The document discusses various topics related to line efficiency calculation including: 1. How to calculate target production for a line based on standard minute value (SMV), manpower, and working hours. 2. How efficiency is affected by changes in output, manpower, and working hours. Efficiency increases with higher output or fewer workers. 3. How to calculate an operator's capacity based on the time taken to complete a process. Faster cycle times mean higher capacity.

2. ON IE

3. Discussion topics/ Av
‡
j v
P
¨ w
el q:
 Efficiency/Kg©
`¶Zvw
K?
 How can you calculate Target?
 How can you balance the line?
 How can you calculate capacity of
an operator?

4. •Efficiency Gi mv‡_ Manpower, Production I Time Gi
m¤úK©
•How can you increase/Efficiency wKfv‡e e„w× Kiv hvq ?
What is SMV???
Standard time of a average worker will take to do a job.
In idle environment in predetermined speed a general
operator needs time to do a process.

5. SMV=Standard Minute Value
SMV = Cycle time + allowances
Allowances = personal + machine+ bundle handling
Personal 2%
Machine O/L = 10%, SN = 3%, FL = 8%
Bundle = 2%

6. GKRb kªwgK Gi mvavib Kv‡Ri MwZ‡K 100% †iwUs wnmv‡e MY¨ Kiv nq|
hw` †Kvb kªwgK mvfvweK MwZi †Pq axi MwZ‡Z KvR m¤cbœ K‡i Zvn‡j
Zvi †iwUs 100% Gi †P‡q Kg A_©vr 90% ev
% n‡Z cv‡i|
hw` †Kvb kªwgK mvfvweK MwZi †Pq `ª“Z MwZ‡Z KvR m¤cbœ K‡i Zvn‡j
Zvi †iwUs 100% Gi †P‡q †ewk A_v©r 110% ev
% n‡Z cv‡i|

7. Pick up Sewing
Dispose
Cycle Time

8.  Mv‡g©›Um
†Zvjv
 Ae¯’vb wVK Kiv
 mvRv‡
bv
 †mjvB Kiv
 myZv
KvUv
 †i‡L †`qv
mvB‡Kj UvBg
Pick-up
Position
ing
Aligning
Sewing
Trimmin
g
Dispose

9. Gm,Gg,wf MYbv
mvB‡Kj UvBg = 36, 42, 39,36, 39 sec
= 192 sec =192/60 min =3.2 min cÖvß mgq = 3.2 / 5
= 0.64
†iwUs = 85%
†ewmK UvBg = cÖvß mgq x †iwUs
= 0.64 X 85/100
= 0.54
Gm,Gg,wf = †ewmK UvBg + AwZwi³ mgq

10. = 0.54+15%
= 0.54+(0.54
15/100)
= 0.54+ (0.54*0.15)
= 0.54(1+0.15) =0.54*1.15
= 0.62
wK Kvi‡b AwZwi³ mgq †`qv
nq
cvwb LvIqv
ev_i“g G hvIqv
Kv‡Ri GK‡N‡qwg `~i Kiv
†gwkb mgm¨v

11. myZv †K‡U hvIqv
ev‡Ûj †Lvjv I eÜ Kiv BZvw`
wK Kvi‡b AwZwi³ mgq †`qv nq

12. How can you calculate efficiency?
Efficiency = hv Kv‡R jvMv‡bv
n†”Qhv
Av‡Q
X 100

13. Efficiency
Output x SMV
Efficiency =
Total M/P x W/H x 60
SMV = 1wcP Output Gi Rb¨ †h mgq jv‡M
Example, Bella Hipster
X 100%

14. 2000 x 7.07
Efficiency =
32 x 11 x 60
14140
=
21120
X
100%
= 0.6695 X 100%
= 66.95%
X
100%

15. Efficiency Gi mv‡_ m¤úwK©Z
Output evo‡j Efficiency ev‡o
Manpower Kg‡j Efficiency ev‡o
Time Kg‡j Efficiency ev‡o
We can handle
Output/Total Production

