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BANGUN RUANG
LUAS PERMUKAAN
Hal.110-111
Supriyadi, S.Pd. Gr
LUAS PERMUKAAN kubus
Lp kubus = 6 x s2
s merupakan
panjang rusuk kubus
si
si
si
si
Lp kubus = 6 x s2
= 6 x 10 cm2
= 6 x 100 cm2
= 600 cm2
10
cm
CONTOH
LUAS PERMUKAAN bal
Lp balok = 2 x [(pxl) + (pxt) + (
p merupakan panjang balok
l merupakan lebar balok
t merupakan tinggi balok
panjang
leba
r
ting
gi
CONTOH
20 cm
4 cm
5 cm
Lp balok= 2 x [(pxl) + (pxt) + (lxt)]
= 2 x [(20x4) + (20x5) + (4x5)]
= 2 x [(80) + (100) + (20)]
= 2 x [200]
= 400 cm2
LUAS PERMUKAAN prisma tegak segitiga
Lp prisma
= ( 2 x La ) + ( Ka x tinggi )
= ( 2 x ½ x a x t1) + ( (a+b+c) x t)
= (a x t1) + (a+b+c) x t
a,b,c merupakan sisi-sisi segitiga
t1 sebagai tinggi segitiga alas
t sebagai tinggi prisma
CONTOH
tinggi
c
a
b
t
1
10 cm
6 cm
3 cm
Lp prisma
= (a x t1) + (a+b+c)
x t
= (6 x 3) + (6+5+4)
x 10
= (18) + (15) x 10
= (18) + 150
= 168 cm2
LUAS PERMUKAAN
tabung
Lp tabung
= (2 x la) + L selimut tabung
= (2 x 𝜋 x r2) + (2 x 𝜋 x r x t)
= (2 x 𝜋 x r) x (r + t)
CONTOH
tinggi
r
10cm
7 cm
Lp tabung
= (2 x 𝜋 x r) x (r + t)
= (2 x
22
7
x 7) x (7 + 10
= (2 x 22) x (17)
= 44 cm X 17 cm
= 748 cm2
LUAS PERMUKAAN limAS SEGIEMPAT
Lp limas segiempat
= La + (4 x L sisi tegak)
Dimana La adalah luas alas.
CONTOH
Lp limas segiempat
= La + (4 x L sisi
tegak)
= s x s + (4 x ½ x a
x t)
= 5 x 5 + (4 x ½ x 5
x 12)
= 25 + (4 x 5 x 6)
panjang
lebar
ting
gi
5 cm
5 cm
10 cm
12 cm
LUAS PERMUKAAN KERU
Lp kerucut
= La x L selimut kerucut
= 𝜋 x r2 + 𝜋 x r x s
= 𝜋 x r x (r + s)
CONTOH
t
r
s
Lp kerucut
= 𝜋 x r x (r + s)
=
22
7
x 7 x (7 + 12)
= 22 x (19)
= 418 cm2
r
s
10 cm
7 cm
LUAS PERMUKAAN bola
Lp bola
= 4 x 𝜋 x r2
Dimana 𝜋 =
22
7
atau 3,14
CONTOH
r
7 cm
Lp bola
= 4 x 𝜋 x r2
= 4 x
22
7
x 72
= 4 x
22
7
x 7 x 7
= 4 x 22 x 7
= 616 cm2
Selalu mencoba
Tak putus asa
Supriyadi, S.Pd. Gr

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Luas permukaan bangun ruang

  • 2. LUAS PERMUKAAN kubus Lp kubus = 6 x s2 s merupakan panjang rusuk kubus si si si si Lp kubus = 6 x s2 = 6 x 10 cm2 = 6 x 100 cm2 = 600 cm2 10 cm CONTOH
  • 3. LUAS PERMUKAAN bal Lp balok = 2 x [(pxl) + (pxt) + ( p merupakan panjang balok l merupakan lebar balok t merupakan tinggi balok panjang leba r ting gi CONTOH 20 cm 4 cm 5 cm Lp balok= 2 x [(pxl) + (pxt) + (lxt)] = 2 x [(20x4) + (20x5) + (4x5)] = 2 x [(80) + (100) + (20)] = 2 x [200] = 400 cm2
  • 4. LUAS PERMUKAAN prisma tegak segitiga Lp prisma = ( 2 x La ) + ( Ka x tinggi ) = ( 2 x ½ x a x t1) + ( (a+b+c) x t) = (a x t1) + (a+b+c) x t a,b,c merupakan sisi-sisi segitiga t1 sebagai tinggi segitiga alas t sebagai tinggi prisma CONTOH tinggi c a b t 1 10 cm 6 cm 3 cm Lp prisma = (a x t1) + (a+b+c) x t = (6 x 3) + (6+5+4) x 10 = (18) + (15) x 10 = (18) + 150 = 168 cm2
  • 5. LUAS PERMUKAAN tabung Lp tabung = (2 x la) + L selimut tabung = (2 x 𝜋 x r2) + (2 x 𝜋 x r x t) = (2 x 𝜋 x r) x (r + t) CONTOH tinggi r 10cm 7 cm Lp tabung = (2 x 𝜋 x r) x (r + t) = (2 x 22 7 x 7) x (7 + 10 = (2 x 22) x (17) = 44 cm X 17 cm = 748 cm2
  • 6. LUAS PERMUKAAN limAS SEGIEMPAT Lp limas segiempat = La + (4 x L sisi tegak) Dimana La adalah luas alas. CONTOH Lp limas segiempat = La + (4 x L sisi tegak) = s x s + (4 x ½ x a x t) = 5 x 5 + (4 x ½ x 5 x 12) = 25 + (4 x 5 x 6) panjang lebar ting gi 5 cm 5 cm 10 cm 12 cm
  • 7. LUAS PERMUKAAN KERU Lp kerucut = La x L selimut kerucut = 𝜋 x r2 + 𝜋 x r x s = 𝜋 x r x (r + s) CONTOH t r s Lp kerucut = 𝜋 x r x (r + s) = 22 7 x 7 x (7 + 12) = 22 x (19) = 418 cm2 r s 10 cm 7 cm
  • 8. LUAS PERMUKAAN bola Lp bola = 4 x 𝜋 x r2 Dimana 𝜋 = 22 7 atau 3,14 CONTOH r 7 cm Lp bola = 4 x 𝜋 x r2 = 4 x 22 7 x 72 = 4 x 22 7 x 7 x 7 = 4 x 22 x 7 = 616 cm2
  • 9. Selalu mencoba Tak putus asa Supriyadi, S.Pd. Gr