Create a function called findChar that will return the index of where.docx
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Create a function called findChar that will return the index of where a particular character is found within a CString. Your function should take as parameters the CString to search through and a character variable to search for. The function will return the index of where the character was first found. If the array does not have the character in it, your function should return -1. NOTE: Do not convert or cast the characters to int\'s to do the searching. At this point you should be able to traverse a CString. Solution import java.util.Scanner; import java.io.*; import java.lang.*; public class FindingIndex{ public static void main(String args[]){ String [] Cstring = new String [10]; System.out.println(\"Please enter the string \"); System.out.println(\"Character to search\"); Scanner in = new Scanner(System.in); Cstring = in.nextLine(); char c = in.nextChar(); CstringIndex(Cstring,c); } public static int CstringIndex(String[] Cstring2,char newchar){ for(int i=0;i<Cstring2.length();i++) { if(c == Cstring2[i]) { System.out.println(\"Index of the character \"+i); break; } else { System.out.println(\"-1\"); } } } } .
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![Create a function called findChar that will return the index of where a particular character is
found within a CString.
Your function should take as parameters the CString to search through and a character variable
to search for.
The function will return the index of where the character was first found.
If the array does not have the character in it, your function should return -1.
NOTE: Do not convert or cast the characters to int's to do the searching. At this point you
should be able to traverse a CString.
Solution
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class FindingIndex{
public static void main(String args[]){
String [] Cstring = new String [10];
System.out.println("Please enter the string ");
System.out.println("Character to search");
Scanner in = new Scanner(System.in);
Cstring = in.nextLine();
char c = in.nextChar();
CstringIndex(Cstring,c);
}
public static int CstringIndex(String[] Cstring2,char newchar){
for(int i=0;i<Cstring2.length();i++)
{
if(c == Cstring2[i])
{
System.out.println("Index of the character "+i);
break;](https://image.slidesharecdn.com/createafunctioncalledfindcharthatwillreturntheindexofwhere-230131011206-bac503d0/85/Create-a-function-called-findChar-that-will-return-the-index-of-where-docx-1-320.jpg)
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In the given example only one object will be created. Firstly JVM will not find any string object with the value “Welcome” in the string constant pool, so it will create a new object. After that it will find the string with the value “Welcome” in the pool, it will not create a new object but will return the reference to the same instance. In this article, we will learn about Java Strings.
M C6java7
The document provides an overview of Strings and StringBuilders in Java. It discusses Strings as immutable objects and how StringBuilders can be more efficient for modifying strings. It also covers common String and StringBuilder methods, when to use each, and exceptions in Java using try/catch blocks.
CPP Homework Help
This document provides information about C++ classes and objects. It discusses arrays of class objects, static members and variables, const member functions, and string objects. It also includes examples of catching bugs in C++ code snippets and implementing classes for points, polygons, and rectangles.
07slide
The document discusses processing strings in Java using the String, StringBuffer, and StringTokenizer classes. It provides details on constructing and manipulating strings, including obtaining length, retrieving characters, concatenation, substrings, comparisons, and conversions. It also covers the StringBuffer class for processing mutable strings, and the StringTokenizer class for extracting tokens from strings. Examples provided demonstrate checking palindromes, counting letters, using StringBuffer for output, and processing command-line arguments.
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In the given example only one object will be created. Firstly JVM will not fi...
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More from mrichard5
A rigid- well-insulated gas cylinder contains N0 moles of an ideal gas.docx
A rigid, well-insulated gas cylinder contains N0 moles of an ideal gas at a temperature To  and pressure Po. A venting valve is opened and the gas is pumped out of the tank. Derive an expression for the instantaneous temperature in the cylinder as a function of the number of moles of gas remaining in the cylinder. What is the final temperature Tf, if the tank is evacuated to Nf = 0? Is the prediction physically realistic? The heat  capacity at constant volume of the gas is independent of temperature.
Solution
PV = nRT
nT = PV/R = constant
nT = K
Tdn + ndT = 0
Tdn = - ndT
dT/dn = - T/n
dT/T = -dn/n
Integrating both sides
ln T = - ln n + C
at n=No ; T =To
so
ln To = - ln No + C
C = ln To + ln No = ln To*No
so
ln T = ln To*No - ln n
ln T = ln (To*No/n)
T = (To*No)/n
as n = Nf = 0
Twill tend to infinity...this is not practically possible
.
