Why that partial derivative is zero Why that partial derivative is .pdf

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We are going to put $2500 into an account that earns interest at a rate of 12%. If we w ant to have $4000 in the account when we close it how long should we keep the money in the account if, we compound interest continuously. We compound interest 6 times a year. Solution For compounded interest continuously , the formula of amount is A= Pert Where A= amount, P=Principal, r= rate of interest and t=time period Here Amount ,A= $4000, Principal,P=$2500, Rate of interest,r=12% Substituting these values in the formula 4000=2500e0.12t Dividing both sides by 2500 4000/2500=2500e0.12t/2500 1.6= e0.12t Taking Ln on both sides Ln 1.6=Ln e0.12t .47=0.12t Dividing both sides by 0.12 .47/0.12=0.12t/0.12 3.92=t Or time,t=3.92.

Why that partial derivative is zero? Why that partial derivative is zero? (P + a/V^2)[(partial
differential V/partial differential P)_T - (partial differential b/partial differential P)_T_=0]
Solution
Either B is independent of P or after finding partial derivatives if we put T it's value is zero

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Roll a fair 4-sided dice twice. If A=first roll and B=second roll, then let X=the min(A,B) and Y = |A-B|. a) Give the joint distribution b) Find Cov(X,Y) Solution a) Joint Distribution: (A,B)---->(X,Y) (1,1)---->(1 ,0) (1,2)---->(1,1) (1,3)---->(1,2) (1,4)---->(1,3) (2,1)---->(1,1) (2,2)---->(2,0) (2,3)---->(2,1) (2,4)---->(2,2) (3,1)---->(1,2) (3,2)---->(2,1) (3,3)---->(3,0) (3,4)---->(3,1) (4,1)---->(1,3) (4,2)---->(2,2) (4,3)---->(3,1) (4,4)---->(4,0) b) Cov (X,Y)= E(XY) -E(X)E(Y) E(X) = 30 /16 ( Summation X =30) E(Y) = 20/16 (Summation Y=20) E(XY) = 30/16 (Summation XY =30) Therefore, Cov (X,Y) = 30/16 - ( 30/16 * 20/16) = - 0.4687 ( Negative Correlation ) Answer.

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Provide and discuss examples of sequential, conditional, and iterative operations, from everyday life. How do the ways we state these operations in everyday life differ from ways we state these operations them in pseudocode? Solution 1) Sequential Operations are operations that carried out one after the other. Conditional operations are Operations that are carried out based on certain criteria. Iterative Operations are Operations that are carried out Repeatedly. Examples of them in daily Life 1) Sequential Operations are like waking up, Getting ready and going to School. 2) Conditional Operations are like if it is Weekend we do not need to go to school else if it is a weekday then we have to go to school. 3) Iterative Operations are Operations like if we like a food item we will eat until we feel it is heavy. Difference between them from Pseudo Code 1) Sequential are Operations that are carried out timely in daily life but some may not be initialized always whereas in PseudoCode we have to initialize everything. 2) Conditional also needs initialization whereas in daily life we need not initialize. 3) Iterative are Operations that where a sequential flow is followed and in daily life they can start anytime.

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Part II – Research Dr. Siddiqui tells Angela that her test results will be back in a few days and that she will give her a call when she knows something. You go home and do some research on various thyroid conditions so that you’ll have a good idea of what is going on with Angela. You find information on hyperthyroidism, hypothyroidism, goiter, Graves’ Disease, iodine deficiency (primary hypothyroidism), Hashimoto’s thyroiditis, and various tumors. You make a chart to help yourself sort out the different disorders. Questions 3. Describe hyperthyroidism and hypothyroidism. List at least three symptoms of each. 4. What is a goiter? 5. Please fill out the chart below. Record whether the hormone levels are expected to be high, low, or either. For antibody/immunoglobulins and goiter, answer yes, no, or possible. (The antibodies and immunoglobulins in question are those specific to the thyroid disorder.) Primaryhypothyroidism (iodine deficiency) Graves’Disease Hashimoto’s Disease TRH-secretingtumor TSH-secretingtumor TRH-suppressingtumor TSH-suppressingtumor TRHlevels TSHlevels T3and T4levels Antibodies or immunoglobulins present? Goiterpresent? Ispatient hyper- or hypothyroid? 6. Use the chart below to record whether the hormone levels are expected to be high, low, or either. For antibody/ immunoglobulin and goiter, answer yes, no, or possible. Hypothyroidism Hyperthyroidism TSHlevels T3and T4levels Antibodies or immunoglobulins? Goiterpresent? 7. If you gave a person with primary hypothyroidism (iodine deficiency) an injection of TSH would T3 and T4 levels increase? Why or why not? 8. Some patients with HPT axis problems develop a goiter. Describe two different scenarios/conditions in which a goiter would be present and explain physiologically why/how the goiter occurs within each scenario/condition. Make sure to include axis feedback in your answer. Part III – Test Results Angela’s test results come back and Dr. Siddiqui gives you a copy to look over. Please use the data below and the initial information about Angela to answer the following questions. A. Barber – Test Results Test Result Normal Range Serum thyroxine (T4)(ug/dl) 1.8 4.6-12 Thyrotropin(TSH)(IU/mL) 0.3 0.5-6 TPOand Tg antibodies Normal Normal TSI(immunoglobulins) Normal Normal Serum Triiodothyronine (T3) (ng/dl) 57 80-180 BloodPressure 98/60 90-120/60-80 Hematocrit(%) 39 36-45 Hemoglobin (g/100 ml blood) 12.9 11-14 Glucose(mg/dl) 102 70-110 Sodium (mmol/L) 136 135-145 Potassium(mmol/L) 4.5 3.5-5.0 Questions 9. Are any of Angela’s values outside the normal range? If so, which ones, and are they high or low? 10. Is Angela’s thyroid axis functioning properly? If not, does she have symptoms consistent with hypothyroidism or hyperthyroidism? Part IV – Diagnosis Questions 11. Dr. Siddiqui asks you what you think is wrong with Angela. What is your diagnosis? (Note: do not simply say hyper- or hypothyroidism; that portion of the question was already answered above.) 12. Angela does not hav.

