More Related Content More from Revika Nurul Fadillah More from Revika Nurul Fadillah (7) 1. - 1 -
A. Evaluasi Pengertian atau Ingatan
1. C. x
6
+c
dxx5
6 =
6
6
x6
+c
= x6
+c
2. B.
n
a
xn
+c , dengan n≠0
cx
n
a
dxax nn 111
11
=
n
a
xn
+c , dengan n≠0
3. B. c
xn
a
n
1
)1(
dxaxdx
x
a n
n
cx
n
a n
1
)1(
c
xn
a
n
1
)1(
4. A.
4
1
z4
-z3
+
2
1
z2
-3z+c
dxzzz )33( 23
=
4
1
z4
-z3
+
2
1
z2
-3z+c
5. B. cx 3
1
1
4
5
cxdxx 3
1
3
1
1
3
4
3
5
3
5
cx 3
1
1
4
5
6. A. cx
x
2
3
3
22
cxxdxxx 2
3
2
1
3
2
1
2
)2( 12
cx
x
2
3
3
22
7. C. 0
cxxxdxxx 5342
3
1
)51(
A=1 B=1 → A-B=0
8. A. 0
dxxdx
x
xx
)12(
2
2
23
cxx 2
A=1 B= -1 → (A+B)2
=0
9. C. 0
cxxxdx
xx
3
1
3
2
3
1
3
165 35
24
A=
3
1
B=
3
2
D=
3
1
→ A+B+D=0
10. A. c
tt
3
3
11
dt
tt
dt
t
t
424
2
111
c
tt
3
3
11
B. Evaluasi Pemahaman dan Penguasaan Materi
1. a. cxxxx 3
8
3
8
3
8
3
5
8
3
8
3
b. xxxxx 2
5
3
22 3
5
3
5
3
2
cxx 2
5
3 3
5
c. cxxxx 10101011
10
1
10
1
d. cxxxx 5554
5
3
5
3
33
e. cxxx
x
22
1
f.
423
3232 xxxxx
cxxxxxx 422422
4
1
2
3
4
1
2
3
g.
524
2323 xxxxx
cxxxxxx 5252
5
1
3
5
1
3
h. xxxxxxx 52345234
23423
cxxxxxxxx 55
234234
BAB I
INTEGRAL
Latihan Kompetensi
Siswa 1
2. - 2 -
2. a.
cxdxx
xx
dx 2
1
2
3
2
c
x
2
b. ctttdttt 322
3
1
3)23(
c.
dxxxxdx
x
xx 345
5
2
25
25
cxxx
234
4
1
4
5
c
xxx
234
1
3
1
4
5
d. dxxxx )1634(
23
cxxxx
234
2
e. c
x
xdx
x
x
1
3
21
2 3
2
2
f. dxxx 1612
23
cxxx
34
23
g.
dxxxdx
x
x 33
3
3
105
2
5
cxx 24
5
4
5
h.
c
x
xxdx
x
xx
1
5
11
2 25
2
4
3. a. cxdxxdxx 4
9
4
5
9
44 5
b.
cxdxxdx
x
3
13
4
3
1
3 4
c. cxxxdx
xx
535
32 12
23
d.
dx
x
xx
2
2
1
cxxxx 4
4
1 2
e.
dxydx
y
yy 2
2
22
21
12
cx
y
x 2
1
3
f.
cxxxdx
x
x 2
3
2
2
1
2
g.
dx
x
xx
5
531
cxxxx 2
11
11
10
22
h. cxxdxxx 3623
6
1
3
4. a. dxxxdxx 121
2422
cxxx 35
3
2
5
1
b. dxxxxdxx
323
6128)2(
cxxxx 432
4
1
268
c. dxxxdxx
6323
211
cxxx 74
7
1
2
1
d. dxxx 222
)4(
dxxxx
642
816
cxxx 753
7
1
5
8
3
16
e. cxxdxxx 3623
6
1
)3(
f. dxxxxdxxx
7423
2)1(
cxxx 852
8
1
5
2
2
1
5. a. dxxxxdxxx 963323
2)1(
cxxx 1074
10
1
7
2
4
1
b. cxxxxdxxx 2
5
2
3
2
)1(
c.
dx
x
x
3
1
dxxxxx 2
3
2
1
2
1
2
3
33
cxxxx
2
1
2
1
2
3
2
5
262
5
2
d.
dxxxdx
x
x
2
)1( 2
1
2
cxxx 2
3
2
1
3
2
22
e. dxxx
22
1
dxxxxx 1232 234
cxxxxx 2345
2
1
5
1
f.
dx
x
xx )2)(1(
dxxxx 2
1
2
3
2
cxxx 2
1
2
3
2
5
4
3
2
5
2
3. - 3 -
A. Evaluasi Pemahaman dan Penguasaan
Materi
1. a.
cxxdx
x
xx 24
3
46
2
334
b.
c
x
xdx
x
xx 1
4
1 4
3
6
c. dxxxxx 245327
357
cxxxxx 2
3
2
4
45
2
1
8
27 468
d. dxxxxx 335
232
cxxxx 3456
3
3
4
3
6
1
e.
dzzzzdz
z
z 2
1
2
3
2
7
2
1
22
czzz 2
1
2
5
2
9
2
5
4
9
2
f. dxxx
2
3
cxxx 27
2
1
9
4
7
1 2
9
g. dttt
2
2
cttt 23 2
5
5
24
3
1
h.
crrrdr
r
rr 2
3
2
5
2
7
3
2
5
4
7
21
2
i.
dx
x
x
4 5
3 2 4
cxx
4
1
3
5
16
5
3
j.
dx
x
xx
1
2
cxx 2
1
2
5
2
5
4
2. a. dxx
x
12
3 2
3
3
cxx
x
2
5
5
4
2
3
2
b.
dx
xx 3
2
4
3
32
cxx 3
1
4
1
98
c.
dx
x
x
3
3 2 6
4
cxx 3
2
3
5
9
5
12
d. dxxx
33
)1(
dxxxxx 3
1
3
4
3
7
3
10
33
cxxxx 3
4
3
7
3
10
3
13
4
3
7
9
10
9
13
3
e. dxxx
3
)1(
dxxxxx 2
7
2
5
2
3
2
1
33
cxxxx 2
9
2
7
2
5
2
3
9
2
7
6
5
6
3
2
f.
dx
x
xx
2
34
7
532
c
x
xx
7
5
14
3
21
2 3
g.
dx
x
x 2
)43(
dxxxx 2
1
2
1
2
3
16249
cxxx 2
1
2
3
2
5
3216
5
18
h.
dx
xx
x 3
)43(
2
3
6414410827 23
x
xxx
dxxxxx 2
3
2
1
2
1
2
3
6414410827
cxxxx
2
1
2
1
2
3
2
5
12828872
5
54
i. dxx
4
)1(
dxxxxx 1464
2234
cxxxxx 3345
3
4
2
5
1
j. dtt
5
)119(
)119()119(
9
1 5
tdt
ct )119(
54
1
3. a. dxxx )3)(1(
5
3
dxxx
5
9
5
12
5
3 2
cxxx
5
9
5
6
5
1 23
Latihan Kompetensi
Siswa 2
4. - 4 -
b.
dx
x
x
3
2 1
dxxxx
338
33
cxxxx 249
2
1
3
4
3
9
1
c.
dt
t
t
4
22
1
dttt
42
21
cttt 31
3
1
2
d.
dxxx
x
x
x
x 211
dxxx
x
x 2
2
2 1
dxxxx
234
1
cxxxx 145
4
1
5
1
4. a. dxxxx
7 5 355
cxdxx 5
34
5
29
34
5
b. dxxxx 10 354
cxdxx 5
26
5
21
26
5
c. dxxxxx
5 7 3 253
cxdxx 6
25
6
19
25
6
d. dxxxx 7 5 26
22
dxx 219
1263
35
6
2
dxx 79
421
35
6
2
cx 70
421
35
6
491
70
2
5. a. dx
xxx 10 354
3
dx
x15
68
3
cx
15
53
53
45
b. dx
x
xx
4
10 32
322
dxx
39
113
30
1
10
11
32
c
x
83
323 30
83
30
1
10
11
c.
dxxx
5 3 2
42
dxx6
1
3
1
2
cx
6
7
3
1
7
26
d. dxxx 7 53
3222
dxx 70
211
70
1
35
41
32
cx
79
281
70
1
35
41
70
28132
B. Evaluasi Kemampuan Analisis
1.
dx
xx
22
)1(
11
1
= ...
= ...
2. dxxx
52
1
dx
x
xxxx
xxxx
15
15304656
453010
2346
67810
cxxxxx
x
xxxx
2345
6
78911
2
5
3
15
4
30
5
46
6
56
7
45
8
30
9
10
11
cxxxxx
x
xxxx
2345
6
78911
2
5
5
2
15
5
46
3
28
7
45
4
15
9
10
11
3. ...33 22
xxy dengan x≠0
...333 2244
xxxy
yxy 44
3
43
4
3xy
y
y
3
4
3
3xy
dxxydx 3
4
3
3
cx 3
7
7
333
5. - 5 -
4. ...
222
xxxy
= ...
= ...
A. Evaluasi pengertian atau Ingatan
1. D. 10
cxxxdxxx
322
23)343(
f(-3)= -9-18+27+c=10
c=10
2. C. 2x3
-x2
+x-10
f(x)= dxxx )126(
2
= 2x
3
-x
2
+x+c
f(2)=16-4+2+c=4
14+c=4
c= -10
f(x)= 2x3
-x2
+x-10
3. D. 5
cxxdxxxf 23)(
19442)4( cf
c=3
32)( xxxf
f(1)=5
4. A. x
4
-x
2
-5
y
1
=f
1
(x)= dxx )212(
2
= 4x
3
-2x+c1
y=f(x)= dxcxx )24( 1
3
= x4
-x2
+c1x+c2
f(0)=c2= -5
f(2)= 16-4+2c1-5=7
c1=0
f(x)= x
4
-x
2
-5
5. C. x
2
-2x
y1
=f1
(x)= dx2 =2x+c1
f1
(x)= 2+c1=0
c1= -2
f1
(x)=2x-2
f(x)= dxx22
= x
2
-2x+c2
f(0)=02
-2∙0+c2
c2=0
f(x)= x2
-2x
6. B. -
x
1
+3
f(x)= c
x
dx
x
11
2
f(1)= -1+c=2
c=3
f(x)= -
x
1
+3
7. B. x
3
+2x
2
+x-2
f1
(x)= dxx 46 =3x2
+4x+c1
f(x)= dxcxx )43( 1
2
= x3
+2x2
+c1x+c2
f(1)=1+2+c1+c2= 2
c1+c2= -1 ... (a)
f(-2)= -8+8-2c1+c2= -4
-2c1+c2= -4 ... (b)
a dan b dieliminasi, didapat:
c1=1 dan c2= -2
f(x)= x
3
+2x
2
+x-2
8. B.
2
1
15
f
1
(x)= dxxdxxf )32()(
11
=x
2
-3x+c1
5=0-0+c1 → c1=5
f
1
(x)=x
2
-3x+5
f(x)= dxxxdxxf )53()( 21
= 2
23
5
2
3
3
1
cxxx
5=0-0+0+c2 → c2=5
f(x)= 55
2
3
3
1 23
xxx
f(3)= 5)3(5)3(
2
3
)3(
3
1 23
=
2
1
15
Latihan Kompetensi
Siswa 3
6. - 6 -
9. C. 11
y= dxx )14( =2x2
+x+c
0=8+2+c1 → c1= -10
y=2x
2
+x-10
x=3 → y=18+3-10=11
10. D.
3
1
55 xy
cxxdxxy 32
3
1
)1(
0=0-0+c → c=0
y=
3
1
x
3
-x
m=y
1
(2)=2
2
-1=3
y(2)=
3
2
2
3
8
)2(3
3
2
xy
3
1
53 xy
B. Evaluasi Pemahaman dan Penguasaan Materi
1. a. F(x)= dxx )46( = 3x2
-4x+c
3=0-0+c → c=3
Jadi F(x)= 3x
2
-4x+3
b. F(x)= dxxx )263( 2
= x3
-3x2
+2x+c
7=0-0+0+c → c=7
Jadi F(x)= x3
-3x2
+2x+7
c. F(x)= c
x
dx
x
11
2
2
1
3
2
1
3 cc
Jadi F(x)=
2
1
3
1
x
d. F(x)=
dxx2
4
1
cxx 3
3
1
4
1
c 3
)1(
3
1
)1(
4
1
2
12
11
1
12
1
2 cc
Jadi F(x)
12
11
1
3
1
4
1 3
xx
e. F(x)= dxxx )2)(1(
= dxxx )23(
2
= cxxx 2
2
3
3
1 23
c 6
2
27
9
2
3
c=0
Jadi F(x)= xxx 2
2
3
3
1 23
f. F(x)=
c
x
xdx
x
x
2
2
12 2
2
9=2+1+c → c=6
Jadi F(x)= 6
2
2
1 2
x
x
g. cxxdxxxF
3
2
)(
c 44
3
2
0
3
16
c
Jadi, cxxxF
3
2
)(
h.