A soil is shaken with water and then allowed to stand- After standing-.docx
A soil is shaken with water and then allowed to stand. After standing:
the soil particles will settle out of the water
only the soluble metals will remain in the water
the insoluble metals will settle to the bottom with the soil
all of the above will occur
Solution
Option d is The correct answer that is all the above will occur as per given options.
.
a societal right- None of the above- a group right- Both A and B- an i.docx
a societal right.
None of the above.
a group right.
Both A and B.
an individual right.
Solution
1) quota , goal
2) By the end of 19th century , the supreme court was interpreting statutes and amendments in such a way that freedom for black americans were expanded
3) an individual right for owns a fire arm and may posses a gun on his person may consider his gun ownership in district of columbia.
.
A simple camera telephoto lens consists of two How far behind the conc.docx
A simple camera telephoto lens consists of two How far behind the concave lens should the film be placed? Express your answer using two significant figures concave lens with a focal length f210.1 cm The object to be photographed is 4.01 m in front of the objective lens. cm Submit Part B What is the linear magnification of this lens combination? Express your answer using two significant figures.
Solution
The image from the first (convex) lens is formed at a distance i1 from the object
1/o1 + 1/i1 = 1/f1
1/401 + 1/i1 = 1/39
i1 = 43.2 cm
This image is formed 43.2 - 36.0 = 7.2 cm behind the second lens. That becomes the virtual image of the convex lens at i2 = -7.2 cm.
The object for that image is 1/o2 + 1/i2 = -1/f2
1/o2 - 1/7.2 = -1/10.1
o2 = 25.1 cm
o2 is actually the image of the lens system (interchange object and image in the concave lens formula).
Image i1 has magnification 43.2/401 = 0.108, and the image i2 has magnification 25.1/7.2 = 3.5. Overall magnification is 0.108*3.5 = 0.378
.
A priniciple purpose of a representation letter from management is to-.docx
A priniciple purpose of a representation letter from management is to:
Solution
Management representation is a letter issued by an auditor\'s client to the auditor in writing as one of audit evidences. The date of the document must not be later than the date of audit work completion. It is used to let the client\'s management declare in writing that the financial statements and other presentations to the auditor are sufficient and appropriate and without omission of material facts to the financial statements, to the best of the management\'s knowledge. it is a form letter written by a company\'s external auditors, which is signed by senior company management.
The letter states that all of the information submitted is accurate, and that all material information has been disclosed to the auditors. The auditors use this letter as part of their audit evidence. The letter also shifts some blame to management, if it turns out that some elements of the audited financial statements do not fairly represent the financial results, condition, or cash flows of the business.
.
A process or task in Linux is represented by a Answer data structure-S.docx
Each process in Linux is represented by a task_struct data structure that contains information about the process's state. A process can be in one of five states - running, interruptible sleep, uninterruptible sleep, zombie, or stopped - which is indicated by a flag in the task_struct. The task vector stores pointers to all current task_struct structures.
Crystal clear water sports has 14-000 shares of $1 par value common st.docx
Crystal clear water sports has 14,000 shares of $1 par value common stock outstanding. Crystal Clear distributes a 10% stock dividend when the market value of its stock is $20 per share. Journalize Crystal Clear\'s declaration of the stock dividend on July 15 and distribution on July 31. What is the overall effect of the stock dividend on Crystal Clear\'s total assets? What is the overall effect on total stockholder\'s equity?
Solution
Date Account heads Debit Credit 15-Jul To record declaration of stock dividend Retained earnings (14000 * 10% = 1400 * $20) 28000 Stock dividend distributable (1400 * 1) 1400 Paid in Capital in excess of par (1400 * 19) 26600 31-Jul To record distribution of stock dividend Stock dividend distributable (1400 * 1) 1400 Common stock account 1400 2. Unlike cash dividend, stock dividend involves no distribution of assets or liabilities. So, it has no effect on the Assets or Liabilities 3. Stockholders\' equity, also called owners\' equity, is the surplus of a company\'s assets over its liabilities. Cash dividends reduce stockholders\' equity by distributing excess cash to shareholders. Stock dividends distribute additional shares to shareholders and do not affect the balance of stockholders\' equity. Net worth (Share capital + retained earnings) is not affected. It is an inter change of Numbers between the two. Equity capital balance is increased and retained earnings balance is reduced
.
Critical thinking question- what structural features (hint- there are.docx
Critical thinking question: what structural features (hint: there are four) do all ten of these opioid drugs have in common?
