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Rational Numbers
Rational Numbers
                                              a
Rational numbers can be expressed in the form   where a and
b are integers.                               b
Rational Numbers
                                              a
Rational numbers can be expressed in the form   where a and
b are integers.                               b




 Irrational Numbers
Rational Numbers
                                              a
Rational numbers can be expressed in the form   where a and
b are integers.                               b




 Irrational Numbers
Irrational numbers are numbers which are not rational.
All irrational numbers can be expressed as a unique infinite
decimal.
e.g . Prove 2 is irrational
e.g . Prove 2 is irrational
                  “Proof by contradiction”
e.g . Prove 2 is irrational
                  “Proof by contradiction”
      Assume 2 is rational
e.g . Prove 2 is irrational
                  “Proof by contradiction”
      Assume 2 is rational
            a
       2       where a and b are integers with no common factors
            b
e.g . Prove 2 is irrational
                  “Proof by contradiction”
      Assume 2 is rational
            a
       2       where a and b are integers with no common factors
            b
       b 2a
e.g . Prove 2 is irrational
                   “Proof by contradiction”
      Assume 2 is rational
               a
       2         where a and b are integers with no common factors
               b
       b 2a
        2b 2  a 2
e.g . Prove 2 is irrational
                   “Proof by contradiction”
      Assume 2 is rational
               a
       2         where a and b are integers with no common factors
               b
       b 2a
        2b 2  a 2
       Thus a 2 must be divisible by 2
e.g . Prove 2 is irrational
                   “Proof by contradiction”
      Assume 2 is rational
               a
       2         where a and b are integers with no common factors
               b
       b 2a
        2b 2  a 2
       Thus a 2 must be divisible by 2
       Any square that is divisible by 2 is divisible by 4
e.g . Prove 2 is irrational
                   “Proof by contradiction”
      Assume 2 is rational
               a
       2         where a and b are integers with no common factors
               b
       b 2a
        2b 2  a 2
       Thus a 2 must be divisible by 2
       Any square that is divisible by 2 is divisible by 4
      Thus a 2 must be divisible by 4
e.g . Prove 2 is irrational
                   “Proof by contradiction”
      Assume 2 is rational
               a
       2         where a and b are integers with no common factors
               b
       b 2a
        2b 2  a 2
       Thus a 2 must be divisible by 2
       Any square that is divisible by 2 is divisible by 4
      Thus a 2 must be divisible by 4
       2b 2  4k where k is an integer
e.g . Prove 2 is irrational
                   “Proof by contradiction”
      Assume 2 is rational
               a
       2         where a and b are integers with no common factors
               b
       b 2a
        2b 2  a 2
       Thus a 2 must be divisible by 2
       Any square that is divisible by 2 is divisible by 4
      Thus a 2 must be divisible by 4
       2b 2  4k where k is an integer
          b 2  2k
e.g . Prove 2 is irrational
                   “Proof by contradiction”
      Assume 2 is rational
               a
       2         where a and b are integers with no common factors
               b
       b 2a
        2b 2  a 2
       Thus a 2 must be divisible by 2
       Any square that is divisible by 2 is divisible by 4
      Thus a 2 must be divisible by 4
       2b 2  4k where k is an integer
            b 2  2k
   So a 2 and b 2 are both divisible by 2 and must have a common factor
e.g . Prove 2 is irrational
                   “Proof by contradiction”
      Assume 2 is rational
               a
       2         where a and b are integers with no common factors
               b
       b 2a
        2b 2  a 2
       Thus a 2 must be divisible by 2
       Any square that is divisible by 2 is divisible by 4
      Thus a 2 must be divisible by 4
       2b 2  4k where k is an integer
            b 2  2k
   So a 2 and b 2 are both divisible by 2 and must have a common factor
   However, a and b have no common factors
e.g . Prove 2 is irrational
                   “Proof by contradiction”
      Assume 2 is rational
               a
       2         where a and b are integers with no common factors
               b
       b 2a
        2b 2  a 2
       Thus a 2 must be divisible by 2
       Any square that is divisible by 2 is divisible by 4
      Thus a 2 must be divisible by 4
       2b 2  4k where k is an integer
            b 2  2k
   So a 2 and b 2 are both divisible by 2 and must have a common factor
   However, a and b have no common factors
   so 2 is not rational
e.g . Prove 2 is irrational
                   “Proof by contradiction”
      Assume 2 is rational
               a
       2         where a and b are integers with no common factors
               b
       b 2a
        2b 2  a 2
       Thus a 2 must be divisible by 2
       Any square that is divisible by 2 is divisible by 4
      Thus a 2 must be divisible by 4
       2b 2  4k where k is an integer
            b 2  2k
   So a 2 and b 2 are both divisible by 2 and must have a common factor
   However, a and b have no common factors
   so 2 is not rational
    2 is irrational
e.g . Prove 2 is irrational
                   “Proof by contradiction”
      Assume 2 is rational
               a
       2         where a and b are integers with no common factors
               b
       b 2a
        2b 2  a 2
       Thus a 2 must be divisible by 2
       Any square that is divisible by 2 is divisible by 4
      Thus a 2 must be divisible by 4
       2b 2  4k where k is an integer
            b 2  2k
   So a 2 and b 2 are both divisible by 2 and must have a common factor
   However, a and b have no common factors
   so 2 is not rational
    2 is irrational             Exercise 2B; 2a, 3, 4 (root 3), 8, 14*

