How are satellites identifiedSolutionGenerally Satelites are i.pdf
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How are satellites identified? Solution Generally Satelites are identified based on the orbit they are placed in. there are 4 kinds of satelites they are i)Low Earth orbits:Satelites which are placed in the low earth orbits mainly used for military purposes. It will be placed above 160 Km from earths surface. ii)Sun synchronous Satelites: These are placed in heliosynchronous orbits or polar orbits.These satelites orientation is fixed to the orientation of the sun through out the year. iii)Geo Stationary satelites:These satelites take 24 hrs to complete one rotation.These satelites are mainly used for communication purposes.These are placed directly over the equator and their path is the equitorial plane.These are placed at a height of about 35778 Km. iv)Geo synchronous satelites: These are the earth synchronous orbits placed in the orbit so that it revolves exactly along the moment of the earth..
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JP=sample(c(\"J\",\"P\"), n, replace=TRUE), Drink=factor( sample(c(\"Rarely\",\"Often\"), n,
p=c(.2,.8), replace=TRUE), levels=c(\"Rarely\", \"Often\")), Count=rpois(n,5) ) library(plyr)
MBdrink <- ddply(MBdrink, c(\"EI\",\"SN\",\"TF\",\"JP\",\"Drink\"), summarize,
Count=sum(Count)) # dis-aggregate the data d <- ddply(MBdrink, \"Count\", function (u)
do.call( rbind, replicate(unique(u$Count), u, simplify=FALSE))) # Run the regression you want r
<- glm( Drink ~ EI + SN + TF + JP, data=d, family=binomial(link=\"logit\") # Logistic
regression ) result <- cbind(d, Probability=predict(r, type=\"response\")) result <- unique(result)
result <- result[order(result$Probability),] result.
How does RFID work and differentiate with bar coding. Also what is th.pdf
How does RFID work and differentiate with bar coding. Also what is the impact of RFID in
B2B e-Commerce. Discuss Collaborative Commerce and its benefits
Solution
RFID stands for radio frequency identification tag associated with each products. The main
difference between the working of RFID and Barcoding are as follows:
RFID Working: In RFID method a tag is affixed to the products which is used to identify and
track product via radio waves. These tags can store or carry upto 2,000 bytes of data. RFID
technology has three parts namely the scanning antenna, a transceiver and a transponder. The
transceiver comes with a decoder to interpret the data and the transponder comes with the pre-set
with information.The scanning antenna is used to send a radio-frequency signal to the RFID
tag. As the RFID tag is passed through the frequency field of the scanning antenna; it will be
able to detect the activation signal and further will be able to transfer the information data it
holds to be picked up by the scanning antenna.
Bar Coding: A visual representation of data that is scanned and interpreted for information is
called as barcodes. A certain code is present in each barcode which works as a tracking
technology for products. It is usually represented as a sequence of lines or in other shapes.
Barcodes initially were one dimensional and were based on the width and spaces between
parallel lines but later they were developed as two-dimensional with many geometrical shapes
used for bar-coding. The barcode technology can be scanned with the help of bar-code readers.
Impact of RFID in B2B and E-Commerce are as follows: RFID has a great impact on the B2B
and E-commerce business since the radio frequency codes can now be checked easily. RFID has
playeda significant role in fostering a higher level of integration between the supply chain
members.
Collaborative Commerce: C-Commerce or Collaborative commerce is a new business strategy
that looks at the supply chain managment in a difference way. It describes about the selection
and project based cooperation between one or more parties or parteners along the supply chain.
Collaborative commerce is further seen as a tool that combines knowledge management, supply
chain management and e-commerce.
Benefits of Collaborative Commerce are as follows:
1. Cost Advantages.
2. Concentration on core competencies
3. Innovations are encouraged
4. Reduction in inventory
5. Reduced time-to-market.
How do you calculate the stock price for both scenarios He asked .pdf
How do you calculate the stock price for both scenarios? He asked Ms. Firewater to prepare a
formal report to Prairie Home stockholders, valuing the company on the assumption that its
shares were publicly traded. Ms. Firewater asked two questions immediately. First, what should
she assume about investment and growth? Mr. Breezeway suggested two valuations, one
assuming more rapid expansion (as in the top panel of Table 3.8) and another just projecting past
growth (as in the bottom panel of Table 3.8). Second, what rate of return should she use? Mr.
