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Review
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Question 1
An English test contains five
different essay questions labeled A, B,
C, D, and E. You are supposed to
choose 2 to answer. How many
different ways are there to do this?
A voicemail system password is 1
letter followed by a 3-digit number
less than 600. How many different
voicemail passwords are possible if all
digits are allowed?
Question 2
A family of 3 plans to sit in the
same row at a movie theater. How
many ways can the family be seated
in 3 seats?
Question 3
Ingrid is stringing 3 different
types of beads on a bracelet. How
many ways can she string the next
three beads if they must include one
bead of each type?
Question 4
Nathan wants to order a
sandwich with two of the following
ingredients: mushroom, eggplant,
tomato, and avocado. How many
different sandwiches can Nathan
choose?
Question 5
A group of 8 swimmers are
swimming in a race. Prizes are
given for first, second, and third
place. How many different
outcomes can there be?
Question 6
How many different ways
can 9 people line up for a
picture?
Question 7
Four people need to be selected
from a class of 15 to help clean up
the campus. How many different
ways can the 4 people be chosen?
Question 8
Question 9
Four people need to be selected
from a class of 15 to help clean up
the campus. How many different
ways can the 4 people be chosen, if
the only two girls refuse to help?
A basketball team has 12
members who can play any position.
How many different ways can the
coach choose 5 starting players?
Question 10
A basketball team has 12
members who can play any
position. How many different ways
can the coach choose 5 starting
players if the captain MUST play the
first half?
Question 11
When ordering a pizza, you can
choose 2 toppings from the following:
mushrooms, olives, pepperoni,
pineapple, and sausage. How many
different types of pizza can you order?
Question 12
Nine people in a writing contest
are competing for first, second and
third prize. How many ways can the
3 people be chosen?
Question 13
You are ordering a triple-scoop
ice-cream cone. There are 18 flavors
to choose from and you don’t care
which flavor is on the top, middle, or
bottom. How many different ways can
you select a triple-scoop ice-cream
cone?
Question 14
An art gallery has 12 paintings
in storage. They have room to
display 4 of them, with each painting
in a different room. How many
possible ways can they display the 4
additional paintings.
Question 15
Permutation
GAGANI, MARYNEL C.
A permutation is an arrangement of things
in a certain order or the arrangement of
distinguishable objects without allowing
repetitions among the objects.
In general, if n is a positive integer, then n
factorial denoted by n! is the product of all
positive integers less than or equal to n.
n!=n•(n-1)•(n-2)•…•2•1
Permutation
Compute
The notation P(n,r) represents the number of
permutations (arrangements) of n objects taken r
at a time when r is less than or equal to n.
In general,
P(n,r) = n(n-1)(n-2)(n-3)…(n-r+1)
Permutation
Permutation Formula
)!(
!
),(
rn
n
rnPPrn


