Match the enzyme activity in DNA synthesis with its function. DNA po.pdf
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Match the enzyme activity in DNA synthesis with its function. DNA pol III (_) fragments Helicase (_) Primase (_) using template strand DNA pol I (_) double helix DNA ligase (_) adds nucleotides Topoisomerase (_) primer A. anneals DNA B. relieves overwinding C. adds nucleotides D. unwinds parental E. removes RNA primer, F. adds a short RNA 10 Proofreading and repair of the DNA double helix does NOT involves a. detecting a mis-match in base pairs. b. removing the mis-match with a nuclease. c. annealing the Okazaki fragments together with DNA ligase. d. repairing the mis-match with polymerase. e. annealing the edited DNA with the rest of the molecule with ligase. Solution 4. DNA Pol III- (C)- DNA polymerase III is the primary enzyme involved in DNA replication which adds nucleotides to the 3\' end of the forming DNA strand during replication. 5. Helicase- (D)- Helicases are enzymes that separates double-stranded DNA into single strands allowing each strand to be copied. 6. Primase- (F)- Primase functions by synthesizing short RNA sequences that are complementary to a single-stranded DNA. 7. DNA Pol I- (E)- DNA polymerase-I fills in the necessary nucleotides between the Okazaki fragments in a 5\'3\' direction. 8. DNA ligase- (A)- DNA ligases are essential for the joining of DNA fragments during replication. 9. Topoisomerase- (B)-Topoisomerases are enzymes that participate in the overwinding or underwinding of DNA. 10. Okazaki fragments are only formed during DNA replication and not observed during DNA proof reading and repair. Therefore answer is (C).
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Central Dogma Assignment Print Name ________________.docx
Central Dogma Assignment
Print Name ___________________________________________
Directions: Complete this worksheet after listening to the Central Dogma recorded lecture posted
on Blackboard. Each student will turn in his/her individual worksheet at the beginning of class.
COMPLETE THE TABLE. LABEL YOUR 5’ AND 3’ ENDS.
YOU MUST GET THE ENTIRE TABLE CORRECT FOR CREDIT. NO PARTIAL CREDIT.
DNA template (-) 5’ GTACTATTAATT TACTGGGTGCAT CCGCATGGTACG 3’
DNA coding (+) strand
mRNA (+) codons
Only write the tRNA
anticodons for actual
codons coding for
amino acids
amino acid sequence
1. You isolate and sequence a novel cytoplasmic membrane protein from Staphylococcus aureus
that appears to function in the transport of cations into the cell. A colleague working in a competing lab
in France isolates a cytoplasmic membrane protein from Streptococcus pyogenes that appears to have
the identical function as your protein. In fact, the primary structure of the S. pyogenes protein is
identical to the S. aureus protein. Does this mean that the genes for these two proteins are identical in
Staphylococcus aureus and Streptococcus pyogenes? Explain your answer.
2. What is the effect of DNA mutation on protein sequence?
3. In sickle-cell disease, the replacement of A by T at the 17th nucleotide of the gene for the beta
chain of hemoglobin changes the mRNA codon as shown below (in red).
Wild-type mRNA 5’… A C U C C U G A G G A G…
Sickle-cell mRNA 5’… A C U C C U G U G G A G….
a. What amino acids are encoded by the two mRNAs?
Wild-type amino acids:
Sickle-cell amino acids:
b. What kind of mutation does this cause in the protein?
Bio 241 Quiz #3 March 22, 2018
Print First and Last Name _______________________________________
I. Multiple Choice: Read each question carefully and select the one best answer for each
question. Write your answer using CAPITAL LETTERS on the line in front of each question.
Questions will be counted wrong if the answer is not written on the line. (1 point each)
_____1. Which of the following is incorrect?
A. RNA polymerase – makes a molecule of RNA from an RNA template
B. DNA polymerase – makes a molecule of DNA from a DNA template
C. DNA ligase – joins segments of DNA
D. DNA gyrase (topoisomerase) – releases overwinding strain and untwists DNA
E. All of the above are correct.
_____2. A nucleotide is
A. a five-carbon sugar, a phosphate group and a nitrogen-containing base
B. a sugar with an attached base containing nitrogen
C. a six-carbon sugar, a phosphate group and a nitrogen-containing base
D. a nitrogen-containing base with an attached five-carbon sugar
E. A is correct for DNA and C is correct for RNA
_____3. In DNA synthesis, the primer is synthesized by
A. RNA polymerase
B. DNA polymerase I
C. DNA polymerase III
D. Helicase
E. DNA gyrase
...
