This document outlines the substitution method for solving systems of linear equations. It lists the steps as isolating a variable in one equation, substituting that equation into the other to eliminate the variable, then solving the resulting equation for the remaining variable and substituting back to find the original variable. It then provides 6 example systems of equations to solve using this substitution method.

1. Lesson 6­2.notebook January 17, 2013
Lesson 6.2:
*Another method for solving a system of linear equations is called
substitution.
**Steps for using SUBSTITUTION:
­­solve one equation for one variable (isolate 1 variable)
­­substitute the new equation into the other equation for the
isolated variable; then solve the equation
­­then substitute the value from step 2 into either equation and
solve for the other variable
­­write the solution as an ordered pair
[check the solution in both equations!]

2. Lesson 6­2.notebook January 17, 2013
Lesson 6.2 examples:
Use substitution to solve the system of equations.
A) y = 2x + 1
3x + y = ­9
B) x + 2y = 6
3x ­ 4y = 28

3. Lesson 6­2.notebook January 17, 2013
C) y = 2x ­ 4
­6x + 3y = ­12
D) 2x ­ y = 8
y = 2x ­ 3

4. Lesson 6­2.notebook January 17, 2013
E) y = 4x ­ 6
5x + 3y = ­1
F) 4x + 5y = 11
y ­ 3x = ­13