This document provides an example of programming for the 8085 microprocessor. It shows two 8-bit values A and B being XOR'd (exclusive OR operation) together, with the initial values of A and B being 45H (0100 0101 binary) for both. Performing the XOR operation on A and B results in a value of 0110 0111 binary being stored in the accumulator. The carry flag is initially set to 1 but becomes 0 after the operation.

1. MICROPROCESSOR 8085
LECTURE 15
PROGRAMMING EXAMPLE-VI
PROF. SANDIP DAS

3. A=45H=0100 0101
B=45H=0100 0101
CY=1
CY=0
0 1 0 0 0 1 0 10
ACCUMULAT
OR
CARRY
STATUS
0 0 1 0 0 0 1 01
ACCUMULAT
OR
CARRY
STATUS
Solution:

4. So, new A=0010 0010
Next instruction says, XOR B
Where, B=0100 0101
Doing A xor B, we get-
0110 0111
Which is stored in accumulator, thus the content of A=0110
0111
Solution: