This document discusses calculating torques, forces, and distances for a problem involving a beam with weights attached. It finds the maximum distance the beam can extend using torque equations, solving for 1.5 m. It then uses equilibrium equations to find the horizontal force of 433 N and vertical force of 250 N.

1. 30. (a) Computing torques about point A, we find
L
Tmax L sin θ = W xmax + Wb .
2
We solve for the maximum distance:
Tmax sin θ − Wb
2 500 sin 30◦ − 200
2
xmax = L= (3.0) = 1.5 m .
W 300
(b) Equilibrium of horizontal forces gives
Fx = Tmax cos θ = 433 N .
(c) And equilibrium of vertical forces gives
Fy = W + Wb − Tmax sin θ = 250 N .