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ACEEE International Journal on Communication, Vol 1, No. 1, Jan 2010



 AM-RF partially overlapped channels separation
        by Volterra integral equations.
                                                        Dan Ciulin.
                                               E-I-A/Lausanne, Switzerland
                                               Email: dan.ciulin@gmail.com

Abstract—Sources - Separation methods allows the                     function of the band-pass filter with its central frequency
possibility to transmit many signals through a given channel         shifted to zero.
without multiplexing them. These signals may be frequency
overlapped. As an extension, the paper presents a method to                     Channel 1                                            Channel 2
reconstruct the transmitted signals from amplitude-                                                           Δω1
modulation radio frequency (AM-RF) channels that are
partially overlapped in frequency. The cross talks due to the




                                                                                   Carrier ω1




                                                                                                                                                      Carrier ω2
overlapping procedure leads to a lost of information but
increase the number of channels in the RF band. The signals
reconstruction implies the use of Volterra-integral
equations. Data transmissions imply also the improvement
of the receiver equalizer. Simulations are presented. The
presented method lead then to a diminishing of the                                                                                   angular frequency
equivalent frequency bandwidth of the transmitting signals.                                                     a
Index Terms—Source Separation, R.F. Signals.
                                                                                                Channel 1            Channel 2
                                                                                                                Δω
                    I. INTRODUCTION.
   Many signals may be transmitted through a given



                                                                                                 Carrier ω1




                                                                                                                                       Carrier ω2
channel without multiplexing them by using the Source -
Separation methods [5], [6]. In this case, only the
receivers have to be modified. Such methods lead then to
a diminishing of the equivalent bandwidth of the
transmitting signals. An other method to diminish the                                                                 angular frequency
bandwidth of an audio signal based on a Volterra-                                                               b
                                                                     Figures 1: Two AM-RF channels: (a) non-overlapped and (b) partially
Hammerstein integral equation [7] has been presented in              overlapped in frequency.
[1], [3] and [4]. To diminish the necessary bandwidth of
AM-RF channels placed into a RF transmission band, one                   Similarly, we can shift to zero the carrier angular
cans partially overlap these channels in frequency. This             frequency ω 2 and denote by s 2 (t ) the transmitted signal
method leads to cross talk errors but increases the number           on channel 2 with its carrier shifted to zero. For similar
of transmitted channels into the band. As an extension of            RF channels, the time responses h1 (t ) and h2 (t ) of the
[5], [6] and [2], a method to separates these frequency-
                                                                     band-pass filters corresponding to the first and second
overlapped signals will be presented.
                                                                     channel will differ only by their central frequency. One
      Let us first consider the simple case of only 2
                                                                     denote by h(t ) the time response function of the band-
transmitting AM-RF channels like in figure 1 a.
Diminishing the channel bandwidth may be realized by                 pass filter with its central frequency shifted to zero. The
partially overlapping these transmitting channels as in              received signals r1 (t ) and r2 (t ) (considered also with
figure 1 b. One can observe that the shift Δω1 between               their carrier shifted to zero) will be distorted by cross talk
the angular frequency carriers ω1 and ω2 is bigger than              due to the overlapping procedure for the first channel:
 Δω due to the overlapping procedure and thus, the total                     r1 (t ) = [ s1 (t ) + Re{ s 2 (t ).e [ j .( ω   2   − ω 1 ). t ]
                                                                                                                                                }] * h (t ).       (1)
bandwidth of the AM-RF channels is smaller.
     Let us make a frequency shift so that the angular                  We remark that the second RF channel is shifted by
frequency ω1 carrier becomes zero. We denote by s1 (t )              Δω 1before having been filtered by the first channel filter
the transmitted the transmitted signal on channel l with its         h(t ) . One gets also for the second channel:
carrier shifted to zero. Similarly, we can shift to zero the                r2 (t ) = [ s 2 (t ) + Re{ s1 (t ).e [ j .( ω        2   − ω 1 ). t ]
                                                                                                                                                    }] * h (t ).   (2)
carrier angular frequency ω 2 and denote by s 2 (t ) the
transmitted signal on channel 2 with its carrier shifted to             Of course:
zero. For similar RF channels, the time responses h1 (t )                                       ⎧ s1 (t ) = s1 (t ) * h (t ).
                                                                                                ⎨ s (t ) = s (t ) * h (t ).                                        (3)
and h2 (t ) of the band-pass filters corresponding to the                                       ⎩ 2          2

first and second channel will differ only by their central
                                                                     Taking into account (1), (2) and (3) we get finally:
frequency. One denote by h(t ) the time response

                                                                28
© 2010 ACEEE
DOI: 01.ijcom.01.01.07
ACEEE International Journal on Communication, Vol 1, No. 1, Jan 2010

          ⎧ r1 (t ) = s1 (t ) + s 2 (t ). cos[( Δω .t ] * h (t ).                 (4)        product’. Using an oscillator which frequency is Δω , the
          ⎨ r (t ) = s (t ) + s (t ). cos[ Δω .t ] * h(t ).
          ⎩ 2           2          1                                                         multipliers M 1 and M 2 , two channel filters ( h(t ) ) and
   where ‘*’ stand for convolution.                                                          two devices to subtract, we get the signals f 1 (t ) and
                                                                                              f 2 (t ) .
     II. SIGNALS RECONSTRUCTION BASED ON
         VOLTERRA INTEGRAL EQUATIONS.
                                                                                                                             M1
  Equations (4) represent a system of 2 equations where                                         r1 (t)                                h(t)                          Γ1(t,τ)          ~
                                                                                                                                                                                     s1 (t)
                                                                                                                                                           f1 (t)
only the transmitted signals s1 (t ) and s 2 (t ) are unknown.
                                                                                                Cos(Δωt)
Solving this system results in:                                                                                              M2
                                                                                                 r2 (t)                              h(t)                           Γ2(t,τ)          ~
                                                                                                                                                                                     s2 (t)
                s 2 (t ) = r2 (t ) − s1 (t ). cos[ Δω .t ] * h (t ).                                                                                      f2 (t)