Breezeway said that 15 percent, Prairie Home?s usual return on book equity, sounded right to
him, but he referred her to an article in the Journal of Finance indicating that investors in rural
supermarket chains, with risks similar to Prairie Home Stores, expected to earn about 11 percent
on average. Rapid-Growth Scenario 1 2 3
4 5 6 Book value, start of year 80 92 105.8 121.7 139.9 146.9 Earnings
12 13.8 15.9 18.3 21 22 Dividends 0 0 0 0 14
14.7 Retained Earnings 12 13.8 15.9 18.3 7 7.4 Book value, end of year
92 105.8 121.7 140 146.9 154.3 Constant-Growth Scenario
1 2 3 4 5 6 Book value, start of year 80 84 88.2
92.6 97.2 102.1 Earnings 12 12.6 13.2 13.9 14.6 15.3 Dividends
8 8.4 8.8 9.3 9.7 10.2 Retained Earnings 4 4.2 4.4 4.6
4.9 5.1 Book value, end of year 84 88.2 92.6 97.2 102.1 107.2
Notes: 1. Both panels assume earnings equal to 15 percent of start-of-year
book value. This profitability rate is constant. 2. The top panel assumes all earnings are
reinvested from 2005 to 2009. In 2010 and later years, two-thirds of earnings are paid out as
dividends and one-third reinvested. 3. The bottom panel assumes two-thirds of earnings are paid
out as dividends in all years. 4. Columns may not add up because of rounding.
Solution
Valuation based on constant growth scenario
Growth Rate = Return on Equity x Plowback ratio = 15% x 1/3 = 5%
Value of the equity =DIVx(1+g)/ (r-g) =$10.2 million x (1+0.05)/(15%- 5%) =$10.71 million/
10%
= 107.10 million
Value per share = Value of the equity / No. of shares Common Shares Outstanding =
= $107.10 million /400,000
= $267.75 per share
Valuation based on rapid growth scenario
Plowback ratio is 1 as the entire income is reinvested for the next five years.
Value of equity = DIV 2010 x (1+g) / r-g (Assume same as in constant growth scenario)
= $14.7 million x (1+.05) / (15%- 5% )
= 154.35 milion
Value per share = $154.35 / 400,000
= $385.875
Rapid growth scenario is preferable as the value of per share is greater in rapid growth scenario..
if f and g are surjective, then f o g is surjective.SolutionL.pdf
if f and g are surjective, then f o g is surjective.
Solution
Let me explain in a bit more detail :
Let fog : A -> C
fog is onto if, for every c in C, there exists as a in A such that fog(a) = c.
But since f is onto, we have that f(b) = c for some b in B, and
since g is onto, we have that b = g(x) for some x in A (I changed the letters to avoid confusion).
So g(x) = b
f(g(x)) = f(b) = c
So this value of x exists, which is what we wanted to show.
I hope this helps!.
If one of the students knows one-half of the list at time t = 0 and t.pdf
If one of the students knows one-half of the list at time t = 0 and the
Solution
(1) Which student has a faster rate of learning at t = 0 if they both start memorizing together
having never seen the poem before?
Beth
(2) Which student has a faster rate of learning at t = 0 is they both start memorizing together
having already learned one-half of the poem?
Aly
(3) Which student has a faster rate of learning at t = 0 is they both start memorizing together
having already learned one-third of the poem?
They have the same rate..
How do these two groups compare in terms of variability in MATH score.pdf
How do these two groups compare in terms of variability in MATH scores? Explain.
Solution
the second group has more variation, but only SLIGHTLY.. the first group has a
standard deviation of 14.538, where as the second group has a standard deviation of 14.782,
therefore making it have more variability. the standard deviation is the best to use because it is
not affected by outliers. the second group has also a more skewed distribution than the first
group..
Ido not understand V,VI and Part B IV and any help on how to fi.pdf
Ido not understand V,VI and Part B IV and any help on how to find the results on SPSS would
be helpful. I have tried to work it out no idea. WHY DO MY P VALUES IN BOTH METHODS
DIFFER SO GREATLY?
Solution
try splitting the question..You will get positive responses.. it takes much time to
answer this ..and it is for only 175 points..so try splitting up.