dx
x
xxF 2
3 2
3)(
c
x
x
2
4
3 4
4
1
22
4
3
1 c
Jadi,
4
1
2
2
4
3
)( 4
x
xxf
i.
dx
x
xxxF 3
4 3
3)(
c
x
xx 2
25
2
3
2
3
5
1
c
2
3
2
3
5
1
1
5
4
1c
Jadi,
5
4
1
2
3
2
3
5
1
)( 2
25
x
xxxF
j. dxxxF
3
)2()(
dxxxx )8126(
23
cxxxx 862
4
1 234
c 16241641
5c
Jadi, 5862
4
1
)( 234
xxxxxF
7. - 7 -
2. a. cxxdxxxg 21
2
3
)13()(
b. cxxdxxxg
3
2
)(1
c.
dx
x
xdx
x
x
xg 33
4
1 11
)(
cx
2
1
2
1 2
d. dxxxg )32()(
1
cxx 3
2
e. cxxg 3
4
)(
1
cxx 32
7
3
f. cxxdxxxxg 2321
2
1
3
1
)()(
3. a. cxxdxy 2
2
213 2
cc
22
xy
b. cxxdxxy 2
2
1
)1(
2
1
31
2
1
3 cc
2
1
3
2
1 2
xxy
c. cxxdxxy 2
2
1
)1(
2
1
11
2
1
3 cc
2
1
1
2
1 2
xxy
d. cxxdxxy 2
2
3
)13(
2
1
21
2
3
3 cc
2
1
2
2
3 2
xxy
e. cxxdxxy 32
3
1
1
3
2
31
3
1
3 cc
3
2
3
3
1 3
xxy
f. c
x
dx
x
y
11
2
110 cc
1
1
x
y
g. cxxdxxy
3
2
c 44
3
2
5
3
1
c
3
1
3
2
xxy
h. dxxxy 123
2
cxxx
23
11110 cc
123
xxxy
i. dxxxy 164
23
cxxx
34
2
6216168 cc
62
34
xxx
j. c
x
dx
x
y
2
1
2
1
2
3
4
1
4
3
2 cc
3
2
1
x
y
4. a. dxxxF )14()(
cxx 2
2
131820 cc
12)( 2
xxxF
9128)2( F
b. dxxxxF 126)( 2
cxxx 23
2
50005 cc
52)( 23
xxxxF
1952416)2( F
c.
c
x
xdx
x
xF
11
1)( 2
3113 cc
3
1
)(
x
xxF
2
1
43
2
1
2)2( F
8. - 8 -
d. xdx
dx
xdF
6
)(
1
2
3 cx
000 11 cc
2
3
)(
x
dx
xdF
2
32
3)( cxdxxxF
880 22 cc
16)2(8)( 3
FxxF
e. 122
)(
cxdx
dx
xdF
3023 1 cc
32
)(
x
dx
xdF
dxxxF )32()(
2
2
3 cxx
7315 22 cc
73)( 2
xxxF
17764)2( F
f. c
x
dx
x
xF
2
1
2
1
)( 2
3
1
1
6
1
6
7
cc
3
1
1
2
1
)(
x
xF
12
1
1
3
1
1
4
1
)2( F
g. dxxxxF )204)(1()(
dxxx )20164(
2
cxxx 208
3
4 23
3
2
36208
3
4
10 cc
3
2
36208
3
4
)( 23
xxxxF
3
2
364032
3
32
)2( F
3
1
25
h. dxx
dx
xdF
)16(2
)( 2
dxx )212(
2
1
3
24 cxx
5005 11 cc
524
)( 3
xx
dx
xdF
dxxxxF 524)(
3
2
24
5 cxxx
35112 22 cc
35)( 24
xxxxF
19310416)2( f
Soal Aplikasi Bidang Geometri
5. cxxdxxy 3)32(
2
2992 cc
Persamaan kurva:
232
xxy
6. dxxxxdxxxy
23422
2
cxxx 345
3
1
2
1
5
1
00000 cc
Persamaan kurva:
345
3
1
2
1
5
1
xxxy
7. dtkttF )25()(
cktt
2
5
00050
2
cck
01151 k
4k
2
45)( tttF
8. cxxdxxxF 23)(
509924 cc
502)( xxxF
9. a. dxxxy 583
2
cxxx 54
23
c 1536274
2c
254 23
xxxy
9. - 9 -
b. Akan dibuktikan (2,0) memenuhi persamaan
kuva tersebut.
2252420
23
2101680
00 (terbukti)
Jadi, (2,0) melalui persamaan kurva
254 23
xxxy
10. cx
b
axdxbxay 2
2
)(
0000 cc
2
2
x
b
axy
1)0( ba
1a
22
)1(
2
)1(1)1(
2
)1(3
bb
a
4
2
13 b
b
2
2xxy
11. 1
2
36 cxxdx
dx
dy
01212 11
cc
2
3x
dx
dy
2
32
3 cxdxxy
484 22 cc
43
xy
12. 21
3145)( tttF
cttttF 32
75)(
Sumbu simetri
3
7
6
14
t
c
27
343
9
49
7
3
7
525
7
326
75)(
27
326 32
ttttFc
13. dxxxf )34()(
cxx 32
2
0)(1
xf
034 x
4
3
x
c
4
3
3
4
3
2
8
1
2
c
8
18
8
9
8
1
4
5
8
10
c
4
5
32)( 2
xxxf
Soal Aplikasi Bidang Mekanika
14. dttadttv )210()(
1
2
10 ctt
1
2
001000)0( cv
01 c
2
10)( tttv
dtttts )10()(
2
2
32
3
1
5 ctt
0)0( s
2
32
0
3
1
050 c
02 c
32
3
1
5)( ttts
Benda akan berhenti ketika 0)( ts
0
3
1
5 32
tt
0
15
1
15 2
tt
t=0 t=15
Benda itu akan berhenti ketika 15t
15. dtttv )218()(
1
2
18 ctt
20)0( v
1
0020 c
201
c
2018)( 2
tttv
2036108)6( v
s
m
92
10. - 10 -
2018)(
2
ttts
2
23
209
3
1
cttt
81)3( s
26081981 c
512 c
51209
3
1
)( 23
tttts
16. a. dtts
3
1
)36(
3063633
3
1
2
tt
b.
4
2
2
23 dttts
681280
4
2
23
tt
c.
9
4
5 dtts
3
1
35635
3
2
9
4
ttt
3
2
27
d.
5
0
)22( dtts
152
5
0
2
tt
e.
4
0
2
23 dttts
4
0
23
2
2
3
3
1
ttt
3
1
5824
3
64
17. Total biaya = xdx)005,0064,1(
cxx
2
0025,0064,1
biaya awal = 16,3
Total biaya = c
2
00025,00064,1
3,16c
Total biaya = 3,160025,0064,1 2
xx
Rata-rata biaya
x
x
3,16
0025,0064,1
18. Total biaya )(xf
dxxx
2
6602
cxxx
32
2302
Rata-rata biaya
x
c
xx 2
2302
19. Fungsi pendapatan total )(xR
dxxx
2
268
cxxx 32
3
2
38
Fungsi Demand:
x
c
xx 2
3
2
38
20. Fungsi pendapatan total
cx
x
dx
xx
ln2
323
2
Fungsi Demand
x
c
x
xx
ln
23
2
C. Evaluasi Kemampuan Analisis
1. a. cbxaxy 2
cba 0)0,1( ... (1)
cba 390)0,3( ... (2)
048 ba
cba 12)12,1( ... (3)
(1) dieliminasi dengan (3), diperoleh:
6b
Subsitusi 6b ke 048 ba
248 a
3a
96312 cc
Jadi, persamaan kurva adalah:
963 2
xxy
b. Sketsa grafik kurva.
8
10
12
2
2
4
4
6
6
-2-4 x
11. - 11 -
2. 12
x
a
dx
dy
31
dx
dy
x
21
1
3 2
a
a
1
2
2
xdx
dy
dx
x
y 1
2
2
cx
x
2
31 yx
c
1
1
2
3
4c
4
2
x
x
y
3. ))(( qxpxa
dx
dy
apqxqpaax
dx
dy
)(2
apqxqpaaxy )(2
capqxx
qpa
x
a
23
2
)(
3
a
xcapqqpaa
1
2)(2
3
8
0
a
xcapq
qpaa 2
2
)(
3
1
pqqp 222
...
4. baxx
dx
dy
2
3
330 baba
5332732 baba
84 a
2a
1b
dxxxy 123 2
cxxx 23
5.
...
6. ctdtv 3232
5003250)0( cv
50c
50432)4( v
178 kaki/detik
dtts 5032
ktt 5016
2
10000500161000)0( 2
ks
1000k
10005016)( 2
ttts
1000200256)4( s
1456 m
A. Evaluasi Pemahaman dan Penguasaan
Materi
1. a. duuu cos36 2
cuu sin32 3
b. d1tan2
cd tansec2
c.
dd sectan
cos
sinsec
c sec
d. d)cos3sin2(
c sin3cos2
e.
d2
cos1
cos
deccoscos
cec cos
f. dxx )1(cot2
xdxec2
cos
cx cot
Latihan Kompetensi
Siswa 4
12. - 12 -
g.
dx
x
x
2
sin1
sin
xdxx sectan
cx sec
h. dxxxx sin2
cxxxx
3
2
cos
3
1 3
2. a. dxxx
2
4cos6
cxx 3
3
4
sin6
b. dxxx sin6cos8
cxx cos6sin8
c. dx
x
x
2
cos
sin
cx sec
d. dx
x
x
2
sin
cos
cecx cos
e. xdxxxx
2244
cossin2cossin
dxxx
222
cossin
cxdx
2
1
f. d 2cos1
c cos2sin2
g. d 2cos1
c sin2cos2
h. dxxx 1secsec
2
xdxx tansec
cx sec
3. a. xdxxF sin23)(
cxx cos23
csc 002031
1c
b. xdxxF cos23)(
cxx sin23
c 0sin2035
5c
5sin23)( xxxF
c. dxxxF 3sec)(
2
cxx 3tan
c
4
3
4
tan
4
3
2
1c
13tan)( xxxF
4. a. xxxF sincos)(
cxx cossin
c
2
cos
2
sin5
4c
4
4
cos
4
sin
4
F
24
b. xdxxxF cossin)(
cxx sincos
c
3
sin
3
cos3
2
1
2
1
c 3
2
1
2
1
3
2
1
2
1
1c
1
4
sin
4
cos
4
F
12
c. cxdx
x
x
xF sec
cos
sin
)( 2
c
3
sec7
5c
5
4
sec
4
F
25
5. a. dxxx 22
sec2cos4
xdxx 2
sec22cos
2
1
2
1
4
cxxx tan22sin2
b. dxxxecxx sectancoscos
cxecx seccos
c. dxxecx 0cossec
2
cecxx costan
d. dxxxxecxx tanseccoscos2sin4
2
xdxxxx seccotsin2cos4
e. dxx 5tan
2
dx61tan
2
dxx 6sec
2
cxx 6tan
f. dxx 7cot
2
dxx 61cot
2
dxxec 6cos
2
cxx 6cot
13. - 13 -
B. Evaluasi Kemampuan Analisis
1.a.