DNA POLYMERASE
DNA polymerases are a group of enzymes that are used to make copies of DNA templates, essentially used in DNA replication mechanisms. These enzymes make new copies of DNA from existing templates and also function by repairing the synthesized DNA to prevent mutations. DNA polymerase catalyzes the formation of the phosphodiester bond which makes up the backbone of DNA molecules. It uses a magnesium ion in catalytic activity to balance the charge from the phosphate group.
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Central Dogma Assignment Print Name ________________.docx
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Print Name ___________________________________________
Directions: Complete this worksheet after listening to the Central Dogma recorded lecture posted
on Blackboard. Each student will turn in his/her individual worksheet at the beginning of class.
COMPLETE THE TABLE. LABEL YOUR 5’ AND 3’ ENDS.
YOU MUST GET THE ENTIRE TABLE CORRECT FOR CREDIT. NO PARTIAL CREDIT.
DNA template (-) 5’ GTACTATTAATT TACTGGGTGCAT CCGCATGGTACG 3’
DNA coding (+) strand
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identical to the S. aureus protein. Does this mean that the genes for these two proteins are identical in
Staphylococcus aureus and Streptococcus pyogenes? Explain your answer.
2. What is the effect of DNA mutation on protein sequence?
3. In sickle-cell disease, the replacement of A by T at the 17th nucleotide of the gene for the beta
chain of hemoglobin changes the mRNA codon as shown below (in red).
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Wild-type amino acids:
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Print First and Last Name _______________________________________
I. Multiple Choice: Read each question carefully and select the one best answer for each
question. Write your answer using CAPITAL LETTERS on the line in front of each question.
Questions will be counted wrong if the answer is not written on the line. (1 point each)
_____1. Which of the following is incorrect?
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_____2. A nucleotide is
A. a five-carbon sugar, a phosphate group and a nitrogen-containing base
B. a sugar with an attached base containing nitrogen
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_____3. In DNA synthesis, the primer is synthesized by
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...
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DNA polymerases are a group of enzymes that are used to make copies of DNA templates, essentially used in DNA replication mechanisms. These enzymes make new copies of DNA from existing templates and also function by repairing the synthesized DNA to prevent mutations. DNA polymerase catalyzes the formation of the phosphodiester bond which makes up the backbone of DNA molecules. It uses a magnesium ion in catalytic activity to balance the charge from the phosphate group.
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Astronomers were able to find a new planet in a far away solar system.pdf
Astronomers were able to find a new planet in a far away solar system. They are calling this
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Solution
def nova(st):
st = list(st)
for i in range(0,len(st)):
if st[i] == \'z\':
st[i] = \'a\'
elif st[i] == \'Z\':
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else:
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return \'\'.join(str(i) for i in st).
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Healthcare is arguably the most complex of the complex,sociotechnical systems studied by the
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Astronomers were able to find a new planet in a far away solar system. They are calling this
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speak in a strange language. Thankfully, a scientist was able to decode their language to English.
He found that they also use the same letters as English, but they swap each pair of consecutive
alphabets in English. For example, they swap A with B and Y with Z. Create a function that
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Solution
def nova(st):
st = list(st)
for i in range(0,len(st)):
if st[i] == \'z\':
st[i] = \'a\'
elif st[i] == \'Z\':
st[i] = \'A\'
else:
st[i] = chr(ord(st[i])+1)
return \'\'.join(str(i) for i in st).
