SIDRA
MAHMOOD
BS chemistry
MS
biochemistry
General Aspects
 Carbohydrates are aldehydes or ketone
compounds with multiple hydroxyl groups.
 It is found in relatively in all animals and
plants.
 They are the most abundant biomolecule on
earth.
 But in human they form only 1%of body mass.
 Word carbohydrate is derived from the fact
that the first compound of carbohydrate had an
empirical formula C1H2O1.
 This formula was showing hydrogen and
oxygen in same ratio as in water 2:1.
 But now it is known that many carbohydrate
hydrogen and oxygen not in same proportion
as in water. E.g. Deoxyribose whose molecular
formula is C5H10O4.
 Carbohydrate is derived from two words
Carbo which means Carbon and Hydrate
which means Water.
 So simply it signifies hydrate of water.
 Carbohydrate is define as “the
polyhydroxylated compound with at least
three carbon atom with potentially active
carbonyl group.
 This carbonyl group may be aldehyde or
ketone.
 Carbohydrate contain carbon , hydrogen and
water.
 But some also contain nitrogen, phosphorus, or
sulfur.
 Carbohydrate including sugar are called
saccharide.
 “Saccharides "is from Greek word saccharon
which means sugar.
 Carbohydrates have a wide range of functions.
The following of them are:
 Source of energy for living beings, e.g. glucose
 Storage form of energy, e.g. glycogen in animal
tissue and starch in plants
 Carbohydrates serve as structural component,
e.g. glycosaminoglycan's in humans,
 Cellulose in plants and chitin in insects
 Non-digestible carbohydrates like cellulose,
serve as dietary fibers.
 Constituent of nucleic acids RNA and DNA,
e.g. ribose and deoxyribose sugar.
 Play a role in lubrication, cellular
intercommunication and immunity.
 Carbohydrates are also involved in
detoxification, e.g. glucuronic acid.
 Carbohydrate are divided into following
classes
 Monosaccharide
 Disaccharide
 Oligosaccharide
 Polysaccharide
 Derived carbohydrate
 Lets explain them one by one
 These include simple sugar which consist of a
single polyhydroxylated aldehyde or ketone
units.
 They cannot be further hydrolyzed into simple
carbohydrate as they are the simplest form of
the carbohydrate.
 with few exception it has the empirical formula
(CH2O)n where n=3 or larger number
 When aldehyde is present in monosaccharide
then it always occur at the end of carbon chain.
 But when ketone is present then it never occur
at the end but at some other place.
 For example glucose contain aldehyde while
fructose contain ketone group.
 The most abundant monosaccharide in nature
is six carbon sugar D-glucose.
 May be subdivided into two groups as follows:
 Depending upon the number of carbon atom
they posses
 For example ;trioses, tortoises , pentose's ,
hexoses , heptodes.
 Depending upon the functional aldehyde
(CHO) or ketone (C=O) group present:
 Aldoses and ketoses
 Classification of monosaccharide's based on the
number of carbon and the type of functional
group present examples are given in table;
 It is given in the table;
 The compounds possessing identical molecular
formula but different structures are referred to
as isomers.
 The phenomenon of existence of isomers is
called isomerism.
 (Greek “isos” means equal, “meros” means
parts).
 The five types of isomerism exhibited by sugar
are as follows:
1. Ketose-aldose isomerism
2. D and L isomerism
3. Optical isomerism
4. Epimerism
5. Anomerism
 Glucose and fructose are isomers of each other
having the same chemical (molecular) formula
C6H12O6.
 But they differ in structural formula with
respect to their functional groups.
 There is a keto group in position two of
fructose and an aldehyde group in position one
of glucose.
 This type of isomerism is known as ketose-
aldose isomerism.
 D and L isomerism depends on the orientation
of the H and OH groups around the
asymmetric carbon atom adjacent to the
terminal primary alcohol carbon,
 e.g. carbon atom number 5 in glucose
determines whether the sugar belongs to D or
L isomer.
 D stand for dextrorotatory designated as (+)
 L stand for levorotatory designated as (-)
 When OH group on this carbon atom is on the
right, it belongs to D-series, when it is on the
left; it is the member of the L-series.
 The structures of D and L-glucose based on the
reference monosaccharide, D and L
glyceraldehyde, a three carbon sugar.
 • D and L isomers are mirror images of each
other. These two forms are called enantiomers.
 These are the pair of stereoisomer that are the
mirror image of each other in regard to
asymmetric carbon atom present in the
molecule.
 For example D and L form of glucose isomer.
