Could someone help me with this Linux system program- Using C language.docx
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Could someone help me with this Linux system program. Using C language. Write your own simple client/server set of processes. The client should use a shared memory segment to send a command message to the server. The server process should monitor the shared memory segment, and respond as follows: \"HI\" -- The server prints \"Greetings\" to the screen. \"PID\" -- The server prints it\'s process id to the screen. \"QUIT\" -- The server terminates gracefully, detaching and releasing the shared memory segment. Sample run: Client : Server: HI PID QUIT Solution #include #include #include #include #include #include #include #include #include #include int main(int argc, char *argv[]) { int listenfd = 0, connfd = 0; struct sockaddr_in serv_addr; char sendBuff[1025]; time_t ticks; listenfd = socket(AF_INET, SOCK_STREAM, 0); memset(&serv_addr, \'0\', sizeof(serv_addr)); memset(sendBuff, \'0\', sizeof(sendBuff)); serv_addr.sin_family = AF_INET; serv_addr.sin_addr.s_addr = htonl(INADDR_ANY); serv_addr.sin_port = htons(5000); bind(listenfd, (struct sockaddr*)&serv_addr, sizeof(serv_addr)); listen(listenfd, 10); while(1) { connfd = accept(listenfd, (struct sockaddr*)NULL, NULL); ticks = time(NULL); snprintf(sendBuff, sizeof(sendBuff), \"%.24s\ \ \", ctime(&ticks)); write(connfd, sendBuff, strlen(sendBuff)); close(connfd); sleep(1); } } .
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![Could someone help me with this Linux system program. Using C language.
Write your own simple client/server set of processes. The client should use a shared memory
segment to send a command message to the server. The server process should monitor the shared
memory segment, and respond as follows:
"HI" -- The server prints "Greetings" to the screen.
"PID" -- The server prints it's process id to the screen.
"QUIT" -- The server terminates gracefully, detaching and releasing the shared memory
segment.
Sample run:
Client :
Server:
HI PID QUIT
Solution
#include #include #include #include #include #include #include #include #include #include int
main(int argc, char *argv[]) { int listenfd = 0, connfd = 0; struct sockaddr_in serv_addr; char
sendBuff[1025]; time_t ticks; listenfd = socket(AF_INET, SOCK_STREAM, 0);
memset(&serv_addr, '0', sizeof(serv_addr)); memset(sendBuff, '0', sizeof(sendBuff));
serv_addr.sin_family = AF_INET; serv_addr.sin_addr.s_addr = htonl(INADDR_ANY);
serv_addr.sin_port = htons(5000); bind(listenfd, (struct sockaddr*)&serv_addr,
sizeof(serv_addr)); listen(listenfd, 10); while(1) { connfd = accept(listenfd, (struct
sockaddr*)NULL, NULL); ticks = time(NULL); snprintf(sendBuff, sizeof(sendBuff), "%.24s
", ctime(&ticks)); write(connfd, sendBuff, strlen(sendBuff)); close(connfd); sleep(1); } }](https://image.slidesharecdn.com/couldsomeonehelpmewiththislinuxsystemprogram-usingclanguage-230131011203-7bd7f76e/85/Could-someone-help-me-with-this-Linux-system-program-Using-C-language-docx-1-320.jpg)
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so
ln To = - ln No + C
C = ln To + ln No = ln To*No
so
ln T = ln To*No - ln n
ln T = ln (To*No/n)
T = (To*No)/n
as n = Nf = 0
Twill tend to infinity...this is not practically possible
.
A soil is shaken with water and then allowed to stand- After standing-.docx
A soil is shaken with water and then allowed to stand. After standing:
the soil particles will settle out of the water
only the soluble metals will remain in the water
the insoluble metals will settle to the bottom with the soil
all of the above will occur
Solution
Option d is The correct answer that is all the above will occur as per given options.
.
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20145-5SumII_CSC407_assign1.htmlCSC 407 Computer Systems II.docx
20145-5SumII_CSC407_assign1.html
CSC 407: Computer Systems II: 2015 Summer II, Assignment #1
Last Modified 2015 July 21Purpose:
To go over issues related to how the compiler and the linker
serve you, the programmer.
Computing
Please ssh into ctilinux1.cstcis.cti.depaul.edu, or use your own Linux machine.
Compiler optimization (45 Points)
Consider the following program.