dx
x
x
xx 2
2
sin1
sin2
sectan
= xdxxxxxx sectan2sectan2sectan 22
dxxx 1sec1tan
22
dxx 1sec2
2
cxx tan
b. dx
x
x
xx 2
2
sec
sin2
sectan
xdxxxxxx 222
cossin2sectan2sectan
xxxx sectan21sec1tan 22
)(coscos2 2
xxd
cxxxx 3
cos
3
2
sectan2
c. dx
x
x
ecxx 2
2
sin
cos2
coscot
ecxxxecx coscot2coscot 22
ecxdxx coscot2
dxxecx 1cos1cot 22
cxx cot2
2. a.
dx
xx
xx
2
33
cossin
cossin
...
b.
dx
xx
xx
2
33
cossin
sincos
...
c.
dx
xx
xx
42
33
coscos
cossin
...
d.
dx
xx
xx
42
33
sinsin
sincos
...
A. Evaluasi Pengertian atau Ingatan
1. B. aabb
3
2
b
a
b
a
xxdxx
3
2
aabb
3
2
2. C. babababa )(
3
2
ab
ba
ab
ba
xxdxx
3
2
= babababa )(
3
2
3. C.
3
1
2
1
2
2
1
2
1
)2(
2
1
dxxxdxxx
2
1
32
6
1
2
1
xx
6
1
2
1
3
4
2
3
1
4. 104
9
1
9
1
46 xxdxx
1044108
Latihan Kompetensi
Siswa 5
14. - 14 -
5. D.
2
1
2
6
2
6
sincos
xxdx
2
1
2
1
1
6. C. 5
123)32( 1
2
1
n
n
xxdxx
12)31(32
nn
0103
2
nn
0)2)(5( nn
5n
7. C. -1
63)23(
22
2
a
a
xxdxx
6)3(46 2
aa
043
2
aa
0)1)(4( aa
1a
8. E. 4
2
0
)(9 dtt
2
1
1
0
)(9)(9 tdtt
1
2
1
0
)(9)(9 dttdtt
4)2(2
9. D. 2
3
263 1
3
1
2
t
t
xdxx
261tt
22
3
3t
33 3
2
t
10. C. 388
7
3
3
210 dxxx
7
3
24
25
4
1
xxx
=388
11. B. -13,5
4
1
2
12153 dxxx
5,1312
2
15
4
1
23
xxx
12. A. 2
xdxx cos3sin
0
0sin3cos xx
2)01(01
13. A. 4
2
0
cos)tan5(
xdxx
2
0
sincos5
xdxx
2
0
cossin5
xx
4)10(05
14. A. -6
0
sin)3(cot xdxx
0
sin3cos xdxx
0cos3sin xx
6)30(30
15. A. -2, 0 dan 3
n
dxxx
1
2
623
46 1
23
n
xxx
4611623
nnn
0623
nnn
0)2)(3( nnn
n= -2 n=0 n=3
B. Evaluasi Pemahaman dan Penguasaan Materi
1. a.
5
0
2
5
0
2
1
cxxdx
)0(
2
25
cc
2
25
b.
3
1
4
3
1
3
4
1
cxdxx
20
4
1
4
81
cc
15. - 15 -
c.
5
0
3
5
0
2
3
5
5
cxdxx
)0(
3
625
cc
3
625
d.
3
2
3
2
2
1
c
xx
dx
cc
2
1
3
1
6
1
e.
2
1
3
4
2
1
3
4
3
cxdxx
cc
4
3
16
4
3 3
14,1116
4
3 3
f.
3
1
2
3
1
2
2
3
23
cxxdxx
cc 2
2
3
6
2
27
8
g.
4
1
2
4
1
3
1632
c
x
dx
x
15)16(1 cc
h.
2
1
23
234 xdxxx
2
1
34
2 cxxx
)211(4816 cc
30
i.
1
1
42
42 dxxx
1
1
53
5
4
3
2
cxx
5
4
3
2
5
4
3
2
c
5
1
3
15
48
15
2420
5
8
3
4
j.
3
2
3
32
2
1111
c
xx
dx
xx
cc
18
1
3
1
2
1
1
9
2
1
18
22
18
16918
2. a. 2242
4
1
4
1
x
x
dx
b. 6
2
1
2)2(
2
0
2
2
0
xxdxx
c.
2
0
2
2
0
2
44)2( dxxxdxx
3
8
3
1
24
2
0
32
xxx
d.
3
0
2
23 dxxx
9
3
1
3
3
0
32
xxx
e.
2
1
3
2
1
2
1 dttttdtt
2
1
42
4
1
2
1
tt
4
1
2
4
1
2
1
42
f.
4
1
)1( duuu
4
1
duuuu
4
1
2
5
2
3
2
uuuu
5
2
3
2
5
64
3
16
15
18670
5
62
3
14
15
11
7
15
116
g.
2
0
25
2
0
32
1 dxxxdxxx
2
0
36
3
1
6
1
xx
3
40
3
8
3
32
h.
1
0
2
1 dxxx
1
0
2
dxxx
6
1
3
1
2
1
1
0
32
xx
16. - 16 -
i.
8
1
3 2
8
1
3
2
5
3
xxdxx
5
93
5
3
5
96
j.
2
1
)12)(5( dxxx
2
1
2
592 dxxx
2
1
23
5
2
9
3
2
xxx
5
2
9
3
2
1018
3
16
2
9
3. a.
5
1
5
1
)(2)(2 dxxhdxxh
842
b.
5
1
3)( dxxh
5
1
5
1
3)( dxdxxh
16)15(34
c.
1
5
)( dxxh
4)(
5
1
dxxh
d.
5
1
)( dxkxxh
28)(
5
1
kxdxdxxh
2815
2
4 22
k
2k
4. a.
3
0
)( dxxf
3
2
2
0
)()( dxxfdxxf
1055
b.
2
3
2
0
)()( dxxfdxxf
3
2
2
0
)()( dxxfdxxf
055
c.
2
0
2)(4 dxxf
2
0
2
0
2)(4 dxdxxf
22)02(254
d.
0
2
)( dxxf
5)(
2
0
dxxf
5. a.
2
0
)1(cos
dxx
2
0
sin
xx
2
1
b.
4
0
2
tan1
dxx
1tan 4
0
x
c.
0
0
cossin xxdx
211
d.
2
0
)sin(
dxxx
2
0
2
cos
2
1
xx
)10(0
8
2
1
8
2
e.
4
4
)(cos
dxxx
4
4
2
2
1
sin
xx
32
2
2
1
32
2
2
1
22
2
f.
4
0
2
cot1
xdx
1cot 4
0
x
17. - 17 -
g.
4
4
sincot2
xdxx
2sincos2 4
4
xx
h.
3
4
2
tan1
xdx
3
4
tan
x
31)1(3
i.
4
3
2
cot1
xdx
4
3
cot
x
13
3
1
3
1
1
j.
2
4
costan2
xdxx
2
4
sincos2
xdxx
2
4
cossin2
xx
2
2
1
202
2
2
3
2
6. a. 4)12( 1
2
1
a
a
xxdxx
06
2
aa
0)2)(3( aa
a= -3 a=2
HP={-3,2}
b. 462)32(2 1
2
1
a
a
xxdxx
0862 2
aa
0432
aa
0)1)(4( aa
a=4 a= -1
HP={-8,3}
c. 185)52( 1
2
1
a
a
xxdxx
02452
aa
0)3)(8( aa
a= -8 a=3
HP={-8,3}
d. 24
2
1
)13(
3
1
23
3
2
xxdxx
a
24
2
1
2
9
27 23
aa
48954
23
aa
03
23
aa
13
2
1
2
1
2
1211
2,1
a
HP=
2
131
,
2
131
7. a.
5
2
2
28 dttts
5
2
32
3
1
8
ttt
3
8
416
3
125
2540
6
3
117
45
b.
3
1
2
8
2 dt
t
ts
3
1
2 8
t
t
3
8
)81(
3
8
9
c. dttt
3
0
2
2
3
0
23
2
2
1
3
1
ttt
2
1
106
2
9
9
8. a.
3
1
)2)(1( dxxxx
dxxxx
3
1
23
2
3
1
234
3
1
4
1
xxx
1
3
1
4
1
99
4
81
3
2
20
18. - 18 -
b.
dx
x
xxx
2
2
dx
xxx
21
2
xx
41
1
c. dx
x
xx
3
1
2
32
1
3
1
2
1
1
dxx
x
3
1
2 1
2
1
x
xx
1
2
1
1
3
1
2
9
1
3
2
6
d.
3
2
2
234
)1(
22
dx
x
xxxx
3
2
2
22
1
)2)(1(
dx
x
xxx
3
2
23
3
1
xx
4
3
8
99
3
1
11
e.
2
1
23
5438 dxxxx
2
1
234
522 xxxx
525212208832
f.
33
22
3 2
3 2 12
5 dx
x
x
2
3
2
3
3
2
33 2
363
xxx
236223336393
242363
223321
9.
2
1
)2(
1
n
dxx
2
1
2
2
1
1
2
n
xx
2
1
2
2
1
2
n
n
142
2
nn
034
2
nn
0)3)(1( nn
n=1 n=3
(tm)
a. 1232 n
b. 49)12( 2
n
c. 1)2( 2
n
d. 25)2( 2
n
10.
a
dxx
1
10)52(
105 1
2
a
xx
045
2
aa
0)1)(4( aa
a= -4 (tm) a= -1
1
0)12(
b
dxx
0
12
b
xx
02 2
bb
022
bb
0)1)(2( bb
b=2 b= -1
(tm)
a. 9)21()( 22
ba
b. 1)21()( 22
ba
c. 341
22
ba
d. 314
22
ab
19. - 19 -
C. Evaluasi Kemampuan Analisis
1. a.
23
23
2
76 dxxx
23
23
23
73
3
1
xxx
2721218332
3
29
15
272121832
3
19
5
2620
b.
dxcbxax
2
cxx
b
x
a 23
23
c
ba 2233
23
c.
a
a
dttt
22
2
a
a
dttttt 4452
234
a
a
ttttt
42
3
5
2
1
5
1 2345
334455
3
5
2
1
5
1
aaaaaa
aaaa 42 22
aaa 8
3
10
5
2 35
d.
12
2
x
x
dtt
12
3
3
1
x
x
t
xxxx 112128
3
1 23
3
1
3
11
4
3
8 23
xxx
2. dcxbxaxxf 23
)(
00)0( df
00)1( cbaf
cbxaxxf 23)( 21
3636)0(1
cf
sehingga 36ba
36 ab
1
0
23
5ddxcxbxax
1
0
23
36)( xdxxaax
518
3
36
4
1
0
234
xx
a
x
a
51812
34
aa
1
12
a
12a
483612 b
3.