Opioids Opioids are a powerful class of alkaloids that act on the central nervous narcotic analgesics. All opioids presumably bind to the same mu-opioid receptor sites in the brain and spinal cord. The most prevalent naturally occurring isolated from the opium poppy-is morphine (named after Morpheus, the sod of dreams). A methoxy derivative of morphine that is also isolated from opium poppy is codeine, which is both less addictive and less effective as a reliever than morphine. By contrast, the diacetyl derivative of morphine (heroin) isanalgesic not only a more powerful as a narcotic but also more addictive than morphine Many other synthetic derivatives of morphine are opioid agonists that are used as narcotic analgesics (including oxycodone, oxymorphone, hyd system as a plant-derived nitrogenout bases that have pronounced physiologial acevity on humans the arcotic a drug dhas numbs the ngonisa molecule that combines antagonist a molecule that inhibits senses and induces stupor a druE hat with a receptor to initiate and meperidine), while others (such as methadone and buprenorphine) are used to treat opioid addiction. Naloxone is an opioid antagonist that is used to counteract opioid overdose the physiological action of anocher CHyo 0 CH, Ho* CH CH (OxyContin) (Opana) Dlaudid) (Demerol Ph N-CH3 CHa (where Ph (Butrans, Suboxone) ritical Thinking Question Phat structural features (hint: there are four) do all ten of these opioid drugs have in commom? mene ving, Contein nivonen
Solution
Common features in all the given opiod structures are -
1. Presnece of a tertiary amine group.
2. Presence of a phenyl ring.
3. At least two rings are there in all the molecules.
4.All the opioids are polar compounds.
.
Create an array of size 10 Assign values to the array Print the arra.docx
Create an array of size 10 Assign values to the array Print the array Swap the first and last elements in the array Print the array Shift all elements by one to the right Print the array Replace even elements with 0 Replace each element except the first and last by the larger of its two neighbors Print the array
Solution
/*Program to replace EVEN elements by 0 and ODD elements by 1.*/
#include <stdio.h>
/** funtion : readArray()
input : arr ( array of integer ), size
to read ONE-D integer array from standard input device (keyboard).
**/
void readArray(int arr[], int size)
{
int i =0;
printf(\"\ Enter elements : \ \");
for(i=0; i < size; i++)
{
printf(\"Enter arr[%d] : \",i);
scanf(\"%d\",&arr[i]);
}
}
/** funtion : printArray()
input : arr ( array of integer ), size
to display ONE-D integer array on standard output device (moniter).
**/
void printArray(int arr[], int size)
{
int i =0;
printf(\"\ Elements are : \");
for(i=0; i < size; i++)
{
printf(\"\ \\tarr[%d] : %d\",i,arr[i]);
}
printf(\"\ \");
}
/** funtion : replaceEvenOdd()
input : arr ( array of integer ), size
to replace EVEN elements by 0 and ODD elements by 1.
**/
void replaceEvenOdd(int arr[], int size)
{
int i=0;
for(i=0; i < size; i++)
{
if( arr[i] % 2 == 0 )
arr[i] = 0 ;
else
arr[i] = i;
}
}
int main()
{
int arr[10];
readArray(arr,10);
printf(\"\ Before replacement : \");
printArray(arr,10);
replaceEvenOdd(arr,10);
printf(\"\ After replacement : \");
printArray(arr,10);
return 0;
}
.
Create a text file that contains ten person objects where each object.docx
Create a text file that contains ten person objects where each object is represented on a separated line with each attribute separated by a comma. Create a method that reads form the file, creates one person object per line, and stores the object in an Array List object. Write the stored objects out by last name of the console.
Solution
//Program
package person;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.util.ArrayList;
import java.util.Scanner;
//person class
class Person
{
String lastname;
String firstname;
int age;
public Person(String last, String first, int a)
{
firstname=first;
lastname=last;
age=a;
}
@Override
public String toString()
{
return (lastname+\" \"+firstname+\" \"+age);
}
}
public class PersonDemo {
public static void main(String[] args) throws FileNotFoundException {
//creating array list
ArrayList <Person> persons=new ArrayList<>();
//reading person data file
Scanner infile=new Scanner(new FileReader(\"person.txt\"));
while(infile.hasNextLine())
{
String words[]=infile.nextLine().split(\",\");
persons.add(new Person(words[0],words[1],Integer.parseInt(words[2])));
}
//display person s details
System.out.println(\"Person details: \");
for(int i=0;i<persons.size();i++)
{
System.out.println(persons.get(i).toString());
}
}
}
///////////////////////////////////////////////////////////////////
//person.txt input file
Joseph,Daniel,23
Jhon,Stephen,34
Joseph,Maria,25
Fernandez,George,67
Jaitely,Arun,29
Kumar,Narendra,50
Victor,Prince,40
George,Jincy,35
Roldan,Tinu,28
Antony,Tim,27
.
