Captain Jabbamathee’s steps to success: Logs and Exponents 7.2 The Natural Logarithm Function by flickr user mseery
Graphing Graph the function: y = |log x| Need to find: a) asymptote b) domain c) range d) is it increasing or decreasing Using three main steps.. 5
Step 1 Graph y = 5^x which is the inverse of y = log  x To choose a value for x, you would look to the x-axis. Ex. When x = 1: 5^1 = 5, so the y-coordinate = 5 Ex. When x = -1: 5^(-1) = ½, so y-coordinate = 1/2 5
Step 2 Graphing y = log  x is the same as graphing the inverse of y = 5^x Therefore the values for x and y would be reversed This means if the original graph had points (1,5) than the inversed points would be (5,1). All the inverse points would make a new graph, which is a reflection of the original graph that was reflected over the line y = x. 5
Step 3 This graph is an absolute value, therefore all the values have to be positive. The graph bounces off the x-intercept and back into the positive quadrants.
Solutions The asymptote is x = 0 The domain is (0, ∞) The range is [o,  ∞) The graph is both increasing and decreasing

Logsexponents

  • 1.
    Captain Jabbamathee’s stepsto success: Logs and Exponents 7.2 The Natural Logarithm Function by flickr user mseery
  • 2.
    Graphing Graph thefunction: y = |log x| Need to find: a) asymptote b) domain c) range d) is it increasing or decreasing Using three main steps.. 5
  • 3.
    Step 1 Graphy = 5^x which is the inverse of y = log x To choose a value for x, you would look to the x-axis. Ex. When x = 1: 5^1 = 5, so the y-coordinate = 5 Ex. When x = -1: 5^(-1) = ½, so y-coordinate = 1/2 5
  • 4.
    Step 2 Graphingy = log x is the same as graphing the inverse of y = 5^x Therefore the values for x and y would be reversed This means if the original graph had points (1,5) than the inversed points would be (5,1). All the inverse points would make a new graph, which is a reflection of the original graph that was reflected over the line y = x. 5
  • 5.
    Step 3 Thisgraph is an absolute value, therefore all the values have to be positive. The graph bounces off the x-intercept and back into the positive quadrants.
  • 6.
    Solutions The asymptoteis x = 0 The domain is (0, ∞) The range is [o, ∞) The graph is both increasing and decreasing