EXAM II(Practice)
Charles Zhang
Spring 2015
Math 220 Name:_______________________
Show work to get partial credit, and show enough work to get full credit!
1. Find each of the following limits or state it does not exist (DNE):
(1)
2
2 20
1 1
lim
x
x
x x
 
 
 
 
(2)
0
lim
x
( )f x where 4sin)(4 2
 xxfx
(3)
2
3
2 15
lim
3x
x x
x
 

(4)
867
345
lim 2
2


 xx
xx
x
(5)  1215lim 22


xxxx
x
(6)  1215lim 22


xxxx
x
2. Given the graph of y = ( )f x as follows:
Find each of the following if it exists.
(a)
1
lim ( )
x
f x
 
(b)
1
lim ( )
x
f x
 
(c)
1
lim ( )
x
f x

(d) Why is ( )f x discontinuous at x=1?
(e) Classify the discontinuity of ( )f x at x=1 as (circle one):
Removable Jump Infinite
(f) Is f(x) continuous from the left? (circle one)
Yes No
(g) Is f(x) continuous from the right? (circle one)
Yes No
3. Find the interval over which each of the following function is continuous:
(a) ln( 2)y x 
(b) 2
sin( 2)y x 
(c)
1
2
y
x


4. (a) How close to 3 do we have to take x so that 7x - 6 is within a distance of 0.001
from 15? The equivalent problem is: find  such that
|(7x - 6) - 15|< 0.001 whenever |x - 3|<  .
(b) What is the related limit? (Circle one)
(1)
15
lim
x
(7x - 6) = 3
(2)
3
lim
x
(7x - 6) = 15
(3)
3
lim
x
(7x - 6) does not exist
(4)
3
lim
x
(7x - 6) = .001
5. Use The Intermediate Value Theorem to show that the equation cos sin 0x x x  has
a solution in the interval
.
 2 , 3 
..
6. Evaluate the limit in terms of the constant involved:
1 1
lim , 0
h a
a h a
h a



7. Find the values of , ,a b c which make the function continuous:













xifc
xbifx
bxifxx
xifa
xf
4
43
0)8(
4
1
0
)(
8. Find the limit:








 2
sinlim
0 x
x
x

9. Find each of the following derivatives by definition:
(a) )2(f  for
3
2
)(


x
xf
(b) )(ag for 1)(  ttg
(c) )(xh for 32)( 2
 xxxh
10. Find the value of a so that the following function will be continuous every where:










5
5
5
152
)(
2
xifa
xif
x
xx
xf

Exam ii(practice)

  • 1.
    EXAM II(Practice) Charles Zhang Spring2015 Math 220 Name:_______________________ Show work to get partial credit, and show enough work to get full credit! 1. Find each of the following limits or state it does not exist (DNE): (1) 2 2 20 1 1 lim x x x x         (2) 0 lim x ( )f x where 4sin)(4 2  xxfx (3) 2 3 2 15 lim 3x x x x    (4) 867 345 lim 2 2    xx xx x (5)  1215lim 22   xxxx x (6)  1215lim 22   xxxx x 2. Given the graph of y = ( )f x as follows: Find each of the following if it exists. (a) 1 lim ( ) x f x   (b) 1 lim ( ) x f x   (c) 1 lim ( ) x f x  (d) Why is ( )f x discontinuous at x=1? (e) Classify the discontinuity of ( )f x at x=1 as (circle one): Removable Jump Infinite (f) Is f(x) continuous from the left? (circle one) Yes No
  • 2.
    (g) Is f(x)continuous from the right? (circle one) Yes No 3. Find the interval over which each of the following function is continuous: (a) ln( 2)y x  (b) 2 sin( 2)y x  (c) 1 2 y x   4. (a) How close to 3 do we have to take x so that 7x - 6 is within a distance of 0.001 from 15? The equivalent problem is: find  such that |(7x - 6) - 15|< 0.001 whenever |x - 3|<  . (b) What is the related limit? (Circle one) (1) 15 lim x (7x - 6) = 3 (2) 3 lim x (7x - 6) = 15 (3) 3 lim x (7x - 6) does not exist (4) 3 lim x (7x - 6) = .001 5. Use The Intermediate Value Theorem to show that the equation cos sin 0x x x  has a solution in the interval .  2 , 3  .. 6. Evaluate the limit in terms of the constant involved: 1 1 lim , 0 h a a h a h a    7. Find the values of , ,a b c which make the function continuous:              xifc xbifx bxifxx xifa xf 4 43 0)8( 4 1 0 )( 8. Find the limit:          2 sinlim 0 x x x 
  • 3.
    9. Find eachof the following derivatives by definition: (a) )2(f  for 3 2 )(   x xf (b) )(ag for 1)(  ttg (c) )(xh for 32)( 2  xxxh 10. Find the value of a so that the following function will be continuous every where:           5 5 5 152 )( 2 xifa xif x xx xf