 The D and L monosaccharide are metabolized
by a specific enzymes.
 The D enzymes will not work on L enzymes
and vice versa.
 In mammals mostly D-type of monosaccharide
are present.
 The presence of asymmetric carbon atoms exhibits
optical activity on the compound.
 Optical activity is the capacity of a substance to rotate
the plane polarized light passing through it.
 When a beam of plane-polarized light is passed
through a solution of an optical isomer, it will be
rotated either to the right and is said to be
dextrorotatory (d) or (+) or to the left and is said to be,
levorotatory (l) or (-).
 • When equal amount of D and L isomers are present,
the resulting mixture has no optical activity.
 Since the activity of each isomer cancel one another,
such a mixture is said to be a racemic or dl mixture
 Naturally occurring glucose is dextro while
fructose is levorotatory.
Optical activity in monosaccharide:
 Light being an electromagnetic radiation vibrates in
plane which are perpendicular to its direction od
propagation.
 If light is made to pass through a certain media then
the light leaving these media possess only one plane of
oscillation.
 In other words light becomes polarized in one plane
and such a light is called plane-polarized light.
 Plane-polarized light is measured in a Polari
meter or Polaris cope.
 Principle of instrument:
 A beam of light of known wave length is passed
through a nicol prism.
 This prism is acting as the polarizer converts it into a
plane polarized light.
 This beam is then passes through a solution of a
chemical substance contained in a glass tube of known
length.
 A 2nd nicol prism acts as analyzer it can be rotated to
find out degree of rotation.
 When two monosaccharide's differ from each other
in their configuration around a single asymmetric
carbon (other than anomeric carbon) atom, they
are referred to as epimers of each other.
 For example, galactose and mannose are two
epimers of glucose.
 They differ from glucose in the configuration of
groups (H and OH) around C-4 and C-2
respectively.
 Galactose and mannose are not epimers of each
other as they differ in configuration at two
asymmetric carbon atoms around C-2 and C-4.
α and β Anomerism:
 The predominant form of glucose and fructose in a solution are
not an open chain. Rather, the open chain form of this sugar in
solution cyclize into rings.
 An additional asymmetric center is created when glucose cyclizes.
 Carbon-1 of glucose in the open chain form becomes an
asymmetric carbon in the ring form and two ring structures can be
formed.
 These are:
• a-D-glucose
• b-D-glucose
 The designation a means that the hydroxyl group attached to C-1
is below the plane of the ring, b means that it is above the plane of
the ring. The C-1 carbon is called the anomeric carbon atom and
so, a and b forms are anomers.
 Some of the important chemical properties of
monosaccharide's are:
 1. Action of strong acids: Furfural formation
 2. Action of alkalis: Enolization
 3. Oxidation: Sugar acid formation
 4. Reduction: Sugar alcohol formation
 5. Action of phenyl hydrazine: Osazone
formation.
 On heating a sugar with mineral acids (H2SO4
or HCl), the sugar loses water and forms
furfural derivatives.
 These may condense with a-naphthol, thymol,
or resorcinol to produce
 colored complexes. This is the basis of the:
 • Molisch’s test
 • Seliwanoff’s test
 • Bial’s test
 • Tollen’s-phloroglucinol-HCl test.
 On treatment with dilute aqueous alkalis, both
aldoses and ketoses are changed to enediols.
 Enediol is the enol form of sugar because two OH
groups are attached to the double bonded carbon.
 • Enediols are good reducing agents and form
basis of the
 Benedict’s test and Fehling’s test.
 • Thus, alkali enolizes the sugar and thereby
causes them to be strong reducing agents.
 • Through the formation of a common 1, 2-enediol,
glucose, fructose, and mannose may isomerize into
each other in a dilute alkaline solution
 When aldoses oxidize under proper conditions they
may form:
 –– Aldonic acid
 –– Saccharic acids
 –– Uronic acid.
 • Oxidation of an aldose with hypobromous acid
(HOBr), which acts as an oxidizing agent gives aldonic
acid.
 Thus, glucose is oxidized to gluconic acid.
 • Oxidation of aldoses with nitric acid under proper
conditions converts both aldehyde and terminal
primary alcohol groups to carboxyl groups, forming
saccharic acid.
 Both aldoses and ketoses may be reduced by
enzymes or non-enzymatically to the
corresponding polyhydroxy alcohols.
 Manitol, the sugar alcohol derived from
mannose, is frequently used medically as an
osmotic diuretic to reduce cerebral edema.
