Phy youngs modulus
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This document describes a physics experiment to determine Young's modulus. The experiment involves measuring the deflection of a metal rod under different loads to calculate Young's modulus. Key results include: 1) Young's modulus was calculated to be between 0.888*1011 N/m2 to 1.01*1011 N/m2 for a 225g load. 2) For a 264g load, Young's modulus was calculated to be between 0.885*1011 N/m2 to 0.9958*1011 N/m2. 3) The time period of oscillations for the rod was measured to be 0.50372 seconds. Potential sources of error in the experiment are discussed.
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- 2. 2
- 3. 3 TASK 1-PART A T1____________weight=225grams sno. x(cm) y(cm) 1 12 2.3cm 2 14 2.9cm 3 16 3.4cm 4 18 4cm 5 At F 4.6(for demonstration in video) T2____________weight=225grams sno. x(cm) y(cm) 1 12 2.2 2 14 2.9 3 16 3.4 4 18 3.9 We see that the values of the deflection in table are nearly equal and thus by reciprocity theorem the values are consistent.
- 4. 4 T3____________weight=225grams sno. x(cm) t1 t2 mean[(t1+t2)/2] 1 12 2.3cm 2.2cm 2.25 2 14 2.9cm 2.9cm 2.9 3 16 3.4cm 3.4cm 3.4 4 18 4cm 3.9cm 3.95 Calculation for c for x=18cm
- 5. 5 Sno. values C(all lengths in si) 1 12 2.25 576 *10-4 2 14 2.9 585.74*10-4 3 16 3.4 627.45*10-4 4 18 3.95 656.20*10-4 Where l=22 cm W=(225/1000)*g b=2.4cm d=0.09cm sn c Y(N/m2 ) 1 576 0.888*1011 2 585.74 0.903*1011 3 627.45 0.9682*1011 4 656.20 1.01*1011
- 6. 6 The mean ymean is= Error: Value Error% Result 0.888*1011 5.85 Accepted 0.903*1011 4.02 Accepted 0.9682*1011 2.5 Accepted 1.01*1011 6.68 Rejected TASK 1- part b T!____________weight=264grams sno. x(cm) y(cm) 1 12 2.7cm 2 14 3.4cm 3 16 4cm 4 18 4.7cm
- 7. 7 T2____________weight=264grams sno. x(cm) y(cm) 1 12 2.6 2 14 3.4 3 16 3.9 4 18 4.7 We see that the values of the deflection in table are nearly equal and thus by reciprocity theorem the values are consistent. T3____________weight=264grams sno. x(cm) t1 t2 mean[(t1+t2)/2] 1 12 2.7cm 2.6 2.65 2 14 3.4cm 3.4 3.4 3 16 4cm 3.9 3.95 4 18 4.7cm 4.7 4.7
- 8. 8 Sno. values C(all lengths in si) 1 12 2.65 0.0489 2 14 3.4 0.0499 3 16 3.95 0.054 4 18 4.7 0.055 Where l=22 cm W=(264/1000)*g b=2.4cm d=0.09cm
- 9. 9 sn c Y(N/m2 ) 1 0.0489 0.885*1011 2 0.0499 0.9035*1011 3 0.054 0.977*1011 4 0.055 0.9958*1011 The mean ymean is= 0.9403*1011 Error: Value Error% Result 0.885*1011 5.53 Accepted 0.9035*1011 3.68 Accepted 0.977*1011 3.67 Accepted 0.9958*1011 5.55 Rejected
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- 11. 11 8.522*1010 N/m2 TASK 3 The ruler may be unstable as it may not be fixed.The ruler may slip so we need to fix it properly. The block sliding with wall would experience friction and would be better if no sliding is done. If the ruler is rigid the oscillations may be small and fast and taking reading would be difficult and need to measure it properly. Taking two people instead of one during the reading of oscillation would lower the errors due to human error.
- 12. 12 The oscillation should be small as it follows the SHM condition for small oscillations and care should be made that the ruler oscillates perpendicularly. Taking long number of oscillation would cause the inclusion of damping factor in the time period so medium no. of oscillations should be taken into consideration.