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T.Chhay



                                                m:Um:g;sþaTicénépÞrab
                                                First moment of area
     1> niymn½y (Definition)
       m:Um:g;sþaTicénépÞrab A eFobnwgGkS½ X CaGaMgetRkalépÞGnnþtUc dA éncMgayBITIRbCMuTMgn;énépÞ
GnnþtUcenaHeTAGkS½ X . ¬rUbTI1¦
      QX =      ∫ y.dA
               ( A)

     Edl       - m:Um:g;sþTicénépÞrab A eFobnwgGkS½ X
                QX

           y - cMgayBITIRbCMuTMgn;énépÞGnnþtUc dA eTAGkS½ X

           dA -épÞGnnþtUc

        dUcKña m:Um:g;sþaTicénépÞrab A eFobnwgGkS½ Y Ca
GaMgetRkalépÞGnnþtUc dA éncMgayBITIRbCMuTMgn;énépÞGnnþ
tUcenaHeTAGkS½ Y . ¬rUbTI1¦
      QY =      ∫ x.dA
               ( A)

     Edl        QY- m:Um:g;sþTicénépÞrab A eFobnwgGkS½ Y
               x - éncMgayBITIRbCMuTMgn;énépÞGnnþtUc dA eTAGkS½ Y

    2> épÞsmas (Composite area)
       épÞsmas CaépÞEdlpSMeLIgedayrUbFrNImaRtsamBaØCaeRcIn. ebIépÞsmas A mYypSMeLIg
edayépÞsamBaØ A / A />>>/ A EdlmanTIRbCMuTMgn;erogKña c / c />>>/ c ehIy y / y />>>/ y CacMgay
                             1          2   n                       1     2   n   1   2   n


erogKñaBITIRbCMuTMgn;TaMgenaHdl;GkS½ X . épÞrab A manTIRbCMuTMgn; c EdlenAcMgay y BIGkS½ X .
       m:Um:g;sþaTicénépÞsmas A eFobnwgGkS½ X KW³
                                  n
            QX = A. y = ∑ Ai . yi
                                 i =1

           dUcKñaenHEdr
                                  n
            QY = A.x = ∑ Ai .xi
                                 i =1

           Edl          A - épÞrab b¤épÞsmas
                        A - épÞsamBaØTI i
                         i


                        y - cMgayBITIRbCMuTMgn;énépÞsmasmkGkS½ X

                        y - cMgayBITIRbCMuTMgn;énépÞsamBaØTI i mkGkS½ X
                         i



m:Um:g;sþaTicénépÞrab                                                                               42
T.Chhay


                     - cMgayBITIRbCMuTMgn;énépÞsmasmkGkS½ Y
                             x

                   x - cMgayBITIRbCMuTMgn;énépÞsamBaØTI i mkGkS½ Y
                               i


cMNaM³ m:Um:g;sþaTicénépÞrab A eFobnwgGkS½Edlkat;tamTIRbCMuTMgn;rbs;vamantMélesμIsUnü.
]TahrN_³ cUrrkm:Um:gsþaTicénépÞrabxageRkameFobGkS½kUGredaen.
dMeNaHRsay³
m:Um:g;sþaTicénépÞrabeFobGkS½ X
            QX = A. y
           Edl A = 6 × 4 = 24cm    2


                  h 4
            y=     = = 2cm
                  2 2
            ⇒ QX = 24 × 2 = 48cm3
m:Um:g;sþaTicénépÞrabeFobGkS½ Y
            QY = A.x
           Edl A = 6 × 4 = 24cm    2


                  b 6
            x=     = = 3cm
                  2 2
            ⇒ QY = 24 × 3 = 72cm3
]TahrN_³ cUrrkm:Um:gsþaTicénépÞrabxageRkameFobGkS½kUGredaen.
dMeNaHRsay³
m:Um:g;sþaTicénépÞrabeFobGkS½ X
                         n
            QX = ∑ Ai . yi
                        i =1