5. If we found AB+ blood at a crime scene and we knew one of our 5 s.pdf
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suspect now a lead suspect. Why or Why not? Use Punnett squares to make your case. What
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crime scene we find the murder’s baseball cap without blood, a pair of stained underwear no
blood, no fingerprints, no fibers, no hairs. Based on these items, do we have any possible
chemical, or immunological or other analyses we can perform that will identify the murderer as it
relates to the genotypic info we have on him or her. If so how would you go about doing those
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Solution
5. ANS:
No, At first the D antigen additional test would need to be performed. It is because AB+ is the
most common blood group and the the perp would have to be either Dd or DD (Rh+ve). we
could only really use the evidence to exclude suspects.
6. ANS:
In this case the blood strains are not there. Genetic material on it and use that to identify the
genotype is the best way to detects suspect. So genotyping performing will identify the murderer.
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households try to claim Sydnee, who is entitled to do so?
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out. Then, in November, Kelly married Austin (29), and Sydnee moved in with Kelly and Austin,
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households try to claim Sydnee, who is entitled to do so?
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households try to claim Sydnee, who is entitled to do so?
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households try to claim Sydnee, who is entitled to do so?
Solution
According to the law passes in April,\"Parent paying child support
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Blossom Company had these transactions during the current period..pdf
Blossom Company had these transactions during the current period.
Nov. 28June 12Issued 78,000 shares of $1 par value common stock for cash of $292,500.July
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Equity Paid-in-Capital Retained Earnings Cash +Common Stock+ PIC in Excess of Pa +Pref.
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Using the case study below, develop a written report of your market analysis. Include a visual
diagram of your overall market analysis use of strategic thinking maps (see diagram in the
Module) as a tool to assist with the different facets of the strategic planning process.
The map is to be used as a supplement for your written market analysis. The market analysis
produced will be used in the final submission of your Capstone Project.
Your well-written market analysis should meet the following requirements:
Be 3-4 pages in length, not including the cover, abstract (optional), or reference pages.
Utilize headings to organize the content.
Include the strategic thinking map in addition to/or as a part of the 3-4 pages of content.
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The circumstances in Pocahontas County resonate in many rural communities across the country:
• A depressed local economy
• Substantial barriers to health access
• Difficulty in attracting health professionals.
Portrait of Pocahontas County
Pocahontas County is located in the southeast region of West Virginia. The county has a total of
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River, Elk River, Ganley River, Greenbriar River, Tygart Valley River, Williams River, and
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Bartow, Buckeye, Cass, Dunmore, Durbin, Greenbank, Hillsboro, Marlington, and Slatyfork.
As of the 2010 Census there are 9,131 people residing in Pocahontas County. The racial makeup
is 98% Caucasian, .78% African American, .43% Hispanic, .14% Asian, and .07% Native
American. The median income for a household within the county is $26,401.
Access to Health Services
Pocahontas County has a shortage of healthcare providers. There is one hospital, Pocahontas
Memorial Hospital, and one nursing home, Pocahontas Center. The ratio for dentists is 8,851 to
1. The ratio for primary care physicians is 8508 to 1 (County Health Roadmaps & Rankings,
n.d.). The county’s physician-to-population ratio is significantly higher than the Unites States
overall ratio.
Pocahontas Memorial Hospital is a 25-bed, level-4 trauma center. A rural health clinic is located
within the hospital. The health clinic offers laboratory services, immunizations, disease
management, and monthly specialty clinics (cardiology, podiatry, and nephrology).
For more information about Pocahontas Memorial Hospital, visit the following website:
http://www.pmhwv.org/
Solution
Health care Limitations
Executive summary
The health care industry which is also known as the health economy or the medical industry is a
broad industry which specializes in the delivery of services regarding treatment of diseases,
conducting diagnostic services and therapies to identify various diseases so at to understand the
kind of treatment to be subjected to such diseases (World Health Organization. (2002). the
industr.
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B. contains an origin of replication.
C. has a site for inserting foreign DNA.
D. integrates into the host chromosome.
E. has lacZ gene at the insertion site
Solution
D. integrates into the host chromosome.
a vector is a DNA molecule that is used as a vehivle for the introduction of foreign genetic
material in the cell.Most commonly used vectors are plasmids,cosnids,viral vectors.Some
features that are common to all vectors are origin of replication,multicloning site and a selectable
marker system.A vector replicates autonomously irrespective of the replication of host DNA.A
vector does not integrate into the host chromosome..
