 x 6.1 One short edge
Discontinuous
27.5 100
6 3 × 6.1 One short edge
Discontinuous
44.6 100
7 4 × 6.1 One short edge
Discontinuous
54 100
8 4 × 3.6 Interior panel 42.56 100
9 4 × 2 Interior panel 29.11 100
10 3 × 3.6 Interior panel 35.5 100
11 1.5× 3.6 Interior panel 33 100
12 3 × 2 Interior panel 26.3 100
13 1.5 × 2 Interior panel 18.15 100
Preliminary design of slab

Preliminary design of slab

  • 1.
    PRELIMINARY DESIGN OFSLAB STEP 1:- LOAD CALCULATIONS Inner dimensions = (4×3.6) m2 Assuming fy = 415 N/mm2 Fck = 20 N/mm2 Effective span (Lx) = 3.6m Effective span (Ly) = 4 m Aspect ratio (Ly/Lx) = [4/ 3.6] = 1.1 < 2 Assume over all depth of slab = 120 m Effective depth = 120 – 15-10/2 = 100mm Self weight of slab = 0.12 × 25 =3 kN/m2 Live load = 2kN/m2 Dead load = 1kN/m2 Total weight = 6kN/m2 Load per meter run = 6.0 × 1.0 = 6.0kN/m Factored load = 1.5 × 6.0 = 9.0 kN/m Edge condition = Interior panel. STEP 2:- DESIGN MOMENTS Using bending moment coefficients from table – 26 of IS 456:2000, the bending moments are calculated as follows. Mx=αxwLx 2 My=αywLx 2 BENDING MOMENTCOEFFICIENTS AT SUPPORTS AT MID SPAN ALONG SHORT SPAN (αx) - 0.037 0.028 ALONG LONG SPAN (αy) -0.032 0.024
  • 2.
    BENDING MOMENTS AT SUPPORTS(kN-m) AT MID SPANS (kN-m) ALONG SHORT SPAN Mx (-ve) = -4.3 Mx (+ve) = 3.2 ALONG LONG SPAN My (-ve) = -3.73 My (+ve) = 2.79 STEP:-3 CHECK FOR EFFECTIVE DEPTH Maximum bending moment (Mu) = 0.138 × fck × bd2 4.3 ×106 = 0.138 × 20 × 1000 × d2 d = 42.56 mm < 100.00mm Therefore, provide total depth of slab( D) = 120mm S.NO SPAN(m x m) EDGE CONDITION REQUIRED DEPTH(mm) PROVIDED DEPTH(mm) 1 3 x 6.1 Two Adjacent edges Discontinuous 51.6 100 2 3 x 3.6 One Long Edge Discontinuous 39 100 3 2 x 3 One Short Edge Discontinuous 27.2 100 4 4 x 3.6 One Short Edge Discontinuous 42 100 5 1.5 x 6.1 One short edge Discontinuous 27.5 100 6 3 × 6.1 One short edge Discontinuous 44.6 100 7 4 × 6.1 One short edge Discontinuous 54 100 8 4 × 3.6 Interior panel 42.56 100 9 4 × 2 Interior panel 29.11 100 10 3 × 3.6 Interior panel 35.5 100 11 1.5× 3.6 Interior panel 33 100 12 3 × 2 Interior panel 26.3 100 13 1.5 × 2 Interior panel 18.15 100