A1 = 66 × 10 = 660cm 2
                    10
y1 = 20 + 24 + 30 +    = 79cm
                     2
A2 = 30 × 40 = 1200cm 2
               30
y2 = 20 + 24 +    = 59cm
                2
A3 = 24 × 56 = 1344cm 2
          24
y3 = 20 +    = 32cm
           2
      ⇒ QX = 660 × 79 + 1200 × 59 + 1344 × 32 = 165948cm3
m:Um:g;sþaTicénépÞrabeFobGkS½ Y
m:Um:g;sþaTicénépÞrab                                                                    43
T.Chhay

                           n
               QY = ∑ Ai .x i
                          i =1

                                                         66
               A1 = 66 × 10 = 660cm 2          x1 = 30 +     = 63cm
                                                          2
                                                           40
               A2 = 30 × 40 = 1200cm2            x2 = 30 +     = 50cm
                                                            2
                                                           56
               A3 = 24 × 56 = 1344cm 2           x3 = 30 +    = 58cm
                                                            2
           ⇒ QY = 660 × 63 + 1200 × 50 + 1344 × 58 = 179532cm3

           3> TIRbCMuTMgn;énépÞrab nigTIRbCMuTMgn;énm:as (Centroid and center of gravity)
      TIRbCMuTMgn;énépÞrab CacMnucEdlrkSalMnwgrbs;épÞrab. TIRbCMuTMgn;énm:as
  CacMnucEdlrkSalMnwgrbs;m:as. ebIépÞsmasmYymanRkLaépÞ A nigmanm:assrub M enaH
  y cMgayBITIRbCMuTMgn;eTAGkS½ X nig x cMgayBITIRb CMuTMgn;eTAGkS½ Y .

                                                                    ∑ Ai . y i ∑ Ai . y i
                                                                                                 ∫ y.dA              QX
                                                                                                ( A)
                                                                 y=           =           =                      =
                                                                     ∑ Ai
 cMgayBITIRbCMuTMgn;énépÞeTAGkS½ X nig GkS½ Y                                    A                     A              A

                                                                    ∑ Ai .x i ∑ Ai .x i
                                                                                                 ∫ x.dA Q
                                                                                                ( A)
                                                                 x=          =          =                Y
                                                                                                                 =
                                                                     ∑ Ai       A                      A             A


                                                                ∑ M i . yi ∑ M i . yi
                                                                 y=        =
                                                                 ∑ Mi         M
cMgayBITIRbCMuTMgn;énm:aseTAGkS½ X nig GkS½                Y
                                                                ∑ Ai .xi ∑ Ai .xi
                                                             x=           =
                                                                ∑ Mi         M
  cMNaM³ -sMrab;rUbFatuesμIsac; (homogeneous) TIRbCMuTMgn;énm:as nigTIRbCMuTMgn;énépÞsßitenAelIcMnucEtmYy.
  sMrab;rUbFatusmas TIRbCMuTMgn;énm:as nigTIRbCMuTMgn;énépÞsßitenAelIcMnucBIepSgKña. ¬rUbTI2¦
           -sMrab;rUbFatuesμIsac; cMeBaHépÞrabEdlmanGkS½qøúHTIRbCMuTMgn;rbs;vasßitenAelIGkS½qøúHTaMgenaH.
  ¬rUbTI3¦                       Centroid    Center of gravity




   0.25m
                                                                         Y                                                Y

                      0.38m          0.38m
                                                                                                                                      b
                   Wood            Steel                  h/2
                                                                                    X       h
             rUbTI2 Centroid and center of gravity
                                                          h/2


                                                                      b/2 b/2                                e       b/2 b/2   e


                                                           GkS½ X; Y CaGkS½qøúHrbs;va                      GkS½ Y CaGkS½qøúHrbs;va
                                                                                   rUbTI3
  m:Um:g;sþaTicénépÞrab                                                                                                              44
T.Chhay


taragTI1³ RkLaépÞ nigTIRbCMuTMgn;
                                                                                                                                 Vertex



