Geometri Transformasi Unnes 2018
- 1. Melukis Bayangan Suatu Segitiga oleh Komposisi Lima
Transformasi
𝐺 𝑃𝑄°𝑀𝑆°𝑅 𝐴,𝜑1
°𝑆 𝐵° 𝐺 𝐾𝐿°𝑀𝑡
OLEH:
PUTRI WIJAYANTI 4101415044
RETNO FARIZUL KHASANAH 4101415045
INTAN SARI 4101415046
NANDA OLGA ELITA 4101415051
ANISA HAYU DIANI 4101415052
- 2. 𝐺 𝑃𝑄°𝑀𝑆°𝑅 𝐴,𝜑1
°𝑆 𝐵° 𝐺 𝐾𝐿°𝑀𝑡
= 𝑀𝑎 ∘ 𝑀𝑏 ∘ 𝑀𝑠 ∘ 𝑀𝑐 ∘ 𝑀𝑑 ∘ 𝑀𝑑 ∘ 𝑀𝑒 ∘ 𝑀𝑓 ∘ 𝑀𝑔 ∘ 𝑀𝑡
= 𝑀𝑎 ∘ (𝑀𝑏 ∘ 𝑀𝑠) ∘ 𝑀𝑐 ∘ (𝑀𝑑 ∘ 𝑀𝑑) ∘ 𝑀𝑒 ∘ 𝑀𝑓 ∘ (𝑀𝑔 ∘ 𝑀𝑡)
= 𝑀𝑎 ∘ 𝑅 𝐷,𝜑2 ∘ 𝑀𝑐 ∘ 𝐼 ∘ 𝑀𝑒 ∘ 𝑀𝑓 ∘ 𝑆𝑐
= 𝑀𝑎 ∘ 𝑅 𝐷,𝜑2 ∘ (𝑀𝑐 ∘ 𝑀𝑒) ∘ 𝑀𝑓 ∘ 𝑆𝑐
= 𝑀𝑎 ∘ 𝑅 𝐷,𝜑2 ∘ 𝑅 𝐸.𝜑3 ∘ 𝑀𝑓 ∘ 𝑆𝑐
= 𝑀𝑎 ∘ (𝑀ℎ ∘ 𝑀𝑖)(𝑀𝑖 ∘ 𝑀𝑗) ∘ 𝑀𝑓 ∘ 𝑆𝑐
= (𝑀𝑎 ∘ 𝑀ℎ) ∘ (𝑀𝑖 ∘ 𝑀𝑖) ∘ (𝑀𝑗 ∘ 𝑀𝑓) ∘ 𝑆𝑐
= 𝑅 𝐹,𝜑4∘ 𝑅 𝐺,,𝜑5 ∘ 𝑆𝑐
= 𝑅 𝐹,𝜑4∘ (𝑀𝑘 ∘ 𝑀𝑙)(𝑀𝑙 ∘ 𝑀𝑚)
= 𝑅 𝐹,𝜑4∘ 𝑀𝑘 ∘ (𝑀𝑙 ∘ 𝑀𝑙) ∘ 𝑀𝑚)
= 𝑅 𝐹,𝜑4∘ 𝑀𝑘 ∘ 𝐼 ∘ 𝑀𝑚
= 𝑅 𝐹,𝜑4∘ (𝑀𝑘 ∘ 𝑀𝑚)
= 𝑅 𝐹,𝜑4 ∘ 𝑅 𝐻,𝜑5
= 𝑀𝑛 ∘ 𝑀𝑜 ∘ 𝑀𝑜 ∘ 𝑀𝑝
= 𝑀𝑛 ∘ 𝑀𝑝
= 𝑅𝐼,𝜑7
Jadi, 𝐺 𝑃𝑄°𝑀𝑆°𝑅 𝐴,𝜑1
°𝑆 𝐵° 𝐺 𝐾𝐿°𝑀𝑡 △ 𝑋𝑌𝑍 = 𝑅𝐼,𝜑7
△ 𝑋𝑌𝑍