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SHAPES AND SPACE / BENTUK DAN RUANG
1 Area of trapezium =
2
1
× sum of parallel sides × height
Luas trapezium =
2
1
x hasil tambah sisi selari x tinggi
2 Circumference of circle = d = 2r Lilitan bulatan = d = 2j
3 Area of circle = r2 Luas bulatan = j2
4 Curved surface area of cylinder = 2rh Luas permukaan melengkung silinder = 2jt
5 Surface area of sphere = 4r2 Luas permkaan sfera = 4j 2
6 Volume of right prism = cross sectional area × length
Isipadu prisma tegak = luas keratan rentas x panjang
7 Volume of cylinder = r2h Isipadu silinder = πj2t
8 Volume of cone =
3
1
r2h Isipadu kon =
3
1
 j 2t
9 Volume of sphere =
3
4
r3 Isipadu sfera =
3
4
j3
10 Volume of right pyramid =
3
1
× base area × height
Isipadu piramid tegak =
3
1
× luas tapak × tinggi

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Formula ujian 1 matematik tingkatan 4

  • 1. SHAPES AND SPACE / BENTUK DAN RUANG 1 Area of trapezium = 2 1 × sum of parallel sides × height Luas trapezium = 2 1 x hasil tambah sisi selari x tinggi 2 Circumference of circle = d = 2r Lilitan bulatan = d = 2j 3 Area of circle = r2 Luas bulatan = j2 4 Curved surface area of cylinder = 2rh Luas permukaan melengkung silinder = 2jt 5 Surface area of sphere = 4r2 Luas permkaan sfera = 4j 2 6 Volume of right prism = cross sectional area × length Isipadu prisma tegak = luas keratan rentas x panjang 7 Volume of cylinder = r2h Isipadu silinder = πj2t 8 Volume of cone = 3 1 r2h Isipadu kon = 3 1  j 2t 9 Volume of sphere = 3 4 r3 Isipadu sfera = 3 4 j3 10 Volume of right pyramid = 3 1 × base area × height Isipadu piramid tegak = 3 1 × luas tapak × tinggi