                                                                                                                                                                        h
                                                             h                                                           h
                                                      h/2                                                                          2
                                                                                                                   h/3               h
                                                                                                                                   5
                                   b/2                                                                     b/3                           3
                                                                                                                                           b
                            b                                                                 b                                          8
                                                                                                                                                           b

                            Rectangle                                                 Right Triangle                                     Second- degree palabola
                                                                                                                                                        2
                                A=b.h                                                         A=b.h/2                                                A = b.h
                                                                                                                                                        3



                                                                                                                                 Vertex


                                                       3                                                          n +1
                                                         h                                                              h
                                                      10                                                         4n + 2                                                 h
                                                               h                                                            h
      Vertex                                                       Vertex                                                        h.n
                                                                                                   b                            2 n +1
                                             b/4
                        b                                                             b           n+2                            b.( n+1)
                                                                                                                                 2( n+ 2)                  b

                  Second- degree palabola                                        th
                                                                               n - degree palabola
                                                                                                                                               th
                                                                                                                                            n - degree palabola
                                 1                                                                      b.h                                              n.b.h
                            A=     b.h                                                            A=                                                A=
                                 3                                                                     n +1                                              n +1




                        a                b

                                                                                                                 2h
                                                             h                                                   5       h
                                                                                                                                                                       4R
                                                      h/3                                                                                                              3π
     1 ( a + L)                                    1 (b + L)                                       b/2                                      R              R
      3                                             3
                            L                                                                 b


                             Triangle                                       Second- degree palabola                                                 Semi-cicle
                             A=L.h/2                                                             2
                                                                                              A = b.h                                                      πR 2
                                                                                                                                                      A=
                                                                                                 3                                                             2



                                                                                          R


                                                                                                       θ

                                                                                                       θ

                                                                                      2 R. sin θ                                                                            R
                     4R             R                                                    3θ
                     3π
                                                                                                                                                                   R
                                                                                  Circular sector
                        Quarter-cicle                                                                                                                 Circle
                                                                                          A = R 2 .θ
                                  πR 2                                                                                                                A = π .R 2
                             A=
                                    4                                  Note: θ is in radians




m:Um:g;sþaTicénépÞrab                                                                                                                                                           45
T.Chhay


]TahrN_³ cUrrkTItaMgTIRbCMuTMgn;eFobnwgkUGredaenEdleKeGay                      Y

dMeNaHRsay³
A1 = 12 × 2 = 24cm 2                    x1 = 1cm               y1 = 6cm

A2 = 2 × 8 = 16cm 2                     x2 = 6cm               y2 = 1cm                                                10cm



TItaMgTIRbCMuTMgn;eFobGkS½kUGredaen                                                          C(3,4)

  A1.x1 + A2 .x2 24 × 1 + 16 × 6
x=               =                = 3cm                                                                                2cm
     A1 + A2         24 + 16                                                                                                  X
                                                                           O
  A . y + A2 . y2 24 × 6 + 16 × 1
y= 1 1           =                = 4cm
                                                                                   2cm         8cm


      A1 + A2        24 + 16


]TahrN_³ cUrrkTItaMgTIRbCMuTMgn;eFobnwgkUGredaenEdleKeGay                                Y

dMeNaHRsay³                                                                                           A2
A1 = 18 × 2 = 36cm            2
                                        x1 = 11cm              y1 = −1cm   6cm




A2 = 12 × 6 = 72cm 2                    x2 = 6cm               y2 = 11cm
                                                                                               A3                A1
A3 = 8 × 6 = 48cm         2
                                        x3 = 3cm               y3 = 4cm
                                                                           8cm