Identify elements associated with the preparation of a programmable l.pdf
Identify elements associated with the preparation of a programmable logic controller program.
Before starting the development of a programmable logic controller program, there are a number
of important steps which shall be taken into consideration e.g. selection of PLC based on
input/output, etc...identify some other important steps and elements.
Solution
A programmable logic controller, PLC, or programmable controller is a digital computer used
for automation of typically industrialelectromechanical processes, such as control of machinery
on factory assembly lines, amusement rides, or light fixtures. PLCs are used in many machines,
in many industries. PLCs are designed for multiple arrangements of digital and analog inputs and
outputs, extended temperature ranges, immunity to electrical noise, and resistance to vibration
and impact. Programs to control machine operation are typically stored in battery-backed-up or
non-volatile memory. A PLC is an example of a \"hard\" real-time system since output results
must be produced in response to input conditions within a limited time, otherwise unintended
operation will result.
Before the PLC, control, sequencing, and safety interlock logic for manufacturing automobiles
was mainly composed of relays, cam timers,drum sequencers, and dedicated closed-loop
controllers. Since these could number in the hundreds or even thousands, the process for
updating such facilities for the yearly model change-over was very time consuming and
expensive, as electricians needed to individually rewire the relays to change their operational
characteristics.
Digital computers, being general-purpose programmable devices, were soon applied to control of
industrial processes. Early computers required specialist programmers, and stringent operating
environmental control for temperature, cleanliness, and power quality. Using a general-purpose
computer for process control required protecting the computer from the plant floor conditions.
An industrial control computer would have several attributes: it would tolerate the shop-floor
environment, it would support discrete (bit-form) input and output in an easily extensible
manner, it would not require years of training to use, and it would permit its operation to be
monitored. The response time of any computer system must be fast enough to be useful for
control; the required speed varying according to the nature of the process.[1] Since many
industrial processes have timescales easily addressed by millisecond response times, modern
(fast, small, reliable) electronics greatly facilitate building reliable controllers, especially because
performance can be traded off for reliability.
In 1968 GM Hydra-Matic (the automatic transmission division of General Motors) issued a
request for proposals for an electronic replacement for hard-wired relay systems based on a white
paper written by engineer Edward R. Clark. The winning proposal came from Bedford
Associates of Bedford, Massachusetts. T.
Identify the main Transportation agents for the following types of so.pdf
Identify the main Transportation agents for the following types of soil. Wind Sea (salt water)
Lake (fresh water) River\" Ice
Solution
River - Colluvial soil deposits
Ice - Glacier soilm deposits
Sea - Marine Deposits
Wind - Aeolin deposits
Lake - Lacustrine Deposits.
Identify all zero-force members. Solution1. roller load at F s.pdf
Identify all zero-force members.
Solution
1. roller load at F so both Fx and Fy exist thus, DF and EF will have some force.
DE= 0 , BC= 0, as at any joint there can be three members and two of which are collinear, DC =
F
2. M0 U1 , M0L1, M4 U3, M4 L3, U1 L2, U3 L2.
I would appreciate you helping me do the following problem...PLEA.pdf
I would appreciate you helping me do the following problem...PLEASE explain you steps so i
can follow them on similar problems. Thanks!!
A random variable X has the following probability density function
f(X) ={ (X+2)/4 for -1 < x < 1
{ 0 elsewhere
Let us define a random variable Y = -2X + 1.
(a) Find Var(X).
(b) Find Var(Y)
Solution
=*3.25, not +.
I need to calcuate the vertical analysis This is from the Financ.pdf
I need to calcuate the vertical analysis? This is from the Financial & Managerial Text book
Edition 12
Prepare a comparative balance sheet for 2014 and 2013, stating each asset as a percent of total
assets and each liability and stockholders\' equity item as a percent of the total liabilities and
stockholders\' equity.