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A department at a university plans to recruit a new faculty member. The 410 applications yielded the following information. A candidate is picked at random and let event A be that the candidate is female and let event8 be that the candidate has 5 or more years of teaching experience. Calculate the following: Are the events A and B mutually exclusive? Justify your answer Are the events A and B independent? Justify your answer. Solution.

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How many different samples of size n = 2 can be selected from this population if you sample without replacement? Please help, thank you! Solution the population contains four elements: 6,2,5,4 the sample size is n=2. the sample is drawn by without replacement. so from 4 elements we can select 2 elements in 4C2 ways. a) number of different samples: 4C2=6 [answer] b)the possible samples are- (2,4) (2,5) (2,6) (4,5) (4,6) (5,6) c) the sample means are [ for (a,b) xbar=(a+b)/2 ] for (2,4) xbar=3 (2,5) xbar=3.5 (2,6) xbar=4 (4,5) xbar=4.5 (4,6) xbar=5 (5,6) xbar=5.5 d) as the sample is drawn using simple random sampling without replacement. all the samples are equally likely. hence the sampling distribution of xbar is option d) p(xbar)=1/6 for all values of xbar= d) the correct histogram is option b) [top right] because it has bars for all the values of xbar=3, 3.5, 4, 4.5, 5, 5.5 with equal length. e) population mean mu= (6+2+4+5)/4=4.25 f) none of the samples produce a value of xbar equal to mu..

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Explain the intercellular junctions found on the lateral surface of an epithelial cell starting from the apical pole and progressing to the basal pole of the cell. How is the terminal bar seen on a light microscope related? Solution Epithelia are tissues composed of closely aggregated cells that cover most body surfaces, cavities, and tubes. Surface epithelia form continuous sheets that can have one or multiple cell layers. Several different types of cell junctions mediate physical strength and cell communication within the epithelium. A basement membrane lies beneath the epithelium and separates it from underlying tissue; because blood vessels do not penetrate the basement membrane, nutrients like oxygen and metabolites reach the epithelium by diffusion. Epithelia are polarized, with an apical surface that faces the external environment and a basal surface that faces the basement membrane. Microvilli are small processes that project from the apical surface of most types of epithelial cells, greatly increasing the surface area. They are notably found at the intestinal brush border and in the proximal convoluted tubule of the kidney. Stereocilia are unusually long, non- motile microvilli that are found on the surface epithelium in the epididymis and ductus deferens. Cilia are actively motile processes with a complex internal structure found on the epithelial lining of the respiratory tract and the female reproductive tract. The basement membrane, a thin non-cellular layer, intervenes between the epithelium and the connective tissue. This membrane is 30 to 60 nanometers thick and made up of collagenous and non-collagenous glycoproteins and proteoglycans. It provides structural support for the epithelium and serves as a selective barrier for the movement of materials to and from the supporting tissue. Using light microscopy, terminar bar appears as a bar at the apical surface of the cell, wherein the structures listed cannot be resolved. With electron microscopy, the terminal bar can be visually disseminated into these structures. The terminal bar is located on the lateral surface of epithelial cells, where the lateral surface meets the apical surface. It should not be confused with the Terminal web, which is an actinous web underlying microvilli on specialized epithelial cells.

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Diastrophic dysplasia- Is an inherited autosomal recessive manner. D represents the normal allele and d represents the mutant. Achondroplasia- Inherited in an autosomal dominant manner A represents the mutant allele and a represents the normal allele. AA individuals do not survive embryogenesis. Both of these make the person small Matt has Diastrophic dysplaisa who is the father. The mother has Achondroplasia- whose family has no history of Diastrophic dysplaisa (assume they are not carriers) They have a son who is also small is it because ofDiastrophic dysplaisa or Achondroplasia. How do you know? Solution The genotypes of the parents are (Mother) AaDD X aadd (Father) Their offspring will be AaDd- who will be exhibiting the character Achondroplasia as it is autosomal dominant.

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1. Why that partial derivative is zero? Why that partial derivative is zero? (P + a/V^2)[(partial differential V/partial differential P)_T - (partial differential b/partial differential P)_T_=0] Solution Either B is independent of P or after finding partial derivatives if we put T it's value is zero