                                                                                                                                                          Separation System
             r1 ( t ) = s 1 (t ) + { r2 (t ) − s 1 (t ). cos[ Δ ω .t ] *          (5)
                                                                                             Figures 2: Reconstruction time-varying filter.
             h (t )}. cos[ Δ ω .t ] * h (t ).
                                                                                                 A pair of generalized filters which kernel is Γ(t ,τ )
   This is an integral equation that can also be written as:                                 and two adders leads to the reconstructed signals. The
                                                                                             reconstruction system implies thus only filters and
                    r1 ( t ) − r 2 ( t ). cos[ Δ ω .t ] * h ( t ) =
                                                                                             mixers. This corresponds to a linear time-varying system.
                                                                                             As for ordinary AM signals, shifting their carrier to zero
    s1 (t ) − {[ s1 (t ). cos[Δω .t ] * h(t )]}. cos[Δω .t ] * h(t ).            (5’)        correspond to a product demodulation, the resulting
    With:                                                                                    signals ~1 (t ) and ~2 (t ) are in this case the reconstructed
                                                                                                     s           s
                                                                                             demodulated signals.
           f1 (t ) = r1 (t ) − r 2 (t ). cos[ Δ ω .t ] * h (t ).                  (6)

one observes that this function can be easily calculated as                                               III. EXTENSION TO 3 FREQUENCIES
r1 (t ) , r2 (t ) are the received signals and the filter h (t ) is                                           OVERLAPPED RF CHANNELS.
known.                                                                                          The model presented before works only for 2 RF
      The term {[ s1 (t ).Cos [Δω .t ] * h2 (t )]}. cos[ Δω .t ] * h2 (t )} can              channels overlapped in frequency. The case of 3 RF
be written as:                                                                               channels partially overlapped in frequency is shown in
                                                                                             figure 3. In the following we suppose that the angular
       ⎧         t t
                       {[s1 (u ).Cos [Δω .u ]. h 2 (τ − u )]}.                               frequency gap between all the adjacent channels is the
       ⎪         ∫∞ −∫∞cos[Δω .τ ].h (t − τ )}.du .d τ =                                     same and equal to Δω .
       ⎪        −                     2

       ⎪             t

       ⎨             ∫ s1 (u ). cos[Δω .u ].H (t , u ).du .                       (7)
                                                                                                             Channel 1 Channel 2 Channel 3
                                                                                                                      Δω        Δω
       ⎪            −∞

       ⎪
                                    t


       ⎪ H (t , u ) = h(t − u ). ∫ h(τ − u ). cos[Δω .τ ]}.d τ .
       ⎩                           −∞




                                                                                                                                                                        Carrier ω3
                                                                                                                Carrier ω1




                                                                                                                                             Carrier ω2


   Using (6) and (7), the equation (5') becomes:
          ⎧                     t

          ⎪s1 (t ) = f1 (t ) + ∫ s1 (u ). cos[Δω .u ].H (t , u ).du =
          ⎪                                                                       (8)
          ⎨                    −∞
                                         t                                                                                                                    angular frequency
          ⎪         s1 (t ) = f1 (t ) + ∫ s1 (u ).K (t , u ).du .
          ⎪
          ⎩                             −∞
                                                                                             Figures 3: Three partially-frequency overlapped channels.
which is a linear Volterra integral equation of second
                                                                                                 The received signals r1 (t ) , r2 (t ) and r3 (t ) for each
kind and has the solution:
                                                                                             channel, where each signal has its carrier shifted to zero,
             ⎧ ~                      t
                                                                                             will be given by:
             ⎪ s1 (t ) = f1 (t ) + ∫ f (u ).Γ1 (t , u ).du .
             ⎪                       −∞
                                                                                  (9)
             ⎪                          ∞

             ⎨        Γ1 (t , u ) = ∑ K n + 1 (t , u ).
             ⎪∞                       n =1                                                                 ⎧ r1 (t ) = s1 (t ) + s 2 (t ). cos[ Δω .t ] * h(t ).
                                                                                                           ⎪ r2 (t ) = s 2 (t ) + { s1 (t ). cos[ Δω .t ] +
                                   t
             ⎪ K (t , u ) = K ( z , u ). K (t , z ).d .;
             ⎪∑ n + 1              ∫∞ n                                                                    ⎪                                                                         (10)
             ⎩ n =1                                                                                        ⎨
                                                                                                           ⎪ s 3 (t ). cos[ Δω .t ]} * h(t ).
                                  −


                                                                                                           ⎪ r3 (t ) = s 3 (t ) + s 2 (t ). cos[ Δω .t ] * h(t ).
                                                                                                           ⎩
    Taking into account (9) it results that the kernel Γ(t, u)
                                                                                                Solving the system (10) with respect to s 3 (t ) will
does not depend on the received signals. So, it can be a
                                                                                             leads to:
priori computed. The separation will imply only a single
generalized convolution (a single special filter) by                                                      r3 (t ) = s 3 (t ) + ( r2 (t ) − {[ 2.s 3 (t ) + r1 (t ) −
                                                                                                                                                                                     (11)
channel. One observes that due to the symmetry of the                                                     r3 (t )]. cos[ Δω .t ]} * h (t )}). cos[ Δω .t ] * h (t ).
equations (4), an equation similar to (5’) may be obtained
for ~2 (t ) .
    s                                                                                        which is a Volterra integral equation in s 3 ( t ) as all the
    This process is schematized in figure 2. The received                                    other functions are known. The solution of this equation
signals r1 (t ) and r2 (t ) are in the base-band. For ordinary
AM, they correspond to the signals ‘demodulated by
                                                                                        29
© 2010 ACEEE
DOI: 01.ijcom.01.01.07
ACEEE International Journal on Communication, Vol 1, No. 1, Jan 2010

is the reconstructed signal ~ 3 (t ) . The signals ~1 (t ) and
                              s                    s                                         X(k)
 ~ (t ) can also be found out in a similar manner.                                                      T/2           T/2            T/2          T/2             T/2
 s2
    It can be observed that this method may also be
                                                                                              c0         c1           c2                          c N-1            cN
extended to ‘N’ partially overlapped AM-RF channels.
                                                                                                                                    Σ
 IV. EQUALIZER FOR PARTIALLY OVERLAPPED
   DATA QAM-RF (QUADRATURE AMPLITUDE                                                                                                                      a n-i
                                                                                                                           y(k)
         MODULATION) CHANNELS.
     In a data transmission, the equalizer chooses the                                                                                                    en
sampling instants that minimize the intersymbol                                               Figures 5: Transversal equalizer.
interference (ISI) of the received signals. For partially
frequency-overlapped channels, one has to minimize also                                        The coefficients of the transversal equalizer should be
the interference from the spectrally overlapping signals.                                                                             ~
                                                                                           chosen such that the mean squared error E is minimized.
For 2 partially frequency-overlapped channels, as in the                                   For frequency-overlapped channels, this mean squared
figure 1b, one side band of each channel has partially                                     error is a function of two variables because it depends on
spectral interference coming from the other channel as                                     2 statistical independent input signals. The extreme value
shown in the figure 4. This new spectral interference                                      of the mean squared error may be then computed using
implies an improved equalizer. Thus, we chose to sample                                    the Monge conditions. As the system implies 2
all the signals at twice the symbol frequency and use only                                 frequency-overlapped receivers, we have to realize an
finite impulse response (FIR) filters.                                                     extreme value for both receivers at the same time. The
                                                                                           extreme minimum (minimum minimorum) of a function
                 Channel1                            Channel2                               f (u , v ) of 2 variables is given by the following
                                                                                           conditions (Monge):
                                                  Carrier ω2
                            Carrier ω1




                                                                                                        ⎧         ∂f ( u , v )       ∂f (u , v )
                                                                                                        ⎪                      = 0;.             = 0.
                                                                                                        ⎪             ∂u                 ∂v
                                                                                                        ⎪     ∂ f (u , v )
                                                                                                                2
                                                                                                                                       ∂ f (u , v )
                                                                                                                                         2                              (12)
                                                                                                        ⎨                    > 0;.or .               > 0.
                                             Δω                                                         ⎪         ∂u 2
                                                                                                                          2
                                                                                                                                           ∂v 2
                                                                                                        ⎪⎛ ∂ f (u , v ) ⎞
                                                                                                            2
                                                                                                                               ∂ f (u , v ) ∂ f ( u , v )
                                                                                                                                2              2

                                                                                                        ⎪⎜
                                                                                                         ⎜              ⎟ −
                                                                                                                        ⎟                  .              < 0.
 Channel1                                                         Channel2                              ⎩⎝ ∂u .∂v ⎠               ∂u 2           ∂v 2
                                                               Carrier ω2
            Carrier ω1




                                                                                               At the output of the first channel equalizer we will get
                                                                                                                     ~
                                                                                           the mean squared error E1 and at the output of the second
                                                                                                                                                    ~
                                                                                           channel equalizer we will get the mean squared error E 2 .
                                                                                  ω        Each receiver will receive the same signals, uses the same
                                         ω
                                                                                           filters but these are centered on their own carrier. The
                         Zone with frequenc y interferenc e                                function f (u , v ) of 2 variables for which a minimum
                                                                                                                                                ~ ~
Figures 4: Frequency interference zones for 2 partially-frequency
                                                                                           must be found may be constituted as a function g ( E1 , E 2 )
overlapped channels.                                                                       of the mean squared errors of both receivers. The
                                                                                           simplest linear function that may be chosen is:
    The bloc diagram of the transversal filter with (T/2)
                                                                                                                     ~ ~         ~ ~
taps spacing and (N+1) complex coefficients                                                                      g ( E1 , E2 ) = E1 + E2 .                              (13)
c 0 , c1 , c 2 ,..., c N , used as improved equalizer, is shown in
                                                                                           as the minimum of the sum correspond to the minimum
the figure 5. For practical reasons, the number M=N+1                                      of its components. Of course, other types of functions
must be smaller than 30. While the output signal y (k ) of                                 may be chosen too. It can also be remarked that the
the transversal filter delivers output data at twice the                                                    ~ ~
                                                                                           function g ( E1 , E2 ) depends on the equalizers time-
symbol rate, only every second output sample is used to                                    varying coefficients:
derive a decision ( a n − i ) on the transmitted data signals.
                                                                                                    ~ ~
Since the equalizer introduces some delay, one cannot                                           g ( E1 , E2 ) = w ({c 0 , c1 ,...c N }1 , {c 0 , c1 ,...c N }2 ). (14)
obtain the symbol a n at timing instant n but a delayed
                                                                                               We therefore compute the partial first and second
symbol a n − i , where i.T is the delay introduced by the                                  derivatives of the function w ({c 0 , c1 ,...c N }1 , {c 0 , c1 ,...c N }2 )
transversal filter. The difference between the data output                                 for the real and imaginary part of its coefficients and use
 a n − i and the output signal y (k ) at this instant represents                           the Monge conditions for extreme. From this we get a
the error    en of the equalizer.                                                          system of linear equations that can be solved to find out
                                                                                           the optimum coefficients of both equalizers.

