Lesson 12.6, For use with pages 680-684
Evaluate.
1. 3! 2. 5!
Lesson 12.6, For use with pages 680-684
Evaluate.
ANSWER 6
1. 3! 2. 5!
ANSWER 120
Combinations
Section 12.6
Essential Questions
• What are the differences between
permutations and combinations?
• What are the differences between odds
and probability?
• How is probability used to make
predictions?
• What are the differences between
experimental and theoretical probabilities?
• In this section we will learn about selecting
items when order is not important.
• Combination: is a group of items whose
order is NOT important.
• For example – if I were to select three
students from HR to serve on a
committee. The order in which I selected
these 3 does not matter. They form a
committee or group. This is also called a
combination.
• Students A, B, C & D (4) are trying out for
a volleyball team. There are slots for only
3 players. What are the combinations of 3
players that could be chosen for the
team?
• Make an organized list.
• A-B-C
• A-B-D
• A-C-D
• B-C-D
• There are only 4 combinations of 3 players
chosen from a group of 4 players.
EXAMPLE 1 Listing Combinations
County Fair
You have 4 tickets to the county fair and can
take 3 of your friends. You can choose from
Abby (A), Brian (B), Chloe (C), and David (D).
How many different choices of groups of
friends do you have?
SOLUTION
List all possible arrangements of three
friends. Then cross out any duplicate
groupings that represent the same group of
friends.
EXAMPLE 1 Listing Combinations
ABC, ACB, BAC,
BCA, CAB, and
CBA all represent
the same group.
ANSWER
You have 4 different choices of groups to take to
the fair.
Combination
To find the number of combinations of n
objects taken r at a time.
nCr = nPr
r!
If you selected 4 out of 10
books, the notation would
look like this.
10C4 =10P4
4!
Combination
If you selected 4 out of 10 books, the
notation would look like this.
10C4 10P4
4!
= =
10 · 9 · 8 · 7
4 · 3 · 2 · 1
= 210=
5040
24
EXAMPLE 2 Evaluating Combinations
Find the number of combinations.
Combination formulaa.
8C3 = 8P3
3!
= 56 Simplify.
3!
=
8 · 7 · 6
=
8 · 7 · 6
3 · 2 · 1
Expand 3! = 3 · 2 · 1.
Divide out common factors
(8 3)!8 P3=
8!
–
= 8 · 7 · 6
EXAMPLE 2 Evaluating Combinations
b. 9C 7 =
9P7
7!
Combination formula
9 P7 =
9!
(9 7)!–
= 9·8·7·6·5·4·3
Expand 7!.
= 36 Simplify.
=
9 · 8 · 7 · 6 · 5 · 4 · 3
7!
4
1
=
9 · 8 · 7 · 6 · 5 · 4 · 3
7 · 6 · 5 · 4 · 3 · 2 · 1 Divide out common
factors.
GUIDED PRACTICE for Example 2
Find the number of combinations.
2. 8C8 Combination formula
8 · 7 · 6 · 5 · 4 · 3 · 2 · 1=
8!
8 C8 =
(8 - 8)!
8! 8!
0!
=
= 1 Simplify.
8 · 7 · 6 · 5 · 4 · 3 · 2 · 1
=
8 · 7 · 6 · 5 · 4 · 3 · 2 · 1
Expand 8!.= 8 · 7 · 6 · 5 · 4 · 3 · 2 · 1
8p8
8!
=
Divide out common factors.
Tell whether the possibilities can be counted using a
permutation or combination. Then write an
expression for the number of possibilities.
3. You want to use a set of 8 lamps for a window
display. Find how many sets you can choose
from 25 lamps in the stock room.
ANSWER combination; 25C8 = 1,081,575
4. How many different ways can you select a
preferred color and a substitute color from a
mail-order catalog offering 12 colors of slacks?
ANSWER permutation; 12P2 = 132
Tell whether the possibilities can be counted using a
permutation or combination. Then write an
expression for the number of possibilities.
There are 8 swimmers in the 400 meter freestyle
race. In how many ways can the swimmers
finish first, second, and third?
Swimminga.
SOLUTION
Because the swimmers can finish first, second,
or third, order is important. So the possibilities
can be counted by evaluating 8P3 = 336
a.
EXAMPLE 3 Permutations and Combinations
Your track team has 6 runners available for
the 4 person relay event. How many
different 4 person teams can be chosen?
Trackb.
Order is not important in choosing the team
members, so the possibilities can be
counted by evaluating 6C4 = 15.
b.
SOLUTION
GUIDED PRACTICE for Example 3
A pizza shop offers 12 different pizza
toppings. How many different 3 - topping
pizzas are possible?
Pizza Toppings7.
Order is not important in choosing the team
members, so the combination possibilities can
be counted by evaluating 12C3 = 220.
SOLUTION
GUIDED PRACTICE for Example 3
Student Council
There are 15 members on the student council. In
how many ways can they elect a president and a
vice president for the council?
8.
SOLUTION
Because they elect a president and a vice
president order is important. So the permutation
possibilities can be counted by evaluating
15P2 = 210.
Homework
• Page 682 #1-21

12.6 combinations 1

  • 1.
