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1
M01 L01: Pre-requisites
2. Mathematica
1. GeoGebra
3. MATLAB
GeoGebra is an interactive geometry, algebra,
statistics and calculus application and available on
multiple platforms, with apps for desktops, tablets
and web. It’s a freeware and many of the
assignments will be in GeoGebra.
Mathematica and MATLAB will be useful for
understanding the Linear Algebra and Calculus in
more interactive way. IIT Guwahati provide
licenses of these software and Many of the
assignments will be in MATL5AB and
Mathematica.
YOU HAVE TO USE THESE SOFTWARE WITHOUT ANY EXCUSE
M01: Linear Algebra, L01: Fundamentals of Vectors
Course Instructor
Dr. Sajan Kapil
Department of Mechanical Engineering
Indian Institute of Technology, Guwahati
Guwahati, Assam
ME 501
IIT Guwahati
Advanced Engineering Mathematics (3−0−0−6)
3
M01 L01: Contents
 Perspective of Vectors
 Geometry of Vectors
 Vector as Arrow
 Vectors as Coordinates
 Vectors in 𝑹𝒏
 Fundamental Vector Operations
 Vector Addition
 Scalar Multiplication
 Basis Vectors
 Linear Combination of Vectors
 Linear Span of 2D Vectors
 Linear Span of 3D Vectors
4
5
M01 L01: Geometry of Vector
A vector is a term that refers colloquially to some quantities that cannot be expressed by a single number,
OR to elements of some vector spaces.
Displacement, Velocity, Acceleration, Force, Momentum
A vector quantity is defined as the physical quantity that has both directions as well as magnitude.
Vector as Arrow
A
B
X
Y
O
Tail
Head
A
B
X
Y
O
Z
𝐴𝐵 vector in 2D
Coordinate system
Or
XY Cartesian plane
𝐴𝐵 vector in 3D
Coordinate system
6
M01 L01: Perspective of Vector
𝐕
𝑽𝒙
𝑽𝒚
𝑽𝒛
Physics Student Math's Student Computer Science Student
The mathematics perspective is more ABSTRACT. A
vector space over a field F is a set V together with
two binary operations that satisfy the eight
axioms. The elements of V are commonly called
vectors, and the elements of F are called scalars.
This perspective will be considered after a few
lectures.
2D Arrow or 3D Arrows
Ordered list of Numbers
7
M01 L01: Vector as Coordinates
It is also obvious that the 3D vectors
can be also be represented in the 3D
coordinate system as:
𝐚 = 𝑶𝑨 =
𝒂𝒙
𝒂𝒚
𝒂𝒛
𝟓
𝟓
𝟏𝟎
8
M01 L01: Vector as Arrow
A
B
X
Y
O
X
Y
O
A
𝐚
𝑂𝐵
𝑂𝐹
𝑂𝐷
𝑂𝐻
𝑂𝐸
𝑂𝐼 𝑂𝐺
𝑂𝐶
Origin of the 2D Coordinate system
Standard Vector: with tail sitting on the origin
9
M01 L01: Vector as Coordinates
X
Y
ax
ay
O
A
𝐚
𝑂𝐵
𝑂𝐹
𝑂𝐷
𝑂𝐻
𝑂𝐸
𝑂𝐼 𝑂𝐺
𝑂𝐶
𝐚 = 𝑶𝑨 = [𝐚𝐱, 𝐚𝐲]
𝐚𝐱, 𝐚𝐲 ≠ 𝒂𝒚, 𝒂𝒙
The individual coordinate
of the vector is called as
component.
Vectors may also be called as
ordered list of numbers.
It is also more convenient to write the
components in column instead of row. This
helps in further computation of the vectors.
𝐚 = 𝑶𝑨 =
𝒂𝒙
𝒂𝒚
and obviously:
𝒂𝒙
𝒂𝒚
≠
𝒂𝒚
𝒂𝒙
𝐛 =
𝟓
𝟒
𝐟 =
𝟑
𝟕
𝐝 =
−𝟒
𝟓
𝐡 =
−𝟓
𝟐
𝐄 =
−𝟏
−𝟏
𝐈 =
−𝟏
−𝟒
𝐠 =
𝟑
−𝟒
𝐠 =
𝟔
−𝟑
10
M01 L01: Vectors in ℝ𝑛
In order to first understand the illustration of Linear Algebra, we shall keep the current discussion
limited to ℝ𝟐 and ℝ𝟑 and extend the same analogy after a few lectures.