TItaMgTIRbCMuTMgn;eFobGkS½kUGredaen
       A1.x1 + A2 .x2 + A3 .x3 36 × 11 + 72 × 6 + 48 × 3                                                                           X
x=                            =                                                     O
           A1 + A2 + A3              36 + 72 + 48

⇒ x = 6.23cm                                                               10cm




       A1. y1 + A2 . y2 + A3 . y3 36 × (− 1) + 72 × 11 + 48 × 4
y=                               =                                                             6cm         4cm   2cm
            A1 + A2 + A3                  36 + 72 + 48

⇒ y = 6.07cm

     4> karrkTIRbCMuTMgn;énépÞrabedayGaMgetRkal (Solving centroid by integration)
        kñúgkarviPaKrkTIRbCMuTMgn; eKRtUvBinitüFatuGnnþtUc dA EdlCabnÞHQr b¤bnÞHedk.
     - rktambnÞHQr (Verticle element strip)
     Edl dA = y.dx
                                                  L
                                      y               y
             ∫ yele .dA
             ( A)
                                   ∫) 2 .dA
                                  (A
                                                  ∫ 2 y.dx
      y=                  =                   =   0

                 ∫ dA               ∫ dA
                                                      L

                ( ) A              ( )
                                    A                 ∫ y.dx
                                                      0




m:Um:g;sþaTicénépÞrab                                                                                                         46
T.Chhay

                        L
                                y2
                        ∫       2
                                   dx                                                                              dx
      ⇒y=               0
                         L
                                                                                                                         x,y

                            ∫ y.dx                                                                                                                 y=f(x)
                            0                                                                            dA=y.dx

     dUcKñaEdr                                                                                                           C(x,y/2)
                                                 L
                                                                                                   H

                 ∫x
              ( A)
                        ele     .dA              ∫ x. y.dx                                                                     C(x/2,y)                         x,y
                                                                                                                                                                      dy
      x=                                     =   0

                        ∫ dA
                                                     L
                                                                                                                                         dA=x.dy
                    ( A)                          ∫ y.dx
                                                     0

     - rktambnÞHedk (Horizontal element strip)                                                                                 L


     Edl dA = x.dy
                                                 H
                                                         x
                 ∫ xele .dA
              ( A)
                                                 ∫ 2 .x.dy
      x=                                     =   0

                     ∫ dA
                                                     H

                    ( ) A                            ∫ x.dy
                                                     0
                        H           2
                                x
                        ∫ 2 dy
      ⇒x=               0
                         H

                            ∫ x.dy
                            0
                                                 H

                 ∫ yele .dA
                 ( A)
                                                 ∫ y.x.dy
      y=                                     =   0

                        ∫ dA
                                                  H

                    ( A)                             ∫ x.dy
                                                     0

]TahrN_³ kMNt;TIRbCMuTMgn;rbs;épÞrab
dUcbgðajkñúgrUb.
                                                                                                                               y = f (x) =
                                                                                                                                             H
dMeNaHRsay³                                                                                                                                  L2
                                                                                                                                                  x2



FatuGnnþtUcman                                                                                           H
                                                                                                                                                       dx

                                                                                  y
dA = y.dx                               xele = x                         yele =
                                                                                  2                          yele =y/2
TItaMgTIRbCMuTMgn;                                                                                                                                          C


                                        L                        L                             L
                                                                      H 2                 x4
       ∫x
      ( A)
             ele   .dA                  ∫ x. y.dx                ∫ x. L2 x .dx            4         3
                                                                                                                                xele=x

x=                              =       0
                                                             =   0
                                                                                      =      0
                                                                                                   = L                                    L
             ∫ dA
                                         L                           L                     3 L
                                                                       H                            4
                                         ∫ y.dA                      ∫ L2 x.dx
                                                                                          x
          ( A)
                                         0                           0                    3    0




m:Um:g;sþaTicénépÞrab                                                                                                                                                      47
T.Chhay