                                                                                                                     V. SIMULATION.
                                                                                             We will consider two channels, partially overlapped in
                                                                                           frequency, as in figure 1b. The simulated transmitted
                                                                                           signals s1 (t ) and s2 (t ) for each channel are shown in
                                                                                      30
© 2010 ACEEE
DOI: 01.ijcom.01.01.07
ACEEE International Journal on Communication, Vol 1, No. 1, Jan 2010

figure 6. The resulted cross talk errors due to channels                                                                                                                 Separation methods presented in [2], [5] and [6]. The
partially overlapped in frequency are given by                                                                                                                           reconstruction implies a special linear time-varying filter
 r1 (t ) − s1 (t ) and r2 (t ) − s 2 (t ) for the first and second                                                                                                       that uses also mixers. In a simulation, it is observed that
channel respectively. These cross talk errors are shown in                                                                                                               the reconstruction errors are much smaller than the cross
figure 7. Using the equation (9) and a special tool                                                                                                                      talk errors for each considered channel. Extension to 3
described in (Ciulin 2002) we compute ~1 (t ) and ~2 (t )
                                                    s         s                                                                                                          AM-RF channels partially overlapped in frequency is also
                                                                                                                                                                         presented and may be generalized to ‘N’ AM-RF
by considering a sum of 20 terms for Γ(t ,τ ) . The
                                                                                                                                                                         channels partially overlapped in frequency. With some
reconstruction errors are given by s1 (t ) − ~1 (t ) and  s                                                                                                              modifications, this method may be extended to other
            ~ (t ) for the first and second channel respectively.
 s 2 (t ) − s 2                                                                                                                                                          types of amplitude modulation. For a data QAM
                                                                                                                                                                         transmission, due to the spectral overlapping of the
                       Tra n s m it t e d s ig n a l in t h e firs t c h a n n e l               Tra n s m it t e d s ig n a l in t h e s e c o n d c h a n n e l        channels, the equalizers of the receivers have to be
                       10                                                                                    10                                                          improved too. It can be observed that the coefficients of
                                                                                                                                                                         the equalizers have to be optimized simultaneously for all
                         5                                                                                    5
                                                                                                                                                                         spectral overlapped channels due to Monge conditions of
    amplitude




                                                                                     amplitude




                         0                                                                                    0                                                          extrema. Then, for the senders, only their carrier
                                                                                                                                                                         frequencies has to be modified but the receivers must
                        -5                                                                                   -5
                                                                                                                                                                         includes also the reconstruction time-varying filter and a
                       -1 0                                                                            -1 0
                                                                                                                                                                         new equalizer. This equivalent method of bandwidth
                                  100       200     300         400       500                                      100    200     300       400       500
                                                                                                                                                                         compression is simpler than the method presented in [3],
                                             s a m p le s                                                                  s a m p le s
                                                                                                                                                                         [4] but the practical obtained compression factor is
Figures 6: Transmitted signals in partially-frequency overlapped                                                                                                         smaller.
channels.                                                                                                                                                                Applications may be found in increasing the number of
                                                                                                                                                                         transmitted channels for a given AM-RF band as, for
                         C ros s talk errors in the firs t c h ann el                                 C ros s t alk erro rs in t he s ec o nd c han nel
                         5                                                                               5                                                               example, for single side band AM phones channels and
                                                                                                                                                                         for data QAM transmission channels. The present method
                                                                                                                                                                         may save frequency spectrum and then, permit the
                                                                                                                                                                         transmissions of more AM-RF channels in the same
           amplitude




                                                                                             amplitude




                         0                                                                                    0                                                          frequency bandwidth and/or use it for other applications
                                                                                                                                                                         too.

                                                                                                                                                                                                 REFERENCES
                        -5                                                                                   -5
                                  100       200 30 0            400       500                                      10 0   200 30 0           40 0     500
                                             s am ple s                                                                    s a m p le s                                  [1] D. Ciulin, “Method of reducing the useful bandwidth of
                                                                                                                                                                             bandwidth-limited signals by coding and decoding the
Figures 7: Cross talk errors in theses partially-frequency overlapped                                                                                                        signals, and system to carry out the method” U.S.A. Patent
channels.
                                                                                                                                                                             5020104, May 28, 1991.
                                                                                                                                                                         [2] D. Ciulin, “Some tools for speech processing”, 6th WORLD
  These reconstruction errors are shown in figure 8. It                                                                                                                      MULTICONFERENCE ON SYSTEMICS, CYBERNETICS
can be observed that the cross talk errors are well                                                                                                                          AND INFORMATICS (SCI2002), Orlando, Florida, U.S.A
diminished by this method even for an approximation of                                                                                                                       2002.
only 20 terms for the integral kernel.                                                                                                                                   [3] D. Ciulin, “Bandwidth-compression theorem, a new tool in
                                                                                                                                                                             signal processing”, 10th International, Signal Processing
                R ec ons truc tion errors in the firs t c hannel R ec ons truc tion errors in the s ec ond c hannel
                   5                                                   5
                                                                                                                                                                             Conference on Concurrent Engineering: Research and
                                                                                                                                                                             Application, Madeira, Portugal, 2003.
                                                                                                                                                                         [4] D. Ciulin, “New improved blocks for signal processing”,
                                                                                                                                                                             DECOM-TT 2004, AUTOMATIC SYSTEMS FOR
                                                                                                                                                                             BUILDING           THE       INFRASTRUCTURE             IN
           amplitude