What is the evolutionary significance of the amniotic egg Solut.pdf
What is the evolutionary significance of the amniotic egg?
Solution
The fluid in the sac keeps the embryo moist. Birds, reptiles, and mammals have amniotic eggs.
Because amphibian eggs don\'t have an amnion, the eggs would dry out if they were laid on the
land, so amphibians lay their eggs in water. The larvae of most amphibians have gills and look
like fish when they are born..
What is the role of HTTP What types of objects are transmitted in H.pdf
What is the role of HTTP? What types of objects are transmitted in HTTP? Is HTML part of the
HTTP specification?
Solution
Hyper Text Transfer Protocol defines a set of rules that 2 entities namely Client and Server need
to follow while communicating with each other. It is a application layer protocol. This protocol
is based on Client and Server. Client is someone who needs something from web while server is
something who needs to listen to what Client wants and then need to send appropriate response.
Role of HTTP :
1. It allows Client/User to send request for any content that is available in web Server.
2. It provides authentication mechanisms like basic access authentication and digest access
authentication .
3. It allows the seamless transmission of Hyper Text from Server to Client and vice versa.
4. It allows persistent connections as well where a connection could be reused for more than one
request.
Objects Transmitted-
1. Request message - It is a command which Client sends to server which determines the content
wants to access.
Format - GET HTTP version
Example- GET /index.html/hello.jpg HTTP/1.1
2. Response Message - The server send a response to client request if the requested content is
available with it.
Format -
a) A status line which includes the status code and reason message (e.g., HTTP/1.1 200 OK,
which indicates that the client\'s request succeeded).
b) Response header fields (e.g., Content-Type: text/html).
c) An optional message body.
Example-
No, HTML is not a part of HTTP Specification..
What is the difference between a hash in perl and a hashtable in Jav.pdf
What is the difference between a hash in perl and a hashtable in Java? What are some concrete
examples?
Solution
There are lot of differece between hash in perl and hashtable in java
concrete Examples:
1) Insertion is done using a put method in java. It is done directly in perl
In Java: data.put(\'John Paul\',45)
In Perl; $data{\'John Paul\'} = 45;
2) In Java We have to specify datatypes of key and value before hand while defing the hashtable
variable. It is not necessary in perl..
What are the specific linkages among immune surveillance, clonal sel.pdf
What are the specific linkages among immune surveillance, clonal selection, and lymph nodes?
Solution
Immune Surveillance - A hypothesis that the immune system perceives and pulverizes tumor
cells that are continually emerging amid the life of the person. A body component by which early
growths are recognized as being strange and are assaulted and typically pulverised. Immune
Surveillance is a process in which a T cell-intervened handle without which tumor would be
much ordinary.
The immune sytem can distinguish and crush rising cancer cells since it perceives strange
antigens on the cell surface as \'foreign substance\' or outsider. Since outside substances are
typically risky to the body, the immune system is customised to demolish them. This consistent
checking of the body for little tumors is immune surveillance. The immune surveillance of living
body is known to work in the dismissal of tumor cells in people with inherited nonpolyposis
colon growth, likewise called Lynch disorder. Those people acquire a broken DNA confound
repair framework and as an outcome deliver numerous mutant proteins. At the point when such
mutant proteins show up on the surface of tumor cells, they are perceived as foriegn and rejected.
Tumors that do rise are those that have figured out how to sidestep the body\'s immune system.
Lymph nodes are Bean Shaped and encapsulated antigen gathering tissues that channel lymph
and permit lymphocytes to test antigens gained from skin, GI tract and respiratory tract
- deliberately situated all through body, bolstered by reticular system of follicular DCs and
macrophages
- lymphocytes enter from blood crosswise over high endothelial venules and from the
interconnected lymphatic vessels; B cells relocate to the cortex and immune system
microorganisms move to paracortical area; plasma move to medulla and emit counter acting
agent
- DCs with antigen enter from lymphatic vessel; T cells and DCs reach each other the T cell tests
the antigens in setting of the MHC on the DC; enacted T cells leaves lymph hubs and enter the
blood to site of contamination.
Clonal Selection - Clonal selecction is a hypothesis clarifying how the cells of the immune
system deliver vast amounts of the correct counter acting agent at the ideal time, in the sense, at
the point when the proper antigen is experienced. It suggests that there is a previous pool of
lymphocytes i.e B cells comprising of various little subsets. Every subset conveys a one of a kind
arrangement of surface counter acting agent atoms with its own specific restricting qualities. In
the event that a cell experiences and ties the comparing antigen it is `selected\' – empowered to
partition more than once and deliver a substantial clone of indistinguishable cells, all emitting the
counter acting agent. The contribution of aide T cells is basic for actuation of the B cell. A type
of clonal determination is additionally summoned to clarify the improvement of immunological
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True or False –
Paraeducators provide direct or indirect instructional and other services to students under the
supervision of a lead paraeducator.
Solution
it is true
Roles And Responsibilities Of Paraeducators
Over the years, the roles and responsibilities of paraeducators have become more complex and
have expanded to include numerous aspects of the educational process for studentswith
disabilities (Drecktrah, 2000; French & Pickett, 1997; Pickett, 1999). In practice, the dutiesof a
paraeducator may include, but are not limited to:
•
providing direct and small group instruction
•
adapting and modifying curriculum
•
monitoring student behavior
•
communicating with parents and families (many believe this should not reflect the role
of paraeducators)
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performing clerical duties, and
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providing personal care.
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The situation where \"the few who yell the loudest get heard\" Is referred to as the Multiple
Choice special-interest effect. principal-agent problem. moral hazard problem.
Solution
Answer:- the situation where the few who yell the loudest gets heard is referred to as the
Correct Answer:- Special interest effect
Reason:- “the special interest effect,” explains why, over time, the legislative process tends to
generate more expansive government..
Templated Binary Tree implementing function help I need to im.pdf
\"Templated Binary Tree\" implementing function help ?
I need to implement header file which i am working on.
Void expandExternal and void preorder part :
1. Header File :
#ifndef BINARYTREE_H
#define BINARYTREE_H
#include
////////////////////////////////////
// Templated Node Interface
///////////////////////////////////
template // base element type
class Node { // a node of the tree
public:
Node() : elt(), par(NULL), left(NULL), right(NULL) { } // constructor
private:
E elt; // element value
Node* par; // parent
Node* left; // left child
Node* right; // right child
template friend class BinaryTree;
template friend class Position;
};
////////////////////////////////////
// Templated Binary Tree Interface
///////////////////////////////////
template // base element type
class BinaryTree
{
public: // public types
//Defines a node position
class Position
{
public:
Position(Node * _v = NULL) : v(_v) { } // constructor
//Returns the element at the position
E& operator*()
{
return v->elt;
}
//Returns a Position object
Position left() const // get left child
{
return Position(v->left);
}
//Returns a Position object
Position right() const // get right child
{
return Position(v->right);
}
//Returns a Position object
Position parent() const // get parent
{
return Position(v->par);
}
//Returns true or false
bool isRoot() const // root of tree?
{
return v->par == NULL;
}
//Returns true or false
bool isExternal() const // an external node?
{
return v->left == NULL && v->right == NULL;
}
//Returns true or false
bool isInternal() const // an external node?
{
return ! isExternal();
}
private:
Node* v;
template friend class BinaryTree;
};//End Position class definition
/* Position List type definition*/
typedef std::list PositionList;
public: //Binary member functions
BinaryTree() : _root(NULL), n(0) { }
~BinaryTree(); // The destructor need to properly deletes all nodes in the tree to prevent
memory leaks.
int size() const; // Returns and integer tof the number of nodes.
bool empty() const; // Returns a true if the tree is empty else false.
Position root() const; // Return the position of the root node.
void addRoot(); // Creates and adds the initial root node to the tree this must be added first.
void expandExternal(const Position& p); //Expands each external node with a left and right
child that are empty.
// What goes here?
PositionList positions() const; // Returns a std:list of the nodes in the tree call preorder()
function.
void preorder(Node* v, PositionList& pl) const; // Traversal algorithm for the tree to populate
the PositionList
// What goes here?
private:
Node * _root; // pointer to the root
int n; // number of nodes
};
#endif
Thank you
Solution
for the main function, try writing the code like this :
struct Node{
Comparable element;
Node *left;
Node *right;
Node(const Comparable & theElement, Node *lt, Node *rt )
: element( theElement ), left( lt ), right( rt ) {}
}; // Node{}
Node *root;
Node * findMin( Node *t ) const;
Node * findMax( Node *.
State if you agree or disagree with the question and comments made b.pdf
State if you agree or disagree with the question and comments made below and why?
Does Maryland’s new social media campaign rule go far enough to validate who is posting the
political information on social media? Maryland has begun a great new way of identifying
political advertisers support of particular politicians. But, this may not do everything that it needs
to do in order to validate who is behind the postings or what is the motivation of the poster. If a
political poster wished to disguise themselves and pretend to support a particular candidate, he or
she could easily tag the advertisement with the legally required statement but still not be
affiliated with the campaign they are supporting. This law would need to be broadened to include
campaign-assuming responsibility for monitoring or approving any post made in their name. In
order to achieve this goal, campaigns would need huge numbers of paid and volunteer team
members just to monitor social media. Otherwise, social media, such as Facebook and Twitter,
would need to have to take more responsibility for the IP addresses they allow to advertise on
their platforms. Since this is a new legal development, it will need to be fine-tuned in order to
protect the public from scammers.
Solution
With the emergence of social media networking being used to advertising in every field, the
same has been done by the political advertisers. With this grew the forgery in the posts that were
made in the name of political parties. So Maryland levied this law in which the political
advertisers will have to identify their political campaign material before posting it on social
media and can post it following set rules and guidelines.
In the above matter it is mentioned that these rules will not eradicate the issue of false
advertising totally as the political poster can be disguised and pretend to support a particular
candidate. Tagging the advertisement with a legally required statement can be done even though
they may not be affiliated with the campaign they are showing support for. To overcome this
forgery ways will have to be found out to monitor and approve any post made in the name of a
candidate or party by the party or candidates. For this special team members will have to be hired
to keep a monitoring eye on the posts on social media. Also the social media can help by keeping
a track of all the IP addresses they allow for the advertisements done ussing their platforms.
These steps are essential to be taken in the political advertising campaigns as they will help
erasing the false advertising in the names of political parties and make social media a trusted and
genuine platform for such advertising..
A number of benefits that one might expect to see from using a datab.pdf
A number of benefits that one might expect to see from using a database such as MySQL. List
four of these benefits and in your own words describe the benefit.
Solution
Some of the benefits are:
Heavily Supported: It supports software on a variety of platforms and operating systems
including Windows, Linux, Novell NetWare, UNIX and more.
Secure: It help solid data security layers to safeguard sensitive data from outside access. All
passwords used to entry the MySQL database are encrypted.
Fast: When compared to other database software MySQL is much agile in terms of performance,
and users still have approach to all the required features they would through other database
platforms.
Data Storage is Scalable: MySQL can handle a overall file size limit of about 4GB, however, this
can be enlarged to meet our needs – by as much as 8TB of data.
Manages Memory: The database software has been shown to guide memory vastly well and
prevents memory leaks which we might experience on a server where it’s not deployed..
QUESTION If you look at the code, youll see that we keep two list.pdf
QUESTION: If you look at the code, you\'ll see that we keep two lists, one to print the text in
forward order, and one to print the text in reverse order. The forward one is using our empty
add() function, so nothing gets put into it. You\'ll fix that, as well as modifiying insert() and
erase(). The reverse on works by inserting always at the head of the list, like a Stack.Functions
insert(), erase(), and add() must be modified so that if the last node of the list changes, List::last
must change, as well. YOU JUST HAVE TO COMPLETE THE LIST.CPP FILE SO THAT IT
PRINTS THE OUTPUT IN THE FORWARD ORDER.FINISH THE CODE ONLY IN
LIST.CPP FILE AND OTHER FILES ARE JUST FOR REFERENCE. MORE
INFORMATION AND HINTS ARE GIVEN IN THE COMMENTS IN LIST.CPP FILE.