1
0
2
dxmlxbaxx
1
0
23
)()( bmdxxblamxalmlx
0
234
1
0
234
bmxx
blam
x
alm
x
l
= ...
4.
1
0
22
1
0
)66(6612 xabaxadxax
0)6( bdxxab
331
0
2
)22(266 xabaxaxax
0
2
3
1
0
2
bxx
a
b
0
2
322212 b
a
babaa
06
2
1
16 ba
ab
12
33
1
0
222
1
0
2
2 dxbabxxadxa
1
3
1
0
223
2
2
xbabxx
a
xa
1
3
2
2
2
bab
a
a
1
144
1089
12
33
3
2
2
2
aaa
a
a
20. - 20 -
1
144
108939648144 2222
aaaa
144885
2
a
885
1442
a
885
12
a
ab
12
33
885
396
885
12
ba
885
396
885
12
ba
a. 22
334 baba
12,516
885
12492
b. ba 38
885
396
3
885
96
885
1096
885
1096
atau
5. a.
x
dtttxf
1
2
43)(
x
ttt
1
23
4
2
3
3
1
4
2
3
3
1
4
2
3
3
1 23
xxx
6
5
24
2
3
3
1 23
xxx
43)( 21
xxxf
b.
15
1
2
43
x
dttt
223
1)15(
2
3
1)15(
3
1
xx
1154 x
xxxxxx 2015
2
75
525
3
125 223
xxx 10
2
15
3
125 23
1015125)( 21
xxxf
c.
x
x
dttt 12
2
x
x
ttt
23
2
1
3
2
xxxxxx 2233
2
1
3
2
xx 2
3
4 3
24)( 21
xxf
d.
3
1
22
dtxxtt
3
1
223
23
1
txt
x
t
)13()19(
2
)127(
3
1 2
x
x
3
28
44 2
xx
48)(1
xxf
e.
x
dxxxt
3
2
x
xt
x
3
23
2
1
3
2
9
9
2
1
3
3
4
xx
x
9
2
3
3
4
)( 231
xxxf
f.
x
dttxt
3
2
x
tt
x
3
23
3
99
3
2
4
xx
x
92
3
4
)( 231
xxxf
6. a.
2
0
12
)()( dttfxxf
)0()2()( 2
ffxxf
b.
x
a
xxdttf 23)( 21
23)()( 2
xxafxf
)(23)( 2
afxxxf
c.
x
axxdttf
1
21
2)(
axxfxf 2)1()( 2
)1(2)( 2
faxxxf
21. - 21 -
d.
x
xxxfdttf
1
21
7)()(
7)()1()( 2
xxxffxf
)1(f
...
e.
1
1
1
2)( dxxf
2)1()1( ff
x
fxfdttf
0
1
)0()()(
3
9
x
k
7.
a
dttfxxaf
0
)(4)(
a
xxafdttf
0
4)()(
a
xxafdtxf
0
4)()(
8.
x a
dttfaxxdttf
0 0
2
)()(
...
A. Evaluasi Pengertian atau Ingatan
1. C. 1,0;
)1(
1 1
nacbax
na
n
dxbax
n
)()(
1
baxdbax
a
n
cbax
na
n
1
)(
)1(
1
Penyebut tidak boleh nol, sehingga a≠0 dan
n≠-1
2. A. 1;0;)(
)1(2
1 12
nacbax
na
n
baxdbax
a
dxbaxx
nn 222
2
1
)(
cbax
na
n
12
)1(2
1
a≠0 dan n≠-1
3. E. 2
cxa
x
dx
3
3
cx
x
dx
32
3
Jadi, a=2
4. C. 56 x
)65(65
6
1
65 xdxdxx
cxx 65)65(
3
2
6
1
cxxcxxf 65)65(
9
1
65)(
9
1
56)65()( xxxf
5. A. x59
)59()59(
5
1
)59( 66
xdxdxx
cx 7
)59(
35
1
xxf 59)(
6. B. cx 5
)37(
15
1
)37()37(
3
1
)37( 44
xdxdxx
cx 5
)37(
15
1
Latihan Kompetensi
Siswa 6
22. - 22 -
7. C. 0;)cos(
1
2
acbax
a
dxbax
a
)sin(
1
0;)cos(
1
2
acbax
a
8. D. 0);sin( abax
dxbaxa )cos(
0);sin( abax
9. E. cx
3
1
4sin
4
1
dxx
3
1
4cos
= cx
3
1
4sin
4
1
10. D. cx
4
1
5tan
5
1
dxx
4
1
5sec2
cx
4
1
5tan
5
1
11. B.
9
7
1
0
2
31 dxxx
1
0
22
3131
6
1
xdx
1
0
22
3131
9
1
xx
9
7
9
1
9
8
12. D. 122
3
2
dtan1sec
45
0
2
= )(tantan1
45
0
d
=
45
0
tan1)tan1(
3
2
=
3
2
2
2
4
= 122
3
2
13. D. c2
sec
2
1
dd 2
3
sectan
cos
sin
)(secsec d
c 2
sec
2
1
14. A. ctt 33
3
1 22
dtttdttt 33 224
)3(3
2
1 22
tdt
ctt 33
3
1 22
15. D.
3
1
1
0
2
1
0
42
1 dxxxdxxx
1
0
22
)1(1
2
1
xdx
1
0
22
1)1(
3
1
xx
3
1
16. C.
8
17
1
1
3
1
4
1
dxx
1
1
3
1
4
1
1
4
1
4 xdx
1
1
4
1
4
1
x
256
81
256
635
8
17
16
34
256
544
17. E. cxx 552
33
dxxx 59
32
553
33
xdx
cxx 552
33
23. - 23 -
18. C. cx 14 3
dx
x
x
1
6
3
2
1
1
2
3
3
x
xd
cx 14 3
19. B. 28
8
1
4
0
4
sincos5
xdxx
4
0
4
)(coscos5
xxd
4
0
5
cos
x
12
8
1
28
8
1
20. A. cxxxx 41782142 22
dxxxx 417216 2
4174173 22
xxdxx
cxxxx 4174172 22
B. Evaluasi Pemahaman dan Penguasaan Materi
1. a. dxx 2
3
)2(
cx 2
5
)2(
5
2
b.
)1(
)1(
1
)1( 33
xd
xx
dx
c
x
2
)1(2
1
c.
3
3
3 x
xd
x
dx
cx 32
d. )13(13
3
1
13 xdxdxx
cxx 13)13(
9
2
e. xdxx 3
1
2
32
3232
4
1 2
3
1
2
xdx
cxx 3 22
3232
16
3
f. dyyy
34
1
44
11
4
1
ydy
cyy 44
11
6
1
g. dxxx
2
4
22
44
2
1
xdx
cxx 22
44
3
1
h. dxx4
)4(4 xdx
cxx 44
3
2
i.
du
u
u
52
sin1
2sin
)sin1(
sin1
1 2
52
ud
u
c
u
42
sin14
1
cu 8
sec
4
1
j.
32
4x
xdx
32
2
4
4
2
1
x
xd
c
x
22
44
1
2. a.
3
2
2
2
1
2
dx
x
x
3
2
2
2
2
1
1
x
xd
3
2
2
1
1
x
3
1
8
1
24
5
24
83
24. - 24 -
b.
1
0
2
1 dxxx
1
0
22
)1(1
2
1
xdx
1
0
22
11
3
1
xx
3
1
3
1
0
c.
2
0
2cos
xdxx
2
0
)2(2cos
2
1
xxd
2
0
2sin
2
1
x
0
d.
3
0
3
0
2
2
2
9
)9(
2
1
9 x
xd
x
xdx
3
0
2
9
x
329
e.
4
0
4
0
)42()42(
2
1
)42( tdtdtt
4
0
2
)42(
4
1
t
31436
f.
4
0
2
1
4
0
2
1
)42()42(
2
1
)42( tdtdtt
4
042 t
232
g.
0
2
cos dttt
0
22
)(cos
2
1
tdt
0sin
2
1
0
2
t
h.
2
0
2
0
22sin
2
1
2sin
dd
2
0
2cos
2
1
1
2
1
2
1
i.
2
0
3 2
32)1( dxxxx
2
0
23 2
3232
2
1
xxdxx
2
0
3 22
3232
8
3
xxxx
03
8
9
3
8
9 33
j.
2
0
5cos5sin xdxx
2
0
10sin
2
1
xdx
2
0
10cos
20
1
x
0
20
1
20
1
3. a. dxxx 3cos2
cxx 3sin
3
1
3
1 3
b.
tdtt
3
2
3
5
55
3
2 2
3
3
2
3
tdt
ctt
4
5
6
1
c.
dxx 5
4
211
xdx 211211
2
1 5
4
cx 5
1
211
2
5
d.
32
2
32
53
53
53
)96(
xx
xxd
xx
dxx
c
xx
22
532
3
e. dxxx 2
1
32
9
99
3
1 32
1
3
xdx
f. dxxx
2
3sin
22
33sin
2
1
xdx
cx 2
3cos
2
1
25. - 25 -
g. tdttcossin
3
ttd sinsin
3
ct 4
sin
4
1
h. dxxx 2
1
32
4
44
3
1 32
1
3
xdx
cxx 44
9
2 33
i. dxxx 2
1
43
9
994 42
1
4
xdx
cxx 99
3
8 44
j. dxxx 12
)12()12(
2
1
xdx
2
)12(
4
1
x
4. a. dxxx 65
sin12
66
sin2 xdx
cx 6
cos2
b. xdxx cossin8
xxd sinsin8
cx 9
sin
9
1
c. xdxx 38
cossin
)(sinsin8
xxd
cx 9
sin
9
1
d. dx
x
x
2
1
sin4
x
d
x
11
sin4
c
x
1
cos4
e. xdxx 3sin
xxd 33sin
3
1
cx 3cos
9
1
f. xdxxsincos
10
xxd coscos
10
cx 11
cos
11
1
g. xdxx
212
sectan
)(tantan
12
xxd
cx 3
tan
13
1
h. dxxx 2sin42cos
)2sin4(2sin4
2
1
xdx
cxx 2sin42sin4
3
1
i. dsincos1
10
)cos1()cos1(
10
d
c 11
cos1
11
1
j.
dx
x
x
2
)cos2(
sin
2
)cos2(
)cos2(
x
xd
c
x
)cos2(
1
5. a. dxxx 13
4
3
1
11
4
3 3
4
3
4
xdx
cxx
11
2
1 3
4
3
4
b.
dx
xx
10
5
1
10
5
5
2
x
xd
c
x
9
59
2
c. dxxxx 22
sincos
22
coscos
2
1
xdx
cxx 22
coscos
3
1
d. dxxxx 225
cossin
225
sinsin
2
1
xdx
cx 26
sin
12
1
26. - 26 -
e.
dx
xx 2
10
11
1
x
d
x
1
1
1
1
10
cx 11
)1(
11
1
f. dxxx )12(sec)12(tan
26
)12tan()12(tan
6
xdx
cx )12(tan
7
1 7
g. dxxecxx 23cos23cot
2227
)23cot(23cot
6
1 227
xdx
cx 23cot
48
1 28
h. dxxax
322
3232
3
1
xadxa
cxaxa
3232
9
2
6. a.
dx
x
x
1
2
...
b.
dx
x
x
1
...
c.
dt
t
t
23
6
...
d. dttt 45
3
...
e. dxxx 1
2
...
f.
dx
xx
xx
4
32
2
2
3
432
32
2
2
2
1
xx
xxd
c
xx
3
32
26
1
g. dxx
x
100
1
1
xdx 112
100
cx
101
1
101
2
h.
dt
t
t
3
2
tan1
sec
3
)tan1(
)tan1(
t
td
c
t
2
)tan1(2
1
i. xdxxx sincoscos3 2
)(coscos)(coscos3 2
xxdxxd
cxx 32
cos
3
1
cos
2
3
j.
x
xd
dx
x
x
55
sin
)(sin
sin
cos
c
x
4
sin3
1
7. a.