11
M01 L01: Vector (Operations)
Linear algebra revolve around two fundamental operations:
1. Vector Addition
2. Scalar multiplication
This is an abstract perspective of mathematicians
and hence will be explained after a few lectures.
Why only these two operations are chosen by mathematicians ?
12
M01 L01: Vector Addition
y
x
𝑨 + 𝑩
𝑨
𝑩
13
M01 L01: Vector Addition
y
x
𝑨 + 𝑩
𝑨 𝑩
𝑪
Why moving a vector in the space like this is correct ?
14
M01 L01: Vector Addition
y
x
𝑨 + 𝑩
𝑨
Why this method of vector addition is wrong ?
Wrong
𝑩
𝑪
15
M01 L01: Vector Addition
y
x
3
3
+
6
−4
9
−1
3
3
-1+4=3
1
4
-1+4=?
1 4
1+4=? 1+4=5
Do you have answers to the last two question ?
(3 − 4)
(3 + 6)
𝑨
𝑩
𝑪
𝑨 + 𝑩
3
3
+
6
−4
=
3 + 6
3 − 4
=
9
−1
𝑨 + 𝑩 = 𝑪
𝒙𝟏
𝒚𝟏
+
𝒙𝟐
𝒚𝟐
=
𝒙𝟏 + 𝒙𝟐
𝒚𝟏 + 𝒚𝟐
-4
6
16
Vector Scalar Multiplication
y
x
𝑨
−𝟐𝑨
Scaling  Scalars
𝟐𝑨
𝒂𝒙
𝒂𝒚
𝟐𝒂𝒙
𝟐𝒂𝒚
−𝟐𝒂𝒚
−𝟐𝒂𝒙
Multiplying with numbers is basically
flipping and scaling a vector. Hence this
number is called as scalar.
Numerically:
𝑐𝐴 = c
𝑎𝑥
𝑎𝑦
=
𝑐 × 𝑎𝑥
𝑐 × 𝑎𝑦
So we have understood the two
fundamental operations in vectors i.e.
scalar multiplication and vector
addition.
17
Vector: Basis Vectors
y
x
(𝟓)
𝑨
(−𝟖)
5
−8
𝑖
𝑗
5𝑖
−8𝑗
𝑨 = (𝟓) × 𝒊 + −𝟖 × 𝒋
Scalar multiplication
Vector Addition
If there are two vectors 𝑖 and 𝑗 with a
unit length. Vector 𝑖 is along the 𝑥-axis
and vector 𝑗 is along the 𝑦-axis. Then any
vector in the 𝑥𝑦 plane can be represented
by (a linear combination of) using 𝑖 and 𝑗
vector with appropriate scalar
multiplication and vector addition.
𝑖 and 𝑗 are called as basis vectors of the
𝒙𝒚 coordinate system.
Can we represent any vector in the
𝑥𝑦 plane using the aforesaid two
operations and two fundamental
vectors ?
18
Vector: Basis Vectors
𝑣
𝑤
The answer is yes but its not a standard
way of doing it as one may not choose
same basis vectors and hence we can not
be on the same page.
Can we choose some different Basis vectors and still able to define each vector in the plane by (a linear combination
of) using those different basis vectors (𝒗 and 𝒘) with two operations viz., scalar multiplication and vector addition.
If so, it will be a new coordinate system.
𝑣
𝑢
P
2𝑣
1.5𝑤
𝑣 + 𝑤
2𝑣 + 1.5𝑤
1
1
2
1.5
19
Vector: Basis Vectors
𝑣
𝑤
The answer is yes but its not a standard
way of doing it as one may not choose
same basis vectors and hence we can not
be on the same page.
Can we choose some different Basis vectors and still able to define each vector in the plane by (a linear combination
of) using those different basis vectors (𝒗 and 𝒘) with two operations viz., scalar multiplication and vector addition.