                                                                                                 amplitude




                         0                                                                                    0
                                                                                                                                                                             DEVELOPING COUNTRIES, Bansko, Bulgaria, 3-5
                                                                                                                                                                             October 2004.
                                                                                                                                                                         [5] P. Comon, “Blind separation of sources, Part ll: Problem
                                                                                                                                                                             stamens”, Signal processing, volume 24, Nr. 1, July 1991.
                        -5
                                   100       200 300            400       500
                                                                                                              -5
                                                                                                                   100     200 300            400       500
                                                                                                                                                                         [6] Ch. Jutten, and J. Herault, “Blind separation of sources,
                                              s am ples                                                                     s am ples                                        Part l: An adaptive algorithm based on neuromimetic
                                                                                                                                                                             architecture”, Signal processing, volume 24, Nr. 1, July
Figures 8: Reconstruction errors in these partially-frequency overlapped
                                                                                                                                                                             1991.
channels.
                                                                                                                                                                         [7] V. Volterra, Theory of Functionals and of Integral and
                                                                                                                                                                             Integro-differential Equation, Dover Publications, New
                                                          VI. CONCLUSION.                                                                                                    York, 1959.
    A method to diminish the necessary frequency                                                                                                                         D. Ciulin, “Quantizing Theorem”, 4th IEEE Intelligent Systems
                                                                                                                                                                             IS’08: Methodology, Models, Applications in Emerging
bandwidth of an AM-RF band is to partially overlap in
                                                                                                                                                                             Technologies, September 6-8, Varna, Bulgaria, 2008.
frequency their inside transmitted channels. This will
increase the number of inside transmitted channels but
leads to cross talk errors. A method to reconstruct the
cross talk errors of AM-RF signals partially overlapped
in frequency, based on Volterra integral equations, has
been presented. It represents an extension of the Source-
                                                                                                                                                                    31
© 2010 ACEEE
DOI: 01.ijcom.01.01.07

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AM-RF partially overlapped channels separation by Volterra integral equations