                            L                L                              L
                              y                H2 4                H 2 x5
       ∫ yele .dA
       ( A)
                            ∫ 2 y.dx         ∫ 2 L4 x .dx              .
                                                                   2 L4 5           3H
y=                      =   0
                                         =   0
                                                               =          0
                                                                                =
              ∫ dA
                                L            L                         3 L
                                                 H                                  10
                                ∫ y.dx       ∫L      x 2 .dx       H x
          ( A)                                   2                   .
                                0            0                     L2 3     0


dUcenH           3 3
              C ( L; H )
                 4 10




m:Um:g;sþaTicénépÞrab                                                                    48
T.Chhay


lMhat;
   1>            cUrkMNt;rkTIRbCMuTMgn;nUvragFrNImaRtxageRkamedayviFIGaMgetRkal
   k.



     x>



     K>




     X>




     2> cUrkMNt;nUvTIRbCMuTMgn;épÞsmasxageRkam
     k> edayKitBIRCugxagelI nigxageqVg




m:Um:g;sþaTicénépÞrab                                                             49
T.Chhay


     x> edayeFobnwgGkS½ X nig Y




     K> edayeFobnwgGkS½ X nig Y




     X> edayeFobnwgGkS½ X nig Y




     g> edayeFobnwgGkS½ X nig Y




m:Um:g;sþaTicénépÞrab             50
T.Chhay


     c> edayeFobnwgGkS½ X nig Y




     q> edayeFobnwgGkS½ X nig Y




     C> edayeFobnwgGkS½ X nig Y




m:Um:g;sþaTicénépÞrab             51
T.Chhay


     Q> cUrkMNt;TIRbCMuTMgn;énrgVg;TaMgR)aMtamGkS½Qr edayeFobnwgépÞxagelIrbs;ctuekaN




     d> cUrkMNt;TIRbCMuTMgn;rbs;EdkxageRkamEdlmanrUbragdUcbgðajxageRkam




m:Um:g;sþaTicénépÞrab                                                                  52