2
0
)( dxxf
2
1
4
1
0
3
dxxdxx
2
1
5
1
0
4
5
1
4
1
xx
20
9
6
5
1
5
32
4
1
27. - 27 -
b.
0
)( df
2
2
0
cos dd
2
22
0
2
1
sin
82
1
22
8
3
1
2
8. a. xdxx sincos100
xxd coscos100
cx 101
cos
101
1
b. dec270
coscot
cotcot70
d
c 71
cot
71
1
c. dtansec10
secsec9
d
c 10
sec
10
1
d. d220
sectan
tantan20
d
c 21
tan
21
1
e. d3cos3sin4
3sin3sin
3
1 4
d
c 3sin
15
1 5
f. dxxx 3cot3cot 810
dxxx 3cot13cot 28
xdx 3cot3cot
3
1 8
cx 3cot
27
1 9
g. dttt 4tan4tan
68
dttt 4tan14tan
26
)4(tan4tan
4
1 6
tdt
ct 4tan
28
1 7
h. xdxecx
2
coscot1
xdx cot1cot1
cxx cot1cot1
3
2
i. dxxx tan2tan1
22
...
j. dcossinsin2
2
dd cossincossin2
2
)(sinsin)(sinsin2
2
dd
c 32
sin
3
1
sin
C. Evaluasi Kemampuan Analisis
1.
dxxx 3
2
2
11
...
2. a.
a
a
dxxf )(
aa
a
dxxfdxxf
0
)()(
Karena f fungsi ganjil
)()( xfxf , maka
aa
dxxfdxxf
00
)()(
0 (terbukti)
28. - 28 -
b.
a
a
dxxf )(
aa
a
dxxfdxxf
0
)()(
Karena f fungsi genap, maka
aa
dxxfdxxf
00
)()(
a
dxxf
0
)(2
atau
00
)()(
aa
dxxfdxxf
0
)(2
a
dxxf
3. a.
a
dxxf
0
)(
...
b.
2
0
cossin
sin
dx
xx
x
...
4. a.
2
0
)(sin
dxxf
...
b.
0
)(sin dxxxf
...
5. a.
2
0
cos)(3sin)(
xdxxfxxf
...
b.
2
0
cos)(sin)(
tdttfxxf
...
6. a.
x
dt
t
t
xx 0
cos1
cos1
0
lim
...
b.
x
dt
x
t
x 0
2
)sin1(
0
lim
x
tdtt
xx 0
2
sinsin21
1
0
lim
x
tdtt
xx 0
2cos
2
1
2
1
sin21
1
0
lim
x
ttt
xx 0
2sin
4
1
cos2
2
31
0
lim
22sin
4
1
cos2
2
31
0
lim
xxx
xx
xx
x
x
x
x
2
4
2sin1cos2
2
3
0
lim
c.
x
dt
x
t
x 0
2
coslim
x
dt
x
t
x 0
2
1
2
1
2coslim
x
x
tt
x 0
4
1
2
1
2sinlim
29. - 29 -
x
xx
x
2sinlim 4
1
2
1
x
xx
2sin
4
1
2
1lim
2
1
A. Evaluasi Pemahaman dan Penguasaan
Materi
1. a. xdxx 32
sincos
xdxxx sin)cos1(cos 22
xdxxxdxx sincossincos 42
)(coscos)(coscos 42
xxdxxd
cxx 53
cos
5
1
cos
3
1
b. xdxx 34
cossin
xdxxx cos)sin1(sin 24
xdxxxdxx cossincossin 64
)(sinsin)(sinsin 64
xxdxxd
cxx 75
sin
7
1
sin
5
1
c. xdxx 2cos2sin 52
...
d. xdxx
33
cossin
xdxxx cos)sin1(sin
23
)(sinsin)(sinsin
53
xxdxxd
cxx 64
sin
6
1
sin
4
1
e. tdtt
2
sincos
)(sinsin
2
ttd
ct 3
sin
3
1
f. xdx
2
sin
dxx
2cos
2
1
2
1
cxx 2sin
4
1
2
1
g. dxx )2(cos
4
dxx
2
)42cos(
2
1
2
1
dxxx )42(cos
4
1
)42cos(
2
1
4
1 2
dxxx )84cos(
8
1
8
1
)42cos(
2
1
4
1
cxxx )84sin(
32
1
)42sin(
4
1
8
3
h. xdx5sin3
xdxx 5sin5cos1 2
)5(cos5cos
5
1
5sin 2
xxdxdx
cxx 5cos
15
1
5cos
5
1 3
i. xdx2cot
3
xdxxec 2cot2cos1
2
)2(cot2cot
2
1
2cot xxdxdx
cxx 2cot
4
1
2sinln
2
1 2
j. xdx2
cot
dxxec2
cos1
cxx cot
2. a.
3
6
42
sincos
d
3
6
2
2cos
2
1
2
1
2cos
2
1
2
1
d
3
6
4cos
2
1
2
1
4
1
2cos
2
1
2
1
2cos
2
1
2
1
d
3
6
4cos
8
1
2cos
2
1
8
3
2cos
2
1
2
1
d
Latihan Kompetensi
Siswa 7
30. - 30 -
b.
3
0
3
3cos
d
3
0
2
3cos3sin1
d
3
0
2
3
0
)3(sin3sin
3
1
3cos
dd
3
0
3
3
0
3sin
9
1
3sin
3
1
0
c.
0
5
sin tdt
0
2
sin2cos
2
1
2
1
tdtt
0
2
sin4cos
2
1
2
1
4
1
2cos
2
1
4
1
tdttt
0
sin4cos
8
1
sin2cos
2
1
sin
8
3
tdtttdtttdt
ttt coscos
3
1
cos
8
3 3
d.
3
6
2
tan
d
3
6
2
1sec
d
3
6
tan
6
3
3
1
3
3
6
3
3
2
e.
2
4
6
cos
dec
...
f.
0
2
3sin xdx
0
6cos
2
1
2
1
dxx
0
6sin
12
1
2
1
xx
)00(0
2
2
g.
2
2
2sin
xdx
2
4sin
8
1
2
1
xx
0
2
0
4
4
3
h.
2
4
cossin
xdxx
2
4
2
sin
2
1
x
4
1
2
1
4
1
i.
4
0
22
sectan
xdxx
4
0
3
tan
3
1
x
3
1
j.
dx
x
x
4
sin
cot1
dx
x
x
xdxec 5
4
sin
cos
cos
...
31. - 31 -
3. a. xdx3tan
5
dxxx )1(sectan
23
dxxxd
33
tan)(tantan
dxxxxxd )1(sectan)(tantan
23
xdxxdxxxd tan)(tantan)(tantan3
cxxx coslntan
2
1
tan
4
1 24
b. xdx
4
sec
dxxx )tan1(sec
22
)(tantansec
22
xxdxdx
cxx 3
tan
3
1
tan
c. xdxx sectan3
xdxxx sectan)1(sec2
xdxxxxd sectan)(secsec2
cxx secsec
3
1 3
d. tdt3
cot
tdttec cot)1(cos
2
tdtttd
cot)(cotcot
1
ctt
sinln
1
cot
1 2
2
e. xdxx 2sec2tan 33
...
f. xdxecx 2cos2cot
33
...
g. xdx
7
tan
dxxx )1(sectan
25
dxxxd
55
tan)(tantan
dxxxxxd )1(sectan)(tantan
235
dxxxdxxd 335
tan)(tantan)(tantan
)(tantan)(tantan 35
xxdxxd
dxxx )1(sectan
2
)(tantan)(tantan 35
xxdxxd
dxxxxd tan)(tantan
cxxxx coslntan
2
1
tan
4
1
tan
6
1 246
h. x
dx
3
cot
xdx
3
tan
cxx coslntan
2
1 2
i.
xdx5
cos
dxxx )sin1(cos 23
xdxxdx 233
sincoscos
xdxxxdxxx sin)sin1(cos)sin1(cos 22
)(sinsin)(sinsincos 2
xxdxxdxdx
)(sinsin3
xxd
cxxxx 423
sin
4
1
sin
2
1
sin
3
1
sin
j.
dx
x
x
4
sin
cot1
32. - 32 -
A. Evaluasi Pemahaman dan Penguasaan
Materi
1. a.
2
4 x
dx
sin2x
ddx cos2
2
arcsin
x
x
d
2
sin44
cos2
2
sin12
cos2 d
cd
c
x
2
arcsin
b. 2
36 y
dy
6
arcsin
cos6
sin6
y
ddy
y
22
sin16
cos6
sin3636
cos6 dd
cd
c
y
6
arcsin
c. 494 2
t
dt
7
2
arctan
sec
2
7
tan
2
7
2
t
ddt
t
49tan4
sec
2
4
49
2
2
7
d
2
2
2
7
tan149
sec d
c
t
c
7
2
arctan
14
1
14
1
d.
c
x
x
dx
2
arcsin
2
2
e.
c
x
x
dx
5
arctan
5
1
25 2
f.
c
y
y
dy
4
3
arctan
12
1
169 2
g. 2
81 x
dx
ddx
x
cos
22
1
sin
22
1
cos
cos22
1
d
cx 22arcsin
22
1
h.
dx
x
x
2
49
2
dx
x
x
dx
x
22
4949
2
ddx
x
sin
2
3
cos
2
3
2
2
2
49
)49(
8
1
cos13
sin3
x
xdd
cx
x
2
49
4
1
3
2
arccos
i.
dx
x
x
2
4
2
ddx
x
cos2
sin2
2
sin44
cossin d
cd cos4sin4
c
x
2
4
4
2
cx
2
42
j.
dx
x
x
2
916
3
c
x
4
916
12
2
cx 2
9163
Latihan Kompetensi
Siswa 8
33. - 33 -
2. a.
2x
4-x²
22
4 xx
dx
ddx
x
cos2
sin2
22
sin44sin4
cos2 d
dec2
cos
4
1
c cot
4
1
c
x
x
2
4
4
1
c
x
x
4
4
2
b.
2
x x²+4
4
2
xx
dx
ddx
x
2
sec2
tan2
4tan4tan2
sec2
2
2
d
dcot
2
1
c sinln
2
1
c
x
x
4
ln
2
1
2
c.
dx
x
x
2
2
4
ddx
x
cos2
sin2
2
2
sin4
cos2sin44 d
d
2
cot4
...
d.
6
x x²+6
6
2
2
x
dxx
ddx
x
2
sec6
tan6
6tan6
sec6tan6
2
22
d
d2
tan6
d)1(sec6 2
dd 6sec6 2
c 6tan6
c
xx
6
arctan6
6
6
c
x
x
6
6
arctan66
e. 2
25 xx
dx
ddx
x
cos5
sin5
2
sin2525sin5
cos5 d
sin5
1 d
...
f.
34. - 34 -
W²-7 W
7
722
ww
dw
ddw
dw
sectan7
sec7
7sec7sec7
sectan7
22
d
tan7sec7
sectan7
2
d
cd sin
7
1
cos
7
1
c
w
w
7
7
1
2
g. dxxx 22
16
ddx
x
cos4
sin4
dcos4sin1616sin16 22
d22
cossin256
d2cos12cos1
4
256
d2cos164 2
d4cos
2
1
2
1
164
d4cos
2
1
2
1
64
c 4sin832
c
xx
4
arcsin4sin8
4
arcsin32
h.
6
x 4+x²
2
3
2
4 x
dx
ddx
x
2
sec2
tan2
22
2
tan44tan44
sec2 d
sec2sec4
sec2
2
d
cd sin
4
1
cos
4
1
c
x
x
2
44
1
i.
