HIGH VOLTAGE DC UPTO 3KV FROM AC
BY USING DIODE AND CAPACITORS IN
LADDER NETWORK
Submitted by:
Contents
 Project overview
 Block diagram
 Capacitor
 Diode
 Schematic & working of project
 Applications
 Advantages
 Future scope
 Conclusion
Project overview
 This project describes the design and
implementations from a single phase ac to high
voltage DC power supply till 10kVoutput.
 The implementation of the hardware work to
build a high voltage DC power supply is meant
for use in the laboratory.
 The designed DC power supply can be used in
industrial applications also.
 The design of the circuit involves voltage doubler,
whose principle is to double the output voltage.
 The output from the voltage doubler is given to a
series of cascaded circuit that generates up to
10KV but for the student project it is advisable to
go up to 2KV for safety reasons.
Block diagram
Capacitor
 A basic capacitor has
two parallel plates
separated by an
insulating material
 A capacitor stores an
electrical charge
between the two plates
 The unit of capacitance
is Farads (F)
Storing a charge between the plates
 Electrons on the left plate
are attracted toward the
positive terminal of the
voltage source
 This leaves an excess of
positively charged holes
 The electrons are pushed
toward the right plate
 Excess electrons leave a
negative charge
+ -
+
_
Diode
 Simplest semiconductor device
 Non linear
 Used in power supplies
 Voltage limiting circuits
Working of project
 This project uses voltage multiplier circuit in multistage
using a no of silicon diodes (D1-D8) and a set of
electrolytic capacitors of 2 no’s of 100mf/400V connected
in series.
 Thus 16 capacitor of 100mf/400V are used for 8 stage
voltage multiplication.
 Thus if the input is 230v rms the output will be
approximately [sqrt 2 x 230 x 8 = appx 2.5kv].
 In order to measure this voltage a potential divider
arrangement comprising of 10resistors in series is made
such that the voltage across 1 resistor is 2.5/10=250V,
Which can be easily read by any standard meter to indicate
that the full voltage is approximately 2.5kV.
 500k resistors are connected across each pair of capacitors
to discharge them automatically after use, it will prevent
from high voltage electric shock.

High voltage module

  • 1.
    HIGH VOLTAGE DCUPTO 3KV FROM AC BY USING DIODE AND CAPACITORS IN LADDER NETWORK Submitted by:
  • 2.
    Contents  Project overview Block diagram  Capacitor  Diode  Schematic & working of project  Applications  Advantages  Future scope  Conclusion
  • 3.
    Project overview  Thisproject describes the design and implementations from a single phase ac to high voltage DC power supply till 10kVoutput.  The implementation of the hardware work to build a high voltage DC power supply is meant for use in the laboratory.  The designed DC power supply can be used in industrial applications also.  The design of the circuit involves voltage doubler, whose principle is to double the output voltage.  The output from the voltage doubler is given to a series of cascaded circuit that generates up to 10KV but for the student project it is advisable to go up to 2KV for safety reasons.
  • 4.
  • 5.
    Capacitor  A basiccapacitor has two parallel plates separated by an insulating material  A capacitor stores an electrical charge between the two plates  The unit of capacitance is Farads (F)
  • 6.
    Storing a chargebetween the plates  Electrons on the left plate are attracted toward the positive terminal of the voltage source  This leaves an excess of positively charged holes  The electrons are pushed toward the right plate  Excess electrons leave a negative charge + - + _
  • 7.
    Diode  Simplest semiconductordevice  Non linear  Used in power supplies  Voltage limiting circuits
  • 8.
    Working of project This project uses voltage multiplier circuit in multistage using a no of silicon diodes (D1-D8) and a set of electrolytic capacitors of 2 no’s of 100mf/400V connected in series.  Thus 16 capacitor of 100mf/400V are used for 8 stage voltage multiplication.  Thus if the input is 230v rms the output will be approximately [sqrt 2 x 230 x 8 = appx 2.5kv].  In order to measure this voltage a potential divider arrangement comprising of 10resistors in series is made such that the voltage across 1 resistor is 2.5/10=250V, Which can be easily read by any standard meter to indicate that the full voltage is approximately 2.5kV.  500k resistors are connected across each pair of capacitors to discharge them automatically after use, it will prevent from high voltage electric shock.