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4.first moment of area11

  • 1. T.Chhay m:Um:g;sþaTicénépÞrab First moment of area 1> niymn½y (Definition) m:Um:g;sþaTicénépÞrab A eFobnwgGkS½ X CaGaMgetRkalépÞGnnþtUc dA éncMgayBITIRbCMuTMgn;énépÞ GnnþtUcenaHeTAGkS½ X . ¬rUbTI1¦ QX = ∫ y.dA ( A) Edl - m:Um:g;sþTicénépÞrab A eFobnwgGkS½ X QX y - cMgayBITIRbCMuTMgn;énépÞGnnþtUc dA eTAGkS½ X dA -épÞGnnþtUc dUcKña m:Um:g;sþaTicénépÞrab A eFobnwgGkS½ Y Ca GaMgetRkalépÞGnnþtUc dA éncMgayBITIRbCMuTMgn;énépÞGnnþ tUcenaHeTAGkS½ Y . ¬rUbTI1¦ QY = ∫ x.dA ( A) Edl QY- m:Um:g;sþTicénépÞrab A eFobnwgGkS½ Y x - éncMgayBITIRbCMuTMgn;énépÞGnnþtUc dA eTAGkS½ Y 2> épÞsmas (Composite area) épÞsmas CaépÞEdlpSMeLIgedayrUbFrNImaRtsamBaØCaeRcIn. ebIépÞsmas A mYypSMeLIg edayépÞsamBaØ A / A />>>/ A EdlmanTIRbCMuTMgn;erogKña c / c />>>/ c ehIy y / y />>>/ y CacMgay 1 2 n 1 2 n 1 2 n erogKñaBITIRbCMuTMgn;TaMgenaHdl;GkS½ X . épÞrab A manTIRbCMuTMgn; c EdlenAcMgay y BIGkS½ X . m:Um:g;sþaTicénépÞsmas A eFobnwgGkS½ X KW³ n QX = A. y = ∑ Ai . yi i =1 dUcKñaenHEdr n QY = A.x = ∑ Ai .xi i =1 Edl A - épÞrab b¤épÞsmas A - épÞsamBaØTI i i y - cMgayBITIRbCMuTMgn;énépÞsmasmkGkS½ X y - cMgayBITIRbCMuTMgn;énépÞsamBaØTI i mkGkS½ X i m:Um:g;sþaTicénépÞrab 42
  • 2. T.Chhay - cMgayBITIRbCMuTMgn;énépÞsmasmkGkS½ Y x x - cMgayBITIRbCMuTMgn;énépÞsamBaØTI i mkGkS½ Y i cMNaM³ m:Um:g;sþaTicénépÞrab A eFobnwgGkS½Edlkat;tamTIRbCMuTMgn;rbs;vamantMélesμIsUnü. ]TahrN_³ cUrrkm:Um:gsþaTicénépÞrabxageRkameFobGkS½kUGredaen. dMeNaHRsay³ m:Um:g;sþaTicénépÞrabeFobGkS½ X QX = A. y Edl A = 6 × 4 = 24cm 2 h 4 y= = = 2cm 2 2 ⇒ QX = 24 × 2 = 48cm3 m:Um:g;sþaTicénépÞrabeFobGkS½ Y QY = A.x Edl A = 6 × 4 = 24cm 2 b 6 x= = = 3cm 2 2 ⇒ QY = 24 × 3 = 72cm3 ]TahrN_³ cUrrkm:Um:gsþaTicénépÞrabxageRkameFobGkS½kUGredaen. dMeNaHRsay³ m:Um:g;sþaTicénépÞrabeFobGkS½ X n QX = ∑ Ai . yi i =1 A1 = 66 × 10 = 660cm 2 10 y1 = 20 + 24 + 30 + = 79cm 2 A2 = 30 × 40 = 1200cm 2 30 y2 = 20 + 24 + = 59cm 2 A3 = 24 × 56 = 1344cm 2 24 y3 = 20 + = 32cm 2 ⇒ QX = 660 × 79 + 1200 × 59 + 1344 × 32 = 165948cm3 m:Um:g;sþaTicénépÞrabeFobGkS½ Y m:Um:g;sþaTicénépÞrab 43