/* q1.c
*/
#include <stdlib.h>
#include <stdio.h>
#define unsigned int uint
#define LENGTH ((uint) 512*64)
int initializeArray (uint len,
int* intArray
)
{
uint i;
for (i = 0; i < len; i++)
intArray[i] = (rand() % 64);
}
uint countAdjacent (int maxIndex,
int* intArray,
int direction
)
{
uint i;
uint sum = 0;
for (i = 0; i < maxIndex; i++)
if ( ( intArray[i] == (intArray[i+1] + direction) ) &&
( intArray[i] == (intArray[i+2] + 2*direction) )
)
sum++;
return(sum);
}
uint funkyFunction (uint len,
int* intArray
)
{
uint i;
uint sum = 0;
for (i = 0; i < len-1; i++)
if ( (i % 8) == 0x3 )
sum += 7*countAdjacent(len-2,intArray,+1);
else
sum += 17*countAdjacent(len-2,intArray,-1);
return(sum);
}
int main ()
{
int* intArray = (int*)calloc(LENGTH,sizeof(int));
initializeArray(LENGTH,intArray);
printf("funkyFunction() == %d\n",funkyFunction(LENGTH,intArray));
free(intArray);
return(EXIT_SUCCESS);
}
(8 Points) Compile it for profiling but with no extra optimization with:
$ gcc -o q1None -pg q1.c # Compiles q1.c to write q1None to make profile info
$ ./q1None # Runs q1None
$ gprof q1None # Gives profile info on q1None
Be sure to scroll all the way to the top of gprof output!
What are the number of self seconds taken by:
FunctionSelf secondsinitializeBigArray()__________countAdjaceent()__________funkyFunction()__________
(8 Points)
How did it do the operation (i % 8) == 0x3?
Was it done as a modulus (the same as an expensive division, but returns the remainder instead of the quotient) or something else?
Show the assembly language for this C code
using gdb to dissassemble
funkyFunction() of q1None.
Hint: do:
$ gdb q1None
. . .
(gdb) disass funkyFunction
Dump of assembler code for function funkyFunction:
. . .
and then look for the code that sets up the calls to countAdjacent().
The (i % 8) == 0x3 test is done before either countAdjacent() call.
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What are the number of self seconds taken by:
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CODE FOR echo_client.c:
/* A simple echo client using TCP */
#include
#include
#include
#include
#include
#include
#include
#include
#include
#define SERVER_TCP_PORT 3000 /* well-known port */
#define BUFLEN 256 /* buffer length */
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port = SERVER_TCP_PORT;
break;
case 3:
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CODE FOR echo_server.c:
/* A simple echo server using TCP */
#include
#include
#include
#include
#include
#include
#include
#include
#include
#define SERVER_TCP_PORT 3000 /* well-known port */
#define BUFLEN 256 /* buffer length */
int echod(int);
void reaper(int);
int main(int argc, char **argv)
{
int sd, new_sd, client_len, port;
struct sockaddr_in server, client;
switch(argc){
case 1:
port = SERVER_TCP_PORT;
break;
case 2:
port = atoi(argv[1]);
break;
default:
fprintf(stderr, "Usage: %s [port]\n", argv[0]);
exit(1);
}
/* Create a stream socket */
if ((sd = socket(AF_INET, SOCK_STREAM, 0)) == -1) {
fprintf(stderr, "Can't creat a socket\n");
exit(1);
}
/* Bind an address to the socket */
bzero((char *)&server, sizeof(struct sockaddr_in));
server.sin_family = AF_INET;
server.sin_port = htons(port);
server.sin_addr.s_addr = htonl(INADDR_ANY);
if (bind(sd, (struct sockaddr *)&server, sizeof(server)) == -1){
fprintf(stderr, "Can't bind name to socket\n");
exit(1);
}
/* queue up to 5 connect requests */
listen(sd, 5);
(void) signal(SIGCHLD, reaper);
while(1) {
client_len = sizeof(client);
new_sd = accept(sd, (struct sockaddr *)&client, &client_len);
if(new_sd < 0){
fprintf(stderr, "Can't accept client \n");
exit(1);
}
switch (fork()){
case 0: /* child */
(void) close(sd);
exit(echod(new_sd));
default: /* parent */
(void) close(new_sd);
break;
case -1:
fprintf(stderr, "fork: error\n");
}
}
}
/* echod program */
int echod(int sd)
{
char *bp, buf[BUFLEN];
int n,.
