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FACTORING
Factoring Quadratic Equation ax2
+ bx + c = 0, where a>1.
Example 1. Solve 2x2 – x – 6 = 0
Steps Solution
1. Write in standard form. 2x2 – x – 6 = 0
2. Factor the quadratic expression on the
left side of the equation using the
following process.
a. Multiply (a) (c)
b. Find the factors of -12 that gives you
the sum of the value of b which is -1.
c. Copy the expression and replace the
middle term as the value obtain in step b.
d. Factor using the groupings
(2).(-6) = -12
-12 = (-4).(3)
2x2 – x – 6 = 0
2x2 – 4x + 3x - 6 = 0
(2x2 – 4x) + (3x – 6) = 0
2x (x – 2) + 3 (x – 2) = 0
(2x + 3) (x – 2) = 0
3. Use the Zero Product Property. (2x + 3) (x – 2) = 0
So, (2x + 3 ) = 0 and (x – 2) = 0
4. Solve for the roots 2x + 3 = 0 and x – 2 = 0
2x = -3 and x = 2
𝟐𝒙
𝟐
=
−𝟑
𝟐
x = -
𝟑
𝟐
Therefore, the roots of x2 + 3x + 2 = 0 are x = -1 and x = -2.
Example 2. Solve for the roots of 10x2 + 3x - 1 = 0
Steps Solution
1.Write in standard form 10x2 + 3x – 1 = 0
2. Factor the expression on the left side.
a. Multiply (a). (c)
b. Factors of -10 that gives the sum of b
which is 3.
c. Copy the expression and replace the
middle term.
d. Factor using groupings.
(10) . (-1) = -10
(3)= (5) . (-2)
10x2 + 3x – 1 = 0
10x2 + 5x – 2x – 1 = 0
(10x2 + 5x) – (2x – 1) = 0
5x(2x + 1) – 1(2x + 1) = 0
(5x – 1) (2x + 1) = 0
3. Use the Zero Product Property
.
(5x - 1) (2x + 1) = 0
So, 5x – 1 = 0 and 2x + 1 = 0
4. Solve for the roots. 5x – 1 = 0 and 2x + 1 = 0
5x = 1 and 2x = -1
x =
𝟏
𝟓
and x = -
𝟏
𝟐
So, the roots of 10x2 + 3x – 1 = 0 are x =
𝟏
𝟓
and x = -
𝟏
𝟐
Example 3. Find the roots of 3x2 = x + 2
Steps Solution
1.Write in standard form 3x2 – x – 2 = 0
2. Factor the left side of the expression.
a. Multiply (a) . (c) (3). (-2) = -6
b. Find the factors of 6 that gives you
the sum of the value of b which is -1.
c. Copy the expression and replace the
middle term by the value obtain in step
b.
d. Factor using the method of
groupings.
(-1) = (-3) . (2)
3x2 – x – 2 = 0
3x2 – 3x + 2x – 2 = 0
(3x2 – 3x) + (2x – 2) = 0
3x(x – 1) + 2(x – 1) = 0
(3x + 2) (x – 1) = 0
3. Use the Zero Product Property (3x + 2) (x – 1) = 0
(3x + 2) = 0 and (x – 1) = 0
4. Solve for the roots. 3x + 2 = 0 and (x – 1) = 0
3x = -2 and x = 1
3𝑥
3
=
−2
3
x = -
𝟐
𝟑
Therefore, the roots of 3x2 = x + 2 are -
𝟐
𝟑
and 1.
ThankYou!

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Factoring2

  • 2. Factoring Quadratic Equation ax2 + bx + c = 0, where a>1.
  • 3. Example 1. Solve 2x2 – x – 6 = 0 Steps Solution 1. Write in standard form. 2x2 – x – 6 = 0 2. Factor the quadratic expression on the left side of the equation using the following process. a. Multiply (a) (c) b. Find the factors of -12 that gives you the sum of the value of b which is -1. c. Copy the expression and replace the middle term as the value obtain in step b. d. Factor using the groupings (2).(-6) = -12 -12 = (-4).(3) 2x2 – x – 6 = 0 2x2 – 4x + 3x - 6 = 0 (2x2 – 4x) + (3x – 6) = 0 2x (x – 2) + 3 (x – 2) = 0 (2x + 3) (x – 2) = 0
  • 4. 3. Use the Zero Product Property. (2x + 3) (x – 2) = 0 So, (2x + 3 ) = 0 and (x – 2) = 0 4. Solve for the roots 2x + 3 = 0 and x – 2 = 0 2x = -3 and x = 2 𝟐𝒙 𝟐 = −𝟑 𝟐 x = - 𝟑 𝟐 Therefore, the roots of x2 + 3x + 2 = 0 are x = -1 and x = -2.
  • 5. Example 2. Solve for the roots of 10x2 + 3x - 1 = 0 Steps Solution 1.Write in standard form 10x2 + 3x – 1 = 0 2. Factor the expression on the left side. a. Multiply (a). (c) b. Factors of -10 that gives the sum of b which is 3. c. Copy the expression and replace the middle term. d. Factor using groupings. (10) . (-1) = -10 (3)= (5) . (-2) 10x2 + 3x – 1 = 0 10x2 + 5x – 2x – 1 = 0 (10x2 + 5x) – (2x – 1) = 0 5x(2x + 1) – 1(2x + 1) = 0 (5x – 1) (2x + 1) = 0
  • 6. 3. Use the Zero Product Property . (5x - 1) (2x + 1) = 0 So, 5x – 1 = 0 and 2x + 1 = 0 4. Solve for the roots. 5x – 1 = 0 and 2x + 1 = 0 5x = 1 and 2x = -1 x = 𝟏 𝟓 and x = - 𝟏 𝟐 So, the roots of 10x2 + 3x – 1 = 0 are x = 𝟏 𝟓 and x = - 𝟏 𝟐
  • 7. Example 3. Find the roots of 3x2 = x + 2 Steps Solution 1.Write in standard form 3x2 – x – 2 = 0 2. Factor the left side of the expression. a. Multiply (a) . (c) (3). (-2) = -6 b. Find the factors of 6 that gives you the sum of the value of b which is -1. c. Copy the expression and replace the middle term by the value obtain in step b. d. Factor using the method of groupings. (-1) = (-3) . (2) 3x2 – x – 2 = 0 3x2 – 3x + 2x – 2 = 0 (3x2 – 3x) + (2x – 2) = 0 3x(x – 1) + 2(x – 1) = 0 (3x + 2) (x – 1) = 0
  • 8. 3. Use the Zero Product Property (3x + 2) (x – 1) = 0 (3x + 2) = 0 and (x – 1) = 0 4. Solve for the roots. 3x + 2 = 0 and (x – 1) = 0 3x = -2 and x = 1 3𝑥 3 = −2 3 x = - 𝟐 𝟑 Therefore, the roots of 3x2 = x + 2 are - 𝟐 𝟑 and 1.