 • Sorbitol, the sugar alcohol derived from
glucose, often accumulates in the lenses of
diabetics and produces cataracts.
 Osazones are yellow or orange crystalline derivatives of reducing
sugars with phenylhydrazine and have a characteristic crystal
structure, which can be used for identification and
characterization of different sugars having closely similar
properties (like maltose and lactose).
 Osazone formed from glucose, mannose, and fructose are identical
because these are identical in the lower four carbon atoms.
 The osazone crystals of glucose and of the reducing disaccharides,
lactose and maltose differ in forms
 –– Glucosazone is needle shaped
 –– Lactosazone is powder puff or tennis ball shaped
 –– Maltosazone is sunflower shaped.
 Non-reducing sugars like the disaccharide sucrose cannot form
osazone due to the absence of a free carbonyl (CHO or C = O)
group in them.
 Some important sugar derivatives of
monosaccharide's are:
 • Phosphoric acid ester of monosaccharide's
 • Amino sugar
 • Deoxy sugars
 • Sugar acids
 • Sugar alcohols
 • Neuraminic acid
 • Sialic acid.
 Phosphorylation of sugar within cells is
essential to
 prevent the diffusion of the sugar out of the
cell.
 • Nucleic acids (RNA and DNA) of cell nuclei
also contain sugar phosphates of ribose and
deoxyribose.
 • Amino sugars are components of glycolipid
(ganglioside), glycoprotein, and proteoglycans
(glycosaminoglycan's).
 • Several antibiotics, e.g. erythromycin,
carbomycin contain amino sugar.
Deoxy sugars possess a hydrogen atom in place of
one of
 their hydroxy groups e.g. 2-deoxyribose found
in nucleic acid DNA.
Sugar acids are produced by oxidation of the
monosaccharide's,
 for example:
 • Ascorbic acid or vitamin C (not synthesized by
human
 beings) is required for the synthesis of collagen. It
acts
 as water soluble antioxidant.
 • Glucuronic acid (uronic acid) (see properties of
monosaccharide:
 oxidation).
Neuraminic acid is a nine carbon sugar derived
from mannosamine (an epimer of glucosamine)
and pyruvate.
 Mannosamine + Pyruvate ————>
Neuraminic acid
Sialic acids are constituents of both glycoproteins
and glycolipids (ganglioside).
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Carbohydrates And Monosaccharide Notes No# 1

  • 1.
  • 3.
  • 4.
     Carbohydrates arealdehydes or ketone compounds with multiple hydroxyl groups.  It is found in relatively in all animals and plants.  They are the most abundant biomolecule on earth.  But in human they form only 1%of body mass.
  • 5.
     Word carbohydrateis derived from the fact that the first compound of carbohydrate had an empirical formula C1H2O1.  This formula was showing hydrogen and oxygen in same ratio as in water 2:1.  But now it is known that many carbohydrate hydrogen and oxygen not in same proportion as in water. E.g. Deoxyribose whose molecular formula is C5H10O4.
  • 6.
     Carbohydrate isderived from two words Carbo which means Carbon and Hydrate which means Water.  So simply it signifies hydrate of water.
  • 7.
     Carbohydrate isdefine as “the polyhydroxylated compound with at least three carbon atom with potentially active carbonyl group.  This carbonyl group may be aldehyde or ketone.  Carbohydrate contain carbon , hydrogen and water.  But some also contain nitrogen, phosphorus, or sulfur.
  • 8.
     Carbohydrate includingsugar are called saccharide.  “Saccharides "is from Greek word saccharon which means sugar.
  • 9.
     Carbohydrates havea wide range of functions. The following of them are:  Source of energy for living beings, e.g. glucose  Storage form of energy, e.g. glycogen in animal tissue and starch in plants  Carbohydrates serve as structural component, e.g. glycosaminoglycan's in humans,  Cellulose in plants and chitin in insects  Non-digestible carbohydrates like cellulose, serve as dietary fibers.
  • 10.
     Constituent ofnucleic acids RNA and DNA, e.g. ribose and deoxyribose sugar.  Play a role in lubrication, cellular intercommunication and immunity.  Carbohydrates are also involved in detoxification, e.g. glucuronic acid.
  • 11.
     Carbohydrate aredivided into following classes  Monosaccharide  Disaccharide  Oligosaccharide  Polysaccharide  Derived carbohydrate  Lets explain them one by one
  • 12.
     These includesimple sugar which consist of a single polyhydroxylated aldehyde or ketone units.  They cannot be further hydrolyzed into simple carbohydrate as they are the simplest form of the carbohydrate.  with few exception it has the empirical formula (CH2O)n where n=3 or larger number
  • 13.