Permutation
This formula is used when a counting problem
involves both:
Choosing a subset of r elements from a set of n
elements; and
Arranging the chosen elements.
Permutation
EXAMPLE 1:
Suppose we wish to arrange n = 5 people {a, b,
c, d, e}, standing side by side, for a portrait. How
many such distinct portraits (“permutations”) are
possible?
Permutation
Solution:
There are 5 possible choices for which person stands
in the first position (either a, b, c, d, or e). For each of these
five possibilities, there are 4 possible choices left for who is in
the next position. For each of these four possibilities, there are
3 possible choices left for the next position, and so on.
Therefore, there are 5 × 4 × 3 × 2 × 1 = 120 distinct
permutations.
This number, 5 × 4 × 3 × 2 × 1 (or equivalently, 1 × 2 ×
3 × 4 × 5), is denoted by the symbol “5!” and read “5
factorial”, so we can write the answer succinctly as 5! =
120.
Permutation
Permutation
Examples: 6! = 6 × 5 × 4 × 3 × 2 × 1
= 6 × 5!
= 6 × 120 (by previous calculation)
= 720
3! = 3 × 2 × 1 = 6
2! = 2 × 1 = 2
1! = 1
0! = 1,
Permutation
EXAMPLE 2:
Now suppose we start with the same n = 5
people {a, b, c, d, e}, but we wish to make portraits of
only k = 3 of them at a time. How many such distinct
portraits are possible?
Permutation
Permutation
Answer Key
1. Combination
2. Permutation
3. Permutation
4. Permutation
5. Combination
6. Permutation
7. Permutation
8-12. Combination
13. Permutation
14. Combination
15. Permutation
Special Permutation when
letters must repeat
Example:
How many permutations of the word seem
can be made?
Since there are 4 letters, the total possible
ways is 4! IF each “e” is labeled differently. Also,
there are 2! Ways to permute e1e2. But, since
they are indistinguishable, these duplicates must
be eliminated by dividing by 2!.
Special Permutation when
letters must repeat
The number of permutations of n objects in
which k1 are alike, k2 are alike, etc.
!!...!!
!
321 p
rn
kkkk
n
P 
Special Permutation when
letters must repeat
Special Permutation when
letters must repeat
Find the permutations of the word Mississippi.
Number of Letters
– 11 – Total Letters
– 1 – M
– 4 – I
– 4 – S
– 2 - P
34650
)!2!4!4!1(
!11


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Permutation

  • 3. Question 1 An English test contains five different essay questions labeled A, B, C, D, and E. You are supposed to choose 2 to answer. How many different ways are there to do this?
  • 4. A voicemail system password is 1 letter followed by a 3-digit number less than 600. How many different voicemail passwords are possible if all digits are allowed? Question 2
  • 5. A family of 3 plans to sit in the same row at a movie theater. How many ways can the family be seated in 3 seats? Question 3
  • 6. Ingrid is stringing 3 different types of beads on a bracelet. How many ways can she string the next three beads if they must include one bead of each type? Question 4
  • 7. Nathan wants to order a sandwich with two of the following ingredients: mushroom, eggplant, tomato, and avocado. How many different sandwiches can Nathan choose? Question 5
  • 8. A group of 8 swimmers are swimming in a race. Prizes are given for first, second, and third place. How many different outcomes can there be? Question 6
  • 9. How many different ways can 9 people line up for a picture? Question 7
  • 10. Four people need to be selected from a class of 15 to help clean up the campus. How many different ways can the 4 people be chosen? Question 8
  • 11. Question 9 Four people need to be selected from a class of 15 to help clean up the campus. How many different ways can the 4 people be chosen, if the only two girls refuse to help?
  • 12. A basketball team has 12 members who can play any position. How many different ways can the coach choose 5 starting players? Question 10
  • 13. A basketball team has 12 members who can play any position. How many different ways can the coach choose 5 starting players if the captain MUST play the first half? Question 11
  • 14. When ordering a pizza, you can choose 2 toppings from the following: mushrooms, olives, pepperoni, pineapple, and sausage. How many different types of pizza can you order? Question 12
  • 15. Nine people in a writing contest are competing for first, second and third prize. How many ways can the 3 people be chosen? Question 13
  • 16. You are ordering a triple-scoop ice-cream cone. There are 18 flavors to choose from and you don’t care which flavor is on the top, middle, or bottom. How many different ways can you select a triple-scoop ice-cream cone? Question 14
  • 17. An art gallery has 12 paintings in storage. They have room to display 4 of them, with each painting in a different room. How many possible ways can they display the 4 additional paintings. Question 15
  • 19. A permutation is an arrangement of things in a certain order or the arrangement of distinguishable objects without allowing repetitions among the objects. In general, if n is a positive integer, then n factorial denoted by n! is the product of all positive integers less than or equal to n. n!=n•(n-1)•(n-2)•…•2•1 Permutation
  • 21. The notation P(n,r) represents the number of permutations (arrangements) of n objects taken r at a time when r is less than or equal to n. In general, P(n,r) = n(n-1)(n-2)(n-3)…(n-r+1) Permutation
  • 23. Permutation This formula is used when a counting problem involves both: Choosing a subset of r elements from a set of n elements; and Arranging the chosen elements.
  • 24. Permutation EXAMPLE 1: Suppose we wish to arrange n = 5 people {a, b, c, d, e}, standing side by side, for a portrait. How many such distinct portraits (“permutations”) are possible?
  • 25. Permutation Solution: There are 5 possible choices for which person stands in the first position (either a, b, c, d, or e). For each of these five possibilities, there are 4 possible choices left for who is in the next position. For each of these four possibilities, there are 3 possible choices left for the next position, and so on. Therefore, there are 5 × 4 × 3 × 2 × 1 = 120 distinct permutations. This number, 5 × 4 × 3 × 2 × 1 (or equivalently, 1 × 2 × 3 × 4 × 5), is denoted by the symbol “5!” and read “5 factorial”, so we can write the answer succinctly as 5! = 120.
  • 27. Permutation Examples: 6! = 6 × 5 × 4 × 3 × 2 × 1 = 6 × 5! = 6 × 120 (by previous calculation) = 720 3! = 3 × 2 × 1 = 6 2! = 2 × 1 = 2 1! = 1 0! = 1,
  • 28. Permutation EXAMPLE 2: Now suppose we start with the same n = 5 people {a, b, c, d, e}, but we wish to make portraits of only k = 3 of them at a time. How many such distinct portraits are possible?
  • 31. Answer Key 1. Combination 2. Permutation 3. Permutation 4. Permutation 5. Combination 6. Permutation 7. Permutation 8-12. Combination 13. Permutation 14. Combination 15. Permutation
  • 32. Special Permutation when letters must repeat Example: How many permutations of the word seem can be made? Since there are 4 letters, the total possible ways is 4! IF each “e” is labeled differently. Also, there are 2! Ways to permute e1e2. But, since they are indistinguishable, these duplicates must be eliminated by dividing by 2!.
  • 34. The number of permutations of n objects in which k1 are alike, k2 are alike, etc. !!...!! ! 321 p rn kkkk n P  Special Permutation when letters must repeat
  • 35. Special Permutation when letters must repeat Find the permutations of the word Mississippi. Number of Letters – 11 – Total Letters – 1 – M – 4 – I – 4 – S – 2 - P 34650 )!2!4!4!1( !11 