HINT: AFTER the existing code runs, there\'s an easy way to know if you just changed the last
node in the list; if you did, it\'s time to update the \"last\" pointer. And remember that \'add\'-ing
the first item is a special case. We could make a Linked List behave a lot like a Queue if it were
really efficient to add a node at the end of the list, that is, without having to chase links from the
head to the tail. So we will add another pointer to our List class that will always point at the last
item in the list. Read the existing code carefully and understand how it works. The \"add\"
function is now empty. If you run the file you should get an output that starts out like this:
?CURRENT LIST.CPP:
CURRENT OUTPUT:
MAIN.CPP FILE:
LIST.H FILE: include list include
Solution
PROGRAM CODE:
/*
* List.cpp
*
* Created on: 29-Nov-2016
* Author: kasturi
*/
#include \"List.h\"
#include
#include
#include
using namespace std;
void List::insert(ElemetType item, int position)
{
Node * predptr = first;
for(int i=1; i< position && predptr && predptr->next; i++)
{
predptr = predptr->next;
}
Node * newptr = new Node;
newptr->payload = item;
if(!predptr)
{
newptr->next = 0;
first = newptr;
}
else if(position == 0)
{
newptr->next = first;
first = newptr;
}
else
{
newptr->next = predptr->next;
predptr->next = newptr;
}
}
void List::erase(int position)
{
Node * predptr = first;
for(int i=1; inext; i++)
{
predptr = predptr->next;
}
if(!predptr)
{
}
else if(position == 1)
{
first = predptr->next;
delete predptr;
}
else
{
Node *ptr = predptr->next;
predptr->next = ptr->next;
delete ptr;
}
}
void List::display(ostream& ostr)
{
Node * ptr = last; //changed the display function to print the first
while(ptr)
{
ostr<payload<next;
}
}
List::List()
{
first = 0;
last = 0;
}
List::~List()
{
while(first)
{
Node *nxt = first->next;
delete first;
first = nxt;
}
}
void List::add(ElemetType item)
{
//added code to add values into the last node
Node * predptr = last;
Node *newptr = new Node;
newptr->payload= item;
while( predptr && predptr->next)
{
predptr = predptr->next;
}
if(!predptr)
{
newptr->next = 0;
last = newptr;
}
else
{
newptr->next = predptr->next;
predptr->next = newptr;
}
}
OUTPUT:
Forward:
The
quick
brown
fox
jumped
over
the
back.
Question 11 What is the volume of 17.0 grams of carbon dioxide gas if.pdf
Question 11 What is the volume of 17.0 grams of carbon dioxide gas if its pressure is 568 Torr
and its temperature is 25 degrees Celsius? 4.2L O120.8 8.4 L 12.7L
Solution
Mole of carbon dioxide= mass/molar mass
Molar mass of co2 =44g/mol
Mole = 17/44=0.386 mole
We use pv=nrt
Pressure=568 torr. = 0.747 atm
R = 0.08206atm.L/mol.k
0.747*V= 0.386*0.07206*298
Volume=12.7 L.
Please help with this. program must be written in C# .. All of the g.pdf
Please help with this. program must be written in C# .. All of the game logic must be written in a
seperate class using using an array that is passed in through a prperty that represents the game
board. The class needs to have methods to determine of someone won, or if there was a tie,
make sure all business logic is in a seperate class anot behind the UI..
***** These are the complete in instructions for the game assignment design
Create a Tic-Tac-Toe game that can be played by two players. The form will consist of a Tic-
Tac-Toe board in which the users’ click on to choose their space. As the game is being played
the Game Status section will tell whose turn it is. When someone wins or there is a tie, a message
will be displayed in the Game status section telling the users the status. When someone wins the
game the winning move needs to be indicated. There also needs to be a section that keeps track
of the number of wins for each player, and the number of ties. When the game is finished the
user may click the “Start Game” button to start a new game.