  • 1. ACEEE International Journal on Communication, Vol 1, No. 1, Jan 2010 AM-RF partially overlapped channels separation by Volterra integral equations. Dan Ciulin. E-I-A/Lausanne, Switzerland Email: dan.ciulin@gmail.com Abstract—Sources - Separation methods allows the function of the band-pass filter with its central frequency possibility to transmit many signals through a given channel shifted to zero. without multiplexing them. These signals may be frequency overlapped. As an extension, the paper presents a method to Channel 1 Channel 2 reconstruct the transmitted signals from amplitude- Δω1 modulation radio frequency (AM-RF) channels that are partially overlapped in frequency. The cross talks due to the Carrier ω1 Carrier ω2 overlapping procedure leads to a lost of information but increase the number of channels in the RF band. The signals reconstruction implies the use of Volterra-integral equations. Data transmissions imply also the improvement of the receiver equalizer. Simulations are presented. The presented method lead then to a diminishing of the angular frequency equivalent frequency bandwidth of the transmitting signals. a Index Terms—Source Separation, R.F. Signals. Channel 1 Channel 2 Δω I. INTRODUCTION. Many signals may be transmitted through a given Carrier ω1 Carrier ω2 channel without multiplexing them by using the Source - Separation methods [5], [6]. In this case, only the receivers have to be modified. Such methods lead then to a diminishing of the equivalent bandwidth of the transmitting signals. An other method to diminish the angular frequency bandwidth of an audio signal based on a Volterra- b Figures 1: Two AM-RF channels: (a) non-overlapped and (b) partially Hammerstein integral equation [7] has been presented in overlapped in frequency. [1], [3] and [4]. To diminish the necessary bandwidth of AM-RF channels placed into a RF transmission band, one Similarly, we can shift to zero the carrier angular cans partially overlap these channels in frequency. This frequency ω 2 and denote by s 2 (t ) the transmitted signal method leads to cross talk errors but increases the number on channel 2 with its carrier shifted to zero. For similar of transmitted channels into the band. As an extension of RF channels, the time responses h1 (t ) and h2 (t ) of the [5], [6] and [2], a method to separates these frequency- band-pass filters corresponding to the first and second overlapped signals will be presented. channel will differ only by their central frequency. One Let us first consider the simple case of only 2 denote by h(t ) the time response function of the band- transmitting AM-RF channels like in figure 1 a. Diminishing the channel bandwidth may be realized by pass filter with its central frequency shifted to zero. The partially overlapping these transmitting channels as in received signals r1 (t ) and r2 (t ) (considered also with figure 1 b. One can observe that the shift Δω1 between their carrier shifted to zero) will be distorted by cross talk the angular frequency carriers ω1 and ω2 is bigger than due to the overlapping procedure for the first channel: Δω due to the overlapping procedure and thus, the total r1 (t ) = [ s1 (t ) + Re{ s 2 (t ).e [ j .( ω 2 − ω 1 ). t ] }] * h (t ). (1) bandwidth of the AM-RF channels is smaller. Let us make a frequency shift so that the angular We remark that the second RF channel is shifted by frequency ω1 carrier becomes zero. We denote by s1 (t ) Δω 1before having been filtered by the first channel filter the transmitted the transmitted signal on channel l with its h(t ) . One gets also for the second channel: carrier shifted to zero. Similarly, we can shift to zero the r2 (t ) = [ s 2 (t ) + Re{ s1 (t ).e [ j .( ω 2 − ω 1 ). t ] }] * h (t ). (2) carrier angular frequency ω 2 and denote by s 2 (t ) the transmitted signal on channel 2 with its carrier shifted to Of course: zero. For similar RF channels, the time responses h1 (t ) ⎧ s1 (t ) = s1 (t ) * h (t ). ⎨ s (t ) = s (t ) * h (t ). (3) and h2 (t ) of the band-pass filters corresponding to the ⎩ 2 2 first and second channel will differ only by their central Taking into account (1), (2) and (3) we get finally: frequency. One denote by h(t ) the time response 28 © 2010 ACEEE DOI: 01.ijcom.01.01.07
  • 2. ACEEE International Journal on Communication, Vol 1, No. 1, Jan 2010 ⎧ r1 (t ) = s1 (t ) + s 2 (t ). cos[( Δω .t ] * h (t ). (4) product’. Using an oscillator which frequency is Δω , the ⎨ r (t ) = s (t ) + s (t ). cos[ Δω .t ] * h(t ). ⎩ 2 2 1 multipliers M 1 and M 2 , two channel filters ( h(t ) ) and where ‘*’ stand for convolution. two devices to subtract, we get the signals f 1 (t ) and f 2 (t ) . II. SIGNALS RECONSTRUCTION BASED ON VOLTERRA INTEGRAL EQUATIONS. M1 Equations (4) represent a system of 2 equations where r1 (t) h(t) Γ1(t,τ) ~ s1 (t) f1 (t) only the transmitted signals s1 (t ) and s 2 (t ) are unknown. Cos(Δωt) Solving this system results in: M2 r2 (t) h(t) Γ2(t,τ) ~ s2 (t) s 2 (t ) = r2 (t ) − s1 (t ). cos[ Δω .t ] * h (t ). f2 (t) Separation System r1 ( t ) = s 1 (t ) + { r2 (t ) − s 1 (t ). cos[ Δ ω .t ] * (5) Figures 2: Reconstruction time-varying filter. h (t )}. cos[ Δ ω .t ] * h (t ). A pair of generalized filters which kernel is Γ(t ,τ ) This is an integral equation that can also be written as: and two adders leads to the reconstructed signals. The reconstruction system implies thus only filters and r1 ( t ) − r 2 ( t ). cos[ Δ ω .t ] * h ( t ) = mixers. This corresponds to a linear time-varying system. As for ordinary AM signals, shifting their carrier to zero s1 (t ) − {[ s1 (t ). cos[Δω .t ] * h(t )]}. cos[Δω .t ] * h(t ). (5’) correspond to a product demodulation, the resulting With: signals ~1 (t ) and ~2 (t ) are in this case the reconstructed s s demodulated signals. f1 (t ) = r1 (t ) − r 2 (t ). cos[ Δ ω .t ] * h (t ). (6) one observes that this function can be easily calculated as III. EXTENSION TO 3 FREQUENCIES r1 (t ) , r2 (t ) are the received signals and the filter h (t ) is OVERLAPPED RF CHANNELS. known. The model presented before works only for 2 RF The term {[ s1 (t ).Cos [Δω .t ] * h2 (t )]}. cos[ Δω .t ] * h2 (t )} can channels overlapped in frequency. The case of 3 RF be written as: channels partially overlapped in frequency is shown in figure 3. In the following we suppose that the angular ⎧ t t {[s1 (u ).Cos [Δω .u ]. h 2 (τ − u )]}. frequency gap between all the adjacent channels is the ⎪ ∫∞ −∫∞cos[Δω .