Multiplication 4
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'Lilavati' was one of the mathematical texts written by Bhaskaracharya-II (1114 - 1193 CE), a well-known Indian mathematician. In this presentation we have shared one of the techniques of multiplying numbers which has been explained in Lilavati. To learn more techniques of Lilavati, join Vedic Mathematics Home Study Course. For details, visit vedicmaths.chinfo.org
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'Lilavati' was one of the mathematical texts written by Bhaskaracharya-II (1114 - 1193 CE), a well-known Indian mathematician. In this presentation we have shared one of the techniques of multiplying numbers which has been explained in Lilavati.
To learn more techniques of Lilavati, join Vedic Mathematics Home Study Course. For details, visit vedicmaths.chinfo.org
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'Lilavati' was one of the mathematical texts written by Bhaskaracharya-II (1114 - 1193 CE), a well-known Indian mathematician. In this presentation we have shared one of the techniques of multiplying numbers which has been explained in Lilavati.
To learn more techniques of Lilavati, join Vedic Mathematics Home Study Course. For details, visit vedicmaths.chinfo.org
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'Lilavati' was one of the mathematical texts written by Bhaskaracharya-II (1114 - 1193 CE), a well-known Indian mathematician. In this presentation we have shared one of the techniques of multiplying numbers which has been explained in Lilavati.
To learn more techniques of Lilavati, join Vedic Mathematics Home Study Course. For details, visit vedicmaths.chinfo.org
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Have you ever wondered why is (a+b)^2 = a^2 + 2ab + b^2? Here is a presentation that will explain this algebraic identity. This was one of the algebraic identities that ancient Indian mathematician Bhaskaracharya-II (1114-1193 CE) gave in his mathematical treatise 'Lilavati' (1150 CE)
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6. multiplying 2 to 4-digit numbers by multiplies of 10
This document discusses multiplying numbers by multiples of 10. It provides examples of multiplying 2-4 digit numbers by multiples of 10. The key points are:
- To multiply by a multiple of 10, multiply the non-zero digits first and then add the appropriate number of zeros to the end based on the multiple of 10.
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'Lilavati' was one of the mathematical texts written by Bhaskaracharya-II (1114 - 1193 CE), a well-known Indian mathematician. In this presentation we have shared one of the techniques of multiplying numbers which has been explained in Lilavati.
To learn more techniques of Lilavati, join Vedic Mathematics Home Study Course. For details, visit vedicmaths.chinfo.org
Multiplication 1
'Lilavati' was one of the mathematical texts written by Bhaskaracharya-II (1114 - 1193 CE), a well-known Indian mathematician. In this presentation we have shared one of the techniques of multiplying numbers which has been explained in Lilavati.
To learn more techniques of Lilavati, join Vedic Mathematics Home Study Course. For details, visit vedicmaths.chinfo.org
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'Lilavati' was one of the mathematical texts written by Bhaskaracharya-II (1114 - 1193 CE), a well-known Indian mathematician. In this presentation we have shared one of the techniques of multiplying numbers which has been explained in Lilavati.
To learn more techniques of Lilavati, join Vedic Mathematics Home Study Course. For details, visit vedicmaths.chinfo.org
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Have you ever wondered why is (a+b)^2 = a^2 + 2ab + b^2? Here is a presentation that will explain this algebraic identity. This was one of the algebraic identities that ancient Indian mathematician Bhaskaracharya-II (1114-1193 CE) gave in his mathematical treatise 'Lilavati' (1150 CE)
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* Let A's age be x and B's age be y
* Then average of A and B is (x + y)/2 = 20
* So, x + y = 40
* If C replaces A, average is (y + c)/2 = 19
* So, y + c = 38
* If C replaces B, average is (x + c)/2 = 21
* So, x + c = 42
* Solving the three equations, we get:
x = 22, y = 18, c = 20
The ages are:
A = 22
B = 18
C = 20
The answer is option 1.
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* Let A's age be x and B's age be y
* Then average of A and B is (x + y)/2 = 20
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- 1. Multiplication – 4 (from Bhaskara’s Lilavati) Vinay Nair SCHOOL OF VEDIC MATHS
- 2. Splitting the number 8 (i) 28 x 8 8 8 = 10 - 2 10 - 2 Hence, 28 x 8 = 28 x 10 - 28 x 2 28 x 10 = 280 - 28 x 2 = 56 Answer = 224
- 3. Splitting the number 19 (ii) 19 x 32 19 19 = 20 - 1 20 - 1 Hence, 19 x 32 = 32 x 20 - 32 x 1 32 x 20 = 640 - 32 x 1 = 32 Answer = 608
- 4. Splitting the number 39 (iii) 42 x 39 39 39 = 40 - 1 40 - 1 Hence, 42 x 39 = 42 x 40 - 42 x 1 42 x 40 = 1680 - 42 x 1 = 42 Answer = 1638
- 5. Splitting the number 28 (iv) 28 x 35 28 28 = 30 - 2 30 - 2 Hence, 35 x 28 = 35 x 30 - 35 x 2 35 x 30 = 1050 - 35 x 2 = 70 Answer = 980
- 6. Splitting the number 35 (iv) 28 x 35 35 35 = 40 - 5 40 - 5 Hence, 28 x 35 = 28 x 40 - 28 x 5 28 x 40 = 1120 - 28 x 5 = 140 Answer = 980
- 7. More calculations 43 x 98 99 x 72 49 x 64 38 x 26 104 x 98
- 8. Thank you!