How to get pure culture from mixed sample How to get pure culture from mixed sample Solution ANSWER: The two major steps involved in obtaining pure culture from a mixed population. 1)First, take the mixture and make them to dilute until the various micro organisms individuals become separated far.After incubation on the agar plate form visible colonies isolated from other microorganisms.this is formed on isolated plate. 2)Then an isolated colonies can be picked off from isolated plate, and transferred to a new sterile medium. After incubation all organisms in the new culture will be descendants of the same organism, that forms a pure culture......

1. I came upon this and I would love to know how this works :-)
The majority of your development may take place in the function task2().
1. You need to implement code to output the following line to the screen:
–- Task 2 –-
2.Declare an int array named numbers and initialise it with the following values: 1 4 9 16 9 7 4 9
11 (2 marks)
3. Declare a second array of the same size and using a loop populate it with random numbers in
the range of 1 – 25 inclusive.
4. Use a loop to compute the ‘total’ of the numbers based on the following rule: If the number
being considered is odd then add this to the total, however if the number to be added is even then
subtract this from the total. For example for the initialised array it would compute: 1 4 + 9 16 +
9 + 7 4 + 9 + 11 = 22
5. Print both of the arrays and the results of the ‘total’ operation. For example for the initialised
array the output could resemble: [ 1, 4, 9, 16, 9, 7, 4, 9, 11 ] the total is RESULT Where
RESULT is the calculated value from the ‘total’ operation. Notice that the lists should be comma
space separated and that the final element in the list is not terminated with a comma but with a
space followed by a square bracket. Also note that each line should begin with a left square
bracket followed by a space.
Solution
// C++ code
#include
#include
#include
using namespace std;
int main ()
{
int array1[] = {1,4,9,16,9,7,4,9,11};
int size = sizeof(array1)/sizeof(array1[0]);
int array2[size];
for (int i = 0; i < size; ++i)
{
// random numbers in the range of 1 – 25 inclusive.aa

2. array2[i] = rand() % 25 + 1;
}
int total1 = 0;
int total2 = 0;
for (int i = 0; i < size; ++i)
{
if(array1[i]%2 == 0)
total1 = total1 - array1[i];
else
total1 = total1 + array1[i];
if(array2[i]%2 == 0)
total2 = total2 - array2[i];
else
total2 = total2 + array2[i];
}
cout << " [ ";
for (int i = 0; i < size-1; ++i)
{
cout << array1[i] << ", ";
}
cout << array1[size-1] << " ] the total is " << total1 << endl;
cout << " [ ";
for (int i = 0; i < size-1; ++i)
{
cout << array2[i] << ", ";
}
cout << array2[size-1] << " ] the total is " << total2 << endl;
return 0;
}
/*
output:
[ 1, 4, 9, 16, 9, 7, 4, 9, 11 ] the total is 22
[ 9, 12, 3, 16, 19, 11, 12, 18, 25 ] the total is 9

3. */