This program will consist of the main form and at least one class that will define the rules of the
game. This class will have an array that is passed in through a property that represents the game
board. The class will then have methods within it that determines if someone won, if there is a
tie, or if neither has occurred yet. Make sure all business logic is in a separate class and not
behind the UI.
EXTRA CREDIT (10 Points)
Create a computer player that can be played against. The computer player will need to be smart
enough to make a winning move or to block a winning move.
Solution
using System;
using System.Collections.Generic;
using System.Drawing;
using System.Windows.Forms;
namespace Tic_Tac_Toe
{
///
/// Description of MainForm.
///
public partial class MainForm : Form
{
Logic logicObj = new Logic();
public MainForm()
{
//
// The InitializeComponent() call is required for Windows Forms designer support.
//
InitializeComponent();
//
// TODO: Add constructor code after the InitializeComponent() call.
//
}
int turn=1;
int click1=0,click2=0,click3=0,click4=0,click5=0,click6=0,click7=0,click8=0,click9=0;
int player1=0,player2=0;
void Button1Click(object sender, EventArgs e)
{
if(click1==0)
{
if(turn%2!=0)
{
button1.Text=\"X\";
click1++;
}
else
{
button1.Text=\"O\";
click1++;
}
turn++;
}
else
{
button1.Text=button1.Text;
}
display();
int a = logicObj.winLossFunc(button1.Text, button2.Text, button3.Text, button4.Text,
button5.Text, button6.Text, button7.Text, button8.Text, button9.Text);
if (a==1)
{
player1++;
player1score.Text = player1.ToString();
cleargame();
}
else if(a==2)
{
player2++;
player2score.Text = player2.ToString();
cleargame();
}
}
void Button2Click(object sender, EventArgs e)
{
if(click2==0)
{
if(turn%2!=0)
{
button2.Text=\"X\";
click2++;
}
else
{
button2.Text=\"O\";
click2++;
}
turn++;
}
else
{
button2.Text=button2.Text;
}
display();
int a = logicObj.winLossFunc(button1.Text, b.
Introduction to Engineering ExperimentationSurface temperature con.pdf
Introduction to Engineering Experimentation
Surface temperature conduction error of a thermal probe...(more than one answer may be correct)
a. is systematic
b. is random
c. will produce a lower reading (assuming the surface is hotter than the surroundings)
d. will produce a higher reading
Solution
answer is C and D.
Systematic errors are situation dependent.
sometimes poor probe design or bad installation can easily give a system significant temperature
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Match the enzyme activity in DNA synthesis with its function. DNA po.pdf
- 1. Match the enzyme activity in DNA synthesis with its function. DNA pol III (_) fragments Helicase (_) Primase (_) using template strand DNA pol I (_) double helix DNA ligase (_) adds nucleotides Topoisomerase (_) primer A. anneals DNA B. relieves overwinding C. adds nucleotides D. unwinds parental E. removes RNA primer, F. adds a short RNA 10 Proofreading and repair of the DNA double helix does NOT involves a. detecting a mis-match in base pairs. b. removing the mis-match with a nuclease. c. annealing the Okazaki fragments together with DNA ligase. d. repairing the mis-match with polymerase. e. annealing the edited DNA with the rest of the molecule with ligase. Solution 4. DNA Pol III- (C)- DNA polymerase III is the primary enzyme involved in DNA replication which adds nucleotides to the 3' end of the forming DNA strand during replication. 5. Helicase- (D)- Helicases are enzymes that separates double-stranded DNA into single strands allowing each strand to be copied. 6. Primase- (F)- Primase functions by synthesizing short RNA sequences that are complementary to a single-stranded DNA. 7. DNA Pol I- (E)- DNA polymerase-I fills in the necessary nucleotides between the Okazaki fragments in a 5'3' direction. 8. DNA ligase- (A)- DNA ligases are essential for the joining of DNA fragments during replication. 9. Topoisomerase- (B)-Topoisomerases are enzymes that participate in the overwinding or underwinding of DNA. 10. Okazaki fragments are only formed during DNA replication and not observed during DNA proof reading and repair. Therefore answer is (C)