If so, it will be a new coordinate system.
2𝑣
1.5𝑤
𝑣 + 𝑤
2𝑣 + 1.5𝑤
1
1
2
1.5
𝑖
𝑗
10𝑖 + 4.5𝑗
10
4.5
≠
Just like:
𝟏𝟎𝟏𝟐 ≠ 𝟏𝟎𝟏𝟏𝟎
So, in this course, if you see a vector
𝑎𝑥
𝑎𝑦
and no specific base of the
vector is mentioned then you will
consider 𝑥 and 𝑦 axes as base vector
𝑣
𝑢
P
20
Paradox:
Statement: ‘101’ is a number in base ‘10’
Is the base of this number ‘10’
Is the base of this number ‘10’
Is the base of this number is ‘10’
Importance of Basis Vectors
Vector: Basis Vectors
21
Vector: Linear combination
In mathematics, a linear combination is an expression constructed from a set of terms by multiplying each term by an
scalar and adding the results (e.g. a linear combination of x and y would be an expression of the form of 𝒂𝒙 + 𝒃𝒚,
where a and b are scalar).
Term  Vector
𝒂 𝒗 + 𝒃𝒖
This is a vector which is a linear
combination of vectors 𝑣 & 𝑢
Scalars
22
Vector: Linear combination
Determine whether
4
−1
is a linear combination of
2
3
and
3
1
4
−1
= x1
2
3
+ x2
3
1
If
4
−1
is a linear combination of
2
3
and
3
1
then:
4
−1
=
2x1 + 3x2
3𝑥1 + 𝑥2
2x1 + 3x2 = 4
3𝑥1 + 𝑥2 = −1
2x1 + 3x2 = 4
−9𝑥1 − 3𝑥2 = 3
−7x1 = 7
𝒙𝟏 = −𝟏 𝒙𝟐 = 𝟐
4
−1
= −1 ×
2
3
+ 2 ×
3
1
It’s a unique solution hence
4
−1
is a linear combination of
2
3
and
3
1
23
Vector: Linear combination
24
Vector: Linear combination
Determine whether
−4
−2
is a linear combination of
6
3
and
2
1
−4
−2
= x1
6
3
+ x2
2
1
If
−4
−2
is a linear combination of
6
3
and
2
1
then:
−4
−2
=
6𝑥1 + 2𝑥2
3𝑥1 + 𝑥2
6𝑥1 + 2𝑥2 = −4
3𝑥1 + 𝑥2 = −2
3x1 + x2 = −2
Any combination of 𝑥1and 𝑥2which satisfy the 3x1 + x2 = −2 is a solution, hence there are infinite solutions.
One such solution can be: 𝑥1 = 2 & 𝑥2 = 4, so
−4
−2
= −2 ×
6
3
+ 4 ×
2
1
Therefore:
−4
−2
is a linear combination of
6
3
and
2
1
25
Vector: Linear combination
26
Vector: Linear combination
Determine whether
1
2
is a linear combination of
2
3
and
6
9
1
2
= x1
2
3
+ x2
6
9
If
1
2
is a linear combination of
2
3
and
6
9
then:
1
2
=
2𝑥1 + 6𝑥2
3𝑥1 + 9𝑥2
2𝑥1 + 6𝑥2 = 1
3𝑥1 + 9𝑥2 = 2
Here,
1
3
= 0, hence there are no solutions.
Therefore:
1
2
is NOT a linear combination of
2
3
and
6
9
𝑥1 + 𝑥2 = 1/3
𝑥1 + 𝑥2 = 2/3
27
Vector: Linear combination
28
Vector: Linear combination
Write the vector
1
2
3
as a linear combination of the vectors:
1
0
1
,
1
1
0
&
0
1
1
29
Vector: Linear Span
𝒂 𝒗 + 𝒃𝒖 The span of vector 𝒗 & 𝒖 is the set of all the
linear combinations of vectors 𝒗 & 𝒖
𝑣
𝑢
P
So, basically if 𝑣 and 𝑢 are linearly
independent (𝑣 ≠ 𝑐𝑢) then the span of 𝑣 and 𝑢
will be the entire 2D space.
