form view

The working of Form View control is same as
Detail View control but the default UI of Form
View control is different.
Detail View control displays the records in tabular
format. Form View control does not have
predefined layout but it depend upon template.
According to the need of application, we can
display the data with the help of template.

 We can insert, update, delete and paging the
record in Form View.
 Adding validation controls to a Form View is
easier than Detail View control. For displaying
data, Item Template is used.
Displaying Data with the Form View

using System;
using System.Data;
using System.Data.SqlClient;
using System.Configuration;
using System.Web.UI.WebControls;
using System.Web.UI;
public partial class FormViewDemo :
System.Web.UI.Page
{
SqlConnection conn;
SqlDataAdapter adapter;
DataSet ds;
SqlCommand cmd;
string cs =
ConfigurationManager.ConnectionStrings["conStri
ng"].ConnectionString;
protected void Page_Load(object sender,
EventArgs e)

{
if (!IsPostBack)
{
PopulateFormView();
}
}
protected void PopulateFormView()
{
try
{
conn = new SqlConnection(cs);
adapter = new SqlDataAdapter("select *
from tblEmps", conn);
ds = new DataSet();
adapter.Fill(ds);
FormView1.DataSource = ds;
FormView1.DataBind();
}

 catch (Exception ex)
{
Label1.Text = "ERROR :: " + ex.Message;
}
}
protected void
FormView1_ModeChanging(object sender,
FormViewModeEventArgs e)
{
FormView1.ChangeMode(e.NewMode);
PopulateFormView();
}
}

The ItemTemplate supports a databinding
expression that is used to bind the database
table column. The Eval() or Bind() method is used
to retrieves the values of these columns.

<ItemTemplate>
<table border="1">
<tr>
<th><b>EmpID:</b></th>
<td ><%# Eval("EmpID") %></td></tr>
<tr>
<td><b>Name:</b></td>
<td ><%# Eval("Name") %></td> </tr>
<tr>
<td><b>Gender:</b></td>
<td ><%#Eval("Gender") %></td></tr>
<tr>
<td><b>Salary:</b></td>
<td><%# Eval("Salary") %></td> </tr>
<tr>
<td><b>Address:</b></td>

<td><%# Eval("Address") %></td>
</tr>
<tr>
<td><b>DepID:</b></td>
<td><%#Eval("DepID") %>
</tr>
</table>
<asp:LinkButton ID="lnkEdit" Text="Edit
" CommandName="Edit" runat="server" />
<asp:LinkButton ID="lnkNew" Text="Ne
w" CommandName="New" runat="server" />
<asp:LinkButton ID="lnkDelete"
Text="Delete" CommandName="Delete"
runat="server" />
</ItemTemplate>

 We can perform paging with Form View
Control by using its AllowPaging property.
 By default Allow Paging property is false. Set
the value of Allow Paging property as true for
performing the paging.
 It will generate the paging link automatically.
Write code in Page Index Changing event as
follows.

protected void
FormView1_PageIndexChanging(object sender,
FormViewPageEventArgs e)
{
FormView1.PageIndex = e.NewPageIndex;
PopulateFormView();
}
OUTPUT:

 The Form View control uses templates to edit
records.
 It enables us to use Edit ItemTemplate and
specify the user interface.
 If we want simply display the record then use
Eval() method otherwise use Bind() method.
 For editing the record you must have editable
control, therefore we have used Text Box control
within Edit Item Template and bind the Text
property of Text Box

 If we click on Edit link, then Update and Cancel
link will display in place of Edit Link.
 By default these links are not available in Form
View control.
 We must provide these links in template fields
explicitly.
 Form View control has a Data Key Names
property that is used to hold the name of the
primary key from the database table.
 We have to specify a primary key explicitly when
editing records.

 This Link Button supports a Command Name
property which has the value Edit.
 When we click on Edit link the Form View mode is
changed from Read Only mode to "Edit" mode.
 We can use Button or Image Button control in
place of Link Button.
 The Bind("EmpID") method binds the Employee ID
column database table to the Text property of
the Text Box control.