    Lesson 12.6, Foruse with pages 680-684 Evaluate. 1. 3! 2. 5!
  • 2.
    Lesson 12.6, Foruse with pages 680-684 Evaluate. ANSWER 6 1. 3! 2. 5! ANSWER 120
  • 3.
  • 4.
    Essential Questions • Whatare the differences between permutations and combinations? • What are the differences between odds and probability? • How is probability used to make predictions? • What are the differences between experimental and theoretical probabilities?
  • 5.
    • In thissection we will learn about selecting items when order is not important. • Combination: is a group of items whose order is NOT important. • For example – if I were to select three students from HR to serve on a committee. The order in which I selected these 3 does not matter. They form a committee or group. This is also called a combination.
  • 6.
    • Students A,B, C & D (4) are trying out for a volleyball team. There are slots for only 3 players. What are the combinations of 3 players that could be chosen for the team? • Make an organized list.
  • 7.
    • A-B-C • A-B-D •A-C-D • B-C-D • There are only 4 combinations of 3 players chosen from a group of 4 players.
  • 8.
    EXAMPLE 1 ListingCombinations County Fair You have 4 tickets to the county fair and can take 3 of your friends. You can choose from Abby (A), Brian (B), Chloe (C), and David (D). How many different choices of groups of friends do you have? SOLUTION List all possible arrangements of three friends. Then cross out any duplicate groupings that represent the same group of friends.
  • 9.
    EXAMPLE 1 ListingCombinations ABC, ACB, BAC, BCA, CAB, and CBA all represent the same group. ANSWER You have 4 different choices of groups to take to the fair.
  • 10.
    Combination To find thenumber of combinations of n objects taken r at a time. nCr = nPr r! If you selected 4 out of 10 books, the notation would look like this. 10C4 =10P4 4!
  • 11.
    Combination If you selected4 out of 10 books, the notation would look like this. 10C4 10P4 4! = = 10 · 9 · 8 · 7 4 · 3 · 2 · 1 = 210= 5040 24
  • 12.
    EXAMPLE 2 EvaluatingCombinations Find the number of combinations. Combination formulaa. 8C3 = 8P3 3! = 56 Simplify. 3! = 8 · 7 · 6 = 8 · 7 · 6 3 · 2 · 1 Expand 3! = 3 · 2 · 1. Divide out common factors (8 3)!8 P3= 8! – = 8 · 7 · 6
  • 13.
    EXAMPLE 2 EvaluatingCombinations b. 9C 7 = 9P7 7! Combination formula 9 P7 = 9! (9 7)!– = 9·8·7·6·5·4·3 Expand 7!. = 36 Simplify. = 9 · 8 · 7 · 6 · 5 · 4 · 3 7! 4 1 = 9 · 8 · 7 · 6 · 5 · 4 · 3 7 · 6 · 5 · 4 · 3 · 2 · 1 Divide out common factors.
  • 14.
    GUIDED PRACTICE forExample 2 Find the number of combinations. 2. 8C8 Combination formula 8 · 7 · 6 · 5 · 4 · 3 · 2 · 1= 8! 8 C8 = (8 - 8)! 8! 8! 0! = = 1 Simplify. 8 · 7 · 6 · 5 · 4 · 3 · 2 · 1 = 8 · 7 · 6 · 5 · 4 · 3 · 2 · 1 Expand 8!.= 8 · 7 · 6 · 5 · 4 · 3 · 2 · 1 8p8 8! = Divide out common factors.
  • 15.
    Tell whether thepossibilities can be counted using a permutation or combination. Then write an expression for the number of possibilities. 3. You want to use a set of 8 lamps for a window display. Find how many sets you can choose from 25 lamps in the stock room. ANSWER combination; 25C8 = 1,081,575 4. How many different ways can you select a preferred color and a substitute color from a mail-order catalog offering 12 colors of slacks? ANSWER permutation; 12P2 = 132
  • 16.
    Tell whether thepossibilities can be counted using a permutation or combination. Then write an expression for the number of possibilities. There are 8 swimmers in the 400 meter freestyle race. In how many ways can the swimmers finish first, second, and third? Swimminga. SOLUTION Because the swimmers can finish first, second, or third, order is important. So the possibilities can be counted by evaluating 8P3 = 336 a.
  • 17.
    EXAMPLE 3 Permutationsand Combinations Your track team has 6 runners available for the 4 person relay event. How many different 4 person teams can be chosen? Trackb. Order is not important in choosing the team members, so the possibilities can be counted by evaluating 6C4 = 15. b. SOLUTION
  • 18.
    GUIDED PRACTICE forExample 3 A pizza shop offers 12 different pizza toppings. How many different 3 - topping pizzas are possible? Pizza Toppings7. Order is not important in choosing the team members, so the combination possibilities can be counted by evaluating 12C3 = 220. SOLUTION
  • 19.
    GUIDED PRACTICE forExample 3 Student Council There are 15 members on the student council. In how many ways can they elect a president and a vice president for the council? 8. SOLUTION Because they elect a president and a vice president order is important. So the permutation possibilities can be counted by evaluating 15P2 = 210.
  • 20.