Create a polynomial function that meets the following conditions- Expl.docx
Create a polynomial function that meets the following conditions. Explain how you created your polynomial.
4. Degree 3, 2 positive real zeros, 1 negative real zero, 0 complex zeros.
Polynomial:
Solution
Polynomial may be : f(x) = -x^3 + x^2 + x - 1 Reasoning : the number of positive roots of the polynomial is either equal to the number of sign differences between consecutive nonzero coefficients. so here has two sign change(the sequence of pairs of successive signs is -+, ++, +-). So it has 2 positive roots. for negative root we change the signs of the coefficients of the terms with odd exponents, i.e., apply Descartes\' rule of signs to the polynomial f(-x), to obtain a second polynomial f(-x) = x^3 + x^2 - x - 1 it has 1 sign change so f(-x) has one positive root so f(x) has 1 negative root.
.
Create a method assuming we have a listed list- use linear search in j.docx
Create a method a ssuming we have a listed list, use linear search in java
Create a method assuming we have a listed list, use linear search in java//Linear Search in a Linked List public static void LinkedListSearch(intNode head, int key)
Solution
Since you have not specified structure of IntNode class,so I am assuming that structure of IntNode:
class IntNode{
int data;
IntNode next;
//other methods and constructors
}
public static void LinkedListSearch(IntNode head, int key){
while(head != null){
if(head.data == key){ // if found, then print message and return
System.out.println(key+\" is founded!!\");
return;
}
head = head.next;
}
System.out.println(key+ \"is not in linked list\");
}
.
Create a JAVA Program that traverses through an array recursively- rat.docx
Create a JAVA Program that traverses through an array recursively, rather than with a loop, and prints out each element in the array. Java only, this will be a short program.
Solution
public void dosomethingtoall(List list)
{
//begin recurssion dosomethingtoall(list,0);
}
private void dosomethingtoall(Last list,int index)
{
//break recurssion when to proceed entire list.
if(index>=list.size())
return;
//do what ever you want with the list.
process(list.get(index));
//recursive step.process the next element.
dosomethingtoall(list,index+1);
}
or by using traversal
import java.util.Listiterator;
import java.util.Arraylist;
public class
traverseforwordingusingListiteratorexample
{
public static void main(String args[])
{
//create an array of object list
Arraylist alist=new Arraylist();
//add elements to arraylist object
alist.add(\"1\");
alist.add(\"2\");
alist.add(\"3\");
alist.add(\"4\");
alist.add(\"5\");
//get an object of Listiterator using listiteratot()
Listiterator listiterator=alist.listiterator();
/*traverse arraylist in forward direction using hasNext and next methods of listiterator.hasNEXT Returns true if Listiterator has more elements to traverse in forwrd direction.next methid returns next element in the list*/
Sysytem.out.println(\"traversing arraylist in forward direction using Listiterator\");
while(listiterator.hasNext())
system.out.println(listiterator.next());
}
}
.
Create a Java Applet that uses two integer (int) variables x and y to.docx
Create a Java Applet that uses two integer (int) variables x and y to place the picture of four circles on the screen. Alternate the colors by setting the g.setColor method . Also, use the g.drawString to place your name above the circles.
Solution
import java.applet.*;
import java.awt.*;
public class Bullseye extends Applet {
public void paint(Graphics g) {
int appletHeight = this .getSize().height;
int appletWidth = this .getSize().width;
for ( int i=8; i >= 0; i--) {
if ((i % 2) == 0) g.setColor(Color.red);
else g.setColor(Color.white);
// Center the rectangle
int rectHeight = appletHeight*i/8;
int rectWidth = appletWidth*i/8;
int rectLeft  = appletWidth/2 - i*appletWidth/16;
int rectTop   = appletHeight/2 - i*appletHeight/16;
g.fillOval(rectLeft, rectTop, rectWidth, rectHeight);
}
}
}
.
Could someone help me with this Linux system program- Using C language.docx
Could someone help me with this Linux system program. Using C language.
Write your own simple client/server set of processes. The client should use a shared memory segment to send a command message to the server. The server process should monitor the shared memory segment, and respond as follows:
\"HI\" -- The server prints \"Greetings\" to the screen.
\"PID\" -- The server prints it\'s process id to the screen.