However, if 𝑣 and 𝑢 are linearly dependent (𝑣 = 𝑐𝑢) then
the span of 𝑣 and 𝑢 will be the entire a line.
𝑣
𝑢 = 𝑐𝑣
𝑖
𝑗
30
Vector: Linear Span
𝒂 𝒗 + 𝒃𝒖
So, basically if 𝑣 and 𝑢 are linearly independent (𝑣 ≠ 𝑐𝑢)
then the span of 𝑣 and 𝑢 will be the entire 2D space.
31
if 𝑣 and 𝑢 are linearly dependent (𝑣 = 𝑐𝑢) then the span of
𝑣 and 𝑢 will be the entire a line.
Vector: Linear Span
𝒂 𝒗 + 𝒃𝒖
32
Vector: Linear Span
It a bad idea to show the span of two vectors (which is a set all the 2D vectors for linearly independent
vectors) to show by ARROWS. Hence it is the time to represent them by points.
33
Vector: Linear Span
34
Vector: Linear Span
35
Vector: Linear Span
36
Vector: Linear Span
𝒂𝒗 + 𝒃𝒖 + 𝒄𝒘
Case 1: 𝒗, 𝒖 and 𝒘 are linearly independent
Demo in Solidworks & GeoGebra
37
Vector: Linear Combinations
38
Vector: Linear Span
𝒂𝒗 + 𝒃𝒖 + 𝒄𝒘
Case 2: 𝒗 is independent to 𝑢, but 𝑢 are 𝑤 linearly dependant
Demo in Solidworks & GeoGebra
39
Vector: Linear Span
𝒂𝒗 + 𝒃𝒖 + 𝒄𝒘
Case 3: 𝑣, 𝑢, and 𝑤 are linearly dependent
Demo in Solidworks & GeoGebra
40
Vector: Basis Vectors
The basis of vector space is a set of linearly independent vectors that span the full
space.
Thank You
Course Instructor
Dr. Sajan Kapil
Department of Mechanical Engineering
Indian Institute of Technology, Guwahati
Guwahati, Assam
ME 501
IIT Guwahati
Advanced Engineering Mathematics (3−0−0−6)

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M01L01 Advance Engineering Mathematics.pptx

  • 1. 1 M01 L01: Pre-requisites 2. Mathematica 1. GeoGebra 3. MATLAB GeoGebra is an interactive geometry, algebra, statistics and calculus application and available on multiple platforms, with apps for desktops, tablets and web. It’s a freeware and many of the assignments will be in GeoGebra. Mathematica and MATLAB will be useful for understanding the Linear Algebra and Calculus in more interactive way. IIT Guwahati provide licenses of these software and Many of the assignments will be in MATL5AB and Mathematica. YOU HAVE TO USE THESE SOFTWARE WITHOUT ANY EXCUSE
  • 2. M01: Linear Algebra, L01: Fundamentals of Vectors Course Instructor Dr. Sajan Kapil Department of Mechanical Engineering Indian Institute of Technology, Guwahati Guwahati, Assam ME 501 IIT Guwahati Advanced Engineering Mathematics (3−0−0−6)
  • 3. 3 M01 L01: Contents  Perspective of Vectors  Geometry of Vectors  Vector as Arrow  Vectors as Coordinates  Vectors in 𝑹𝒏  Fundamental Vector Operations  Vector Addition  Scalar Multiplication  Basis Vectors  Linear Combination of Vectors  Linear Span of 2D Vectors  Linear Span of 3D Vectors
  • 4. 4
  • 5. 5 M01 L01: Geometry of Vector A vector is a term that refers colloquially to some quantities that cannot be expressed by a single number, OR to elements of some vector spaces. Displacement, Velocity, Acceleration, Force, Momentum A vector quantity is defined as the physical quantity that has both directions as well as magnitude. Vector as Arrow A B X Y O Tail Head A B X Y O Z 𝐴𝐵 vector in 2D Coordinate system Or XY Cartesian plane 𝐴𝐵 vector in 3D Coordinate system