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A rigid, well-insulated gas cylinder contains N0 moles of an ideal gas at a temperature To  and pressure Po. A venting valve is opened and the gas is pumped out of the tank. Derive an expression for the instantaneous temperature in the cylinder as a function of the number of moles of gas remaining in the cylinder. What is the final temperature Tf, if the tank is evacuated to Nf = 0? Is the prediction physically realistic? The heat  capacity at constant volume of the gas is independent of temperature.
Solution
PV = nRT
nT = PV/R = constant
nT = K
Tdn + ndT = 0
Tdn = - ndT
dT/dn = - T/n
dT/T = -dn/n
Integrating both sides
ln T = - ln n + C
at n=No ; T =To
so
ln To = - ln No + C
C = ln To + ln No = ln To*No
so
ln T = ln To*No - ln n
ln T = ln (To*No/n)
T = (To*No)/n
as n = Nf = 0
Twill tend to infinity...this is not practically possible
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A soil is shaken with water and then allowed to stand- After standing-.docx
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the insoluble metals will settle to the bottom with the soil
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a societal right- None of the above- a group right- Both A and B- an i.docx
a societal right.
None of the above.
a group right.
Both A and B.
an individual right.
Solution
1) quota , goal
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Solution
The image from the first (convex) lens is formed at a distance i1 from the object
1/o1 + 1/i1 = 1/f1
1/401 + 1/i1 = 1/39
i1 = 43.2 cm
This image is formed 43.2 - 36.0 = 7.2 cm behind the second lens. That becomes the virtual image of the convex lens at i2 = -7.2 cm.
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A priniciple purpose of a representation letter from management is to:
Solution
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Solution
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Critical thinking question- what structural features (hint- there are.docx
Critical thinking question: what structural features (hint: there are four) do all ten of these opioid drugs have in common?
Opioids Opioids are a powerful class of alkaloids that act on the central nervous narcotic analgesics. All opioids presumably bind to the same mu-opioid receptor sites in the brain and spinal cord. The most prevalent naturally occurring isolated from the opium poppy-is morphine (named after Morpheus, the sod of dreams). A methoxy derivative of morphine that is also isolated from opium poppy is codeine, which is both less addictive and less effective as a reliever than morphine. By contrast, the diacetyl derivative of morphine (heroin) isanalgesic not only a more powerful as a narcotic but also more addictive than morphine Many other synthetic derivatives of morphine are opioid agonists that are used as narcotic analgesics (including oxycodone, oxymorphone, hyd system as a plant-derived nitrogenout bases that have pronounced physiologial acevity on humans the arcotic a drug dhas numbs the ngonisa molecule that combines antagonist a molecule that inhibits senses and induces stupor a druE hat with a receptor to initiate and meperidine), while others (such as methadone and buprenorphine) are used to treat opioid addiction. Naloxone is an opioid antagonist that is used to counteract opioid overdose the physiological action of anocher CHyo 0 CH, Ho* CH CH (OxyContin) (Opana) Dlaudid) (Demerol Ph N-CH3 CHa (where Ph (Butrans, Suboxone) ritical Thinking Question Phat structural features (hint: there are four) do all ten of these opioid drugs have in commom? mene ving, Contein nivonen
Solution
Common features in all the given opiod structures are -
1. Presnece of a tertiary amine group.
2. Presence of a phenyl ring.
3. At least two rings are there in all the molecules.
4.All the opioids are polar compounds.
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Solution
/*Program to replace EVEN elements by 0 and ODD elements by 1.*/
#include <stdio.h>
/** funtion : readArray()
input : arr ( array of integer ), size
to read ONE-D integer array from standard input device (keyboard).
**/
void readArray(int arr[], int size)
{
int i =0;
printf(\"\ Enter elements : \ \");
for(i=0; i < size; i++)
{
printf(\"Enter arr[%d] : \",i);
scanf(\"%d\",&arr[i]);
}
}
/** funtion : printArray()
input : arr ( array of integer ), size
to display ONE-D integer array on standard output device (moniter).
**/
void printArray(int arr[], int size)
{
int i =0;
printf(\"\ Elements are : \");
for(i=0; i < size; i++)
{
printf(\"\ \\tarr[%d] : %d\",i,arr[i]);
}
printf(\"\ \");
}
/** funtion : replaceEvenOdd()
input : arr ( array of integer ), size
to replace EVEN elements by 0 and ODD elements by 1.
