1) Light can be reflected, absorbed, or refracted when interacting with mirrors and lenses. The law of reflection states that the angle of incidence equals the angle of reflection.
2) For a flat plane mirror, the image location is the same distance behind the mirror as the object is in front. The image is virtual, upright, and the same size as the object.
3) Concave mirrors can focus light to a real, inverted, and enlarged or reduced image location that can be calculated using the mirror equation. Ray diagrams and calculations of magnification can be used to determine image characteristics.
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2024.06.01 Introducing a competency framework for languag learning materials ...Sandy Millin
http://sandymillin.wordpress.com/iateflwebinar2024
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Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
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2. Facts about Light
It is a form of Electromagnetic Energy
It is a part of the Electromagnetic Spectrum and the only part we
can really see
3. Facts about Light
The speed of light, c, is constant in a vacuum.
Light can be:
•REFLECTED
•ABSORBED
•REFRACTED
Light is an electromagnetic wave in that it has wave like properties
which can be influenced by electric and magnetic fields.
4. The Law of “REFLECTION”
The Law of Reflection states that- " the angle
of incidence (incoming ray) equals the
angle of reflection (outgoing ray)"
The law works for FLAT,
PLANE surfaces only.
The angles are measured
from a perpendicular line
to the surface called a
NORMAL.
NORMAL
5. Plane Mirror
Suppose we had a flat , plane mirror mounted vertically. A candle is
placed 10 cm in front of the mirror. WHERE IS THE IMAGE OF
THE CANDLE LOCATED?
mirror
Object Distance, Do = 10 cm
Same side as the object?
On the surface of the mirror?
Behind the mirror?
6. Plane Mirror
Suppose we had a flat , plane mirror mounted vertically. A candle is
placed 10 cm in front of the mirror. WHERE IS THE IMAGE OF
THE CANDLE LOCATED?
mirror
Object Distance, Do = 10 cm Image Distance, Di = 10 cm
Do=Di, and the heights are equal as well
Virtual Image
7. Virtual Images
Virtual Images are basically images which cannot be
visually projected on a screen.
If this box gave off
light, we could project
an image of this box
on to a screen
provided the screen
was on the SAME
SIDE as the box.
You would not be able to project the image of the
vase or your face in a mirror on a screen, therefore
it is a virtual image.
CONCLUSION: VIRTUAL IMAGES are ALWAYS on the OPPOSITE side of
the mirror relative to the object.
8. Real Image
Real Images are ones you can project on to a screen.
For MIRRORS they always appear on the SAME SIDE of the mirror as the object.
object
image
The characteristics of the
image, however, may be
different from the original object.
These characteristics are:
•SIZE (reduced,enlarged,same
size)
•POSITION (same side,
opposite side)
•ORIENTATION (right side up,
inverted)
What if the mirror isn’t flat?
9. Spherical Mirrors – Concave & Convex
Also called CONVERGING mirror
Also called DIVERGING mirror
10. Converging (Concave) Mirror
A converging mirror is one that is spherical in nature
by which it can FOCUS parallel light rays to a point
directly in front of its surface. Every spherical mirror
can do this and this special point is at a “fixed”
position for every mirror. We call this point the
FOCAL POINT. To find this point you MUST use
light from “infinity”
Light from an “infinite”
distance, most likely the
sun.
11. Converging (Concave) Mirror
Since the mirror is
spherical it technically
has a CENTER OF
CURVATURE, C. The
focal point happens to
be HALF this distance.
We also draw a line through the
center of the mirror and call it the
PRINCIPAL AXIS.
f
C
C
f
2
2
12. Ray Diagram
A ray diagram is a pictorial representation of how the
light travels to form an image and can tell you the
characteristics of the image.
Principal axis
f
C
object
Rule One: Draw a ray, starting from the top of the object, parallel to the
principal axis and then through “f” after reflection.
13. Ray Diagrams
Principal axis
f
C
object
Rule Two: Draw a ray, starting from the top of the object, through the focal
point, then parallel to the principal axis after reflection.
14. Ray Diagrams
Principal axis
f
C
object
Rule Three: Draw a ray, starting from the top of the object, through C, then
back upon itself.
What do you notice about the three lines? THEY INTERSECT
The intersection is the location of the image.
15. Ray Diagram – Image Characteristics
Principal axis
f
C
object
After getting the intersection, draw an arrow down from the principal axis to
the point of intersection. Then ask yourself these questions:
1) Is the image on the SAME or OPPOSITE side of the mirror as the object?
Same, therefore it is a REAL IMAGE.
2) Is the image ENLARGED or REDUCED?
3) Is the image INVERTED or RIGHT SIDE UP?
16. The Mirror/Lens Equation
Is there any OTHER way to predict image characteristics besides
the ray diagram? YES!
One way is to use the MIRROR/LENS equation to
CALCULATE the position of the image.
i
o d
d
f
1
1
1
17. Mirror/Lens Equation
Assume that a certain concave spherical mirror has a
focal length of 10.0 cm. Locate the image for an
object distance of 25 cm and describe the image’s
characteristics.
i
i
i
o
d
d
d
d
f
1
25
1
10
1
1
1
1
16.67 cm
What does this tell us? First we know the image is BETWEEN “C” & “f”. Since the
image distance is POSITIVE the image is a REAL IMAGE.
Real image = positive image distance
Virtual image = negative image distance
What about the size and orientation?
18. Magnification Equation
To calculate the orientation and size of the image we
use the MAGNIFICATION EQUATION.
x
M
M
h
h
d
d
M
o
i
o
i
67
.
0
25
67
.
16
Here is how this works:
•If we get a POSITIVE magnification, the image is
UPRIGHT.
•If we get a NEGATIVE magnification, the image is
INVERTED
•If the magnification value is GREATER than 1, the
image is ENLARGED.
•If the magnification value is LESS than 1, the image
is REDUCED.
•If the magnification value is EQUAL to 1, the image
is the SAME SIZE as the object.
Using our previous data we see that our image was INVERTED, and REDUCED.
19. Example
Assume that a certain concave spherical mirror has a focal
length of 10.0 cm. Locate the image for an object distance of
5 cm and describe the image’s characteristics.
5
1
5
1
10
1
1
1
1
i
i
i
i
o
d
M
d
d
d
d
f
-10 cm
2x
•VIRTUAL (opposite side)
•Enlarged
•Upright
Characteristics?