     When aldehydeis present in monosaccharide then it always occur at the end of carbon chain.  But when ketone is present then it never occur at the end but at some other place.  For example glucose contain aldehyde while fructose contain ketone group.  The most abundant monosaccharide in nature is six carbon sugar D-glucose.
  • 16.
     May besubdivided into two groups as follows:  Depending upon the number of carbon atom they posses  For example ;trioses, tortoises , pentose's , hexoses , heptodes.  Depending upon the functional aldehyde (CHO) or ketone (C=O) group present:  Aldoses and ketoses
  • 17.
     Classification ofmonosaccharide's based on the number of carbon and the type of functional group present examples are given in table;
  • 18.
     It isgiven in the table;
  • 19.
     The compoundspossessing identical molecular formula but different structures are referred to as isomers.  The phenomenon of existence of isomers is called isomerism.  (Greek “isos” means equal, “meros” means parts).
  • 20.
     The fivetypes of isomerism exhibited by sugar are as follows: 1. Ketose-aldose isomerism 2. D and L isomerism 3. Optical isomerism 4. Epimerism 5. Anomerism
  • 21.
     Glucose andfructose are isomers of each other having the same chemical (molecular) formula C6H12O6.  But they differ in structural formula with respect to their functional groups.  There is a keto group in position two of fructose and an aldehyde group in position one of glucose.  This type of isomerism is known as ketose- aldose isomerism.
  • 23.
     D andL isomerism depends on the orientation of the H and OH groups around the asymmetric carbon atom adjacent to the terminal primary alcohol carbon,  e.g. carbon atom number 5 in glucose determines whether the sugar belongs to D or L isomer.  D stand for dextrorotatory designated as (+)  L stand for levorotatory designated as (-)
  • 24.
     When OHgroup on this carbon atom is on the right, it belongs to D-series, when it is on the left; it is the member of the L-series.  The structures of D and L-glucose based on the reference monosaccharide, D and L glyceraldehyde, a three carbon sugar.  • D and L isomers are mirror images of each other. These two forms are called enantiomers.
  • 26.
     These arethe pair of stereoisomer that are the mirror image of each other in regard to asymmetric carbon atom present in the molecule.  For example D and L form of glucose isomer.  The D and L monosaccharide are metabolized by a specific enzymes.  The D enzymes will not work on L enzymes and vice versa.  In mammals mostly D-type of monosaccharide are present.
  • 27.
     The presenceof asymmetric carbon atoms exhibits optical activity on the compound.  Optical activity is the capacity of a substance to rotate the plane polarized light passing through it.  When a beam of plane-polarized light is passed through a solution of an optical isomer, it will be rotated either to the right and is said to be dextrorotatory (d) or (+) or to the left and is said to be, levorotatory (l) or (-).  • When equal amount of D and L isomers are present, the resulting mixture has no optical activity.  Since the activity of each isomer cancel one another, such a mixture is said to be a racemic or dl mixture
  • 28.
     Naturally occurringglucose is dextro while fructose is levorotatory. Optical activity in monosaccharide:  Light being an electromagnetic radiation vibrates in plane which are perpendicular to its direction od propagation.  If light is made to pass through a certain media then the light leaving these media possess only one plane of oscillation.  In other words light becomes polarized in one plane and such a light is called plane-polarized light.
  • 29.
     Plane-polarized lightis measured in a Polari meter or Polaris cope.  Principle of instrument:  A beam of light of known wave length is passed through a nicol prism.  This prism is acting as the polarizer converts it into a plane polarized light.  This beam is then passes through a solution of a chemical substance contained in a glass tube of known length.  A 2nd nicol prism acts as analyzer it can be rotated to find out degree of rotation.
  • 30.
     When twomonosaccharide's differ from each other in their configuration around a single asymmetric carbon (other than anomeric carbon) atom, they are referred to as epimers of each other.  For example, galactose and mannose are two epimers of glucose.  They differ from glucose in the configuration of groups (H and OH) around C-4 and C-2 respectively.  Galactose and mannose are not epimers of each other as they differ in configuration at two asymmetric carbon atoms around C-2 and C-4.
  • 32.