**/
void replaceEvenOdd(int arr[], int size)
{
int i=0;
for(i=0; i < size; i++)
{
if( arr[i] % 2 == 0 )
arr[i] = 0 ;
else
arr[i] = i;
}
}
int main()
{
int arr[10];
readArray(arr,10);
printf(\"\ Before replacement : \");
printArray(arr,10);
replaceEvenOdd(arr,10);
printf(\"\ After replacement : \");
printArray(arr,10);
return 0;
}
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Create a text file that contains ten person objects where each object.docx
Create a text file that contains ten person objects where each object is represented on a separated line with each attribute separated by a comma. Create a method that reads form the file, creates one person object per line, and stores the object in an Array List object. Write the stored objects out by last name of the console.
Solution
//Program
package person;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.util.ArrayList;
import java.util.Scanner;
//person class
class Person
{
String lastname;
String firstname;
int age;
public Person(String last, String first, int a)
{
firstname=first;
lastname=last;
age=a;
}
@Override
public String toString()
{
return (lastname+\" \"+firstname+\" \"+age);
}
}
public class PersonDemo {
public static void main(String[] args) throws FileNotFoundException {
//creating array list
ArrayList <Person> persons=new ArrayList<>();
//reading person data file
Scanner infile=new Scanner(new FileReader(\"person.txt\"));
while(infile.hasNextLine())
{
String words[]=infile.nextLine().split(\",\");
persons.add(new Person(words[0],words[1],Integer.parseInt(words[2])));
}
//display person s details
System.out.println(\"Person details: \");
for(int i=0;i<persons.size();i++)
{
System.out.println(persons.get(i).toString());
}
}
}
///////////////////////////////////////////////////////////////////
//person.txt input file
Joseph,Daniel,23
Jhon,Stephen,34
Joseph,Maria,25
Fernandez,George,67
Jaitely,Arun,29
Kumar,Narendra,50
Victor,Prince,40
George,Jincy,35
Roldan,Tinu,28
Antony,Tim,27
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Create a polynomial function that meets the following conditions- Expl.docx
Create a polynomial function that meets the following conditions. Explain how you created your polynomial.
4. Degree 3, 2 positive real zeros, 1 negative real zero, 0 complex zeros.
Polynomial:
Solution
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Create a method assuming we have a listed list- use linear search in j.docx
Create a method a ssuming we have a listed list, use linear search in java
Create a method assuming we have a listed list, use linear search in java//Linear Search in a Linked List public static void LinkedListSearch(intNode head, int key)
Solution
Since you have not specified structure of IntNode class,so I am assuming that structure of IntNode:
class IntNode{
int data;
IntNode next;
//other methods and constructors
}
public static void LinkedListSearch(IntNode head, int key){
while(head != null){
if(head.data == key){ // if found, then print message and return
System.out.println(key+\" is founded!!\");
return;
}
head = head.next;
}
System.out.println(key+ \"is not in linked list\");
}
.
Create a JAVA Program that traverses through an array recursively- rat.docx
Create a JAVA Program that traverses through an array recursively, rather than with a loop, and prints out each element in the array. Java only, this will be a short program.
Solution
public void dosomethingtoall(List list)
{
//begin recurssion dosomethingtoall(list,0);
}
private void dosomethingtoall(Last list,int index)
{
//break recurssion when to proceed entire list.
if(index>=list.size())
return;
//do what ever you want with the list.
process(list.get(index));
//recursive step.process the next element.
dosomethingtoall(list,index+1);
}
or by using traversal
import java.util.Listiterator;
import java.util.Arraylist;
public class
traverseforwordingusingListiteratorexample
{
public static void main(String args[])
{
//create an array of object list
Arraylist alist=new Arraylist();
//add elements to arraylist object
alist.add(\"1\");
alist.add(\"2\");
alist.add(\"3\");
alist.add(\"4\");
alist.add(\"5\");
//get an object of Listiterator using listiteratot()
Listiterator listiterator=alist.listiterator();
/*traverse arraylist in forward direction using hasNext and next methods of listiterator.hasNEXT Returns true if Listiterator has more elements to traverse in forwrd direction.next methid returns next element in the list*/
Sysytem.out.println(\"traversing arraylist in forward direction using Listiterator\");
while(listiterator.hasNext())
system.out.println(listiterator.next());
}
}
.