  • 3. T.Chhay n QY = ∑ Ai .x i i =1 66 A1 = 66 × 10 = 660cm 2 x1 = 30 + = 63cm 2 40 A2 = 30 × 40 = 1200cm2 x2 = 30 + = 50cm 2 56 A3 = 24 × 56 = 1344cm 2 x3 = 30 + = 58cm 2 ⇒ QY = 660 × 63 + 1200 × 50 + 1344 × 58 = 179532cm3 3> TIRbCMuTMgn;énépÞrab nigTIRbCMuTMgn;énm:as (Centroid and center of gravity) TIRbCMuTMgn;énépÞrab CacMnucEdlrkSalMnwgrbs;épÞrab. TIRbCMuTMgn;énm:as CacMnucEdlrkSalMnwgrbs;m:as. ebIépÞsmasmYymanRkLaépÞ A nigmanm:assrub M enaH y cMgayBITIRbCMuTMgn;eTAGkS½ X nig x cMgayBITIRb CMuTMgn;eTAGkS½ Y . ∑ Ai . y i ∑ Ai . y i ∫ y.dA QX ( A) y= = = = ∑ Ai cMgayBITIRbCMuTMgn;énépÞeTAGkS½ X nig GkS½ Y A A A ∑ Ai .x i ∑ Ai .x i ∫ x.dA Q ( A) x= = = Y = ∑ Ai A A A ∑ M i . yi ∑ M i . yi y= = ∑ Mi M cMgayBITIRbCMuTMgn;énm:aseTAGkS½ X nig GkS½ Y ∑ Ai .xi ∑ Ai .xi x= = ∑ Mi M cMNaM³ -sMrab;rUbFatuesμIsac; (homogeneous) TIRbCMuTMgn;énm:as nigTIRbCMuTMgn;énépÞsßitenAelIcMnucEtmYy. sMrab;rUbFatusmas TIRbCMuTMgn;énm:as nigTIRbCMuTMgn;énépÞsßitenAelIcMnucBIepSgKña. ¬rUbTI2¦ -sMrab;rUbFatuesμIsac; cMeBaHépÞrabEdlmanGkS½qøúHTIRbCMuTMgn;rbs;vasßitenAelIGkS½qøúHTaMgenaH. ¬rUbTI3¦ Centroid Center of gravity 0.25m Y Y 0.38m 0.38m b Wood Steel h/2 X h rUbTI2 Centroid and center of gravity h/2 b/2 b/2 e b/2 b/2 e GkS½ X; Y CaGkS½qøúHrbs;va GkS½ Y CaGkS½qøúHrbs;va rUbTI3 m:Um:g;sþaTicénépÞrab 44
  • 4. T.Chhay taragTI1³ RkLaépÞ nigTIRbCMuTMgn; Vertex h h h h/2 2 h/3 h 5 b/2 b/3 3 b b b 8 b Rectangle Right Triangle Second- degree palabola 2 A=b.h A=b.h/2 A = b.h 3 Vertex 3 n +1 h h 10 4n + 2 h h h Vertex Vertex h.n b 2 n +1 b/4 b b n+2 b.( n+1) 2( n+ 2) b Second- degree palabola th n - degree palabola th n - degree palabola 1 b.h n.b.h A= b.h A= A= 3 n +1 n +1 a b 2h h 5 h 4R h/3 3π 1 ( a + L) 1 (b + L) b/2 R R 3 3 L b Triangle Second- degree palabola Semi-cicle A=L.h/2 2 A = b.h πR 2 A= 3 2 R θ θ 2 R. sin θ R 4R R 3θ 3π R Circular sector Quarter-cicle Circle A = R 2 .θ πR 2 A = π .R 2 A= 4 Note: θ is in radians m:Um:g;sþaTicénépÞrab 45
  • 5. T.Chhay ]TahrN_³ cUrrkTItaMgTIRbCMuTMgn;eFobnwgkUGredaenEdleKeGay Y dMeNaHRsay³ A1 = 12 × 2 = 24cm 2 x1 = 1cm y1 = 6cm A2 = 2 × 8 = 16cm 2 x2 = 6cm y2 = 1cm 10cm TItaMgTIRbCMuTMgn;eFobGkS½kUGredaen C(3,4) A1.x1 + A2 .x2 24 × 1 + 16 × 6 x= = = 3cm 2cm A1 + A2 24 + 16 X O A . y + A2 . y2 24 × 6 + 16 × 1 y= 1 1 = = 4cm 2cm 8cm A1 + A2 24 + 16 ]TahrN_³ cUrrkTItaMgTIRbCMuTMgn;eFobnwgkUGredaenEdleKeGay Y dMeNaHRsay³ A2 A1 = 18 × 2 = 36cm 