τ ].h (t − τ )}.du .d τ = same and equal to Δω . ⎪ − 2 ⎪ t ⎨ ∫ s1 (u ). cos[Δω .u ].H (t , u ).du . (7) Channel 1 Channel 2 Channel 3 Δω Δω ⎪ −∞ ⎪ t ⎪ H (t , u ) = h(t − u ). ∫ h(τ − u ). cos[Δω .τ ]}.d τ . ⎩ −∞ Carrier ω3 Carrier ω1 Carrier ω2 Using (6) and (7), the equation (5') becomes: ⎧ t ⎪s1 (t ) = f1 (t ) + ∫ s1 (u ). cos[Δω .u ].H (t , u ).du = ⎪ (8) ⎨ −∞ t angular frequency ⎪ s1 (t ) = f1 (t ) + ∫ s1 (u ).K (t , u ).du . ⎪ ⎩ −∞ Figures 3: Three partially-frequency overlapped channels. which is a linear Volterra integral equation of second The received signals r1 (t ) , r2 (t ) and r3 (t ) for each kind and has the solution: channel, where each signal has its carrier shifted to zero, ⎧ ~ t will be given by: ⎪ s1 (t ) = f1 (t ) + ∫ f (u ).Γ1 (t , u ).du . ⎪ −∞ (9) ⎪ ∞ ⎨ Γ1 (t , u ) = ∑ K n + 1 (t , u ). ⎪∞ n =1 ⎧ r1 (t ) = s1 (t ) + s 2 (t ). cos[ Δω .t ] * h(t ). ⎪ r2 (t ) = s 2 (t ) + { s1 (t ). cos[ Δω .t ] + t ⎪ K (t , u ) = K ( z , u ). K (t , z ).d .; ⎪∑ n + 1 ∫∞ n ⎪ (10) ⎩ n =1 ⎨ ⎪ s 3 (t ). cos[ Δω .t ]} * h(t ). − ⎪ r3 (t ) = s 3 (t ) + s 2 (t ). cos[ Δω .t ] * h(t ). ⎩ Taking into account (9) it results that the kernel Γ(t, u) Solving the system (10) with respect to s 3 (t ) will does not depend on the received signals. So, it can be a leads to: priori computed. The separation will imply only a single generalized convolution (a single special filter) by r3 (t ) = s 3 (t ) + ( r2 (t ) − {[ 2.s 3 (t ) + r1 (t ) − (11) channel. One observes that due to the symmetry of the r3 (t )]. cos[ Δω .t ]} * h (t )}). cos[ Δω .t ] * h (t ). equations (4), an equation similar to (5’) may be obtained for ~2 (t ) . s which is a Volterra integral equation in s 3 ( t ) as all the This process is schematized in figure 2. The received other functions are known. The solution of this equation signals r1 (t ) and r2 (t ) are in the base-band. For ordinary AM, they correspond to the signals ‘demodulated by 29 © 2010 ACEEE DOI: 01.ijcom.01.01.07
  • 3. ACEEE International Journal on Communication, Vol 1, No. 1, Jan 2010 is the reconstructed signal ~ 3 (t ) . The signals ~1 (t ) and s s X(k) ~ (t ) can also be found out in a similar manner. T/2 T/2 T/2 T/2 T/2 s2 It can be observed that this method may also be c0 c1 c2 c N-1 cN extended to ‘N’ partially overlapped AM-RF channels. Σ IV. EQUALIZER FOR PARTIALLY OVERLAPPED DATA QAM-RF (QUADRATURE AMPLITUDE a n-i y(k) MODULATION) CHANNELS. In a data transmission, the equalizer chooses the en sampling instants that minimize the intersymbol Figures 5: Transversal equalizer. interference (ISI) of the received signals. For partially frequency-overlapped channels, one has to minimize also The coefficients of the transversal equalizer should be the interference from the spectrally overlapping signals. ~ chosen such that the mean squared error E is minimized. For 2 partially frequency-overlapped channels, as in the For frequency-overlapped channels, this mean squared figure 1b, one side band of each channel has partially error is a function of two variables because it depends on spectral interference coming from the other channel as 2 statistical independent input signals. The extreme value shown in the figure 4. This new spectral interference of the mean squared error may be then computed using implies an improved equalizer. Thus, we chose to sample the Monge conditions. As the system implies 2 all the signals at twice the symbol frequency and use only frequency-overlapped receivers, we have to realize an finite impulse response (FIR) filters. extreme value for both receivers at the same time. The extreme minimum (minimum minimorum) of a function Channel1 Channel2 f (u , v ) of 2 variables is given by the following conditions (Monge): Carrier ω2 Carrier ω1 ⎧ ∂f ( u , v ) ∂f (u , v ) ⎪ = 0;. = 0. ⎪ ∂u ∂v ⎪ ∂ f (u , v ) 2 ∂ f (u , v ) 2 (12) ⎨ > 0;.or . > 0. Δω ⎪ ∂u 2 2 ∂v 2 ⎪⎛ ∂ f (u , v ) ⎞ 2 ∂ f (u , v ) ∂ f ( u , v ) 2 2 ⎪⎜ ⎜ ⎟ − ⎟ . < 0. Channel1 Channel2 ⎩⎝ ∂u .∂v ⎠ ∂u 2 ∂v 2 Carrier ω2 Carrier ω1 At the output of the first channel equalizer we will get ~ the mean squared error E1 and at the output of the second ~ channel equalizer we will get the mean squared error E 2 . ω Each receiver will receive the same signals, uses the same ω filters but these are centered on their own carrier. The Zone with frequenc y interferenc e function f (u , v ) of 2 variables for which a minimum ~ ~ Figures 4: Frequency interference zones for 2 partially-frequency must be found may be constituted as a function g ( E1 , E 2 ) overlapped channels. of the mean squared errors of both receivers. The simplest linear function that may be chosen is: The bloc diagram of the transversal filter with (T/2) ~ ~ ~ ~ taps spacing and (N+1) complex coefficients g ( E1 , E2 ) = E1 + E2 . (13) c 0 , c1 , c 2 ,..., c N , used as improved equalizer, is shown in as the minimum of the sum correspond to the minimum the figure 5. For practical reasons, the number M=N+1 of its components. Of course, other types of functions must be smaller than 30. While the output signal y (k ) of may be chosen too. It can also be remarked that the the transversal filter delivers output data at twice the ~ ~ function g ( E1 , E2 ) depends on the equalizers time- symbol rate, only every second output sample is used to varying coefficients: derive a decision ( a n − i ) on the transmitted data signals. ~ ~ Since the equalizer introduces some delay, one