3
2x4x²-9
2
3
2
94x
dx
ddx
x
sectan
2
3
sec
2
3
9sec99sec9
sectan
22
2
3
d
tan3tan9
sectan
2
2
3
d
dseccot
18
1 2
2
sin18
)(sind
c
sin18
1
c
x
x
9418
2
2
c
x
x
949 2
j.
24
16 xx
dx
ddx
x
2
sec4
tan4
24
2
tan1616tan64
sec4 d
sec4tan64
sec4
4
2
d
dseccot
64
1 4
35. - 35 -
x
x
4
3
sin
cos
64
1
3.
4x
16-x²
a.
2
0
2
3
16 x
dxx
sin4x
ddx cos4
6
0
2
3
sin1616
cos4sin64
d
6
0
3
sin64
d
6
0
2
sincos164
d
dd sincos64sin64
2
6
0
6
0
3
cos
3
64
cos64
6
0
222
64
1616
3
64
4
16
64
xxx
3
64
6438332
3
128
324
b.
4
x 16+x²
4
0
2
3
2
16 x
dx
ddx
x
2
sec4
tan4
4
0
22
2
tan1616tan1616
sec4
d
4
0
2
sec16
sec
d
4
0
cos
16
1
d
4
0
sin
16
1
4
0
2
1616
1
x
x
5
40
1
58
1
c.
3
x x²+9
33
3
22
9xx
dx
ddx
x
2
sec3
tan3
3
6
22
2
9tan9tan9
sec3
d
3
6
2
tan9
sec
d
d
3
6
2
sin9
cos
3
6
sin9
1
33
3
2
9
9
x
x
39
32
327
6
3
81
6
9
2
3
27
2
9
2
d.
36. - 36 -
2x
4-x²
1
0
2
2
4 x
dxx
ddx
x
cos2
sin2
6
0
2
2
sin44
cos2sin4
d
6
0
2cos
2
1
2
1
4
d
6
0
2cos22
d
6
02sin2
1
0
2
4
4
2
2
arcsin2
xxx
1
0
2
2
4
2
arcsin2
xxx
)00(1
3
1
3
e.
6
4
2
4xx
dx
ddx
x
sectan2
sec2
3
1
arccos
3
2
4sec4sec2
sectan2
d
3
1
arccos
3
2
1
d
3
1arccos
3
2
1
6
4
2
sec
2
1
x
arc
6
3sec
2
1
arc
f.
2
ww²-4
8
4
2
3
2
4w
dw
ddw
w
sectan2
sec2
4sec
4
22
4sec44sec4
sectan2
arc
d
4sec
4
2
tan2
sec
arc
d
d
arc
4sec
4
2
sin2
cos
4sec
3
sin2
1
arc
8
4
2
42
w
w
2
g.
5
0
22
25 dxxx
5
0
5
arcsin4sin
32
625
5
arcsin
8
625
xx
16
625
)00(0
16
625
h.
3
1
24
3xx
dx
...
i.
6 x
6-x²
37. - 37 -
2
1
2
3
2
6 x
dx
ddx
x
cos6
sin6
6
2
arcsin
6
1
arcsin
22
sin66sin66
cos6
d
6
2
arcsin
6
1
arcsin
2
cos6
d
6
2
arcsin
6
1
arcsin
2
sec6 d
6
2
arcsin
6
1
arcsin
tan6
2
1
2
6
66
x
5
66
63
30
5
6
63
j.
3
0
2
16 x
dx
ddx
x
2
sec
tan4
4
3arctan
0
2
2
tan1616
sec4
d
4
3arctan
0
4
1
d
4
1
3
0
4
arctan
4
1
x
4
3
arctan
4
1
4. a.
0
2
2sin1
2cos
dx
x
x
...
b.
4
0
2
2cos1
2sin
dx
x
x
...
5. a.
2
4 xx
dx
....
6.
dt
t
t
2
2
4
1
ddt
t
2
sec
tan
2
22
tan4
sectan1 d
d
ec
4
cossec
2
...
38. - 38 -
1. a. x
dx
sin53
...
b. 1tan x
dx
112
zz
dz
...
A. Eavaluasi Pemahaman dan Penguasaan
Materi
1. a. x
xdx
3
dxxdz
xz
3
4
4
z
z
dz
z
3
2
2
dz
z
z
)3(2
2
3
...
A. Evaluasi Pemahaman dan Penguasaan
Materi
1. a. dyyy
3
3
Cara Tabulasi
y
3
3 y
1
4
3
4
1
y
0
5
3
20
1
y
cyyy 54
3
20
1
3
4
1
b.
dx
x
x
1
x
2
1
1
x
1 2
1
12 x
0
cx 2
3
1
3
4
cxxxx 11
3
4
12
c. dxxx
23
3
dxxxx 63
69
x 63
69 xx
1 74
7
1
2
3
9 xxx
0 852
56
1
10
3
2
9
xxx
cxxxxxx
852852
56
1
10
3
2
9
7
1
2
3
9
d. dxxx 1
2
2
x 2
1
1 x
x2
2
3
1
3
2
x
2
2
5
1
15
4
x
0
2
7
1
105
8
x
cx
xxxx
2
7
2
5
2
32
1
105
16
1
15
8
1
3
2
Latihan Kompetensi
Siswa 9
Latihan Kompetensi
Siswa 10
Latihan Kompetensi
Siswa 11
39. - 39 -
e. dyyy
2
8
y 2
8y
1
3
8
3
1
y
0
4
8
12
1
y
cyyy 43
8
12
1
8
3
1
f. dxxx 242
2
x 2
1
24 x
x2
2
3
24
3
1
x
2
2
5
24
15
1
x
0
2
7
24
105
1
x
2
5
2
3
2
24
15
2
24
3
1
x
x
xx
cx 2
7
24
105
2
g.
dx
x
x
3
5
21
...
h. dxxax 222
...
i. dxxx 62
2
x 2
1
6x
x2
2
3
6
3
2
x
2
2
5
6
15
4
x
0
2
7
6
105
8
x
2
5
2
3
2
6
15
8
6
3
2
x
x
x
x
cx 2
7
6
105
16
j. dttt 24
1
...
2. a. cxxxxx cossincos
x xcos
1 xsin
0 xcos
b. xxxxxx cos2sincos
22
cx sin2
2
x xcos
x2 xsin
2 xcos
0 xsin
c. cbx
b
a
bx
b
ax
bxax cossincos 2
ax bxcos
a
bx
b
sin
1
0
bx
b
cos
1
2
d.
dxxxxdxx 2cos
2
1
2
1
cos2
x
x2cos
2
1
2
1
1
xx 2sin
4
1
2
1
0
xx 2cos
8
1
4
1 2
xxxxx 2cos
8
1
4
1
2sin
4
1
2
1 22
e. xdxxxdxxx 2sin
2
1
cossin
x
x2sin
2
1
1
x2cos
4
1
0
x2sin
8
1
40. - 40 -
cxx 2sin
8
1
2cos
4
1
f. xdxxx 3cos3sin8
xdxx 6sin4
x4 x6sin
4
x6cos
6
1
0
x6sin
6
1
cxxx 6sin
3
2
6cos
3
2
g. dxxx )12cos(
x )12cos( x
1
)12sin(
2
1
x
0
)12cos(
4
1
x
cxxx )12cos(
4
1
)12sin(
2
1
h. xdxx 3sin2
2
x x3sin
x2
x3cos
3
1
2
x3sin
9
1
0
x3cos
27
1
xx
x
xx 3cos
27
2
3sin
9
2
3cos
3
1 2
3. a.
2
0
23
1 dttt
...
b.
0
2
cos xdxx
2
x xcos
x2 xsin
2 xcos
0 xsin
0
2
sin2cos2sin xxxxx
202
c.
xdxx 2cos
2
2
x x2cos
x2
x2sin
2
1
2
x2cos
4
1
0
x2sin
8
1
xx
x
xx 2sin
4
1
2cos
2
2sin
2
1 2
22
d.
3
0
cos3sin
xdxx
...
e.
2
0
2
2cos
dxx
...
f.
4
3
4
coscot
ecxdxxx
x ecxx coscot
1 xcot
0 xsinln
4
3
4
sinlncot
xxx
2
2
1
ln
4
2
2
1
ln
4
3
41. - 41 -
g.
2
0
sin
xdxx
x xsin
1 xcos
0 xsin
2
0sincos
xxx
1
h.
8
12
3
2cot
ydy
...
i.
4
0
2
sin
xdxx
2
x xsin
x2 xcos
2 xsin
0 xcos
4
0
2
cos2sin2cos
xxxxx
)200(2
4
2
32
22
22
32
)8(2
j.
0
3 332
sincos dxxxx
0
2
sincos xdxxx
0
2
2sin
2
1
xdxx
2
x x2sin
2
1
x2
x2cos
4
1
2
x2sin
8
1
0
x2cos
16
1
0
2
2cos
8
1
2sin
4
2cos
4
xx
x
x
x
48
1
8
1
4
22
4. a. xdxln
...
b. xdxx ln
2
...
c. dxex x
2
3
3
xu
dxxdu 2
3
2
x
edv
2
2
1 x
e
x
v
...
5. a. dxxe
x
3
x x
e3
1 x
e3
3
1
0 x
e3
9
1
cee
x xx
33
9
1
3
b.
dxex x3
3
x
x
e
2
3x x
e
x6 x
e
42. - 42 -
6 x
e
0 x
e
xxxx
exeexex
663
23
cxxxe x
663 23
c. dxex x3
3
x
x
e
2
3x x
e
x6 x
e
6 x
e
0 x
e
xxxx
exeexex 663 23
cxxxex
663 23
d. xdxx sin
4
xxxxxx cos12sin4cos
234
cxx cos24sin24
e. xdxx cos4
xxxxxx sin12cos4sin 234
cxx sin24cos24
f. dxxt )52sin(
3
3
t )52sin( x
2
3t )52cos(
2
1
x
t6
)52sin(
4
1
x
6
)52cos(
8
1
x
0
)52sin(
16
1
x
)52sin(
4
3
)52cos(
2
1 2
3
x
t
xt
cxxt )52sin(
8
3
)52cos(
3
1
6. a.
2
0
2
dxxe x
2
0
22
2
1
2
1
xx
exe
2
1
0
2
1 44
ee
2
1
2
1 4
e
b.
4
0
3
4sin
xdxe x
...
c.
4
1
sec dxxarc
...
d.
1
0
arcsin xdxx
...
A. Evaluasi Pemahaman dan Penguasaan
Materi
1. a.
3
0
2
2dxxL
3
0
3
2
3
1
xx
1569
b.
4
0
2
4 dyyyL
Latihan Kompetensi
Siswa 12
43. - 43 -
4
0
32
3
1
2
yy
3
32
3
64
32
c. dxxL
9
0
9
03
2
xx
18
d.
1
0
23
0
3
23
3232 xdxxxxxxL
0
3
234
3
3
2
4
1
xxx
1
0
234
3
2
3
4
1
xxx
3
2
3
4
1
2718
4
81
2
1
24
2. a.
4
1
2xdxL
15
4
1
2
x
b.
5
1
)12( dxxL
5
1
2
xx
20020
c.
7
4
62xL
7
4
2
6xx
1587
d.
1
0
1 xdxL
1
0
2
2
1
xx
2
1
3. a.
-2 1 2
4
x
y
2
1
2
4 dxxL
2
1
3
3
1
4
xx
3
1
1
3
8
8
3
14
3
7
7
b.
-2 1 2
4
x
y
dxxL
1
2
2
4
1
2
3
3
1
4
xx
3
8
8
3
1
4
3
43
3
7
12
c.