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11 x1 t02 02 rational & irrational (2013)

  • 2. Rational Numbers a Rational numbers can be expressed in the form where a and b are integers. b
  • 3. Rational Numbers a Rational numbers can be expressed in the form where a and b are integers. b Irrational Numbers
  • 4. Rational Numbers a Rational numbers can be expressed in the form where a and b are integers. b Irrational Numbers Irrational numbers are numbers which are not rational. All irrational numbers can be expressed as a unique infinite decimal.
  • 5. e.g . Prove 2 is irrational
  • 6. e.g . Prove 2 is irrational “Proof by contradiction”
  • 7. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational
  • 8. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational a  2 where a and b are integers with no common factors b
  • 9. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational a  2 where a and b are integers with no common factors b b 2a
  • 10. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational a  2 where a and b are integers with no common factors b b 2a 2b 2  a 2
  • 11. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational a  2 where a and b are integers with no common factors b b 2a 2b 2  a 2 Thus a 2 must be divisible by 2
  • 12. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational a  2 where a and b are integers with no common factors b b 2a 2b 2  a 2 Thus a 2 must be divisible by 2 Any square that is divisible by 2 is divisible by 4
  • 13. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational a  2 where a and b are integers with no common factors b b 2a 2b 2  a 2 Thus a 2 must be divisible by 2 Any square that is divisible by 2 is divisible by 4 Thus a 2 must be divisible by 4
  • 14. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational a  2 where a and b are integers with no common factors b b 2a 2b 2  a 2 Thus a 2 must be divisible by 2 Any square that is divisible by 2 is divisible by 4 Thus a 2 must be divisible by 4  2b 2  4k where k is an integer
  • 15. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational a  2 where a and b are integers with no common factors b b 2a 2b 2  a 2 Thus a 2 must be divisible by 2 Any square that is divisible by 2 is divisible by 4 Thus a 2 must be divisible by 4  2b 2  4k where k is an integer b 2  2k
  • 16. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational a  2 where a and b are integers with no common factors b b 2a 2b 2  a 2 Thus a 2 must be divisible by 2 Any square that is divisible by 2 is divisible by 4 Thus a 2 must be divisible by 4  2b 2  4k where k is an integer b 2  2k So a 2 and b 2 are both divisible by 2 and must have a common factor
  • 17. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational a  2 where a and b are integers with no common factors b b 2a 2b 2  a 2 Thus a 2 must be divisible by 2 Any square that is divisible by 2 is divisible by 4 Thus a 2 must be divisible by 4  2b 2  4k where k is an integer b 2  2k So a 2 and b 2 are both divisible by 2 and must have a common factor However, a and b have no common factors
  • 18. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational a  2 where a and b are integers with no common factors b b 2a 2b 2  a 2 Thus a 2 must be divisible by 2 Any square that is divisible by 2 is divisible by 4 Thus a 2 must be divisible by 4  2b 2  4k where k is an integer b 2  2k So a 2 and b 2 are both divisible by 2 and must have a common factor However, a and b have no common factors so 2 is not rational
  • 19. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational a  2 where a and b are integers with no common factors b b 2a 2b 2  a 2 Thus a 2 must be divisible by 2 Any square that is divisible by 2 is divisible by 4 Thus a 2 must be divisible by 4  2b 2  4k where k is an integer b 2  2k So a 2 and b 2 are both divisible by 2 and must have a common factor However, a and b have no common factors so 2 is not rational  2 is irrational
  • 20. e.g . Prove 2 is irrational “Proof by contradiction” Assume 2 is rational a  2 where a and b are integers with no common factors b b 2a 2b 2  a 2 Thus a 2 must be divisible by 2 Any square that is divisible by 2 is divisible by 4 Thus a 2 must be divisible by 4  2b 2  4k where k is an integer b 2  2k So a 2 and b 2 are both divisible by 2 and must have a common factor However, a and b have no common factors so 2 is not rational  2 is irrational Exercise 2B; 2a, 3, 4 (root 3), 8, 14*