Peacock Company
Comparative Balance Sheet
December 31, 2014 and 2013
2014 Amount
2014 Percent
2013 Amount
2013 Percent
Current assets
$ 1,050,000
Correct 10
$ 750,000
Correct 12
Property, plant, and equipment
1,960,000
Correct 15
2,100,000
Correct 17
Intangible assets
490,000
Correct 20
150,000
Correct 22
Total assets
$ 3,500,000
Correct 25
$ 3,000,000
Correct 27
Current liabilities
$ 630,000
Correct 30
$ 420,000
Correct 32
Long-term liabilities
1,260,000
Correct 35
1,200,000
Correct 37
Common stock
350,000
Correct 40
300,000
Correct 42
Retained earnings
1,260,000
Correct 45
1,080,000
Correct 47
Total liabilities and stockholders\' equity
$ 3,500,000
Correct 50
$ 3,000,000
Correct 52
Prepare a comparative balance sheet for 2014 and 2013, stating each asset as a percent of total
assets and each liability and stockholders\' equity item as a percent of the total liabilities and
stockholders\' equity.
Peacock Company
Comparative Balance Sheet
December 31, 2014 and 2013
2014 Amount
2014 Percent
2013 Amount
2013 Percent
Current assets
$ 1,050,000%
Correct 10
$ 750,000%
Correct 12
Property, plant, and equipment
1,960,000%
Correct 15
2,100,000%
Correct 17
Intangible assets
490,000%
Correct 20
150,000%
Correct 22
Total assets
$ 3,500,000%
Correct 25
$ 3,000,000%
Correct 27
Current liabilities
$ 630,000%
Correct 30
$ 420,000%
Correct 32
Long-term liabilities
1,260,000%
Correct 35
1,200,000%
Correct 37
Common stock
350,000%
Correct 40
300,000%
Correct 42
Retained earnings
1,260,000%
Correct 45
1,080,000%
Correct 47
Total liabilities and stockholders\' equity
$ 3,500,000%
Correct 50
$ 3,000,000%
Correct 52
Solution
The analyzed table is as follows.20142013$%$%Current
Assets10,50,00030.00%7,50,00025.00%Property, Plant &
Equipment19,60,00056.00%21,00,00070.00%Intangible
Assets4,90,00014.00%1,50,0005.00%TOTAL
ASSETS35,00,000100.00%30,00,000100.00%Current
Liabilities6,30,00018.00%4,20,00014.29%Long-Term
Liabilities12,60,00036.00%12,00,00040.82%Common
Stock3,50,00010.00%3,00,00010.20%Retained
Earnings12,60,00036.00%10,20,00034.69%TOTAL LIABILITIES &
EQUITY35,00,000100.00%29,40,000100.00%.
I was able to figure out 2002 but not the rest Develop a.pdf
I was able to figure out 2002 but not the rest:
Develop an index, with 2001 as the base, for the change in earnings per share over the
period.(Round your answers to 1 decimal place.)
Please, I really need help. Thanks! The table below reports the earnings per share of common
stock for Home Depot Inc. for recent years.
Solution
TEST.
I hope this is clear this time.SolutionMoment of inertia is.pdf
I hope this is clear this time.
Solution
Moment of inertia is nothing but second moment of area and is the indicator of flexural stiffness
of the member.
In given problem, Moment of Inertia (MI) = BD3/12-(bd3/12)
= 10*113/12-(2*3.5*53/12) = 1109.16 -72.9 = 1036.2 in4. (about strong axis as the member is
symmetrical about XX or strong axis.
Now MI about weak axis, YY axis or vertical axis
(11*103/12)-(5*73/12) = 916.67-142.91 = 773.75 in4
Hightlighted values are the answers for the MI of strong and weak, ie horizontal and vertical axis
respectively..
I have a nephew Berkeley and niece Chelsea who, when v.pdf
I have a nephew Berkeley and niece Chelsea who, when very young, would occasionally visit
their Uncle Ismor on weekends . Furthermore,
i. Berkeley and Chelsea visited independently of one another.
ii. Berkeley visited with probability 80%.
iii. Chelsea visited with probability 75%.
However, it often happened that some object in his house
Solution
My guess at the problem is what the probability of an accident occurring?
It would equal Prob(both visiting)Prob(accident|both visited) + P(only Berkeley
visiting)P(accident with Berkeley visiting) +
P(Chelsea visiting)P(accident| only Chelsea visited) + P(neither visited)P(accident|neither
visited) =
due to independence
.8*.75*.9 + .8*(1-.75)*.35+(1-.8)*.75*.2+(1-.8)*(1-.75)*.02 = .641.
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