  • 6. 6 M01 L01: Perspective of Vector 𝐕 𝑽𝒙 𝑽𝒚 𝑽𝒛 Physics Student Math's Student Computer Science Student The mathematics perspective is more ABSTRACT. A vector space over a field F is a set V together with two binary operations that satisfy the eight axioms. The elements of V are commonly called vectors, and the elements of F are called scalars. This perspective will be considered after a few lectures. 2D Arrow or 3D Arrows Ordered list of Numbers
  • 7. 7 M01 L01: Vector as Coordinates It is also obvious that the 3D vectors can be also be represented in the 3D coordinate system as: 𝐚 = 𝑶𝑨 = 𝒂𝒙 𝒂𝒚 𝒂𝒛 𝟓 𝟓 𝟏𝟎
  • 8. 8 M01 L01: Vector as Arrow A B X Y O X Y O A 𝐚 𝑂𝐵 𝑂𝐹 𝑂𝐷 𝑂𝐻 𝑂𝐸 𝑂𝐼 𝑂𝐺 𝑂𝐶 Origin of the 2D Coordinate system Standard Vector: with tail sitting on the origin
  • 9. 9 M01 L01: Vector as Coordinates X Y ax ay O A 𝐚 𝑂𝐵 𝑂𝐹 𝑂𝐷 𝑂𝐻 𝑂𝐸 𝑂𝐼 𝑂𝐺 𝑂𝐶 𝐚 = 𝑶𝑨 = [𝐚𝐱, 𝐚𝐲] 𝐚𝐱, 𝐚𝐲 ≠ 𝒂𝒚, 𝒂𝒙 The individual coordinate of the vector is called as component. Vectors may also be called as ordered list of numbers. It is also more convenient to write the components in column instead of row. This helps in further computation of the vectors. 𝐚 = 𝑶𝑨 = 𝒂𝒙 𝒂𝒚 and obviously: 𝒂𝒙 𝒂𝒚 ≠ 𝒂𝒚 𝒂𝒙 𝐛 = 𝟓 𝟒 𝐟 = 𝟑 𝟕 𝐝 = −𝟒 𝟓 𝐡 = −𝟓 𝟐 𝐄 = −𝟏 −𝟏 𝐈 = −𝟏 −𝟒 𝐠 = 𝟑 −𝟒 𝐠 = 𝟔 −𝟑
  • 10. 10 M01 L01: Vectors in ℝ𝑛 In order to first understand the illustration of Linear Algebra, we shall keep the current discussion limited to ℝ𝟐 and ℝ𝟑 and extend the same analogy after a few lectures.
  • 11. 11 M01 L01: Vector (Operations) Linear algebra revolve around two fundamental operations: 1. Vector Addition 2. Scalar multiplication This is an abstract perspective of mathematicians and hence will be explained after a few lectures. Why only these two operations are chosen by mathematicians ?
  • 12. 12 M01 L01: Vector Addition y x 𝑨 + 𝑩 𝑨 𝑩
  • 13. 13 M01 L01: Vector Addition y x 𝑨 + 𝑩 𝑨 𝑩 𝑪 Why moving a vector in the space like this is correct ?
  • 14. 14 M01 L01: Vector Addition y x 𝑨 + 𝑩 𝑨 Why this method of vector addition is wrong ? Wrong 𝑩 𝑪
  • 15. 15 M01 L01: Vector Addition y x 3 3 + 6 −4 9 −1 3 3 -1+4=3 1 4 -1+4=? 1 4 1+4=? 1+4=5 Do you have answers to the last two question ? (3 − 4) (3 + 6) 𝑨 𝑩 𝑪 𝑨 + 𝑩 3 3 + 6 −4 = 3 + 6 3 − 4 = 9 −1 𝑨 + 𝑩 = 𝑪 𝒙𝟏 𝒚𝟏 + 𝒙𝟐 𝒚𝟐 = 𝒙𝟏 + 𝒙𝟐 𝒚𝟏 + 𝒚𝟐 -4 6
  • 16. 16 Vector Scalar Multiplication y x 𝑨 −𝟐𝑨 Scaling  Scalars 𝟐𝑨 𝒂𝒙 𝒂𝒚 𝟐𝒂𝒙 𝟐𝒂𝒚 −𝟐𝒂𝒚 −𝟐𝒂𝒙 Multiplying with numbers is basically flipping and scaling a vector. Hence this number is called as scalar. Numerically: 𝑐𝐴 = c 𝑎𝑥 𝑎𝑦 = 𝑐 × 𝑎𝑥 𝑐 × 𝑎𝑦 So we have understood the two fundamental operations in vectors i.e. scalar multiplication and vector addition.