<EditItemTemplate>
<table border="1">
<tr>
<td><asp:TextBox ID="txtEmpID"
Text='<%# Bind("EmpID") %>' runat="Server"
/></td>
</tr>
<tr>
<td><asp:TextBox ID="txtName"
Text='<%# Bind("Name") %>' runat="Server" /></td>
</tr>
<tr>
<td><asp:TextBox ID="txtGender"
Text='<%# Bind("Gender") %>' runat="Server"/>
</td>
</tr>
<tr>

 <td><b>Salary:</b></td>
<td><asp:TextBox ID="txtSalary"
Text='<%# Bind("Salary") %>' runat="Server"
/></td>
</tr>
<tr>
<td><asp:TextBox
ID="txtAddress" Text='<%# Bind("Address") %>'
runat="Server" /></td>
</tr>
<tr>
<td><asp:TextBox
ID="txtDeptID" Text='<%# Bind("DepID") %>'

</tr>
</table>
<asp:LinkButton
ID="lnkUpdate" Text="Update"
CommandName="Update" runat="server" />
<asp:LinkButton
ID="lnkCancel" Text="Cancel"
CommandName="Cancel" runat="server" />
</EditItemTemplate>
 When we click on Update link ItemUpdating event
fires.
 We have already added TextBox in
EditItemTemplate. Access these textboxes with
the help of FindControl method. Write code for
updating the record as given below.

protected void FormView1_ItemUpdating(object sender,
FormViewUpdateEventArgs e)
{
int ID =
Convert.ToInt32((FormView1.FindControl("txtEmpID") as
TextBox).Text);
string empName = (FormView1.FindControl("txtName") as
TextBox).Text;
string empGender = (FormView1.FindControl("txtGender")
as TextBox).Text;
double empSalary =
Convert.ToDouble((FormView1.FindControl("txtSalary") as
TextBox).Text);
string empAddress = (FormView1.FindControl("txtAddress")
as TextBox).Text;
int depID =
Convert.ToInt32((FormView1.FindControl("txtDeptID") as
TextBox).Text);
string updateQuery = "update tblEmps set
name='"+empName+"',
gender='"+empGender+"',salary="+empSalary+",address='
"+empAddress+"',
depid="+depID+" where empid="+ID;
cmd = new SqlCommand(updateQuery, conn);

conn.Open();
cmd.ExecuteNonQuery();
conn.Close();
FormView1.ChangeMode(FormViewMode.Re
adOnly);
PopulateFormView();
}
OUTPUT:

 We can insert new record into the database with
the help of Form View Control.
 Form View control supports Insert Item Template
that is used to insert new record in database.
 The Item Template contains the "New" Link
Button. When you click on "New" Link Button,
control goes from Read Only mode to Insert
mode. Insert and Cancel Link Button is appeared
in place of "New" Link Button.

<InsertItemTemplate>
<table border="1">
<tr>
<td><asp:TextBox ID="txtEmpID"
Text='<%# Bind("EmpID") %>' runat="Server" /></td>
</tr>
<tr>
<td><asp:TextBox ID="txtName"
Text='<%# Bind("Name") %>' runat="Server" /></td>
</tr>
<tr>
<td><asp:TextBox ID="txtGender"
Text='<%# Bind("Gender") %>' runat="Server" /> </td>
</tr>
<tr>

<td><b>Salary:</b></td>
<td><asp:TextBox ID="txtSalary"
Text='<%# Bind("Salary") %>' runat="Server"/>
</td>
</tr>
<tr>
<td><asp:TextBox
ID="txtAddress" Text='<%# Bind("Address") %>'
runat="Server" /> </td>
</tr>
<tr>
<td><asp:TextBox
ID="txtDeptID" Text='<%# Bind("DepID") %>'
</tr>
</table>
<asp:LinkButton ID="lnkInsert"
Text="Insert" CommandName="Insert" r

<asp:LinkButton ID="lnkCancel" Text="Cancel"
CommandName="Cancel" runat="server" />
</InsertItemTemplate>
When you click on Insert Link Button, ItemInserting event is fires.
protected void FormView1_ItemInserting(object sender,
FormViewInsertEventArgs e)
{
string ID = (FormView1.FindControl("txtEmpID") as
TextBox).Text;
string empName = (FormView1.FindControl("txtName") as
TextBox).Text;
string empGender = (FormView1.FindControl("txtGender") as
TextBox).Text;
double empSalary =
Convert.ToDouble((FormView1.FindControl("txtSalary") as
TextBox).Text);
string empAddress = (FormView1.FindControl("txtAddress") as
TextBox).Text;
string depID = (FormView1.FindControl("txtDeptID") as
TextBox).Text;
string insertQuery = "insert into tblEmps
values("+ID+",'"+empName+"','"+empGender+"',
"+empSalary+",'"+empAddress+"',"+depID+")";
cmd = new SqlCommand(insertQuery, conn);

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