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Diff EQ Quest
Exponential Growth
 In a certain country the number of jobs created is
 proportional to the number of people who already
 have jobs. If there are 15 million people who have jobs
 at time t = 0, and 15.1 million people with jobs 3
 months later, how many jobs will exist in two years?
Exponential Growth
 f(t) = number of people with jobs at time t months
 f’(t) = k f(t) for some constant t
 Given f(0) = 15, then f(t) = 15ekt
 Given f(3) = 15.1, then k = 0.002215
 At 24 months, f(24) = 15.8 million jobs
Population Problem
 A certain population of critters C(t) increases at a rate
  directly proportional to 2000 – C(t) when t > 0.
 If C(0) = 1800, find C(t) in terms of t and a constant k.
 If C(5) = 1750, find C(20)
Solution
 C(t) = 2000 – 200e-kt

 k = -.044629


 C(20) = 2000 – 200e(-.044629)(20)

 C(20) = 1918 critters

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Additional review problems

  • 2. Exponential Growth  In a certain country the number of jobs created is proportional to the number of people who already have jobs. If there are 15 million people who have jobs at time t = 0, and 15.1 million people with jobs 3 months later, how many jobs will exist in two years?
  • 3. Exponential Growth  f(t) = number of people with jobs at time t months  f’(t) = k f(t) for some constant t  Given f(0) = 15, then f(t) = 15ekt  Given f(3) = 15.1, then k = 0.002215  At 24 months, f(24) = 15.8 million jobs
  • 4. Population Problem  A certain population of critters C(t) increases at a rate directly proportional to 2000 – C(t) when t > 0.  If C(0) = 1800, find C(t) in terms of t and a constant k.  If C(5) = 1750, find C(20)
  • 5. Solution  C(t) = 2000 – 200e-kt  k = -.044629  C(20) = 2000 – 200e(-.044629)(20)  C(20) = 1918 critters