  • 17. 17 Vector: Basis Vectors y x (𝟓) 𝑨 (−𝟖) 5 −8 𝑖 𝑗 5𝑖 −8𝑗 𝑨 = (𝟓) × 𝒊 + −𝟖 × 𝒋 Scalar multiplication Vector Addition If there are two vectors 𝑖 and 𝑗 with a unit length. Vector 𝑖 is along the 𝑥-axis and vector 𝑗 is along the 𝑦-axis. Then any vector in the 𝑥𝑦 plane can be represented by (a linear combination of) using 𝑖 and 𝑗 vector with appropriate scalar multiplication and vector addition. 𝑖 and 𝑗 are called as basis vectors of the 𝒙𝒚 coordinate system. Can we represent any vector in the 𝑥𝑦 plane using the aforesaid two operations and two fundamental vectors ?
  • 18. 18 Vector: Basis Vectors 𝑣 𝑤 The answer is yes but its not a standard way of doing it as one may not choose same basis vectors and hence we can not be on the same page. Can we choose some different Basis vectors and still able to define each vector in the plane by (a linear combination of) using those different basis vectors (𝒗 and 𝒘) with two operations viz., scalar multiplication and vector addition. If so, it will be a new coordinate system. 𝑣 𝑢 P 2𝑣 1.5𝑤 𝑣 + 𝑤 2𝑣 + 1.5𝑤 1 1 2 1.5
  • 19. 19 Vector: Basis Vectors 𝑣 𝑤 The answer is yes but its not a standard way of doing it as one may not choose same basis vectors and hence we can not be on the same page. Can we choose some different Basis vectors and still able to define each vector in the plane by (a linear combination of) using those different basis vectors (𝒗 and 𝒘) with two operations viz., scalar multiplication and vector addition. If so, it will be a new coordinate system. 2𝑣 1.5𝑤 𝑣 + 𝑤 2𝑣 + 1.5𝑤 1 1 2 1.5 𝑖 𝑗 10𝑖 + 4.5𝑗 10 4.5 ≠ Just like: 𝟏𝟎𝟏𝟐 ≠ 𝟏𝟎𝟏𝟏𝟎 So, in this course, if you see a vector 𝑎𝑥 𝑎𝑦 and no specific base of the vector is mentioned then you will consider 𝑥 and 𝑦 axes as base vector 𝑣 𝑢 P
  • 20. 20 Paradox: Statement: ‘101’ is a number in base ‘10’ Is the base of this number ‘10’ Is the base of this number ‘10’ Is the base of this number is ‘10’ Importance of Basis Vectors Vector: Basis Vectors
  • 21. 21 Vector: Linear combination In mathematics, a linear combination is an expression constructed from a set of terms by multiplying each term by an scalar and adding the results (e.g. a linear combination of x and y would be an expression of the form of 𝒂𝒙 + 𝒃𝒚, where a and b are scalar). Term  Vector 𝒂 𝒗 + 𝒃𝒖 This is a vector which is a linear combination of vectors 𝑣 & 𝑢 Scalars
  • 22. 22 Vector: Linear combination Determine whether 4 −1 is a linear combination of 2 3 and 3 1 4 −1 = x1 2 3 + x2 3 1 If 4 −1 is a linear combination of 2 3 and 3 1 then: 4 −1 = 2x1 + 3x2 3𝑥1 + 𝑥2 2x1 + 3x2 = 4 3𝑥1 + 𝑥2 = −1 2x1 + 3x2 = 4 −9𝑥1 − 3𝑥2 = 3 −7x1 = 7 𝒙𝟏 = −𝟏 𝒙𝟐 = 𝟐 4 −1 = −1 × 2 3 + 2 × 3 1 It’s a unique solution hence 4 −1 is a linear combination of 2 3 and 3 1