    α and βAnomerism:  The predominant form of glucose and fructose in a solution are not an open chain. Rather, the open chain form of this sugar in solution cyclize into rings.  An additional asymmetric center is created when glucose cyclizes.  Carbon-1 of glucose in the open chain form becomes an asymmetric carbon in the ring form and two ring structures can be formed.  These are: • a-D-glucose • b-D-glucose  The designation a means that the hydroxyl group attached to C-1 is below the plane of the ring, b means that it is above the plane of the ring. The C-1 carbon is called the anomeric carbon atom and so, a and b forms are anomers.
  • 34.
     Some ofthe important chemical properties of monosaccharide's are:  1. Action of strong acids: Furfural formation  2. Action of alkalis: Enolization  3. Oxidation: Sugar acid formation  4. Reduction: Sugar alcohol formation  5. Action of phenyl hydrazine: Osazone formation.
  • 35.
     On heatinga sugar with mineral acids (H2SO4 or HCl), the sugar loses water and forms furfural derivatives.  These may condense with a-naphthol, thymol, or resorcinol to produce  colored complexes. This is the basis of the:  • Molisch’s test  • Seliwanoff’s test  • Bial’s test  • Tollen’s-phloroglucinol-HCl test.
  • 36.
     On treatmentwith dilute aqueous alkalis, both aldoses and ketoses are changed to enediols.  Enediol is the enol form of sugar because two OH groups are attached to the double bonded carbon.  • Enediols are good reducing agents and form basis of the  Benedict’s test and Fehling’s test.  • Thus, alkali enolizes the sugar and thereby causes them to be strong reducing agents.  • Through the formation of a common 1, 2-enediol, glucose, fructose, and mannose may isomerize into each other in a dilute alkaline solution
  • 38.
     When aldosesoxidize under proper conditions they may form:  –– Aldonic acid  –– Saccharic acids  –– Uronic acid.  • Oxidation of an aldose with hypobromous acid (HOBr), which acts as an oxidizing agent gives aldonic acid.  Thus, glucose is oxidized to gluconic acid.  • Oxidation of aldoses with nitric acid under proper conditions converts both aldehyde and terminal primary alcohol groups to carboxyl groups, forming saccharic acid.
  • 39.
     Both aldosesand ketoses may be reduced by enzymes or non-enzymatically to the corresponding polyhydroxy alcohols.  Manitol, the sugar alcohol derived from mannose, is frequently used medically as an osmotic diuretic to reduce cerebral edema.  • Sorbitol, the sugar alcohol derived from glucose, often accumulates in the lenses of diabetics and produces cataracts.
  • 40.
     Osazones areyellow or orange crystalline derivatives of reducing sugars with phenylhydrazine and have a characteristic crystal structure, which can be used for identification and characterization of different sugars having closely similar properties (like maltose and lactose).  Osazone formed from glucose, mannose, and fructose are identical because these are identical in the lower four carbon atoms.  The osazone crystals of glucose and of the reducing disaccharides, lactose and maltose differ in forms  –– Glucosazone is needle shaped  –– Lactosazone is powder puff or tennis ball shaped  –– Maltosazone is sunflower shaped.  Non-reducing sugars like the disaccharide sucrose cannot form osazone due to the absence of a free carbonyl (CHO or C = O) group in them.
  • 41.
     Some importantsugar derivatives of monosaccharide's are:  • Phosphoric acid ester of monosaccharide's  • Amino sugar  • Deoxy sugars  • Sugar acids  • Sugar alcohols  • Neuraminic acid  • Sialic acid.
  • 42.
     Phosphorylation ofsugar within cells is essential to  prevent the diffusion of the sugar out of the cell.  • Nucleic acids (RNA and DNA) of cell nuclei also contain sugar phosphates of ribose and deoxyribose.
  • 44.
     • Aminosugars are components of glycolipid (ganglioside), glycoprotein, and proteoglycans (glycosaminoglycan's).  • Several antibiotics, e.g. erythromycin, carbomycin contain amino sugar.
  • 45.
    Deoxy sugars possessa hydrogen atom in place of one of  their hydroxy groups e.g. 2-deoxyribose found in nucleic acid DNA.
  • 46.
    Sugar acids areproduced by oxidation of the monosaccharide's,  for example:  • Ascorbic acid or vitamin C (not synthesized by human  beings) is required for the synthesis of collagen. It acts  as water soluble antioxidant.  • Glucuronic acid (uronic acid) (see properties of monosaccharide:  oxidation).
  • 47.
    Neuraminic acid isa nine carbon sugar derived from mannosamine (an epimer of glucosamine) and pyruvate.  Mannosamine + Pyruvate ————> Neuraminic acid
  • 48.
    Sialic acids areconstituents of both glycoproteins and glycolipids (ganglioside).
  • 49.