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C3 Trigonometry 2 and Differentiation 1 Assignment<br />DUE: Tuesday 14th December<br />1)Solve the equation sin = 2sin (600 –)    for .   [4]<br />2)Simplify the following:<br />(a)[2]<br />(b)cos 40° cos 20° – sin 40°sin 20°[2]<br />3) If tan A =  and tan B = , find the value of tan (A + B) without a calculator.[2]<br />4) If , show that .[3]<br />5) Prove the following identities:<br />(a)tan( + 45°) + tan( - 45°)  2tan2[4]<br />(b)(sin A + cos A)(sin 2A – cos 2A) <br /> sin A – cos 3A[4]<br />6)Differentiate the following functions with respect to x:<br />(a)(b)<br />(c)(d)(e)(f)(g)(h)[16] <br />Total: 37 <br />EXTENSION:<br />1. Solve the following equation, for 0  x  , giving your answers in terms of .<br />sin 5x – cos 5x = cos x – sin x.<br />[8]<br />2. Prove that <br />tan14π-12x≡secx-tanx (*)<br />(i) Use (*) to find the value of tan18π. Hence show that <br />tan1124π=3+2-13-6+1<br />(ii) Show that <br />3+2-13-6+1=2+2+3+6<br />(iii) Use (*) to show that <br />tan148π=16+102+83+66-2-2-3-6<br />[20]<br />
Core 3 assignement 5 10 11 (trigonometry 2 and differentiation 1)

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Core 3 assignement 5 10 11 (trigonometry 2 and differentiation 1)

  • 1. C3 Trigonometry 2 and Differentiation 1 Assignment<br />DUE: Tuesday 14th December<br />1)Solve the equation sin = 2sin (600 –) for . [4]<br />2)Simplify the following:<br />(a)[2]<br />(b)cos 40° cos 20° – sin 40°sin 20°[2]<br />3) If tan A = and tan B = , find the value of tan (A + B) without a calculator.[2]<br />4) If , show that .[3]<br />5) Prove the following identities:<br />(a)tan( + 45°) + tan( - 45°) 2tan2[4]<br />(b)(sin A + cos A)(sin 2A – cos 2A) <br /> sin A – cos 3A[4]<br />6)Differentiate the following functions with respect to x:<br />(a)(b)<br />(c)(d)(e)(f)(g)(h)[16] <br />Total: 37 <br />EXTENSION:<br />1. Solve the following equation, for 0 x , giving your answers in terms of .<br />sin 5x – cos 5x = cos x – sin x.<br />[8]<br />2. Prove that <br />tan14π-12x≡secx-tanx (*)<br />(i) Use (*) to find the value of tan18π. Hence show that <br />tan1124π=3+2-13-6+1<br />(ii) Show that <br />3+2-13-6+1=2+2+3+6<br />(iii) Use (*) to show that <br />tan148π=16+102+83+66-2-2-3-6<br />[20]<br />