2 x1 = 11cm y1 = −1cm 6cm A2 = 12 × 6 = 72cm 2 x2 = 6cm y2 = 11cm A3 A1 A3 = 8 × 6 = 48cm 2 x3 = 3cm y3 = 4cm 8cm TItaMgTIRbCMuTMgn;eFobGkS½kUGredaen A1.x1 + A2 .x2 + A3 .x3 36 × 11 + 72 × 6 + 48 × 3 X x= = O A1 + A2 + A3 36 + 72 + 48 ⇒ x = 6.23cm 10cm A1. y1 + A2 . y2 + A3 . y3 36 × (− 1) + 72 × 11 + 48 × 4 y= = 6cm 4cm 2cm A1 + A2 + A3 36 + 72 + 48 ⇒ y = 6.07cm 4> karrkTIRbCMuTMgn;énépÞrabedayGaMgetRkal (Solving centroid by integration) kñúgkarviPaKrkTIRbCMuTMgn; eKRtUvBinitüFatuGnnþtUc dA EdlCabnÞHQr b¤bnÞHedk. - rktambnÞHQr (Verticle element strip) Edl dA = y.dx L y y ∫ yele .dA ( A) ∫) 2 .dA (A ∫ 2 y.dx y= = = 0 ∫ dA ∫ dA L ( ) A ( ) A ∫ y.dx 0 m:Um:g;sþaTicénépÞrab 46
  • 6. T.Chhay L y2 ∫ 2 dx dx ⇒y= 0 L x,y ∫ y.dx y=f(x) 0 dA=y.dx dUcKñaEdr C(x,y/2) L H ∫x ( A) ele .dA ∫ x. y.dx C(x/2,y) x,y dy x= = 0 ∫ dA L dA=x.dy ( A) ∫ y.dx 0 - rktambnÞHedk (Horizontal element strip) L Edl dA = x.dy H x ∫ xele .dA ( A) ∫ 2 .x.dy x= = 0 ∫ dA H ( ) A ∫ x.dy 0 H 2 x ∫ 2 dy ⇒x= 0 H ∫ x.dy 0 H ∫ yele .dA ( A) ∫ y.x.dy y= = 0 ∫ dA H ( A) ∫ x.dy 0 ]TahrN_³ kMNt;TIRbCMuTMgn;rbs;épÞrab dUcbgðajkñúgrUb. y = f (x) = H dMeNaHRsay³ L2 x2 FatuGnnþtUcman H dx y dA = y.dx xele = x yele = 2 yele =y/2 TItaMgTIRbCMuTMgn; C L L L H 2 x4 ∫x ( A) ele .dA ∫ x. y.dx ∫ x. L2 x .dx 4 3 xele=x x= = 0 = 0 = 0 = L L ∫ dA L L 3 L H 4 ∫ y.dA ∫ L2 x.dx x ( A) 0 0 3 0 m:Um:g;sþaTicénépÞrab 47
  • 7. T.Chhay L L L y H2 4 H 2 x5 ∫ yele .dA ( A) ∫ 2 y.dx ∫ 2 L4 x .dx . 2 L4 5 3H y= = 0 = 0 = 0 = ∫ dA L L 3 L H 10 ∫ y.dx ∫L x 2 .dx H x ( A) 2 . 0 0 L2 3 0 dUcenH 3 3 C ( L; H ) 4 10 m:Um:g;sþaTicénépÞrab 48
  • 8. T.Chhay lMhat; 1> cUrkMNt;rkTIRbCMuTMgn;nUvragFrNImaRtxageRkamedayviFIGaMgetRkal k. x> K> X> 2> cUrkMNt;nUvTIRbCMuTMgn;épÞsmasxageRkam k> edayKitBIRCugxagelI nigxageqVg m:Um:g;sþaTicénépÞrab 49
  • 9. T.Chhay x> edayeFobnwgGkS½ X nig Y K> edayeFobnwgGkS½ X nig Y X> edayeFobnwgGkS½ X nig Y g> edayeFobnwgGkS½ X nig Y m:Um:g;sþaTicénépÞrab 50
  • 10. T.Chhay c> edayeFobnwgGkS½ X nig Y q> edayeFobnwgGkS½ X nig Y C> edayeFobnwgGkS½ X nig Y m:Um:g;sþaTicénépÞrab 51
  • 11. T.Chhay Q> cUrkMNt;TIRbCMuTMgn;énrgVg;TaMgR)aMtamGkS½Qr edayeFobnwgépÞxagelIrbs;ctuekaN d> cUrkMNt;TIRbCMuTMgn;rbs;EdkxageRkamEdlmanrUbragdUcbgðajxageRkam m:Um:g;sþaTicénépÞrab 52