16. Manpower/(Operator+Helper)
Working Hour

17. GOOD
EFFICIENCY
MAN
POWER
WORKING
HOUR
SMV
OUTPUT

18. How????
 Output
Condition 01:
Let output=1400
,SMV=8.0,Manpower =35, Working
hour=10 Then
Efficiency=(1400 x 8 x 100)/(35 x 10 x 60)
=53 %
Condition 02:
Let output=2000
,SMV=8.0,Manpower =35, Working
hour=10 Then
Efficiency=(2000 x 8 x 100)/(35 x 10 x 60)
=76 %
Out put increase efficiency ????
Out put decrease efficiency???

19. Manpower
Let output=1400,SMV=8.0,Manpower
=35,
Working hour=10 Then
Efficiency=(1400 x 8 x 100)/(35 x 10 x 60)
=53%
Condition 02:
Let output=1400,SMV=8.0,Manpower=28,
Working hour=10 Then

20. Efficiency=(1400 x 8 x 100)/(28 x 10 x 60)
=67%
Manpower increase efficiency ???
Manpower decrease efficiency ???
Working hours
Let output=1400,SMV=8.0,Manpower =35, Working
hour=10 Then
Efficiency=(1400 x 8 x 100)/(35 x 10 x 60)
=53%
Condition 02:
Let output=1400,SMV=8.0,Manpower =35,
Working hour=8 Then

21. Efficiency=(1400 x 8 x 100)/(35 x 8 x 60)
=67%
Working time increase efficiency ???
Working time decrease efficiency ???

22. GOOD
EFFICIENCY
MAN
POWER
????????
WORKING
HOUR
???????
SMV
Unchanged
OUTPUT ??????

23. You can check mobile stop watch& easily calculate…..
How many minutes makes One Hour?
1 Hour = ……………..Minutes?
 How many seconds makes a minutes?
1 Minutes=………….Seconds?

24. TARGET CALCULATION
TARGET FOR A LINE = M/P X W/H X 60
SMV
SUPPOSE, LINE 25+26 (MIKE BOXER)
SMV=5.97, W/H=11,M/P=26
SO…. TARGET AT 100% EFF = (60/5.97) X 11 X 26
=2874 PCS
TARGET AT 55% EFF = 2874 X 0.55=1581 PCS

25. Capacity
If a worker takes 1 min to complete a
process then how many pieces he/she
can complete in an hour?
Answer:60 Pcs????? 30Pcs???
If a worker takes 30 sec complete a
process then how many pieces he/she
can complete in an hour?
Answer:120Pcs???? 200 Pcs???

26. Bottleneck?
Capacity
190 197
98
200 195
0
100
200
300
Rehen maksud Nazma Niha Selina

27. Capacity
190
197
196
200
195
184
186
188
190
192
194
196
198
200
202
Rehana Maksuda Nazma+Kajol Nihar Selina

29. Feeding report Line-37+38 L-25+26
450
1200
1800 2000 2000 2000 2000 2000 2000
450
800
1600
2000 2000 2000 2000 2000 2000
0
1000
2000
3000
4000
5000
1st 2nd 3rd 4th 5th 6th 7th 8th 9th
Capacity
Day
1
st
output time for L 25+ 26
- = 3.5 hrs 1st output time for L-37+38=3.9 hrs

30. ?
?
?
Loss Time Report
L-1-Machine problem
L-10-Elastic N/A
L-15-Label problem
L-25-Input problem
L-33-Quality problem
L-38-Air problem
L-23-Meeting
L-1-Power problem
L-4-Manpower problem
L-2-Merchendiser problem

31. How can You Report?
L-3+4
M/c problem
2.5 hr
Flat lock machine
Process: Leg Hem 28

32. WHICH 1 IS BETTER???
150
90
90
150
Output Output

33. Question
?
?
?

34. Thank You