44. - 44 -
x
y
-3
9
0
3
2
)3( dxxL
0
3
3
)3(
3
1
x
9
d.
x
y
-3 2-4
111
4
3
2
3
2
12 xxL
2
3
32
3
1
2
1
12
xxx
)278(
3
1
)94(
2
1
)5(12
3
35
2
5
60
3
2
11
2
1
260
6
5
50
e.
1
4
x
y
3 4
3
1
2
4 dxxxL
3
1
32
3
1
2
xx
3
26
16
3
22
4. a.
1 x
y
-1
1
1
1
2
1 dyyL
1
1
3
3
1
yy
3
4
3
2
3
2
b.
45. - 45 -
x
y
1
-9
3
3
1
0
2
93 dyyL
1
0
3
9yy
8
c.
4
x
y
2-2
2
2
2
4 dxxL
2
2
3
3
1
4
xx
3
8
8
3
8
8
3
32
3
16
16
d.
x
y
2-3
51
4
2
3
2
6 dxxxL
2
3
32
3
1
2
1
6
xxx
9
2
9
18
3
8
212
2
1
4
3
2
219
6
5
20
e.
1 x
y
1
1
0
2
122 dxxxL
1
0
23
1
3
1
2
xx
3
2
4
f.
1 x
y
-1
10
-10
1
0
3
92 xdxxL
2
19
2
9
4
1
2
1
0
24
xx
46. - 46 -
5. a.
2
0
2
42 dxxL
3
36
3
1
42
2
0
3
xx
b.
8
1
3
1
dyyL
8
1
3
4
4
3
y
4
1
11
4
3
12
c.
dyyL
5
1
1
3
16
11
3
2
5
1
yy
d.
dxxxL .4
0
2
2
0
2
23
2
3
1
xx
3
2
108
3
8
e.
dyyL
2
0
2
3
8
3
1
2
0
3
y
f.
dyyL
5
1
12
2
32
11
3
4
5
1
yy
47. - 47 -
A. Evaluasi Pemahaman dan Penguasaan
Materi
1. a.
dxxxL 39
2
3
2
dxxx
2
3
2
6
2
3
32
3
1
2
1
6
xxx
35
3
1
5
2
1
5.6
3
35
2
5
30
6
5
20
3
2
11
2
1
230
b.
dxxxL
2
1
2
2
2
1
2
2 xx dx
2
1
23
2
1
3
1
2
xxx
3.
2
1
9.
3
1
3.2
2
1
4
2
3
36
c.
dxxxL
1
0
2
6
1
3
1
2
1
1
0
32
xx
d.
dxxxL
1
0
3
2
2
1
4
1
2
1
2 42
xx
e.
dxxxL 444
4
0
2
4
0
2
4xx dx
4
0
23
2
3
1
xx
3
32
3
64
32
Latihan Kompetensi
Siswa 13
39 2
xx
062
xx
023 xx
3x ; 2x
xx 2
2
022
xx
012 xx
2x ; 1x
xx 44 2
042
xx
04 xx
0x ; 4x
48. - 48 -
f.
2
0 2
22 dx
x
L
0
2
3
6
1
22
xx
3
16
3
4
42
g.
dxxxxL
2
0
2
dxxx
2
0
2
.2
2
0
23
3
1
xx
3
4
3
8
4
h.
1
2
2
2 xxL dx
1
2
23
2
1
3
1
2
xxx
2
1
4
2
3
36
i.
2
1
2
2 dxxxL
2
1
32
3
1
2
2
1
xxx
2
1
436
2
3
j.
56 2
xx
0562
xx
051 xx
1x ; 5x
Jika digeser menjadi
5
1
2
56 dxxxL
5
1
23
53
3
1
xxx
2072
3
12
y
3
2
1052
3
1
41
xxx
2
02
2
xx
02 xx
0x ; 2x
xx 2
2
022
xx
012 xx
2x ; 1x
xx
2
2
02
2
xx
012 xx
2x ; 1x
49. - 49 -
2. a.
10
1
12 dxxL
3611
3
4
10
1
xx
b.
0
4
2
4yyL dy
0
4
23
2
3
1
yy
3
32
32
3
64
c.
4
2
2
4
2
2
1
dx
y
yL
4
2
32
12
1
2
4
1
yyy
176203
d.
4
2
2
y
y
822
yy
0822
yy
024 yy
4y ; 2y
4
2
2
2
4 dx
y
yL
4
2
32
6
1
4
2
1
yyy
121224
3. a.
dxxxxxL 26 2
4
0
2
4
0
2
82 xx dx
4
0
23
4
3
2
xx
3
64
64
3
128
50. - 50 -
b.
1
0
32
dxxxL
12
1
4
1
3
1
1
0
43
xx
c.
dxxxxL 2
5
0
2
10
dxxx
5
0
2
210
5
0
32
3
2
5
xx
3
125
3
250
125
4. a. 2
2
xx
02
2
xx
012 xx
2x ; 1x
b. 22
yy
022
yy
012 yy
2y ; 1y
c.
4
cossin xxL dx
4
sincos xx
212
2
1
2
2
1
01
d.
1
0
3
4
1
2 xxL dx
1
0
24
8
1
4
1
2
xx
4
1
8
1
.2
e.
3
2
2
62 dxxxxL
3
2
82 dxxx
3
2
23
8
3
1
xxx
3
1
33405
3
35
f.
0
sinsin22 xxL dx
0
sin2 x dx
4cos2 0
x
g.
2
0
coscos24
xxL dx
4sin4 2
0
x
h.
56,206
56,26
cossin22 xxL dx
360
56,206
sin2cos xx dx
56,206
56,26
sincos2 xx
360
56,206
cos2sin xx
45,079,145,079,1
79,145,020
45,079,145,079,1
82,779,145,020
5. a. xxx 5
xxx 52
042
xx
04 xx
0x ; 4x
xy
44
Koordinat titik 4,4A
dxxxL
2
1
2
2
2
1
32
3
1
2
2
1
xxx
2
1
43
3
2
dyyyL
2
1
2
2
2
1
32
3
1
2
2
1
yyy
2
1
4
51. - 51 -
b.
4
5
2
5xxL
0
4
2
5 dxxxxdx
0
4
23
4
5
23
2
3
1
2
5
3
1
xxxx
32
3
64
2
45
3
61
6
5
12
2
1
54
3
2
41
6.
Persamaan garis lurus PQ
23
2
21
2
2
1
9
1
2
1
xy
2
18
35
2
5
xy
18
115
18
35
xy
3
2
2
10
18
115
18
35
dx
x
xL
3
2
2 10
18
115
36
35
x
xx
2
10
3
10
18
115
37
175
36
5
36
180120230175
7. a. 011 2
xx
1x ; 1x
jadi 0,1A dan 0,1B
11010 2
y
jadi 1,0C
012.111 21
xxxym
0212
22
xxx
0123
2
xx
0113 xx
3
1
x ; 1x
2
1
3
1
1
3
1
y
27
16
9
4
.
3
4
y
Jadi
27
16
,
3
1
M
b. Luas LuasAMCO : OCB
1
0
20
1
2
11:11 dxxxdxxx
1
0
23
0
1
23
1:1 dxxxxdxxxx
1
0
234
0
1
234
234
:
234
x
xxx
x
xxx
1
2
1
3
1
4
1
:1
2
1
3
1
4
1
12
12643
:
12
12643
5:11
12
5
:
12
11
8. Misal mxy
xxm 22
022
xxm
012
xmx
0x ; 2
1
m
x
m
y
1
y
m
1
dy
m
y
tL
t
0
52. - 52 -
9.
Luas
2
0
3
8 dxxA
2
0
4
4
1
8
xx
12416
Luas
2
0
3
dxxB
4
4
1
2
0
4
x
Luas LuasB : 12:4A
3:1
10. a.
3
4
04
3
042
0 ; 2 ; 2
ambil 2 0karena
2.44 x
8
Jadi 2 dan 8
b.
2
0
3
4 dxxxL
2
0
42
4
1
2
xx
448
B. Evaluasi Kemampuan Analisis
1. a. xxxx 5456 22
01010 2
xx
02
xx
01 xx
0x ; 1x
0y ; 1y
gbr tidak jelas,tolong gbr ulang!!!
1
0
22
5654 dxxxxxL
1
0
2
1010 xx dx
1
0
23
5
3
10
xx
3
5
5
3
10
b.
1
0
2
54 xxxLI dx
1
0
2
44 xx dx
1
0
23
2
3
4
xx
3
2
2
3
4
1
0
2
56 dxxxxLII
1
0
2
66 dxxx
123
1
0
32
xx
3
2
:1: LILII
2:3
2. a.
53. - 53 -
3. L
2
2
2
4 dxxAEB
2
2
3
3
4
x
x
3
8
8
3
8
8
3
16
16
3
1
11
3
64
panjang persegi panjangpanjang AB
422
lebar persegi
3
16
4
3
64
panjang
4. gambar & tulisan yang jelas doong!!!
1
0
22 2
1
22 dxxxL
arc
1
3
3
1
2
sin
x
x
11
4
5.
6.
A. Evaluasi Pemahaman dan Penguasaan
Materi
1. a.
3
0
2
2 dxxV
3
0
2
4 dxx
36
3
4
3
0
3
x
b.
6
0
2
2
dy
y
V
6
0
2
4
dy
y
18
12
6
0
3
y
2. a.
2
0
22
2 dxxV
3
0
23
44 dxxx
2
0
34
4
3
4
4
1
xxx
3
2
228
3
32
4
b. 2.2.
3
2
22 2
V
8
3
2
22
3
2
14
c.
2
0
22
42 dxxV
2
0
23
4xx
2424
Latihan Kompetensi
Siswa 14
54. - 54 -
3. a.
1
0
8xV dx
44
1
0
2
x
b.
2
0
8xV dx
164
2
0
2
x
c.
2
1
8xV dx
284
2
1
2
x
d. 88
2
1
xV dx
2
1
2
84 xx
4812
e.
2
0
816 xV dx
16416
2
0
2
xx
f.
2
1
816 xV dx
2
1
2
416 x
41216
4. a.
2
1
2
2 dxxV dx
2
0
23
42
3
1
xxx
3
8
88
3
8
b.
1
0
2
dxxV
3
1
3
1
1
0
3
x
c.
2
2
4
dxxV
2
2
5
5
1
x
5
64
5
32
5
32
d.
1
1
22
316 dxxV
1
1
24
9616 dxxx
1
1
35
2
5
1
7
xxx
5
3
94
5
2
14
e.
1
0
432
2 dxxxxV
30
1
5
1
2
1
3
1
1
0
543
xxx
55. - 55 -
f.
5
0
4
4 dxxV
2500
5
4
5
0
5
x
g.
1
0
4xV dx
22
1
0
2
x
h.
4
0
4 xV dx
8
2
1
4
4
0
2
xx
i.
6
0
4
16
dx
x
V
80
7776
80
1
6
0
5
x
j.
2
0
4
16256 dxxV
5
2048
5
16
256
2
0
5
xx
5. a.
2
0
4
dxxV
5
32
5
1
2
0
5
x
b.
56. - 56 -
2
0
24
12 dxxxV
15
206
3
2
5
1
2
0
35
xxx
c.
2
0
6
dxxV
7
128
7
1
2
0
7
x
d.
2
1
2
1
dx
x
V
2
1
2
1
x
e.
1
2
4
dxxV
5
31
5
1
1
2
5
x
f.
2
1
2
2 1
1 dx
x
xV
2
1
3 1
3
1
x
xx
6
5
1
2
1
1
3
1
g.
1
0
4
1 dxxV
3
2
3
1
1
0
3
xx
6. a.
1
0
2
1
1
dx
x
V
21
1
1
0
x
b.
1
0
21 xxV dx
1
0
2
2
1
3
4
xxxx
62
1
3
4
1
c.