cannot g ( E1 , E2 ) = w ({c 0 , c1 ,...c N }1 , {c 0 , c1 ,...c N }2 ). (14) obtain the symbol a n at timing instant n but a delayed We therefore compute the partial first and second symbol a n − i , where i.T is the delay introduced by the derivatives of the function w ({c 0 , c1 ,...c N }1 , {c 0 , c1 ,...c N }2 ) transversal filter. The difference between the data output for the real and imaginary part of its coefficients and use a n − i and the output signal y (k ) at this instant represents the Monge conditions for extreme. From this we get a the error en of the equalizer. system of linear equations that can be solved to find out the optimum coefficients of both equalizers. V. SIMULATION. We will consider two channels, partially overlapped in frequency, as in figure 1b. The simulated transmitted signals s1 (t ) and s2 (t ) for each channel are shown in 30 © 2010 ACEEE DOI: 01.ijcom.01.01.07
  • 4. ACEEE International Journal on Communication, Vol 1, No. 1, Jan 2010 figure 6. The resulted cross talk errors due to channels Separation methods presented in [2], [5] and [6]. The partially overlapped in frequency are given by reconstruction implies a special linear time-varying filter r1 (t ) − s1 (t ) and r2 (t ) − s 2 (t ) for the first and second that uses also mixers. In a simulation, it is observed that channel respectively. These cross talk errors are shown in the reconstruction errors are much smaller than the cross figure 7. Using the equation (9) and a special tool talk errors for each considered channel. Extension to 3 described in (Ciulin 2002) we compute ~1 (t ) and ~2 (t ) s s AM-RF channels partially overlapped in frequency is also presented and may be generalized to ‘N’ AM-RF by considering a sum of 20 terms for Γ(t ,τ ) . The channels partially overlapped in frequency. With some reconstruction errors are given by s1 (t ) − ~1 (t ) and s modifications, this method may be extended to other ~ (t ) for the first and second channel respectively. s 2 (t ) − s 2 types of amplitude modulation. For a data QAM transmission, due to the spectral overlapping of the Tra n s m it t e d s ig n a l in t h e firs t c h a n n e l Tra n s m it t e d s ig n a l in t h e s e c o n d c h a n n e l channels, the equalizers of the receivers have to be 10 10 improved too. It can be observed that the coefficients of the equalizers have to be optimized simultaneously for all 5 5 spectral overlapped channels due to Monge conditions of amplitude amplitude 0 0 extrema. Then, for the senders, only their carrier frequencies has to be modified but the receivers must -5 -5 includes also the reconstruction time-varying filter and a -1 0 -1 0 new equalizer. This equivalent method of bandwidth 100 200 300 400 500 100 200 300 400 500 compression is simpler than the method presented in [3], s a m p le s s a m p le s [4] but the practical obtained compression factor is Figures 6: Transmitted signals in partially-frequency overlapped smaller. channels. Applications may be found in increasing the number of transmitted channels for a given AM-RF band as, for C ros s talk errors in the firs t c h ann el C ros s t alk erro rs in t he s ec o nd c han nel 5 5 example, for single side band AM phones channels and for data QAM transmission channels. The present method may save frequency spectrum and then, permit the transmissions of more AM-RF channels in the same amplitude amplitude 0 0 frequency bandwidth and/or use it for other applications too. REFERENCES -5 -5 100 200 30 0 400 500 10 0 200 30 0 40 0 500 s am ple s s a m p le s [1] D. Ciulin, “Method of reducing the useful bandwidth of bandwidth-limited signals by coding and decoding the Figures 7: Cross talk errors in theses partially-frequency overlapped signals, and system to carry out the method” U.S.A. Patent channels. 5020104, May 28, 1991. [2] D. Ciulin, “Some tools for speech processing”, 6th WORLD These reconstruction errors are shown in figure 8. It MULTICONFERENCE ON SYSTEMICS, CYBERNETICS can be observed that the cross talk errors are well AND INFORMATICS (SCI2002), Orlando, Florida, U.S.A diminished by this method even for an approximation of 2002. only 20 terms for the integral kernel. [3] D. Ciulin, “Bandwidth-compression theorem, a new tool in signal processing”, 10th International, Signal Processing R ec ons truc tion errors in the firs t c hannel R ec ons truc tion errors in the s ec ond c hannel 5 5 Conference on Concurrent Engineering: Research and Application, Madeira, Portugal, 2003. [4] D. Ciulin, “New improved blocks for signal processing”, DECOM-TT 2004, AUTOMATIC SYSTEMS FOR BUILDING THE INFRASTRUCTURE IN amplitude amplitude 0 0 DEVELOPING COUNTRIES, Bansko, Bulgaria, 3-5 October 2004. [5] P. Comon, “Blind separation of sources, Part ll: Problem stamens”, Signal processing, volume 24, Nr. 1, July 1991. -5 100 200 300 400 500 -5 100 200 300 400 500 [6] Ch. Jutten, and J. Herault, “Blind separation of sources, s am ples s am ples Part l: An adaptive algorithm based on neuromimetic architecture”, Signal processing, volume 24, Nr. 1, July Figures 8: Reconstruction errors in these partially-frequency overlapped 1991. channels. [7] V. Volterra, Theory of Functionals and of Integral and Integro-differential Equation, Dover Publications, New VI. CONCLUSION. York, 1959. A method to diminish the necessary frequency D. Ciulin, “Quantizing Theorem”, 4th IEEE Intelligent Systems IS’08: Methodology, Models, Applications in Emerging bandwidth of an AM-RF band is to partially overlap in Technologies, September 6-8, Varna, Bulgaria, 2008. frequency their inside transmitted channels. This will increase the number of inside transmitted channels but leads to cross talk errors. A method to reconstruct the cross talk errors of AM-RF signals partially overlapped in frequency, based on Volterra integral equations, has been presented. It represents an extension of the Source- 31 © 2010 ACEEE DOI: 01.ijcom.01.01.07