\"QUIT\" -- The server terminates gracefully, detaching and releasing the shared memory segment.
Sample run:
Client :
Server:
HI PID QUIT
Solution
#include #include #include #include #include #include #include #include #include #include int main(int argc, char *argv[]) { int listenfd = 0, connfd = 0; struct sockaddr_in serv_addr; char sendBuff[1025]; time_t ticks; listenfd = socket(AF_INET, SOCK_STREAM, 0); memset(&serv_addr, \'0\', sizeof(serv_addr)); memset(sendBuff, \'0\', sizeof(sendBuff)); serv_addr.sin_family = AF_INET; serv_addr.sin_addr.s_addr = htonl(INADDR_ANY); serv_addr.sin_port = htons(5000); bind(listenfd, (struct sockaddr*)&serv_addr, sizeof(serv_addr)); listen(listenfd, 10); while(1) { connfd = accept(listenfd, (struct sockaddr*)NULL, NULL); ticks = time(NULL); snprintf(sendBuff, sizeof(sendBuff), \"%.24s\ \ \", ctime(&ticks)); write(connfd, sendBuff, strlen(sendBuff)); close(connfd); sleep(1); } }
.
Contrast the argument that terrorist acts are easy to predict with the.docx
Contrast the argument that terrorist acts are easy to predict with the argument that they cannot be identified or predicted. Write it 4-5 paragraph with resources(References).
Solution
By using technology it was easy to predict the terrorist acts. This is because terrorists use social media sites for communication and now-a-days there are many pattern recognization and data mining algorithms are implemented to identify the words and to predict the next action of the terrorists
reference:http://www.iflscience.com/technology/how-technology-help-predict-terrorist-attacks/
And even though advancement of technology cannot predict the terrorist act all the time, because if the terrorists are at one place then they don\'t use the internet or social media sites, so there will be no chance of prediction.
But NSA, which have access to almost every device in the world can easily predict the action of every human being in the world and there are many other security agencies like NSA also can do this thing. Majorly, technology plays an important role in identifying or predicting the action of terrorists
.
contemporary financial management What are the differences between the.docx
contemporary financial management What are the differences between the primary and secondary markets?
Solution
The difference between the primary capital market and the secondary capital market is that in the primary market, investors buy securities directly from the company issuing them, while in the secondary market, investors trade securities among themselves, and the company with the security being traded does not participate in the transaction.
.
Constants Part A By measurement you determine that sound waves are spr.docx
Constants Part A By measurement you determine that sound waves are spreading out equally in all directions from a point source and that the intensity is 2.7x10-2 W/m2 at a distance of 4.5 Im from the source What is the intensity at a distance of 3.5 m from the source? Express your answer using two significant figures W/m2 Submit Incorrect. Try Again; 6 attempts remaining Part B How much sound energy does the source emit in one hour if its power output remains constant? Express your answer using two significant figures Submit
Solution
Part A.
Intensity is given by:
I = P/A = P/(4*pi*r^2)
Since Source is same at both distance, So Power is constant, which means intensity is inversely proportional to square of distance from source.
I2/I1 = (r1/r2)^2
I2 = I1*(r1/r2)^2
I2 = 2.7*10^-2*(4.5/3.5)^2
I2 = 4.5*10^-2 W/m^2
Part B.
Power of source will be
P = I*4*pi*r^2
P = 2.7*10^-2*4*pi*4.5^2
P = 6.87 W
Now energy is given by:
E = Power*time
E = P*t
t = 1 hr = 3600 sec
E = 6.87*3600
E = 24732 J = 2.5*10^4 J
Please Upvote.
.
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- 1. Create a function called findChar that will return the index of where a particular character is found within a CString. Your function should take as parameters the CString to search through and a character variable to search for. The function will return the index of where the character was first found. If the array does not have the character in it, your function should return -1. NOTE: Do not convert or cast the characters to int's to do the searching. At this point you should be able to traverse a CString. Solution import java.util.Scanner; import java.io.*; import java.lang.*; public class FindingIndex{ public static void main(String args[]){ String [] Cstring = new String [10]; System.out.println("Please enter the string "); System.out.println("Character to search"); Scanner in = new Scanner(System.in); Cstring = in.nextLine(); char c = in.nextChar(); CstringIndex(Cstring,c); } public static int CstringIndex(String[] Cstring2,char newchar){ for(int i=0;i<Cstring2.length();i++) { if(c == Cstring2[i]) { System.out.println("Index of the character "+i); break;