Create a Java Applet that uses two integer (int) variables x and y to.docx
Create a Java Applet that uses two integer (int) variables x and y to place the picture of four circles on the screen. Alternate the colors by setting the g.setColor method . Also, use the g.drawString to place your name above the circles.
Solution
import java.applet.*;
import java.awt.*;
public class Bullseye extends Applet {
public void paint(Graphics g) {
int appletHeight = this .getSize().height;
int appletWidth = this .getSize().width;
for ( int i=8; i >= 0; i--) {
if ((i % 2) == 0) g.setColor(Color.red);
else g.setColor(Color.white);
// Center the rectangle
int rectHeight = appletHeight*i/8;
int rectWidth = appletWidth*i/8;
int rectLeft  = appletWidth/2 - i*appletWidth/16;
int rectTop   = appletHeight/2 - i*appletHeight/16;
g.fillOval(rectLeft, rectTop, rectWidth, rectHeight);
}
}
}
.
Create a function called findChar that will return the index of where.docx
Create a function called findChar that will return the index of where a particular character is found within a CString.
Your function should take as parameters the CString to search through and a character variable to search for.
The function will return the index of where the character was first found.
If the array does not have the character in it, your function should return -1.
NOTE: Do not convert or cast the characters to int\'s to do the searching. At this point you should be able to traverse a CString.
Solution
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class FindingIndex{
public static void main(String args[]){
String [] Cstring = new String [10];
System.out.println(\"Please enter the string \");
System.out.println(\"Character to search\");
Scanner in = new Scanner(System.in);
Cstring = in.nextLine();
char c = in.nextChar();
CstringIndex(Cstring,c);
}
public static int CstringIndex(String[] Cstring2,char newchar){
for(int i=0;i<Cstring2.length();i++)
{
if(c == Cstring2[i])
{
System.out.println(\"Index of the character \"+i);
break;
}
else
{
System.out.println(\"-1\");
}
}
}
}
.
Contrast the argument that terrorist acts are easy to predict with the.docx
Contrast the argument that terrorist acts are easy to predict with the argument that they cannot be identified or predicted. Write it 4-5 paragraph with resources(References).
Solution
By using technology it was easy to predict the terrorist acts. This is because terrorists use social media sites for communication and now-a-days there are many pattern recognization and data mining algorithms are implemented to identify the words and to predict the next action of the terrorists
reference:http://www.iflscience.com/technology/how-technology-help-predict-terrorist-attacks/
And even though advancement of technology cannot predict the terrorist act all the time, because if the terrorists are at one place then they don\'t use the internet or social media sites, so there will be no chance of prediction.
But NSA, which have access to almost every device in the world can easily predict the action of every human being in the world and there are many other security agencies like NSA also can do this thing. Majorly, technology plays an important role in identifying or predicting the action of terrorists
.
contemporary financial management What are the differences between the.docx
contemporary financial management What are the differences between the primary and secondary markets?
Solution
The difference between the primary capital market and the secondary capital market is that in the primary market, investors buy securities directly from the company issuing them, while in the secondary market, investors trade securities among themselves, and the company with the security being traded does not participate in the transaction.
.
Constants Part A By measurement you determine that sound waves are spr.docx
Constants Part A By measurement you determine that sound waves are spreading out equally in all directions from a point source and that the intensity is 2.7x10-2 W/m2 at a distance of 4.5 Im from the source What is the intensity at a distance of 3.5 m from the source? Express your answer using two significant figures W/m2 Submit Incorrect. Try Again; 6 attempts remaining Part B How much sound energy does the source emit in one hour if its power output remains constant? Express your answer using two significant figures Submit
Solution
Part A.
Intensity is given by:
I = P/A = P/(4*pi*r^2)
Since Source is same at both distance, So Power is constant, which means intensity is inversely proportional to square of distance from source.
I2/I1 = (r1/r2)^2
I2 = I1*(r1/r2)^2
I2 = 2.7*10^-2*(4.5/3.5)^2
I2 = 4.5*10^-2 W/m^2
Part B.
Power of source will be
P = I*4*pi*r^2
P = 2.7*10^-2*4*pi*4.5^2
P = 6.87 W
Now energy is given by:
E = Power*time
E = P*t
t = 1 hr = 3600 sec
E = 6.87*3600
E = 24732 J = 2.5*10^4 J
Please Upvote.
.
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