  • 24. 24 Vector: Linear combination Determine whether −4 −2 is a linear combination of 6 3 and 2 1 −4 −2 = x1 6 3 + x2 2 1 If −4 −2 is a linear combination of 6 3 and 2 1 then: −4 −2 = 6𝑥1 + 2𝑥2 3𝑥1 + 𝑥2 6𝑥1 + 2𝑥2 = −4 3𝑥1 + 𝑥2 = −2 3x1 + x2 = −2 Any combination of 𝑥1and 𝑥2which satisfy the 3x1 + x2 = −2 is a solution, hence there are infinite solutions. One such solution can be: 𝑥1 = 2 & 𝑥2 = 4, so −4 −2 = −2 × 6 3 + 4 × 2 1 Therefore: −4 −2 is a linear combination of 6 3 and 2 1
  • 26. 26 Vector: Linear combination Determine whether 1 2 is a linear combination of 2 3 and 6 9 1 2 = x1 2 3 + x2 6 9 If 1 2 is a linear combination of 2 3 and 6 9 then: 1 2 = 2𝑥1 + 6𝑥2 3𝑥1 + 9𝑥2 2𝑥1 + 6𝑥2 = 1 3𝑥1 + 9𝑥2 = 2 Here, 1 3 = 0, hence there are no solutions. Therefore: 1 2 is NOT a linear combination of 2 3 and 6 9 𝑥1 + 𝑥2 = 1/3 𝑥1 + 𝑥2 = 2/3
  • 28. 28 Vector: Linear combination Write the vector 1 2 3 as a linear combination of the vectors: 1 0 1 , 1 1 0 & 0 1 1
  • 29. 29 Vector: Linear Span 𝒂 𝒗 + 𝒃𝒖 The span of vector 𝒗 & 𝒖 is the set of all the linear combinations of vectors 𝒗 & 𝒖 𝑣 𝑢 P So, basically if 𝑣 and 𝑢 are linearly independent (𝑣 ≠ 𝑐𝑢) then the span of 𝑣 and 𝑢 will be the entire 2D space. However, if 𝑣 and 𝑢 are linearly dependent (𝑣 = 𝑐𝑢) then the span of 𝑣 and 𝑢 will be the entire a line. 𝑣 𝑢 = 𝑐𝑣 𝑖 𝑗
  • 30. 30 Vector: Linear Span 𝒂 𝒗 + 𝒃𝒖 So, basically if 𝑣 and 𝑢 are linearly independent (𝑣 ≠ 𝑐𝑢) then the span of 𝑣 and 𝑢 will be the entire 2D space.
  • 31. 31 if 𝑣 and 𝑢 are linearly dependent (𝑣 = 𝑐𝑢) then the span of 𝑣 and 𝑢 will be the entire a line. Vector: Linear Span 𝒂 𝒗 + 𝒃𝒖
  • 32. 32 Vector: Linear Span It a bad idea to show the span of two vectors (which is a set all the 2D vectors for linearly independent vectors) to show by ARROWS. Hence it is the time to represent them by points.
  • 36. 36 Vector: Linear Span 𝒂𝒗 + 𝒃𝒖 + 𝒄𝒘 Case 1: 𝒗, 𝒖 and 𝒘 are linearly independent Demo in Solidworks & GeoGebra
  • 38. 38 Vector: Linear Span 𝒂𝒗 + 𝒃𝒖 + 𝒄𝒘 Case 2: 𝒗 is independent to 𝑢, but 𝑢 are 𝑤 linearly dependant Demo in Solidworks & GeoGebra
  • 39. 39 Vector: Linear Span 𝒂𝒗 + 𝒃𝒖 + 𝒄𝒘 Case 3: 𝑣, 𝑢, and 𝑤 are linearly dependent Demo in Solidworks & GeoGebra
  • 40. 40 Vector: Basis Vectors The basis of vector space is a set of linearly independent vectors that span the full space.
  • 41. Thank You Course Instructor Dr. Sajan Kapil Department of Mechanical Engineering Indian Institute of Technology, Guwahati Guwahati, Assam ME 501 IIT Guwahati Advanced Engineering Mathematics (3−0−0−6)