Editor's Notes

  1. The order of outcomes is not important, so this situation involves combinations. 5C2 =10
  2. The order of outcomes is important, so this situation involves permutations. 26 x 6 x 10 x 10 =15600
  3. The order of outcomes is important, so this situation involves permutations. ABC ACB BAC BCA CAB CBA 3 x 2 x 1 = 6
  4. The order of outcomes is important, so this situation involves permutations. 3x2x1=6
  5. The order of outcomes is not important, so this situation involves combinations. 4C2 =6
  6. The order of outcomes is important, so this situation involves permutations. 8 x 7 x 6 = 336
  7. The order of outcomes is important, so this situation involves permutations. 9!= 362,880
  8. The order of outcomes is not important, so this situation involves combinations. 15 Choose 4 = 1365
  9. The order of outcomes is not important, so this situation involves combinations. 13 Choose 4 = 715
  10. The order of outcomes is not important, so this situation involves combinations. 12C5 = 792
  11. The order of outcomes is not important, so this situation involves combinations. 11C4 = 330
  12. The order of outcomes is not important, so this situation involves combinations. Combinations: 5 choose 2 = 10
  13. The order of outcomes is important, so this situation involves permutations. Permutation: 9 x 8 x 7 = 504
  14. The order of outcomes is not important, so this situation involves combinations. 18 choose 3 = 816
  15. The order of outcomes is important, so this situation involves permutations. 12 arrange 4 = 11,880