6
5
6
2
sin4
xV dx
6
5
6
2cos22
x dx
6
5
6
2sin2
xx
3
2
1
6
2
3
2
1
6
10
3
3
4 2
57. - 57 -
A. Evaluasi Pemahaman dan Penguasaan
Materi
1. a.
3
0
2
9
1 dy
y
V
3
0
3
27
y
y
213
b.
3
0
2
9
dy
y
V
3
0
3
27
y
2. a.
1
0
5
1
144 dyydyV
5
1
21
0
2
1
44
yyy
1212204
b.
5
1
14 dyyV
8
2
1
5
5
1
2
yy
c.
5
1
1dyyV
8
2
1
5
1
2
yy
3. a.
22
0
4
64
1 dy
y
V
22
0
5
320
y
y
2
5
8
2
5
2
22
b.
22
0
4
64
4 dy
y
V
2
5
38
320
4
22
0
5
y
y
c.
22
0
4
64
dy
y
V
2
5
2
320
22
0
5
y
d.
4
0
4
64
dy
y
V
5
16
320
4
0
5
y
e.
4
0
4
64
4 dy
y
V
4
0
5
320
4
y
y
5
64
5
16
16
4. a.
4
0
yV dy
8
2
1
4
0
2
y
b. dyyV
5
0
2
3
125
3
5
0
3
y
c. dy
y
V
16
0 4
32
8
16
0
2
y
d. dyyyV
4
1
2
12
4
1
23
3
1
yyy
931521
e. dy
y
V
50
0 2
625
4
50
0
2
y
f. dyyV
0
5
5
0
5
2
5
2
1
yy
2
75
25
2
25
g.
1
0
2
1
11 dydyyV
1
0
2
1
2
2
1
2 yyy
2
3
2
h. dyyV
4
0
4
5
1024
5
4
0
5
y
Latihan Kompetensi
Siswa 15
58. - 58 -
5.
a.
4
0
2
16
9
dxxV
12
48
9
4
0
3
x
b.
3
0
2
9
16
16 dyyV
3
0
3
27
16
16
yx
321648
c.
3
0
2
4
3
4
xdyV
32
27
16
3
0
3
y
d.
4
0
3
4
3
ydxV
12
48
9
4
0
3
x
6. a.
1
0
3
2
dyyV
1
0
32
yy
b.
2
0
4
dyyV
5
32
5
1
2
0
5
y
c.
2
0
yV dy
2
2
1
2
0
2
y
d.
1
0
1dyyV
22
1
1
0
2
yy
A. Evaluasi Pemahaman dan Penguasaan
Materi
1.
5
2
2
2 10
7 dx
x
xV
5
2
2
2 100
1449 dx
x
xx
5
2
32 100
3
1
749
x
xxx
9502039147147
2.
1
0
2
1
22
1
22
dxx
x
dx
x
V
2
1
2
3
1
0
3
2
1
1212
xx
xx
6
1
2
3
12
7
12
3.
2
1
4
2
2
2
2
1
4
1
dx
x
dx
x
V
4
2
3
2
1
23
3
1
4
1
4
1
12
1
x
xxx
192
23
192
7
12
4.
2
3
0
2
46 dxxxV
2
3
0
32
3
4
3
xx
2
9
4
27
4
9
4
1827
5.
1
0
2
1
2
2
2 4
113 dx
x
dxxV
1
0
2
69 xx dx
x
dx
2
1
4
16
2
1
3
1
0
23
3
16
33
x
xx
3
32
3
14
6
Latihan Kompetensi
Siswa 16
59. - 59 -
6.
3
0
4 yV dy
3
0
2
2
1
4
yy
2
15
2
9
12
7.
2
0
22
410 dxxxxV
2
0
32
3
5
5
xx
3
20
3
40
20
8. a.
2
0
2222
1352 dxxxV
2
0
2424
16925204 dxxxxx
2
0
24
24145 dxxx
3
160
24
3
14
2
0
35
xxx
b.
6
2
2
2 12
8 dx
x
xV
6
2
2
2 144
6416 dx
x
xx
6
2
23 144
648
3
1
x
xxx
3
1
217224256256
3
208
c.
4
0
2
1684 xxV dx
4
0
2
16646416 xxx dx
4
0
2
643216 dxxx
3
1600
6416
3
16
4
0
23
xxx
d.
1
0
2
1
2
2222 dxxxdxxV
2
1
231
0
2
45
3
4
xxxx
3
32
415
3
28
9.
1
0
4
dxxxV
10
3
5
1
2
1
1
0
52
xx
10.
2
2
42
124 dxxxV
2
2
53
3
5
1
3
2
xxx
15
74
26
5
28
2
3
8
11.
2
0
2
24 dxxxV
2
0
3
2
3
4
x
xx
3
20
3
8
48
12.
a
a
dy
a
y
aV
2
2
4
2
2
16
a
a
a
y
ya
2
2
2
5
2
80
333
5
16
5
4
4 aaa
13.
5
1
2
100
dx
x
V
80
100
5
1
x
14.
2
1
42
44 dxxxxV
2
1
523
5
1
42
3
1
xxxx
15
182
5
31
46
3
7
15.
4
1
432
12284816 dxyyyyV
4
1
5432
5
1
3
3
28
2416
yyyyy
3
2
486205765
3
1820
36080
B. Evaluasi Kemampuan Analisis
1. a.
4
0
3
64 xV 8yd
192
4
1
64
4
0
4
xx
b.
8
0
3
4
16 yV 4xd
7
512
7
3
164
8
0
3
7
yy
60. - 60 -
c.
8
0
3
4
yV 4xd
7
384
7
3
8
0
3
7
y
d.
4
0
3
xV 8yd
64
4
1
4
0
4
y
2.
0
2
2
0
22
2
4
2
4
dx
xx
dx
xx
V
0
2
22
44
4
xdx
44
4
2
2
0
2
xdx
2
0
2
2
0
2
2
2
4
2
1
4
4
2
1
4
xx
48
4
8
4
3.
4.
2
0
2
64162 dxxxV
4
2
22
1616464162 dxxxxx
4
2
3
2
0
23
322648
3
1
2 xxxxx
3
1
2136456212832
3
8
2
5.
3
4
2
sec
xV dx
13tan 3
4
x
6.
4
0
2
sec
xV dx
4
0
tan x
7. a.
4
0
22
sincos
xxV dx
2
2sin
2
1 4
0
x
b.
4
0
22
cossin2sincos
xxxxV dx
2
1
4
2cos
2
1 4
0
xx
A. Pilihan Ganda
1. C.
0
2
21 dxxxx
2. A.
42
1
3
0
1
456
0
1
5
101051 xxxxdxxx
xx
2
5 dx
0
1
234567
2
1
3
5
2
5
2
6
5
7
1
xxxxxx
42
1
2
1
3
5
2
5
2
6
5
7
1
3.
5
5
2
5
1
4x
x
4. E.
5
5y
2
2
434
sin dxxxxx
2
2
43
2
2cos
2
1
2
1
dxxxxx
xxxx 4cos
2
1
2
1
4
1
2cos
2
1
4
12
2
dxxx
43
xxxx 4cos
8
1
8
1
2cos
2
1
4
12
2
dxxx
43
Uji Kompetensi Akhir
BAB I
61. - 61 -
xxxxx
8
1
2cos
8
1
2sin
4
1
8
1 2
2
2
54
5
1
4
1
4sin
32
1
xxx
5
54
5
64
2
1
000
5. A. cxxx
2
1
cos8
2
1
sin4
xx
2
1
cos2 cxxxdx
2
1
cos8
2
1
sin4
x2 x2
1
cos
2 x2
1
sin2
0 x2
1
cos4
6. C.
3
8
2
0
2
2xxL
2
3
2
2xxdx dx
2
3
23
2
0
23
3
1
3
1
xxxx
3
8
5
3
19
4
3
8
7. B.
5
2
10 satuan volume
2
1
42
44 dxxxxV
2
1
523
5
1
42
3
1
xxxx
5
2
10
5
33
1263
8. C. 0
2
0
22
cossin
xx dx
2
0
2cos
x 02sin
2
1 2
0
xdx
9. D. xx 4sin
8
1
2sin
4
1
xx 3sinsin xxdx 4cos
2
1
2cos
2
1
dx
cxx 4sin
8
1
2sin
4
1
10.
7363
2
7
1
2 xxdxxx
982
2
504
6
2
56
3
x
x
xx
10
2
5040
6
x
6
43
223
2
2
040.5
6
2
504
6
2
56
3
2
7
1
x
xxx
xxxx
6
2
040.5
1
x
lanjutannya manaa !!!
3
x 6
2 x
2
3x 7
7
1 2 x
x6 8
56
1
2 x
6 9
504
1 2 x
0 10
040.5
1
2 x
11. A. cxxxx 753
sin
7
1
sin
5
3
sinsin
x
7
cos xxdx cossin1
3
2
dx
xxxx cossinsin3sin31
642
dx
xcos xdx
2
sin3 xd sin
x
4
sin3 xxd
6
sinsin xd sin
cxxxx 753
sin
7
1
sin
5
3
sinsin
12. D.
6
5
1
3
2
2
312 dxxxxL
3
2
23
2
2
1
3
1
xxx
6
5
12
2
5
3
19
62. - 62 -
13. C. 1,2
k
o
dxxkxL 288,02
288,0
3
1
2
32
k
o
xx
k
2888,0
632
333
kkk
2,1k
14. E.
6
1
dxx
x
dx
x
V 1
44
2
1
2
1
0
2
2
1
23
1
0
3
2
1
12
1
12
1
xxxx
6
1
2
3
12
7
2
15. lanjutannya manaaa!!!
xx
dx
3
16. lanjutannya manaaa!!!
3
0
sincos
ttfxxf dt
3
0
sin
ttf xxfdt cos
17. C.
2
1
1
1
1
1
32
3
1
2
1
1
axxx
a
dxxax
12
3
1
2
3
2
aa
2
1
a
18. lanjutannya manaaa!!!
dxx
xxx
23
23
1
2233
23
1
22
22
33
223
1
3
1
2233
2233
6
3322
2233
19. B. 2
3
8
21
21
2
12 dxxx
21
21
2
3
3
xx
x
3
226231226231
212122212221
2
3
8
22242
3
10
20. D.
12
21
0
1
23
2xxxL dx xxx 22
2
1
3
dx
2
0
224
0
1
234
3
1
4
1
3
1
4
1
xxxxxx
12
21
4
3
4
41
3
1
4
1
63. - 63 -
21. B. satuan
6
343
luas
8
1
2
89 dyyyL
8
1
2
3
8
2
9
3
yy
y
6
343
56
2
567
3
511
22. B. satuan3
5
48
volume
3
3
42
69 dxxxV
3
3
53
5
1
29
xxx
5
348
3
5
18
312318
23. Lanjutannya manaaa!!!
dx
xx
x
3
3
1
24. Lanjutannya manaaa!!!
dx
xx
x
3
3
1
25. Lanjutannya manaaa!!!
dx
x
x
2
tan
1
tan
xx 22
cos2tan dx
B. Evaluasi Kemampuan Analisis
1.
2.
1
0
2
0cdxcbxax
1
0
23
0cexbecdxaebdadx
0
234
1
0
23
cexx
becd
x
aebdad
0
234
ce
becdaebdad
0
12
1266443
cebecdaebdad
01266443 cebecdaebdad
64. - 64 -
3.
4. a. xx cossin dx
lanjutannya mana booo!!!
b.
xx cos
1
sin
1
dx
5.
2
1
4
2
2
1
4
1
4
1
dx
x
dxxL
4
2
2
1
2 1
4
1
8
1
x
xx
satuan
8
3
2
1
4
1
4
1
8
3
luas
