Create a polynomial function that meets the following conditions. Explain how you created your polynomial. 4. Degree 3, 2 positive real zeros, 1 negative real zero, 0 complex zeros. Polynomial: Solution Polynomial may be : f(x) = -x^3 + x^2 + x - 1 Reasoning : the number of positive roots of the polynomial is either equal to the number of sign differences between consecutive nonzero coefficients. so here has two sign change(the sequence of pairs of successive signs is -+, ++, +-). So it has 2 positive roots. for negative root we change the signs of the coefficients of the terms with odd exponents, i.e., apply Descartes\' rule of signs to the polynomial f(-x), to obtain a second polynomial f(-x) = x^3 + x^2 - x - 1 it has 1 sign change so f(-x) has one positive root so f(x) has 1 negative root. .